The three fundamental equations of motion for uniformly accelerated motion are: v = u + at (final velocity equals initial velocity plus acceleration times time), v² = u² + 2as (final velocity squared equals initial velocity squared plus twice acceleration times distance), and s = ut + (1/2)at² (distance equals initial velocity times time plus half acceleration times time squared). These equations can be applied to solve various motion problems, such as calculating the distance traveled by a car accelerating from 5 m/s to 10 m/s in 5 seconds (37.5 m), or determining the stopping distance of a car decelerating at 6 m/s² to come to rest in 2 seconds (12 m).
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Motion Equations Numericals|Day 8 | கண்டிப்பா Question வரும் | Group D Science 2026
Added:Welcome back to Academy of Motion.
Yeah. Group science next.
question.
First question.
A car starts from rest runs for 2 minutes with an uniform acceleration of 1 m/s squared. Find the speed obtained by a car.
First equation equation equation b = u + a t v + u v v = u + a equation equation v² = u ² + 2 a s equation v = u + a t v² = u ² + 2 a s = u t +/ a t² square.
Initial velocity.
starting.
Okay.
Final velocity Vality.
Okay.
for distance.
First question.
First question. car 1 m square= 1 m² okay time t = 2 minutes.
Second 120 m per second. 120 uh minute. 122nd.
Okay, sorry. 1202 order value 1202.
Starting velocity. Start.
for 2 minutes.
For the Answer U order value zero plus A value 1 m/s² B= U + V 120 m per second. Answer me per second.
com.
Next question.
Kilome per kilometer per hour. Okay.
Kilome per hour.
Starting from rest. Starting from rest.
A train attain a speed of 90 km per hour in 5 minutes. Assuming that the acceleration is same, then the distance traveled by a train at the same time will be and the time train.
Okay.
Tal 5 minutes.
Okay.
Second.
Okay. Time 300 second. Okay. Next hour.
Okay.
0.
U= 0.
Velocity final velocity V= 90 kilome per hour. Kilome per hour me second kilome hour 5 by 18 90 into 5 by 18 m/s 10 m/ second 10 m/s. 10 m/s and distance. Speed time distance 10 18 by hour 18 by 5 by 18 by 18 90 km per hour. 90 foreign.
Okay.
5 by 18 by 18. Okay.
18.
Okay.
distance for the equation. S equal to S = U T +/ A B²= U² + 2 A velocity difference.
Final velocity 25 m/ second.
Acceleration difference 25us vus uid second.
Okay. m/s 25 m/s final velocity minus initial velocity divided by time. Okay.
Yes.
UT 300 plus half a A value 25 by 300 25 by 300 in T² T T value 300 300 into 300 T² 300.
Okay.
25.
Okay.
Two two Fore question.
Okay, next question. Car running at the uniform acceleration speed.
Can find the distance traveled by a car at this time.
Okay.
peri.
A car is running at the uniform acceleration of 1 m/s squared. in 5 seconds at a speed of 5 m/s squared to 10 m/s. 10 m/s. 5 m/s to 10 m/s. Find the distance traveled by a car at this time.
1 m².
Initial velocity 5 m/s. U 5 m/ second. V 10 m/ second. 10 m per second.
Okay.
T= 5 second. Okay.
S = UT² + S = UT² +/ A T² UT +/ A² UT +/ A² UT² S = U +/ A² Okay, value.
U five plus half a order value 1 into a t² t value 5 into 5 25. Okay.
/ 2 / 2 answer 37.5.
Okay. 37.5 m. Next question. Next question.
R me per square brake.
A brake applied to a car produce an acceleration of 6 m/s squared in opposite direction of the motion. If the car take 2 seconds to stop after application of brake, calculate the distance traveled during this time.
- 6 m/s square - 6 m/s square.
Okay.
2 second final velocity velocity zero. Final velocity zero in the 2 second time.
S= A square= U for V = V V² = U² + 2 A S.
Okay. for B= U + A for B = B = U + A E B = U + A T U plus A A - 6 in T 2 U= 12 m per second.
A t² value. Okay.
Rend second into 2 +/ a t²/ a value - 6 t² t value 2 into 2 4 okay 24us 12 m distance First V= U +.
Okay.
in the question.
Okay.
When one box is let fall from a tower, it take 4 seconds.
4 seconds to reach the ground. Determine the distance traveled by a box.
Time= 4 second initial velocity.
Starting in velocity acceleration 9 81 m per second square.
9.8 9.8.
Okay. 9.81 81.8.8 question.
Okay.
S = S = U T. S = U T +/ A T².
Okay.
U² 9.81 value 4 into 4. Okay.
4 2 into 4 8 9 9.81 78 78.48 48 answer 8 78.48 m.
A car accelerated uniformly from 18 kmbh to 72 kmbh in 5 seconds. The acceleration of this car is dash car.
Okay.
18. Okay. 18 km per hour 18 by 18 second. hands.
Val 72 km/h. Final velocity 72 km/ hour 72 by 18.
20 m per second.
Five second difference.
Final velocity 20 20 minus 5 divided by time time value 5 / 5 = 15 / 5 = 3 m per sec 3 second answer 15 3 second Oh, sorry. Sorry. 3 m/s square 3 m/ second square. Sorry. Acceleration.
Acceleration.
Final velocity minus initial velocity.
answer question.
Next group like comfort.
Next video.
Bye.
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