This video demonstrates how to solve the cubic equation X³ = √64 by first simplifying to X³ = 8, then using the difference of cubes formula (a³ - b³ = (a-b)(a²+ab+b²)) to factor the equation into (X-2)(X²+2X+4) = 0, yielding one real solution X = 2 and two complex solutions X = -1 ± i√3 from the quadratic equation X²+2X+4 = 0 solved using the quadratic formula.
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Olympiad Mathematics | Germany | Can You Solve This?Añadido:
Hi, everyone.
If you're ready, let's solve this equation in total detail.
X to the power 3 equals the square root of 64.
And 64 is a perfect square.
So, we have X to the power of 3 to be equal to the square root of 64, and that is 8.
We want to get the complete solution to this equation. So, we're getting three solutions.
And our X to the power of 3 is equal to 8, and the 8 there is 2 to the power of 3.
So, now we'll bring 2 to the 2 to the power of 3 to the left-hand side, so that X to the power of 3 minus 2 to the power of 3 is equal to 0.
And this is um difference of two cubes.
I will know that if we have a cube minus b cube, this is expressed as a plus b a minus b, right?
Then multiply by a squared plus ab plus b squared.
Difference of two cubes.
And according to this standard, our a is x and our b is 2. So, a minus b now will be x minus 2 into a squared, which is x squared, plus ab, that is x times 2, then plus 2 squared.
Because b is 2, and all of this is equal to 0.
From here, we work on the second bracket.
X minus two is over here.
Then X squared plus X times two is two X.
Then two squared is four.
This is equal to zero.
So, we are going to apply our zero product rule.
We apply this rule because we are multiplying two terms together zero. So, either of them will be equal to zero. So, we are saying that X minus two is equal to zero or X squared plus two X plus four is equal to zero.
Now, working on the left-hand side, what we have here our X is going to be zero plus two meaning that X is equal to two.
This is our first solution.
Now, we are going to need two more solutions from here.
And that will come out of this.
By the way, this is a quadratic equation because of the power of two the unknown variable X and the equal sign.
Okay, these are the three conditions that make an equation to be a quadratic equation.
The unknown variable, the power of two, and the equal sign, right? So, let's pick a pick the equation and then solve it.
Okay, so we have our quadratic equation now.
And we want to solve it using the quadratic formula.
The formula has A B C, right?
The A is a coefficient of X squared, which is one.
>> [snorts] >> Then B is a coefficient of X, which is two.
And then the C is the constant which is four.
So, what is the formula then? The formula is X equals minus B plus or minus B squared minus four AC all over two times A.
So, what we're going to do now is to put the value of ABC into the formula.
So, that our X will be minus two because B is two, right? Then plus or minus B squared which is two squared.
Then we have minus four times A times C.
A is one, C is four.
And it is all over two times one.
So, from here now we get our X to be minus two plus or minus we have two squared is four. Then four times one times four is 16.
And we're dividing by two.
Now, the value of X is equal to we have minus two plus or minus then the square root of four minus 16 is minus 12.
And this is all over two.
From here, our X is going to be minus two plus or minus square root of 12 multiplied by square root of negative one.
Okay, so I had to do this so that we can easily get the square root of 12.
And um this is all over two. In case you do not know if you multiply root 12 by root negative one, you're going to get root negative 12.
Now, let's work on the root 12 there.
Root 12 of here can be, you know, split to get root 4 * 3 then multiply by I cuz square root of -1 is I. 4 * 3 is 12.
And we still have this over 2.
Now, since we can split this, we can find the square root of 4 separately and then find the square root of 3.
So, our X is -2 plus or minus square root of 4 will give us 2.
Multiply this 2 by this I, so we're having 2i.
Then root 3 will come down here and it's all over 2.
Okay. So, from here now, what should we do?
We can reduce this equation this value.
By the way, 2 is a common factor. So, we can factor out 2 from the numerator.
So, if 2 comes out, we have -1 from here then plus or minus I because 2 is already out, then we have root 3.
This is all over 2.
So, this one here can go with this.
And that means that our value of X is um -1 plus or minus we have I root 3.
And in case you do not know, this is a two-in-one solution because of the plus or minus.
So, this means that our X is equal to -1 plus I root 3 or -1 - I root 3.
Now, we're going to bring the three solutions together.
Okay, I'm going to write the three solutions here.
X1 that we got before now is equal to two.
Then X2 is from here, this particular one.
And it's minus one plus I root three.
Right? That's our second solution. Then the third solution X3 is equal to minus one minus I root three. So, these three are the solutions to the equation.
Thank you for watching.
Remember this is minus one.
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