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This Integral Trick Saves You in Exams!
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1,356 views64likes55nailibOriginal Release: 2026-05-16

To integrate 1/(x² - 4x + 5), complete the square in the denominator to get (x-2)² + 1, then apply the standard formula ∫1/(u² + 1) du = tan⁻¹(u) + C, yielding the final answer tan⁻¹(x-2) + C.

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