Euler's number e can be trapped between two rational fractions (19/7 and 1140/419) using a single definite integral from 0 to 1, where integration by parts yields the expression 14e - 38, and the strict positivity of the integrand provides a lower bound while overestimating the area with e^x < e provides an upper bound.
深掘り
前提条件
- データがありません。
次のステップ
- データがありません。
深掘り
A Calculus Proof That Traps Euler’s Number (e)追加:
Want to perfectly trap Euler's number between two rational fractions? Here's a beautiful calculus trick using a single elegant integral from zero to one.
First, expand the polynomial and apply integration by parts. When we evaluate the bounds, the entire integral simplifies cleanly to 14e - 38. Now, look at the graph. The integrand stays strictly positive between zero and one.
So, the total area under the curve must be greater than zero. With a little algebra, we get our first result. E is strictly greater than 19/7.
Next, we find an upper bound by overestimating the area. Since e to the x is always less than e on this interval, we can pull an e outside the integral. The remaining polynomial integrates to 1/30, giving an upper estimate of e over 30. That means the exact area, 14e - 38, must be less than e over 30.
Solving this inequality shows that e is perfectly trapped between 19/7 and 1140/419.
関連おすすめ
Escaping the Fog
LogicLemurGaming
760 views•2026-06-03
Olympiad Mathematics | Indian | Can You Solve This One?
PhilCoolMath
650 views•2026-06-03
A Brutal Radical Expression Made Easy! The Shortcut Changes Everything.
tamoshop
112 views•2026-06-02
V : jee main /advance class 11 mathematics : Binomial Theorem class-1 ( 29 may 2026 )
dcamclassesiitjeemainsadva9953
125 views•2026-05-29
Is This Pentomino Tileable?
3cycle
241 views•2026-05-30
This Sudoku Has Many Lines!!
CrackingTheCryptic
2K views•2026-05-29
Olympiad Mathematics | Indian Can You Solve This One?
PhilCoolMath
268 views•2026-06-02
Olympiad Mathematics | Indian | Can You Solve This?
PhilCoolMath
669 views•2026-06-02











