To solve a system of equations where x + y = 10 and xy = 10, first express x in terms of y from the first equation (x = 10 - y), then substitute this into the second equation to form a quadratic equation (y² - 10y + 10 = 0). Apply the quadratic formula to find y = 5 ± √15, then substitute back to find corresponding x values, yielding the solution pairs (x, y) = (5 - √15, 5 + √15) and (x, y) = (5 + √15, 5 - √15).
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Olympiad Mathematics | Russian | Can You Solve This?Added:
If you're ready, let's provide the solution to this one very quickly.
We have x + y = 10.
And this is our equation one.
We also have xy = 10.
And it's our equation two.
We're going to solve these two equations simultaneously.
So, what do we do first?
From equation one, from equation one, we're going to make x the subject.
So, that our x from equation one will be 10 - y.
Right?
And this will turn to our equation three.
We're going to need this equation three to get the value of x.
Now, put this equation two, I mean equation three into equation two.
Okay, we're going to substitute this into equation two.
And our equation two is xy = 10, right?
But now, our x is 10 - y. So, here we have 10 - y to multiply y.
And it's equal to 10.
So, the next point is to open the bracket. 10 * y, that is 10y.
- y * y, that is - y squared.
And all of this is equal to 10.
So, the next point is for us to make - y the subject. So, we have - y squared.
Then we have + 10.
This will become - 10.
by way this is um 10 y this one here then this one becomes minus 10 and there is nothing more on the right hand side.
The next point is to multiply everything by negative one so that y squared will have a positive coefficient.
So this would give us y squared it will make this negative 10 y it will make this plus 10 and zero is there.
Now we're going to use quadratic formula to solve this.
Yes and the formula is y equals minus b plus or minus we have b squared minus 4 ac all over 2 times a.
So what we have to do is to know our abc.
Our a is the coefficient of y squared which is 1 b is the coefficient of y which is minus 10 and c is a constant which is 10 right?
So from here we will put in the >> [clears throat] >> the values of abc and our y will be negative this negative is here and b itself is negative 10.
Then we have plus or minus b squared is going to be negative 10 squared right?
Negative 10 squared then we have minus 4 times 1 times 10.
A [snorts] is 1 and c is 10.
So all of this will be over 2 times 1 right? 2 times 1. So let's continue with this.
Okay, so we have our Y now to be negative negative is positive.
Then we have minus 10 squared is 100.
Then 4 * 10 is 40.
This is over two.
Now, our Y is 10 plus minus 40 minus um 100 minus 40 is 60.
And this is over two, right?
Okay, so we continue with this.
Okay, so our Y now will be equal to 10 plus or minus we have square root of um four multiplied by square root of 15.
And everything is over two. Remember, root four times root 15 is root 60.
So that our Y will be 10 plus or minus square root of four is two then multiplied by root 15.
And everything is over two.
And two will divide the two numerators.
So that Y will now be two into 10 is five plus minus two into this it will cancel this two from there and we have just root 15.
But this is a two-in-one kind of solution because Y is five plus root 15 or five minus root 15.
But then, we need to have our corresponding values of X.
And from my equation equation three, we say that let X be equal to 10 - Y.
So, we're going to put in the first value of Y, which is 5 + √15.
So, our X will now be 10 - open bracket 5 + the square root of 15.
So, we open the brackets, and X will be equal to 10 - 5 - √15.
Because the negative will open this, and it will make this to be negative, too.
So, the value of X is equal to The value of X is um 10 - 5 is 5.
Then, we have minus √15.
So, we are saying that when the value of X is 5 - √15, the value of Y is equal to 5 + √15.
But, we'll not stop here because we still have another value of Y, which is 5 - √15. So, let's go back there.
>> [snorts] >> Okay, so we're going to pick this value of Y now.
And um our X will still be 10 - Y.
So, we now have X to be 10 - open bracket, put this, 5 - √15.
We'll open the brackets like we did before.
Yes, we open the bracket like we did before, and we have X to be equal to 10 - 5. Negative negative will turn to positive.
And um we have that.
At the end of the day, we have X to be equal to 10 minus 5 is 5 then we have plus root 15.
So, we are also saying that at the at this point, when X is 5 when X [clears throat] when X is 5 plus root 15 our value of Y is 5 minus root 15.
So, we have solved the equation completely.
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