The video provides a clear demonstration of recursive substitution to simplify radicals, though the "Harvard" branding is mere clickbait for standard competition math. It is a solid pedagogical exercise in algebraic reduction, despite the unnecessary sensationalism.
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Hello, you are welcome to solve this math problem which is square root of 12 over 15 + 3 bracket^ of 12. Now solution into here it will be equal to from square root of 12 is same as square root 12 is same as 3 * 4 then over here square root of 15 is same as square root 15 is same as 3 * 5 then plus this square root of 3 bracket this power here power of 12 then in The next step here it will be equal to from here we separate so it will be square<unk> of 3 * square<unk> of 4 over also into here we separate the square roots so it will be square<unk> of 3 *<unk> of 5 then plus this square<unk> of 3 bracket this power here power of 12 then in the next step here it will = to square<unk> of 3 *<unk> 4 it is 2 then over in the denominator roo<unk> of 3 is common so take roo<unk> 3 outside the bracket now 3 * 5 / 3 it is this square roo<unk> of 5 plus 3 / 3 it is 1 bracket then bracket this power here power of 12.
Then in the next step here we simplify this square root of three. You cancel this square root of three. So it will be equal to this here which is 2 over<unk> of 5 + 1 bracket^ [snorts] of 12.
Then into here it will be equal to 2 over here the denominator. So here square<unk> of 5 + 1 to rationalize the denominator we multiply by square roo<unk> of 5 here it is + one here to be min -1 bracket also into the numerator we multiply by this square roo<unk> of 5 -1 bracket then bracket this power here power of 12 then into here it will be equal to this time this so here 2 bracket 5 - 1 bracket then over here 5 + 1 * 5 - 1 is same as square<unk> of 5² - 1 square then bracket this power here power of 12 then into here it will be equal to 2 bracket square<unk> of 5 - 1 bracket then over here square root of 5 square this square you cancel square so it will be 5 - 1 square it is 1 bracket [snorts] this power here power of 12 then in the next step here it will be 2 bracket square<unk> of 5 - 1 bracket over 5 - 1 it is 4 then bracket this part here power of 12. Now into here to simplify this two cancel by 1 this by 2.
So it will be equal to square<unk> of 5 - 1 / 2 then bracket^ of 12 then from here this here inside the bracket we let as x. So here we let xc is equal to this here which is roo<unk> of 5 - 1 / 2. So here if this will let us x we'll be finding x c^ of 12.
Then in the next step here we will cross multiply. So it will be x * 2 it is 2 x is equal to this<unk> of 5 - 1. Then we take this -1 to the left side. So it will be 2 x + 1 is =<unk> of 5.
Then into here we square in both sides.
So it will be 2 x + 1 bracket² is equal to this square roo<unk> of 5 bracket².
So to expand this here it will be 2 x bracket square + 1² + 2 * this 2x * this 1 is equal to here this square you can say square. So is equal to 5. Then here 2x bracket square. So 2 square is 4 x² + 1² is 1 + 2 * 2x is 4 x * 1. Here it is 4 x is = 5.
Then into here we'll take this one to this side. So here it will be 4 x² is = 5 1 take this side will be -1 and 4x we take this side it will be - 4x then here it will be 4 x² is = 5 - 1 it is 4 - 4x then here it will be 4 x² is = here 4 is common. So we take 4 outside the bracket. 4 / 4 is 1 - 4x / 4 is - x bracket. Then into here we divide by four in both sides. So this and this will cancel. Then it will be x² is equal to this and this will cancel. So it will be equal to 1 - x. Then note this value of x² which is 1 - x. Now here it is x² until we make x^ 12.
So here x² let's x² we square again in both sides. So it will be 1 - x bracket also into this side we square. So it will be x e^ 4 is = 1² then + x² then - 2 * 1 * x then it will be x e^ 4 is = here 1 2 is 1 then plus this x² - 2 * x is - 2 X then into here it will be X E^ 4 is equal to here 1 - 2 1 - 2 XC then form plus here X² we substitute here 1 - X so here 1 - X then into here it will be X^ 4 is equal to here 1 + 1 it is 2 - 2x - x is - 3 x then here x^ 4 until x^ 12 we will power by 3 in both sides so it will be x^ 4 bracket here by 3 is = 2 - 3 x bracket also into here by 3 then into here it will be x c^ of 12 4 * 3 is 12 is equal to here the expansion of this this here it is in the form of a - bracket^ 3 which is equal to a^ 3 - 3 a² b then plus 3 a b² then minus b^ of 3. So we'll apply this form here.
Then here 2 is a 3x is b. So a^ 3 it will be 2^ 3. Then - 3 * a² it will be this 2² then * b is this 3 x then plus 3 a a it is 2. Then time b² it will be 3 x bracket² then minus b^ 3 it will be this 3 x bracket^ 3 then into here it will be x c^ of 12 is equal to 2^ 3 it is 8 then minus here it will 3 * 2^ 2 it is 4. So here it is 3 * 4 it is 12. Then * this 3 x then + 3 * 2 is 6. Then * 3² it is 9 x² then - 3^ 3 is 27 x^ 3.
Then into here it will be x e^ of 12 is = 8 - 12 * 3 is 36 x then plus into here 6 * 9 is 54 x² then - 27 x^ 3 we make into x² so x^ 3 is same as x² * x. So as in the later step into x² we will substitute 1 - x.
So here it will be x c^ of 12 is = 8 - 36 xc then + 54 x² we substitute x² which is 1 - x bracket - 27 x² we substute 1 - x bracket then times x Then here it will be x e^ of 12 is = 8 - 36 x c. Then here it will be + 54 * 1 is 54.
54 * -x [clears throat] is - 54 x - 27 * 1 is - 27 * x is - 27 x - 27 * -x is 27 x * x is positive 27 x² then here it will be X C^ of 12 is = 8 - 36 XC + 54 - 54 XC - 27 XC then + 27 into X² we substitute it is 1 - X so here it will be X^ 12 is equal to 8 + 54 it is 62.
Then here - 36x - 54x here it will be - 6 + 4 it is 10.
So we go with one 3 + 5 is 8 + 1 it is 9 x then into here this here - 27 xc then here plus this * this is 27 27 * -x is - 27 x then into here it will be x e^ of 12 is equal to Here it will be 62 + 27. Now 2 + 7 is 9. Then 6 + 2 it is 8. Then here this plus this.
So it will be minus here 0 + 7 is 7. 9 + 2 is 11 x. Then we have this here. So - 27 x then here to be x e^ of 12 is = 89.
Then here it will be minus 7 + 7 is 14 go with 1. 1 + 2 is 3 + 1 it is 4. Then here 1 x then here it will be x e^ of 12 is = 8 9us here we get x^ 12 then -1 4 x into x we recall before we let x it is this here 5 - 1 / 2 so here bracket square<unk> of 5 - 1 bracket over 2. So here it will be x c^ of 12 is equal to 89. Then minus here to simplify this by 1 this by 72.
So here it will be 72 bracket this here roo<unk> of 5 - 1 bracket.
So here it will be x c^ of 12 is = 89. Then -72 *<unk> 5 is -72<unk> 5 - 72 * -1 is + 72.
Then into here it will be x e^ of 12 is equal to here we add. Now 9 + 2 it is 11 go with 1. Then 8 8 + 7 is 15. 15 + 1 it is 16.
Then this here - 72<unk> of 5. So this here the simplified form of square<unk> of 12 over square<unk> of 15 -<unk> of 15 square<unk> of 15 +<unk> 3 bracket bar of 12 is equal to is equal to this here which is 161 - 72 square<unk> of 5. So this is our final answer.
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