Solving a 'Harvard' University entrance exam question

追加: 2026-05-13

[00:00:00]Hello Friends √(√16-√12)=?

[00:00:10]let's have a solution so we have a problem √(√16-√12), say this is first equation we know √16=4 12 is same as 1x12, 2x6, 4x3 we must choose here '4x3' to solve this problem faster √12=√(4x3) since √xy=√x x √y then It will be √4x√3 2√3 since √4=2 put into first equation √(√16-√12)=√(4-2√3) I hope you understood 4=3+1 √(3+1-2√3) this is same as √((√3)^2+(√1)^2-2x√3x√1) this is like a formula x^2+y^2-2xy=(x-y)^2 apply this formula then It will be √(√3-√1)^2 as we know √x^2=|x| square cancels from square root we get |√3-1| as √3>1 this will be equal to √3-1 finally, √(√16-√12)=√3-1 which is our final answer thanks for watching this video please subscribe this channel to get the notification of my new videos ok bye