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Live GCSE Maths Past PaperAdded:
And we are live, guys. Let me know. Can you hear me? What a beautiful day here on planet Spinning Rock. What a day to be alive. Look at this weather, guys. Come on, man. It's 30°. How we doing?
Emily in the chat. Hello, one more chapter. Hello, Unknown OB2KO.
Hyperfocus Tamim ABD Unknown OB. Guys, I need a way to get my chat a little bit higher because um otherwise I keep looking down.
I am fantastic. Thank you, ABD. Hello, Molly Hearn.
Hey, brilliant. NFX says, "Hi, I joined your group tutoring." Leica said, "I'm literally melting, Matt." Hey, you and me both leaker.
Abd said, "Why is slow mode on?" Guys, how long is it is the uh slow mode setting on for? I think I put it up to 15 seconds.
Um, let me have a quick look. Just to stop people from spamming. You know how you can only put a message every 15 seconds. I think that's just so people can't be spamming.
Any says, "Yes, bro. Can't wait. Come on." Fantastic.
Mento play says for real too hot.
Ah, brilliant. It's only on a few seconds. Guys, talk to me. How are we feeling? GCSE halft term is here officially Monday. You would have had the weekend anyway. This is officially GCSE halft.
Guys, well done for getting the first couple of weeks out of the way.
Hopefully, we're feeling good about them. If we're not, it's a great time to restock, reset, refocus, reenter um before moving on to, you know, the next week after this one where we have, of course, our GCSE maths paper two, bunch of other exams, and then the following week, guys, you're not going to have to do GCSE maths ever again. Oh, assuming things go well and assuming things go right now, a couple of important announcements.
You guys can see right above. So, I want to actually make this announcement right now. It's right, guys. I'm running a halfturn boot camp completely for free, Tuesday, which is tomorrow, until Saturday, 3 p.m. to 4 p.m. every day.
So, scan the QR code, sign up on your phone, or I think I pinned the link in the chat. Let's have a quick look.
Yeah, there we go. I did put the link in the chat. So, yeah, exactly, Ava, it is on YouTube. So, you can watch it on YouTube or you can sign up for the free um for the free pass. If you sign up to the free pass, basically you're going to be able to see what we're doing on each of the days. You're going to be able to download the papers. There's some more free resources in there. Um there are videos and stuff which are going to help you especially for paper two and three.
So, it is completely free. There's no catches. There's no anything like that.
Um it's also on YouTube, right? So, you can see the uh videos all cued on YouTube. Um so, it is completely free.
you could just watch it on YouTube. The reason that I've set up the uh platform as well um is just so that I can uh send the papers ahead of time so that I can give you guys the extra tips, the extra, you know, emails around reminders for the sessions, all of that good stuff and extra little tips. So, if I were you guys, sign up now. You know what? Just at the start of the session, we're going to pause two minutes and I'm going to give you all time to sign up.
S says, "What is the boot camp?"
Fantastic question, Sama. I probably should have said that. So, basically, guys, we're going to be doing paper two and paper three specific revision for an hour every day. It's going to feel very similar to one of these Monday live streams. I pick a pass paper and I go through selected questions, which are especially important for paper two and three based on predicted topics and all of that stuff and the topics that came up in paper one. Um yeah, that's the format basically.
That's the format.
Couple of people saying how do we sign up? You just have to either scan the QR code on your phone or you can use the link in the chat um in the pinned comment and it will just take you to like a a website page which says sign up, you sign up, you make an account and then it just takes you straight there.
Then you get sent an email which has access to all of the classes. Um and you also get access to my platform with all my videos, worksheets, all that stuff for free.
Any other questions on that one, guys?
How are we all feeling? By the way, let me know in the chat how we feeling about everything because I know there's going to be a few mixed emotions around.
Guys, also let me know in the chat. Can you hear my music? If you could let me know, that'd be fantastic because I have some playing in the background. You guys know I like music while I'm uh while I'm doing these classes, but I also can't have you guys hearing it for copyright reasons.
Okay, let's see.
Lots of people saying stressed. What do we have? We have excited, stressed, scared, chilled, more power.
We have um stressed, pretty chill.
Honestly, I think I need to just turn my music down one click probably.
Um, yeah. Tired and scared, stressed, burning, hot, nervous, and excited at the same time. Guys, let me know how many more exams do you have.
How many more exams do each of you have?
Drop it in the chat for me. Are we more than halfway or are we kind of approaching halfway?
I know a lot of you are actually more than halfway there.
Some people are exactly halfway there.
Wow. Some mixed numbers. We have 10 4 8 11 12 4 13. Wow. 13.
Don't worry, Rex. The longer you go, the sweeter it's going to feel when you finish, my friend. Okay, guys. Let's get moving then with this paper. We're going to be jumping straight in focusing on question number two as a little warm-up.
Let's have a look. What do we think for this one? An error intervals question.
Those of you who are looking for predicted topics, check this guy out.
First class maths makes absolutely brilliant videos.
Um, I would say he's got the best GCSE explainer videos. Like the best 10 to 20 minute videos. I've got the best short videos. This guy's videos are fantastic though. Um, he's also a great guy and um, his predicted papers are also very good and they contain a lot of problem solving. They're a little bit trickier I would say than actual papers. Um, but definitely worth checking out his predicted topics.
Yeah, a lot of you guys saying that he makes some good stuff. He absolutely does. Okay, question number two then.
What's it going to be? Let's have a look. Error intervals. A good paper two topic. The length of a pencil is 128 mm correct to the nearest millimeter.
Complete the error interval for the length of the pencil. So what do we do?
We write out 128 mm. We write down the next number 129 and the previous number 127.
Then the lower bound and the upper bound are going to be halfway between each of these. Halfway between 127 and 128 is 127.5.
Halfway between 128 and 129 is 128.5.
So these are our lower and upper bounds.
127.5 mm is less than or equal to the length which is less than 128.5.
So that's question two. Little bit of a error intervals question. Next up question number three. This one is a four marker which we're going to go in with. Good little ratio problem solving question.
So, I'll give you guys maybe three minutes to do this and then I'll go through it and let's see what we can do. Yeah, exactly. Good shout. Thank you, Emily.
So, guys, this is the November 2019 paper two higher tier. Let's get a quick vote in the chat, guys. I'm going to set up a quick poll. Um, will you be joining us for the half term boot camp?
Yes. Can't wait.
Not for me. Let's see, guys. What are we thinking?
You guys know the drill. Well done, Ava, for that last one. Well do. Well done, Anu. Well done, Hyperfocus.
Oh, just be careful, hyperfocus, with the direction of that inequality. Maybe it was a typo, but just to be clear, we have the crocodile's mouth facing the bigger number on the right hand side, and on the left hand side, the crocodile's mouth faces the uh thing in the middle.
Just to be clear, SA says, "Is the boot camp for GCSE non-cal?" The boot camp is for GCSE higher tier paper two and three, which are both calculator papers.
Yeah.
So, we have 26 votes. 92% saying yes, can't wait. 8% saying not for me. Hey, not for everybody.
Um, but great to hear that so many of you are up for it. And now I'm guessing a few more people are gonna are gonna probably vote not for me. Molly says, "Just signed up." Fantastic.
Yeah, I thought it might have been uh thought it might have been Hyperfocus.
Let's get a few answers in the chat for me, guys. I also have another really exciting announcement to make today.
Um and it's something that I'm going to drop into the conversation a little bit over this week just to hear what you guys think of it.
But it's to do with me teaching you guys a little bit more than just GCSE maths.
Ava says, "This looks easy, but I don't know where to start."
My tip, Ava, is going to be to work out how many stamps Tom and Adam both have before and after they um do the exchange.
I can see a few more answers going in the chat.
Okay, then guys, let's have a look.
Question number three. Again, it's a good calculator problem solving question. Tom and Adam have a total of 240 stamps. The ratio of Tom's to Adam's is 3:7. Tom buys some stamps from Adam.
Now, the ratio is 3:5. How many stamps does Tom buy from Adam? You must show all of your working. Basically guys, we're going to work out how many stamps each of them have before, how many stamps each of them have after, and therefore how many that Tom has bought from Adam. So let's firstly work out before.
Before well we've been told the total number of stamps 240 and we've been told that they're shared in the ratio 37. So this is classic ratio division. How do we do it? Step number one, we work out the total number of parts. So the total number of parts is 3 + 7 which is equal to 10. Now we can work out the stamps per part. So the stamps per part stamps per part is going to be the total number of stamps 240 divided by the number of parts which is 10. 240 divided by 10 is 24. Now we can work out Tom's amount.
Well, Tom had three parts. So Tom has 3 * 24, which I'm pretty sure is 72 stamps. And then Adam, well, Adam had seven parts. So 7 * 24, which is 168.
Guys, I did those in my head, but you definitely should not do them in your head um in your exam. Just take your time with it. Take it nice and slowly.
What about afterwards then? Well, afterwards we have 240 stamps, but they're in the ratio 3 to 5. We're going to do exactly the same thing.
We're going to work out the total number of parts.
That is going to be 3 + 5, which is equal to 8. Then we're going to do the stamps per part. Stamps per part.
It's going to be 240 / 8, which is 30.
Then we're going to work out Tom's, which is going to be 3 * 30 because he had three parts. So 3 * 30, which is 90.
And Adam is going to have 5 * 30 because he had five parts, which is 150. Now we could choose Tom or Adam and look at how many their number of stamps has changed by.
Tom did have 72. Now he has 90. So he bought the difference between those, which is how much it increased by. So, he bought 18 stamps, guys. Very well done if you got it. Well done if it makes sense. Any questions, you know the drill. Let me know in the chat.
Good work, Rex. Good work, httpsj.
Nice sama.
Fantastic work, guys. Fantastic work.
Good job, Unknown. Good job, Lea Mika.
Good job, Miro.
Fantastic, guys. Let's keep it moving.
The next question we're going to go through is we're going to go through question number 10. You guys can see that I'm really pushing you towards some of the later questions in this paper and we're going to be doing that all week. We're going to be focusing on the topics which drive the increased marks for the increased grades.
Sama says, "Is the boot camp still beneficial even though I'm doing IGCSC?
because if so, I'd like to join SAMA.
Definitely, definitely, definitely. I mean, IGCSE and regular GCSE teeny differences. Um, I mean, there are differences, but they're very small differences. IGCSE has a couple of extra topics. There's no differentiation in GCSE. Uh, I think there's a bit of series in IGCSC, which isn't in GCSE, but everything in GCSE pretty much.
Yeah. I mean, everything that we'll go through definitely um is in IGCSC as well.
So it will still be very beneficial.
Question 10. What do we think for this one guys? Hey S, my pleasure.
Answers in the chat. Answers in the chat. What do we think, guys?
Make K the subject of the formula.
Okay, I've decided that the other announcement I'm going to do at the end of the session. So, if you're interested in the other announcement because some people have put it in the chat. I'm going to make that one at the end of the session. So, at half 6 UK time. It's not about GCSE maths, but it's something that I'm incredibly excited about.
Question number 10, team. Let's do it.
Another good topic. Make K the subject of the formula. y =<unk> 2 m minus k.
What does it mean to make k the subject?
We need to end up with k equals something. Now, in order to do that, we're basically going to rearrange the equation and move everything over to the other side until the k is on its own. And we do that by reversing whatever's preventing the k from being on its own. So the first thing that I see is I have y equals the square root of 2 minus 2 m minus k. In order to get rid of the square root, which is stopping the k from being on its own, I'm going to square both sides. I'm going to get y^2 equ= 2 mus k. Now at the moment, I don't really like the fact that the k is negative. So I'm going to make it positive by adding k to both sides. On the left hand side, that's going to give me y^ 2 + k. And on the right hand side, we're just going to have 2 m. And now to get the k on its own, we just need to move this y^2 to the right hand side. At the moment, it's being added to the k. So we can minus y^2 from both sides. We're going to get k = 2 mus y^2. And that guys is our answer to question number 10. Well done, Tyler.
Well done, Sama. Well done, Lightning UHD.
Nicely done guys. Fantastic. Okay, the next one we're going to do, guys, is question. Let's do this one, actually. Four marks. Question 12.
Four marks. Question 12.
Let's see what we can do. Good work, Porsche Enthusiast. Good work, Moon.
Good work, Alicia says, "Yes, makes sense." Good work. Fantastic, guys.
Fantastic.
SV says, "I got it wrong. No worries at all." Does it make sense? Now, question 12, guys, even though it looks quite intimidating, I've got to say, is not too bad. It looks harder than it is.
It looks harder than it is. That's what I'll say.
Um, Emily says, "Can you not change the K at the end?" Yes, you can. So, you could have also had something equals minus K and then you could have multiplied both sides by -1. That would have also worked.
That would have also worked.
Hyperfocus says, "I don't even know what to do for this question. Can I have a hint? It's hint time, ladies and gentlemen, boys and girls. So, um, the diagram shows triangle ABC. You've all read the question. Basically, E is the midpoint of DB. So, E is the midpoint of this. Work out the size of angle E A D E A D. So, it's this angle here. Let's call it X. Now, I look at this and I see a right angle triangle.
I see a right angle triangle where I have one side length and I need the angle and I think okay well if I can work out another side length then I can use trig soa to work out x.
Now the next thing I think is well how do I work out this? I've been told that e is the midpoint of db.
Therefore, I can work out the whole of this side length using this triangle and then I can have it to work out this side length. That's my hint for now, guys.
That is my hint for now.
Hey fever team, how we feeling? Has it been bad today? Has it been good today?
I've actually not taken any hay fever tablets today and I'm feeling okay. Hey, I went for a walk as well and I'm feeling pretty good. So fingers crossed.
It's going to be the irony. I'm going to start start sneezing now, but fingers crossed we should be pretty good.
Joe says 32.1 stunning number.
Wicked team. Should we get moving?
Maybe another 15 seconds.
Wow. Said nettle tea for hay fever. Wow.
Joe says, "Yep. Let's go." Okay, guys.
Question 12. I did give my hint. Let's get moving. Question number 12. Great calculator question. Basically, we need to work out this angle here. And we already said that ED is half of BD. So what we need to do is work out this whole side length, half it to find this side length. Then we can use SoCarta trigonometry to work out the size of angle X. So what I'm going to do is I'm going to start off by taking my right hand triangle and just to make it a little bit clearer, I'm going to redraw it. So my right angle triangle here on the right, my right angle is down here. Hypotenuse is 8.6. angle here is 40. And basically, we want to work out this side length here. I'm going to call it y. Step number one for trigonometry, we label our side lengths. Opposite our angle, we have our opposite side. Opposite our right angle, our hypotenuse. Our other one is our adjacent. Then we can choose so, car, or to. Well, in this question, we want the opposite. We have the hypotenuse. So, we're going to choose so. What does so tell us? So tells us that s of our angle is equal to our opposite side divided by our hypotenuse.
We can sub our values in sin 40 is equal to our opposite side. That's y / hypotenuse 8.6. Now we can find y. 8.6 * sin 40 is equal to y. I'm going to type this into the calculator. 8.6 * sin 40. And that is going to give me 5.2. 2 not 5.2 y = 5.52 um 8 to three decimal places. Now because it wants the answer to one decimal place, I'm going to give my working to three. So this side length then this whole side length is 5.528.
To work out this side length ED, then I'm going to need to have that because E is the midpoint of DB. So, I'm going to do 5.528 / two.
So, answer on the calculator divided by two. And that gives me 2.764.
2.764.
Now, I can come back up here. I can label this 2.764.
And now I have a regular trigonometry question or a regular so-cal question.
Again, I'm just going to redraw my Actually, no, I'm not even going to redraw it here. So opposite my angle, I have my opposite side. So I label it.
Opposite my right angle. Right angle triangle. I have my hypotenuse. Other one is the adjacent. Oh, don't know why I wrote the H. So this time, what are we working with? Well, we have the opposite. We want Sorry, we have the opposite and the adjacent is what I meant to say. So we're going to choose to because that includes the opposite and the adjacent. TOA tells us that tan of our angle equals opposite over adjacent. So tan x is equal to 2.764 over 4.4.
And now to work out the value of x, we need to get the x on its own. To move the tan to the right hand side, we do tan minus one of both sides. So we get x equals tan the minus1 of 2.764 over 4.4. four.
I'm going to type this into the calculator. Shift tan to get 10us1.
Fraction 2.764 over 4.4. Close those brackets. 31 30 not 31 32.1 36 etc. which rounding to one decimal place is going to give me 32.1 as my answer.
Guys, good work. If we got it, if you have any questions, let me know.
Question 12 is probably our trickiest one yet, I would say. Two stages of inequality, a lot of trig, a lot of socar toa. Guys, let me know in the chat. Did we get it? Didn't make sense.
Nice. Aa says, "Yeah, yeah, yeah, I got that." Good job, Ava.
Nice, Miro.
Good job, Lightning.
Yeah, nice Porsche enthusiast. Good work, Sama.
Yeah, fantastic. HHTPS says it makes sense now. Fantastic, guys. That is progress. Honestly, we're going to do question 13 and 14 now as well because these are both great topics for um for paper two. Great topics for paper two. Very likely to come up actually.
We have some compound interest from Shakira. Shakira. And then we have some um uh combinations from Sadia.
Sadia and Shakira. The girls are running it in this paper.
A reminder guys of the free halftton boot camp starting tomorrow 3 p.m. to 400 p.m. every day higher tier completely free. You can either watch it just on YouTube. You don't have to sign up. Um but if you do sign up, you're going to see what papers we're doing.
You're going to be able to download the papers. You're going to be able to see some other details. Um so if I were you, I'd sign up, but you can go either way.
Zinogami says, "Will you be streaming the night before the exams?" So, if you check the description for that one, guys, um you can see my night before classes.
It's 20 pounds for each one for four hours,5 an hour or it's £30 for paper two and three. Um so, yeah, you can sign up down below.
Same format as um for paper one.
Basically, I'm going to go through um two past papers. I'm also going to teach the most important topics for paper two and three. Um whereas for paper one it was more general. Paper two and three especially paper three are going to be based on predicted topics rather than being based just on past papers. For paper one you really don't know what's coming up so nobody can predict. Um but for paper two and three you can do a little bit more prediction especially for paper three. So the night before paper two we'll be doing past paper questions for predicted topics. For paper three, I'll be probably teaching some of the predicted topics, which are the most important ones, and also going through past paper questions for the predicted topics. Um, there's limited spaces. You can uh sign up using the link in the description below.
Question 13. I've seen a few answers in the chat, but still not many. And I know it's a pretty tough one, so I'll give you another 30 seconds or so.
Joe says 2.2%. Her interest rate was awful. Poor Shakira.
I know it says Sakira guys, but I'm going with Shakira.
If you guys want to see actually one of the greatest live performances of all time, it's Shakira and W Clef Jean doing Hip Don't Lie I think in Argentina. I can put a link to that at the end of the session. Unbelievable. Probably the best live performance I've ever seen. Up there with the best. Another legendary one was Tiny Temper with Florence and the Machine I think at Glastenbury. That was also just ridiculous.
Okay guys, quick ready in the chat for me if you're ready because I know some of you won't be answering this. There's 70 of us. I've only seen about eight of you put an answer in the chat. Maybe a few more. So, Joe's ready. Unknown is ready.
Lightning is ready. Hyperfocus says we are ready, guys. Let's run it. Question number 13. Compound interest. Very important for paper two and paper three.
Let's have a look. Shakira. Shakira.
invested £3550 in a savings account for three years.
She was paid 2.6% per year or per anum compound interest for each of the first two years. Then in the third year she was paid r%. At the end she had this amount. Work out the value of r. Give your answer correct to one decimal place. As always with this one, we are going to set up an equation using all of the information we've been given and then we're going to solve it for the thing that we need. So we know for compound interest basically that what we do is we take our initial or sorry yeah our end amount A is equal to our initial amount times by 1 plus our interest rate as a decimal raised to our number of time periods. And then if there's more than one interest rate, basically you just have to times it by 1 plus the um the second interest rate raised to the power of however many time periods that is. So basically in this situation, what do we have? Well, we start with this number £3,550 and we end with this number £3,81921.
So basically our end amount of £3,81921 is equal to our initial amount £3,550 times by well we have 2.6% for 2 years.
Now 2.6% as a decimal we divide it by 100. You could do that on the calculator. So 2.6 divided by 100 and that would be 0.026. 026.
So, this is going to be Oh, guys, my um pen just got disconnected.
That's really weird.
I think my screen just got disconnected.
Guys, give me one second.
Troubleshooting. I was mid description.
Let me see what Okay, I think we're back. I think we just had a bit of lag and a bit of scribbles everywhere. There we go. Are we back? We're back.
Beautiful. Okay, let's keep cracking. So times by 1 + 0.026 raised to the number of time periods 2 years times by 1 + and then we're going to say r which is that interest rate as a decimal but because it's only one year because it's the third year it's one year there's like an imaginary power of one there. Now anything to the power of one is itself. So it doesn't actually make a difference. So what we need to do now guys is basically rearrange this to work out r. Now on the right hand side we have this number times by this thing times by this thing. So to get this on its own we're going to divide both sides by this because it's being multiplied by it at the moment. So we essentially end up with 3819.21 21 divided by 3550 times by 1 + 0.026 raised to the number of time periods 2 is equal to 1 + r.
Now we can actually go ahead and we can type this the left hand side into the calculator. So fraction 3819.21 not 241 divided by 3550 times bracket 1 + 0.026 close bracket squared and we get 1 1 2 1 9 etc = 1 + r. Now, because we see these two nines next to each other, it's kind of a hint that they want us to round this, right? Like, this is so close to rounding this up that it's pretty obvious that they want us to round it. So, 1.022 = 1 + r minus one from both sides. 0.022 = r. Now, this is our interest rate as a decimal, remember? So, to convert it into a percentage, we're going to do 0.02 022 times by 100 and we're going to get 2.2%.
2.2%.
And that guys is going to be our value of r. If we come back up, it says work out the value of r. The interest rate was r% so it's just the number. So 2.2 is what we're going to go with. That was supposed to be a bit of a happy face, but it looks more like a sad face. So guys, I'm going to rub that out. Okay.
2.2.
Let's see.
Joe says, "Yay, what a horrible three marks. Surely four." Like, that's a bit nasty. I can't even lie. Yeah, it's a nasty one. Guys, let me know in the chat if it makes sense now. Thank you Miro actually for reminding me team let me know does it make sense now if it does let me know in the chat please compound interest that is a tough problem solving question and it's an important topic um for uh for paper two and paper three comes up a lot nice ava couple of people saying it sort of makes sense says yeah makes sense but it was really hard. Okay, fantastic. Guys, remember all of the live streams are recorded and they're uploaded straight to the YouTube channel, so you can watch it back straight away. Um, and you can uh you can just, you know, see what I did again and see if it makes more sense second time round. Okay, next up, question 14, combinations.
Let's uh let's have a look at this one.
Only two marks. Not too long of a question, but an important one nonetheless.
SV says just super quick.
Unfortunately, SV, I won't be able to, but like I say, you can you can rewatch that one. Fantastic leaker.
Let me know when you're ready for this one, guys, and I'll go through it.
Alicia's ready.
Miro's ready.
Emily Speedy in the chat. Things we love to see.
Sala's ready. Yeah, good job SV.
Fantastic work team. Okay, let's go through it then, guys. Question 14. Um, product rule for counting. Another important paper two topic. Sadia is going to buy a new car. For the car, she can choose one body color, one roof color, one wheel type. She can choose from 19 different body colors, 25 different wheel types. The number of ways she can combine a body color, a roof color, and a wheel type is 3,325.
Work out the number of different roof colors that Sadia can choose from. Now remember guys, when we work out the number of different ways that we can combine, for example, in this case, three things, what we do is we multiply the number of different options that there are for each of them. So basically, we know there's 19 different body colors. We know there's 25 different wheel types. We don't know the number of roof colors, so we're going to call that X. And we know in this case that the product of all of them is 3,325.
And from there it's just rearranging to get the x on its own. It's being multiplied by 19 and 25. So we can divide both sides by 19 and 25. 3325 over 19 * 25.
We can type that into the calculator.
Judging from the chat, it's going to be seven. Let's have a look. I strongly doubt. Yeah, there we go. That any of you were wrong. Nice work, guys. Seven is our answer to that one. Basically, there was that number of different options.
Thanks, Joe. Thanks, Emily. Um, guys, can we please just get a quick round of applause in the chat for the moderators?
I don't actually mention this enough, but there's some fantastic student helpers who are just muting people when they're being annoying. And these sessions would be really hard for me to run if we didn't have help from the moderators. So guys, can we please get a quick like W in the chat? Let's get a quick W in the chat for the moderators.
Let's show some support and some gratitude. Um because they really make these sessions possible.
Nice. Hyperfocus says it makes sense now. Thank you, Miro. Thank you, Unknown. Thank you, Moon. Thank you, Alicia. Thank you, Tyler. Pandas, SV, Unknown, Lightning, Salsa, Evan, Rex, Abdullah, Joseph in there with that little dab emoji. Come on. Um, yeah, nice Emily.
Nice, Tyler.
Yeah, brilliant, guys. Brilliant.
Brilliant. Thank you for that. Um, what do you guys want? Circle theorems.
Should we do a circle theorems question?
Let's do a circle theorems question.
Let's do a circle theorems question. To be honest, I've looked at so many past papers now that I actually can't remember off the top of my head if it was in um paper one, but I'm sure you guys will let me know in the chat if it was. I don't think it was in paper one off the top of my head, but I've looked at a lot of papers, guys. A lot of papers.
Was it in paper one? Okay, you're saying it was okay. Let's keep moving then, guys.
Let's keep moving. Histograms wasn't in there, right?
Histograms wasn't in there. Or maybe it was as well. Honestly, I can't remember.
Histograms. Histograms was as well. Oh, buddy. Let's keep it moving then. Let's keep it moving. I know that I pretty sure volume of a sphere wasn't.
Was volume of a sphere bounds definitely wasn't.
Either way, let's do this one. Yeah.
Cool.
Yeah, volume of a sphere wasn't fantastic.
So guys, question 19, question 20.
Don't worry, when I'm planning the boot camp, we'll be factoring in which topics have come up, which topics haven't.
Um, so this question, volume of a hemisphere.
And then maybe we're going to skip to question 23 probably because that's a big old question.
Leica says, "For some reason I can only do these kinds of questions if the question is in front of me." Um, you mean like in front of you on the paper or Yeah, I can see some answers going in.
We have 155, we have 310.
Team, let's have a look. Question number 19. Um, volume of a hemisphere. The diagram shows a hemisphere with a diameter of 8.4 cm. Work out the volume of the hemisphere. Give your answer correct to three significant figures.
We've been given the formula for the volume of a sphere. 4 over 3 pi r cubed.
Two things. First of all, in the hemisphere, we've got the diameter. So, we need to have it to work out the radius because it's the radius in the formula. Half of 8.4 is 4.2. You can do that on the calculator. Next thing, because we have a hemisphere, when we work this out, we're going to divide it by two. So, I'm going to do 4 over 3 *<unk>* by my radius cubed. 4.2 2 cubed and then I'm going to divide it by two because I have a hemisphere and not a sphere.
I'm going to type that into the calculator. 43 * 4 over 3 time pi * 4.2 cubed / 2 we get 155.16 etc. Now we need to round our answer to three significant figures. Remember guys, significant figures. Our first significant figure is our first number which is not a zero. So the one here is the first significant figure. So first significant figure, second, third.
We look at the fourth one to decide what we round to. Because it's a one, it's less than five, we round down. So we get 155 cm cubed as our answer.
Good work, Ormy. Good work, Leica.
Hey, Sama. Welcome back. Nicely done, guys. Nicely done. Okay, any questions?
Let me know in the chat. Otherwise, question 20 we're going to do. Great question to go through and then we're going to finish with question 23.
Probably just part A. Um maybe part B as well.
Question 20D.
This one, guys, has been coming up quite a lot in recent years and not many students get it at all. This idea of to a suitable degree of accuracy. So, I'm going to show you what this one means.
It's one that we've gone through a lot in the group tutoring actually.
Tyler says, "Can we have a hint?" My hint, guys, is we're going to work out bounds for C, and then we're going to plug in the lower bound to work out the lower bound for D and the upper bound to work out the upper bound for D. And then we're going to check what they both round to.
That's my hint. Another minute or so and then we'll go through it.
Guys, I'm uh I didn't know Eid was coming up.
So, am I right in thinking there's more than one Eid a year or is that completely inaccurate? I should really know this because I do like to honor all of the religious festivals in the lives.
So there's two Eids.
Okay. Because I know there's the main one or well actually I don't know if it's the main one but to me it's the in one the main one. Okay. So a lot of people saying there are two Eids. Okay.
So the first one is timed a little bit earlier in the year and the second one is on Wednesday.
Fantastic. Okay.
So there'll be and do you say ID Mabarak on this one as well.
I really never knew that. I really should know that as well.
Yeah, exactly. Alicia says the first one is after Ramadan. So that's the first one I knew about.
Okay, cool, guys. Cool, cool, cool, cool.
Right, guys? Let's have a look then.
Question 20.
Lock in for this one. Um because it's an important one and most of you won't know how to do this. Let me know in the chat.
Say it makes sense now if if you get it afterwards but didn't know it before because um it's an important one. Um question number 20. Not many people know how to do this. Like I just said, let's have a look. D= 1 8 Cubed. C is 10.9 to three significant figures. by considering bounds work out the value of D to a suitable degree of accuracy. Now what we can do is we can work out a lower bound for D and an upper bound for D by using the lower bound for C and the upper bound for C. The smaller C is, the smaller D is going to be and the bigger C is, the bigger D is going to be. So the lower bound is going to be found by using the lower bound of C. So first off, finding the bounds for C, we write 10.9 in the middle. What is the next thing that it could be to three significant figures?
Well, that would be 11.0 11.0 and the one before would be 10.8.
Now, just like we said earlier in the session, we need to go halfway between these. So, we have 10.85 and we have 10.95 as the lower bound and the upper bound for C. Now that means that the lower bound for D so the lower bound for D will be 1 over8 1 over8 times by 10.85 cubed and the upper bound for D the upper bound for D will be 1 over 8 from up here times by the upper bound for C so 10.95 cubed.
Now both of these I can type into the calculator and I can see what it gives me. So I do one fraction 1 over 8 times bracket 10.85 10.85 uh cubed close brackets and I get 159.66 159.66 etc. And then now doing it with 10.95 10.95 we get 164 16416 etc. Now what does it mean by work out the value of D to a suitable degree of accuracy? What it means is this. We don't know what D is, right? We know what it's between. We know it's between this and we know it's between this.
But what could we definitely say about D? Could we say that it rounds to 160?
Yeah, we could because all of the values within this range round to 160.
So we could say that D is equal to 160 when it's rounded to we could say two significant figures. Two significant figures.
We could also round it if we wanted to to the nearest uh 10. That would also work. But two significant figures is going to be the nicest there. So we look for what both the lower bound and the upper bound round to. That is how we solve this one.
Good work. Zid very close. Says um both round to 160 to the nearest five.
Highest degree of accuracy. So they actually don't both round to 160 to the nearest five because this one rounds to 165.
165 to the nearest five. So you couldn't say to the nearest five. That wouldn't work because this one goes to 165. But they do both go to 160 to the nearest 10 or to two significant figures. Porsche says that was easier than I thought.
Nice Porsche. Tough though. AA says I got it. Good work.
Nice. Heron says it makes sense now.
Brilliant, guys. Absolutely brilliant.
Okay, we're going to keep it moving and we're going to finish, guys, with question 23A.
This is going to be our final one of the day. Maybe we'll do B as well.
Um, let's do A. Let's see how we're doing for time. Uh, and then maybe we'll do part B. Maybe not.
Okay.
Um, El Elderaldinho says, "Why is it two significant figures instead of three?"
So, the reason it's two was because the 164 whatever it was 56 da da da. If you rounded it to three significant figures, it would become 165.
It wouldn't become 160. Whereas the other one would become 160 to three sigfig. this to three sigfig would become 165. So we can't say to three significant figures.
Okay. What's the formula guys? It's an important one for this next paper quite likely to come up.
What's the formula?
SV says it's just base times height.
That's one way to work out the area of a parallelogram. The problem with that method here is that we don't have the height.
This is not the height. This is the length of this side which is a diagonal.
It's not the vertical height. So, we can't use the height.
Let me know guys if you would like a hint.
Somebody's saying half time AB * H. We can't do that. So, that's for a trapezium, not for a parallelogram. So half * a + b * h is for this shape, not this shape. So that's a parallelogram.
That's a trapezium. It would be that.
But not for a parallelogram.
Quite a few people are asking for a hint. Absolutely. It's hint time.
This is my first hint.
Let's split it into two identical triangles. Now I'm going to sneeze.
Oh, I shouldn't have said what I said earlier about hay fever, guys.
And then guys, wow, now my eyes are watering as well. Um, and then we're going to do a half a sin c to work out the area of each of the triangles. That is my hint. That is as far as the hints are going. And then I'm going to go through it. It's a tough question.
Thank you. Thank you, Heron. Thank you, Joseph. Thank you, uh, Emily.
Ava says, "Is a parallelogram a slanted rectangle?" Yes, it is.
So guys, at the end of this session, um, I'm going to make the announcement that I mentioned earlier that's very exciting for me and hopefully exciting for you guys as well. I did mention it on a stream the other day, but not many people were on. Um, the main announcement for today though, if you take one thing away, guys, it's this halftime boot camp, Tuesday to Saturday, 3 p.m. to 4 p.m. higher tier. Sign up using the QR code. Scan it on your phone right now. Um or use the link in the chat. It's completely free. Um you can just watch it on YouTube if you prefer.
You don't have to sign up. The reason why I've made built the kind of space in the platform around it on my gcsmath.com um is because it will allow me to share the resources with you ahead of time.
It'll allow me to give you updates, extra tips. You'll be able to download the papers on there that we're going to go through. I'm going to plan all of that um or like upload all of it. um before the sessions tomorrow. So, there's lots of reasons to sign up. I've called it like the free insider pass just because you get kind of inside information. Um you can also comment on there and interact with each other as well, but you're also welcome to just join on YouTube if you uh if you prefer to do that.
Um SA says, oh no, Carl says there's no link in the chat, Matt. So, it's actually um pinned, guys. So, it's in the pinned comment. It should take you straight there.
Um, I can just drop it in again if you guys can't see the pinned comment. Can you see the pinned comment or the pinned chat or whatever it's the pinned um message in the chat, I think it's called.
Hey, hey, Richard. Good to have you, buddy.
Oh, the poll's in the way, guys. Aha.
Aha. I didn't know the um the poll blocked it.
Okay.
Should we do our final question then guys? Drop ready in the chat for me if you're ready and we will go through it.
Joe's ready. Unknown has no idea how to do it. Joe's ready. Alicia's ready.
Yeah. Yeah. Yeah, yeah, yeah, yeah.
Hyperfocus as well. Team, let's get going. Let's get this question done.
It's a tough one just so I can explain it in its totality. Let me delete that and we can uh we can get started.
Question 23. Problem solving with area equals half a b sin c. Very important for paper two. If not paper three, let's have a look. The diagram shows a parallelogram. the area of the parallelogram is greater than 15. Show that this is true. Now, how do we work out the area of a parallelogram? Well, there's the formula base times by height. But the problem in this case is we don't have the vertical height. So, we can't use that. We can use a little trick which involves splitting the parallelogram in half, guys. So, I can draw a line across it diagonally.
And now I have two equalsized triangles.
If I can work out the area of this triangle, then I can double it to get the total area. Now, how do I work out the area of this triangle? I have two side lengths, 10 - x and 2x - 1, and an angle in between them. This is the classic use of the formula area equals a half a b sin c where a and b are two side lengths and c is the angle in between them. So, we can say like a b and c. Now, what do we know from the question? And we know that the area of the parallelogram is greater than 15. So we know that two cuz there's two of the triangles times by the area of the triangle a half times by 10 oh that looks like a 16 10 - x* 2x - 1* sin 150 is greater than greater than 15.
Now let's go ahead and work this out.
two times by a half. They cancel each other out. Two times a half is just one.
So they cancel. Sin 150 if we type it into the calculator is I'm pretty sure a half off the top of my head. Yeah, there you go. A half. So what we can do, and I'm just to save space, I'm doing this pretty uh uh in a condensed way. We can move the sign 50 over to the right hand side.
How do we move the half over? Well, we can times both sides by two. We can times both sides by two. So, we're going to get 10 - x times by 2x - 1 is greater than 30 is greater than 30. The next thing we can do then is we can expand these brackets and hopefully we can turn it into this.
Let's get it done. So 10 * 2x is 20 x 10 * -1 is - 10 - x * 2x is - 2x^ 2 - x * -1 is + x and this is greater than 30.
Now we can see that the greater than is facing a zero and the minus the x squ here is minus. So I'm going to move everything to the right hand side of my equation. So we um are going to have zero on the left is greater than we're going to add 2x^2 to both sides and then 20x plus x is 21x and minusing them from both sides gives minus 21x and then we're going to add 10 to both sides and 30 + 10 is going to be 40 giving us our answer and it says 0 is greater than 2x^2 - 21x oh I just wrote 40. It should say plus 40. Um, which is exactly the same as this. You can see the inequality is facing the zero. Just to write it in the same form as them though, I'm going to flip everything around. 2x^2 - 21x + 40 is less than zero. And you can see that before the crocodile was eating the zero. Now the crocodile is eating the zero. So we haven't changed anything. We have just rewritten it.
Guys, that is our final question of the day. Let me know. Did it make sense? Do we have any questions? I know it was a tough one. Let me know what you think.
Emily said, "You did that in such an easy way compared to me."
Miro says, "I get it now."
Moon says, "I'm going to go watch Shakira's live now." LOL. Okay, guys.
Couple of things. Couple of things. Um, yeah, Richard, don't worry. I can handle that. Um, so couple of things before we go. Number one, um, we have the boot camp starting tomorrow. It's Tuesday to Saturday, completely free, 3 p.m. to 4 p.m. Sign up using the link which is pinned in the chat or using um the QR code which is on the screen. Second thing, which I don't want to distract you guys from the maths, that's our most important thing. Absolutely. But I have an extremely exciting announcement which I'm going to be mentioning throughout the week. Very exciting for me. Um hopefully exciting for you guys too.
When I was doing the mindset advice and the psychology coaching and the performance coaching ahead of paper one, you guys loved it. I get asked a lot how I manage my time, how I manage my productivity, all of these different kind of general self-improvement things.
And something which is very important to me is teaching you guys not only maths but the things that you actually need to know to thrive in life. At the end of the day, GCSE maths is about passing an exam. I don't wake up thinking of maths.
I don't love maths, but I do know that you guys need to do well in GCSE maths and that's why I do what I do, right?
But now I've kind of built what 16-year-old Matt wanted in that respect.
I've kind of built the GCSE maths platform. So, as I keep doing that, it's time to move on to what I wanted when I was your guys' age, moving into A levels. And for that reason, I am very pleased to announce that I'm actually launching a bit of a personal development and general education community in the summer specifically aimed for people who are 16 to 18, i.e. your guys' age. We're going to be covering the things that you guys need to know. I'm going to cover things like health and wellness, fitness. I'm going to cover things like making money, how to manage money, how to invest. I'm going to cover things like how to use AI, what AI means for the future and what you guys need to know to be ahead of the game and to kind of move forward in your life effectively. I'm going to talk about things like how to plan your life because at the end of the day, guys, it's tough. What A levels do you choose? What university do you choose?
If you want to go to uni, do you want to get an apprenticeship? Do you want to start your own business? How do you do that? Basically, this community is going to be what I wish I had when I was your guys' age. And right now, I am going to put the link in the chat um replacing the pinned message, which is going to go through to a wait list.
So, I've not formalized the plan yet, but I do know it's going to be launching as soon as possible after um you guys have finished exams because that's also when I finish um and and a lot of my work slows down. So, it's going to be launching as quickly as possible. And all you have to do is um click the link in the chat. It will take you through to like a sign up form. It's just a wait list. And all that is going to do is it's going to give me your email address so that when it's ready to launch and when I'm ready to get going and when you can sign up, when you can join, um I can send you guys an email and then you guys can join if you want or not join or whatever. But it gives me a way to communicate with you after GCSEs are finished.
I feel like I was just talking for a long time there, guys. Um, but yeah, any questions in the chat, let me know. I don't want to speak about it for too long because I don't want to distract from the maths, but I'm really excited about this. It's um, it's been something that I've wanted to do for a long time. And it's kind of why I got into teaching GCSE maths in the first place was to kind of a little bit later start teaching some other things which are uh which are you know even more impactful than than GCSE maths. And now I'm at the stage in my journey where I'm ready to share a little bit of what I've learned over the last decade in this world um in the kind of the the um reflection world and and personal development world. So yeah, I'm really I'm really excited.
Sama says, "Good luck and thank you so much." Unknown says, "That's a really cool idea."
Katus says, "Awesome."
Liberty says, "Great idea." He guys, I'm glad you like the sounds of it. I'm glad you like the sounds of it. Is it something you guys are interested in?
Let me know in the chat.
Maybe I'll be able to actually I can see in real time if people are signing up to the weight list. Let's have a quick look. Oh yeah, I can see that a few of you guys have signed up um for the for the weight list. It's completely free, guys, as well, the weight list and everything.
Let's see what the topics of interest are. So, we have investing and GCSE revision.
We have um what A levels to choose. We have uh how to make money. Dylan says life in general, taxes and bills and law, how it all works. Alevel options advice, how to manage stress, how to earn money, apprenticeships, health, health and fitness in general.
Um, we have I really liked Maria's and I'm only saying the name. I won't say most of your names. I'm only saying the name because I know she wouldn't mind.
Identity based habits, dopamine and motivation, discipline versus motivation systems. Now we're talking. That's some serious stuff.
Um, so guys, I'm going to hang around maybe now for five minutes or so and maybe not five minutes, three to five minutes so that you can um join if you want to or like join the wait list if you want to. Um, Leica Milka says, um, it's literally perfect for after exams because I'm going to try and go get a job. I can talk about that stuff.
Fantastic, guys. Fantastic.
What format is it going to take? I'm going to probably do a weekly live. Um, so a weekly live session where I teach a topic. Um, and it's probably going to be half an hour of me teaching the topic, half an hour of Q&A. There's going to be um community features, leaderboards, challenges, accountability, all of that stuff. It's nice cuz I'm just building what I wish I had, you know? So, um yeah, it's going to be really cool. It's going to be really cool.
Yeah, exactly. Joseph, live sessions.
Uh Gina says, "Will this start after exams or during?" It will start um after exams. Porsche Enthusiast says, "Is it similar to Discord?" because that's what I understood. There will be discord like features but it won't be you it won't look like discord. It will look more like my it'll look more like my gcsmaths.com the platform. Um so there's going to be um there's going to be like leaderboards, challenges, you guys can talk with each other outside of the uh sessions. Um there's going to be chat rooms. There's going to be basically it's going to be a really really sick cool community. Um, and I'm really pumped for it. You know, I've been doing the GCSE math stuff for a long time and I really love doing it.
Um, this is absolutely fantastic being with you all, but this feels like the next level, you know. This feels like really the next level. So, I'm pumped for it.
Let's see if many other people have uh put something in. Nice. I can see a fair few of you have have filled out the weight list form. Mia. Oh, actually, no.
I'm not going to read names. Um, some people saying you can cover anything.
Life in general, how to pick a career, what to do in the long summer, university, money management, jobs, travel, choices for Alevel, apprenticeships.
Fantastic, guys. Somebody saying music.
Porsche enthusiast says, "How many people have filled out the form?" Um, maybe 20.
Boxing says, "Matt, you could consider to talk about if you junior apprenticeships are better and which is the better path?
Fantastic guys. We're going to call it a day there. It's been a fantastic session. Always a pleasure, guys. I'm looking forward to tomorrow, day one of the halfterm boot camp, guys. We're going to lock in and we're going to be so ready for paper two and so ready for paper three. And hopefully we're going to at least partially enjoy the buildup.
We're going to put in some great work over the next few days. It's time for me to say good Oh, actually Carmel reminded me. Guys, let's spam the chat full of emojis. I was just about to clock off, but guys, little bit of a party to celebrate another fantastic hour of revision. And we're going to uh we're going to end on that. Carl says, "Wait, the party." Hey, my pleasure. Unknown.
My pleasure. Boxing, good job, Porsche enthusiast in Charlie.
Joe says, "Um, thanks so much. Have a great evening and I look forward to this weekend or this week, sorry. Fantastic.
Emily's partying. Lea Mika's partying.
Joe's partying.
Cookies. Cream's partying."
Okay guys, I'm going to say goodbye.
Goodbye Liberty Y. Goodbye Wasty.
Goodbye Salsa. Goodbye Emily. Goodbye Carl.
Goodbye Joe Unknown.
Goodbye Lea Mika. Goodbye Miro. Porsche enthusiasts SA in Charlie Boxing 90 Chris Panchal Sama Liberty Joe Amily Gina Adiveti guys go enjoy the sun for the evening and I'll catch you tomorrow. Bye for now.
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