To solve the functional equation f(f(x)) = x + 1, assume f(x) is a linear function of the form f(x) = ax + b. Substituting this into the equation yields a²x + ab + b = x + 1. By comparing coefficients, we find a² = 1 (so a = 1 or a = -1) and b(a + 1) = 1. When a = 1, we get b = 1/2, giving f(x) = x + 1/2. When a = -1, we get 0 = 1, which is impossible. Therefore, the solution is f(x) = x + 1/2.
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An Oxford University Test Question | Can you solve ?Added:
Hello, welcome back once again. Today we have this interesting functional problem.
We're given that f of f of x is equal to x plus one. In this video, we're going to find this functional equation with this property. So, let's get started.
Now, take a look at the right-hand side here. The highest degree of x here is one. So, this must be a linear function.
But, let us consider the following.
Say x I mean f is equal to let's say we have x.
And this is a linear function, right?
So, let us compute f of x.
So, here you would see that here f of f of x is going to be equal to this x, replace it with x. So, that will also give us x.
Okay? So, let's say f is equal to 2x plus one. This one here is a linear function. So, let us compute f of f of x. So, here f of f of x is equal to two into bracket. So, this x replace with 2x plus one. So, get 2x plus one and then plus one. So, if you simplify this carefully, we see that f of f of x here is equal to 4x plus three.
And you can see the degree of x here is one. So, therefore, this functional equation must be a linear function. So, let's get started.
Now, we're given that f of f of x is equal to x plus one.
So, let's f of x equals ax plus b since f is a linear function.
So, therefore, here f of f of x is going to be equal to a into bracket.
So, replace x with ax plus b.
So, that will be ax plus b.
And then plus b.
So, here we see f of f of x is equal to here it will be a squared x plus ab.
Then plus b.
Now, let us recall again that this left-hand side is equal to x plus one.
So, therefore, we have a squared x plus ab plus b is equal to x plus one. Now, let's compare coefficients.
So, here we see that a squared is equal to the equation of x here, which is one, right? So, this will give us a is equal to one or a is equal to negative one.
So, let's compare the constants, right?
So, here So, we can factor out b. So, you get b into bracket a plus one is equal to one. Now, you can see that if a is equal to one, we get 2b is equal to one, which is given us b is equal to one over two. But, when a is equal to negative one, we get zero. B times zero is zero, so zero is equal to one is a false statement. So, there's no solution with a is equal to negative one. So, therefore, the functional equation with the above property is equal to So, that is x plus one over two. And this right over here is our correct answer. Thank you for watching. If you enjoyed the video, please kindly subscribe to this channel.
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