When solving rational equations, if the algebraic manipulation leads to a contradiction (such as -1 = 4) or produces a solution that makes the denominator zero (an extraneous solution), the equation has no solution. For example, in the equation (x-2)/(2-x) = 4, factoring out -1 from the numerator gives -1 = 4, which is false, and cross-multiplication yields x = 2, which makes the denominator zero and is therefore invalid.
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This equation seems impossible to solve !追加:
Hello, welcome back once again. Today we have this interesting algebraic equation.
We have to find the value of x given that x minus two divided by two minus x is equal to four.
So, let's get started.
Now, listen guys, an equation does not have a solution does not make the equation useless or meaningless, okay?
Now, in this case here where you ask to find the value of x and maybe the equation doesn't have a solution.
Sometimes this is a normal way to check your level of of understanding of mathematics.
Okay, now let's proceed.
Here we're going to find the value of x, but take a look on this left-hand side.
Actually, x cannot be two, right? If x is equal to two, we're going to have two minus two at the denominator, which will make it zero. And division by zero will make this left-hand side undefined. So, we need to take note of that.
Now, actually here we can actually factor out negative one from the numerator. If you factor out negative one from the numerator, we're going to switch this to two minus x.
And then at the denominator we have two minus x. So, this is equal to four.
And we can see from here this both get cancelled and here we have this first equation negative one is equal to four.
And we know this is false.
So, what is going on? Does it mean that with this method here we just arrive at an equation that is false? We know this is not true.
Or does it mean there's no solution? I think let's just label it that there's no solution.
But what happens when we cross multiply the equation? Let's see.
So, from the original equation we have x minus two divided by two minus x.
This is equal to 4 divided by 1. So, let's cross multiply. So, here 4 or x minus 2 times 1 here will give us x minus 2 is equal to 4 multiplied by 2 minus x.
From here we get x minus 2 is equal to 8 minus 4 x.
Now, let us collect like terms. So, here we have x. So, this one is negative crossing over becomes positive 4 x.
Is equal to here 8 is positive. This one is negative crossing over becomes positive 2.
From here we get 5 x is equal to 8 plus 2 will give us 10.
So, divide both sides by 5.
This both get cancelled. From here, we have that x is equal to 2.
But earlier, we stated that x cannot be 2 because of the denominator. Our left hand side of the equation is x minus 2 divided by 2 minus x. So, it clearly implies that 2 cannot be a solution because it will make this left hand side undefined. Therefore, 2 is an external solution when you cross multiply.
So, in this case this equation doesn't need any cross multiplication. We just factor out negative 1 from here and cancel out and you arrive at just negative 1 is equal to 4, which is probably wrong, right? So, therefore, the best solution to this problem is that there's no solution.
There's no solution. Thank you for watching. If you enjoyed the video, please kindly subscribe to this channel.
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