To solve exponential equations where the variable appears in both the base and exponent, use substitution to express both sides with the same base, then apply the law of indices (if a^b = a^c, then b = c) to solve for the variable. For example, in 3^x = x^9, let x = 3^y, which transforms the equation to 3^(3^y) = 3^(9y), simplifying to 3^y = 9y. Dividing both sides by y and expressing 9 as 27/3 = 3^3/3^1, we get 3^y/y = 3^3/3, which yields y = 3, so x = 3^3 = 27.
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Algebra Lesson: Solving Hard Exponential EquationsHinzugefügt:
The method I'm going to use to solve this equation will amaze you.
Nobody has ever shown this to you. I believe you are going to learn a new thing today.
We have 3 to the power of x is equal to x to the power of 9.
This method is very very simple for you guys.
Now, what we are going to do is that let's say let um x to be equal to 3 to the power of y.
Okay? So, let x equal to 3 to the power of y. Then let's put in 3 to the power of y in this equation and see what we shall have. Anywhere you see our x, put in 3 to the power of y.
Okay? So, this become 3 to the power of over our x here is what? 3 to the power of y. So, this is 3 to the power of y is equal to this x is what?
3 to the power of y all to the power of 9.
Okay? So, this become Look at this.
9 * y is 9y. So, this become 3 to the power of 3 to the power of y is equal to 3 to the power of 9 * y is 9 y.
All right? Now, let's consider this law of indices.
If you have a to the power of b to be equal to a to the power of c, this implies that b is equal to c.
Now, from here, this equation become 3 to the power of y is equal to 9 y.
Let me show you how to solve this.
What we are going to do is that let's divide both sides by 9. So, if I divide No, by y. So, if I divide here by y and also do the same to the left hand side, this will cancel out this. This become um 3 to the power of y divided by y is equal to 9.
Now, what next?
I want to express the left hand side to be like the right hand side. How can I achieve that? And we all know that this 9 can be expressed as 27 divided by 3.
So, we shall have um 3 to the power of y divided by y to be equal to instead of this 9, put in your 27.
Okay, divided by 3.
Because 27 divided by 3 will give you what?
Um sorry, 21.
3 Sorry, 27. Sorry, 27 to the power 23 27 divided by 3 is 9. Okay? Because 9 * 3 is 27.
Now, look at this. This 27 can also be written as 3 to the power of 3. So, this become our 3 to the power of y over 9 Sorry, over y is equal to 3 to the power of 3 by 3.
Now, from the from the numerator, if I say 3 to the power of y to be equal to 3 to the power of of 3, this implies that our y is equal to 3 from the numerator. From the denominator, we can say that our y is just equal to 3.
So, we we have obtained our solution of y to be equal to 3. So, from the given equation, we say x Our x is equal to 3 to the power of y, but our y is 3. So, let's put it back and see what we shall have.
So, our x will be equal to 3 to the power of 3, which implies that our x also therefore our x is equal to 27. So, this happens to be our final answer. I believe this method is very simple for you and you can access this question in a very simple way. Help us to share this video, follow us, and subscribe to our channel. Thank you.
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