This video teaches quick problem-solving strategies for nine organic reagents: thionyl chloride (SOCl2) and HCl with heat both replace OH with Cl; NaI in acetone (Finkelstein reaction) replaces Br with I; bromine with heat or sunlight causes benzylic substitution (replacing H at the carbon adjacent to benzene ring); HX addition follows Markovnikov's rule (negative part attaches to the carbon with fewer hydrogens); and bromine with heat causes allylic substitution (replacing H at the sp3 carbon adjacent to a double bond).
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Deep Dive
Test Yourself Solution on 9 Organic Reagents in 9 Minutes
Added:Hi students. In previous video, I discussed nine reagents in just 9 minutes. In this session, you are going to use that. I gave this question as a test yourself, right? Now, let us see how can we apply and solve the question so fast. This is one of the NCERT question from haloalkanes and haloarenes. When you see thionyl chloride, what is the trick? Remove OH and keep Cl in its place. Very good.
Second question. When HCl in the presence of heat, what you have to do?
Remove the alcohol. HX if it is there, remove OH remaining as it is. Remove HX.
I mean that OH and keep Cl in its place.
Next. When you see NaI over acetone, can you tell me what is the name of a reaction? Finkelstein reaction. What you have to do? Remove the Br and keep iodine in its place. So, the reagent What is the product? CH3CH2I.
How many questions? Three questions are over. Now, bromine if you heat it, I mean in the presence of heat or a sunlight, what is the trick I told you?
With a benzene, benzylic substitution takes place. What you have to do? Remove the hydrogen and benzylic position. What do you mean by benzylic position? The benzene ring next to carbon is benzylic position. From benzylic Remaining as it is everything. Only benzylic position, remove that hydrogen and keep one Br here. Easy. See the next one. Hydrogen iodide. HX if you add.
Then check it out the double bonded carbon. What is the trick? It follows Markovnikov's rule. What do you mean by Markovnikov's rule? The negative part of the species going attached to the double bonded carbon having less number of hydrogens. Let's say one and two. Which is having less hydrogens? If you see this portion, more crowded side. Okay?
It will attack CH3. This iodine comes here. This hydrogen comes here. Right?
Coming to the bromine over in the presence of heat or UV light. Actually, in this many cases we can do any number of questions we can solve. You know, by using Markovnikov's rule. Bromine, same thing. Here bromine, heat. If you are in the presence of heat or UV light. In the presence of heat or UV light. Two three reactions we discussed. What are those?
For allylic substitution, allylic substitution. What do you mean by allylic substitution? Double bonded carbon, next carbon is sp3 carbon.
Remove hydrogen from there and just you put in halogen like a BR. THAT'S IT. IN JUST three minutes you have finished this question. Less than nine minutes you have learned nine reagents in previous video. I'm your Komali your chemistry mentor. Thank you so much for watching this video. See you again in next video with the so many tricks.
Let me know which topics you are feeling difficulty. I'll make a super duper easy videos for you.
Have a great day.
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