While the step-by-step logic is sound, labeling standard algebraic manipulation as a "secret trick" feels more like marketing than a mathematical revelation. It is a solid instructional piece for beginners, though it lacks the depth promised by its Olympiad-level branding.
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The Secret Trick to Solving Exponential Equations Fast!Added:
I'll be showing you how to solve this Olympiad mathematics question.
Do you believe that most students do not accept the solution to this equation?
By the end of this video, you will know it.
We have 3 to the power of x plus 3 to the power of x is equal to 33 to the power of x.
So, we are asked to find the value of x.
Follow me step by step as I provide a solution to this equation.
Okay.
Now, we shall have solution.
Now, the question says 3 to the power of x plus 3 to the power of x to be equal to 33 to the power of x.
Now, this is what we are going to do.
Let's move 33 to the power of x to the left-hand side.
Plus become minus when crosses equal sign.
Then, we shall have 3 to the power of x plus 3 to the power of x minus 33 to the power of x is equal to 0.
Now, look at this.
Do you believe that 3 to the power of x is a factor of this, is also a factor of this, and is also a factor of this?
Let me prove that this is true.
The common factor here is 3 to the power of x multiplied by If this divide this, we shall have one.
You put a plus sign.
This divide this, we shall have one.
Now, you put a minus sign.
Let me show you that this can divide this without a remainder.
If you have 33 to the power of x divided by 3 to the power of x.
There's a law of indices that we are going to apply to solve this.
And the law of indices state that if you have a to the power of b divided by c to the power of b, that this is the same thing as saying a over c all to the power of b.
So, to apply this law to simplify this expression, we shall have 33 over 3 all to the power of x. Of course, 33 divided by 3 is 11. So, the whole of this become 11 to the power of x.
What I'm trying to show you is that I'm going to prove that I'm proving that this can divide this without a remainder. And also, 3 to the power of x is a factor of 33 to the power of x.
So, if this divide [clears throat] this, we are going to have 11 to the power of x. All this is equal to 0.
Are you with me? Are you okay with this?
Now, look at this. 1 + 1 is 2. So, so we shall have 3 to the power of x multiplied by 2 minus 11 to the power of x to be equal to 0.
Okay. Now, we shall have 3 to the power of x to be equal to 0. That is the first equation.
Now, in this place, x is a element of a non-empty set.
[snorts] So, we don't want this solution.
Okay. So, we shall continue with 2 minus 11 to the power of x to be equal to 0.
>> [snorts] >> To solve this, we shall have um 11 to the power of x to [snorts] be equal to 2. Because when you move minus 11 x to the right-hand side, this is what we shall have.
Now, you cannot solve this like this because you cannot express the base to be the same.
What we are going to do is to introduce um log to both side in base of 11.
So, we shall have the log of 11 to the power of x base of 11 is equal to the log of 2 base of 11.
This x multiply the whole of this log.
We shall have the log of 11 or x log of 11 base 11 is equal to the log of 2 base 11.
Log of the same base is always equal to 1.
So, log 11 base 11 is 1.
>> [snorts] >> x * 1 is x.
So, we shall have x to be equal [snorts] to the log of 2 base of 11.
And this happens to be the final answer.
If this is the first time you come across this [snorts] video, air pulse to share, follow, and subscribe for more.
Thank you. Oh, the power of
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