To solve exponential equations like x^1250 = 5^(x^2), use substitution (let m = x^2) and apply exponent rules to transform the equation into a simpler form (m^(1/m) = 5^(1/625)), then solve by matching bases to find m = 3125, and finally substitute back to get x = ±25√5.
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Only 10% Students Solve this exponential math olympiad question | X^1250 =5^X^2 |Added:
Hello everyone. Welcome to Rafa's Classroom. Today we are solve a interesting exponential math problem, which is x to the power 1 2 5 0 is equal to 5 to the power x to the power 2. X is equal to what? How to solve this interesting exponential math problem?
I solve this question easy method our math solution.
Our question which is x to the power 1 2 5 0 is equal to 5 to the power x to the power 2. This is our question.
Now, first of all, I can easily this expression, it will be x to the power This is it will be 2 * 6 2 5 is equal to 5 to the power x to the power 2.
Now, all of that the exponential formula a to the power m n, which is a to the power m whole to the power n.
If I apply this exponential math formula, this expression it will be x to the power 2 bracket whole to the power 6 2 5 is equal to 5 to the power x to the power 2.
Now, this is x to the power 2, this is x to the power 2.
So, at this moment, let x to the power 2 is equal to m.
Now, I substitute this value here. So, it will be m to the power 6 2 5 is equal to This is 5 to the power m.
Now, I use both side exponent 1 over m.
So, this exponential expression it will be M to the power 625 bracket whole to the power 1 over M is equal to 5 to the power M bracket whole to the power 1 over M.
Now, this expression it will be M to the power 625 times which is 1 over M is equal to this is 5 to the power M times 1 over M.
Now, this M this M is cancel out.
We are find out which is M to the power 625.
This time this it will be this over this M is equal to 5.
Now, at this moment I again I use again both side exponent which is M to the power 625 over M bracket whole to the power 1 over 625 is equal to 5 to the power 1 over 625. I use both side exponent 1 over 625.
Now, this time this so it will be M to the power 625 over M times 1 over this is 625 is equal to 5 to the power 1 over 625.
Now, this 625 this 625 is cancel.
We are find out which is M to the power 1 over M is equal to 5 to the power 1 over 625.
Now, how to find out the value of m in this exponential expression?
Let me explain. At this moment, I can say easily this expression, it will be m to the power 1 over m is equal to 5 to the power 1 times this is 1 over 625.
Then this is m power is 1 over m is equal to this expression, it will be 5 to the power 5 over 5. Oh, no, that 5 divide 5, this is 1 times here is exponent 1 over 625.
Now, this is m to the power 1 over m then this expression, you can say it will be 5 to the power 5. I take this 5 here, bracket whole to the power it will be 1 over this 5 here times this exponent will be 6 2 5.
Now, in this expression, m to the power 1 over m is equal to 5 to the power 5 is equal to what? How to simplify this expression?
So, 5 to the power 5, you can say easily it will be 5 to the power 2 times 5 to the power 2 times 5.
This is 25 and this is 25. So, 25 times 25, it will be 625. 625 times 5, it will be 3,000 125.
Now, at this moment, you can say this is 300 1,025.
Then this is 1 and this 5 times 625, this is 3,000 Now, at this moment, if I compare both, at this moment, you can easily hear m is equal to 300 3,000 125.
Now, remember that I recall m is equal to x squared. I substitute this value here. So, m is equal to x squared. So, I take this value here. I take I get x is equal to what? So, this is x to the power 2 is equal to 3 1 2 5.
Then, I use both side square root, so which is x to the power 2 bracket square root, then here is a square root 3 1 2 5.
Then, at this moment, this squared is cancelled. We are find out it will be x, and this is plus minus.
And this x especially it will be 25 * 25 * 5.
Now, this is x, and this is plus minus, and it will be square root 25.
* square root 25. I I separate this case and a square root 5.
Now, at this moment, you can say here x is equal to plus minus.
This is square root 25, which is 5 * square root 25, it will be 5 * and this is a square root 5.
Then, this is x [clears throat] is equal to plus minus. 5 * 5, this is 25.
And this is a square root 5. So, we are find out our final answer, which is x is equal to plus minus 25 whole square root 5. So, our question, which is x to the power 1250 is equal to this is 5 [clears throat and snorts] to the power x to the power 2 here x is equal to plus minus 25 square root 5. This is our final answer in this viral exponential math problem.
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