"Class 12 Chemistry | Chemical Kinetics (रासायनिक बलगतिकी) | Lecture 4 | UP & Bihar Board 2027

[00:00:11]Hello hello dear students, we welcome you to Struggle Academy, so once again my dear children, you all are welcome to Struggle Academy, so quickly join the class, so quickly my dear children, get added to the class.

[00:00:33]Ok?

[00:00:58]Okay, let's come to this platform of Struggle Academy, what is going to happen to us children, lecture number is going to be four, let's do some work, setup work, let's go, who is he, where is he from, so today we have to do instantaneous rate of reaction. Today we have to learn about the speed of instantaneous reaction. So today we have to study the instantaneous rate of reaction.

[00:02:04]So let's see, today our topic is going to be the velocity of instantaneous reaction and there will be questions related to it.

[00:02:15]Children, what is the speed of instantaneous reaction and what is going to happen related to it? There are going to be questions. So now look here, first of all, the velocity of the instantaneous reaction. Look carefully.

[00:02:34]Instantaneous Yes Rate of Reaction Rate of Reaction Instantaneous Rate of Reaction. So dear children this is going to be our topic: velocity of instantaneous reaction.

[00:03:11]Now this instantaneous reaction velocity is calculated for very small changes. It is said that it is used for very small changes. Changes are made for very small changes. is done.

[00:03:49]It is used for very small changes. For example, if there is a reaction, there is 2a and +b. And forming C and sorry if we see that it is forming C then children if it is forming C then how will we write its instantaneous rate of reaction, how will we write the velocity of instantaneous reaction, so we will write it as instantaneous ROR, velocity of instantaneous reaction, instantaneous rate, okay, rate of reaction, so what is the way to write it, the reactant ahead will decrease with time. If the reactant decreases with time, we will put a minus. 1 What will you do upon? So the way to write this will be da / dt da / dt Now after this we will make it equal.

[00:04:42]Then there is b. Nothing is written in front of b but still write 1 / 1. What else is there? db db / what will happen? dt will become Then what will happen after that?

[00:04:55]See, it is C. Write +1 / 1 instead of C and what will happen to this [sound of clearing throat]? What will happen to DC by? DT will be done.

[00:05:05]So how should you write these [nasal sound]? You should know how you can write the method. That means how can you write instantaneous rate of reaction. This should come to you. Ok?

[00:05:25]Like if I tell you simply here that if there is N2 and +3H2 here and what is happening here? If 2NH3 is then how will its instantaneous rate of reaction be written? So its instantaneous.

[00:05:44]Ok? What is instantaneous instantaneous rate of reaction equal to? - what do you write 1 of / 1 d n2 /? dt. Write dn2 / dt. Then write equal to minus 1/3 dh2 / what should I write? Write dt as equal. Then what should you write after that, children? [nasal sound] Then what can you do here after that? What can the majority do here? What can I write there? We'll write plus +1/2 because this is the reactant. If this gets spoiled then this will happen. These minus signs will remain ahead of them and this will remain in plus.

[00:06:31]What remains? DNH3 DNH3 / DT These are all the topics you should pay attention to. Are you getting the point, child? You should pay attention to all these topics and your way of writing should be correct.

[00:06:48]perfect. One you will show by writing H2O + Cl2 and 2HCl and write its instantaneous rate of reaction.

[00:07:06]You should write this HW correctly. Or you can write it down right now. It's not a big deal.

[00:07:11]Ok? So you should know the instantaneous rate of friction as I am writing it.

[00:07:16]Is it clear? It should come conformably and what is better than that, the velocity of instantaneous reaction is used for very small changes, which is very little change, it is at zero point, right, it is for very little change, now what happens on these, let us make some graph for instantaneous reaction, okay, like now we can make some graph in this, let us draw some graph for reactant and product as we talk about graph. Let's talk about graphs. Ok? So if I do this, brother, this is 2a + b. Suppose 2a and + b and here b is there. So I will write its instantaneous rate of reaction.

[00:08:15]What is instantaneous rate of reaction equal to?

[00:08:20]What can I write as 1/2 of minus da/? I can write dt.

[00:08:23]Yes of course I can write. Can I also write -1 / 1 db / what can I write? I can write dt. Yes of course you can write this also.

[00:08:32]And to write this we will have to put a plus. +1 / 1 dp / What do I need to write? dt will have to be written. And this d that is being used is being used for very small changes. What is it being used for? It is being used for very small changes.

[00:08:48]So now here I will tell you that if I talk about the number one graph, then tell me that brother, I want to make a plot from this graph, please tell me about it here. And I'm taking the concentration here of a. I'm saying here's da and what's the thing here? dt then the concentration will decrease with time. And when the concentration decreases, you already know that this is the graph of decreasing concentration.

[00:09:13]Ok? So and then after that, the second graph is this, this is the second graph, this was for what, it was for reactants, what are reactants, reactants, reactants, now the second money, for this, can I tell, for whom should I tell the product? Product.

[00:09:46]What is a product? There is a product. What is a product? There is a product. So the graph for the product should be time versus concentration.

[00:09:54]Here I am writing p dp. dp / what am I writing? What is T i.e. product p? It is a product. t is time.

[00:10:04]What graph can be there between them? You tell me this. What graph can be there between them? Are you getting the point? We can get a graph between these.

[00:10:11]What is it? Their graph product will increase with time.

[00:10:16]What will happen to the product over time? Will increase.

[00:10:19]This is the reactant. This is the reactant.

[00:10:21]What will the reactant turn into? in the product. So what always happens is what is the product? Increases.

[00:10:27]What is a product? Increases. So this product will grow.

[00:10:31]What will happen children? The product will increase. So this is their graph. dp / whose is it? of dt. So now here are some concentration graphs.

[00:10:41]Like giving angles etc. Then how do we ask the question or what could be in it?

[00:10:47]Like if I say, look brother.

[00:10:54]Ok? If I say this is the graph of the reactant like this. da here okay?

[00:11:08]So should I say this is da and what is this thing? dt is. And from here a tangent line has been drawn and its angle has also been given here. I suppose that some angle may have been given to it. Ok? Some angle should be given. Ok? So we do n't have to take this angle as it happens. Remember, we don't have to take this angle. So what is this that happens? There is a slope.

[00:11:40]What does slope mean? Shield.

[00:11:44]What happens? Shield. Whatever this slope is, the slope of the slope is equal to tan theta. What is it equal to? tan is equal to theta. So tan theta is equal to what? tan theta equals what? perpendicular/base. perpendicular/ base. So what is the perpendicular thing here? The perpendicular da is the base dt. So what will become of the perpendicular da/?

[00:12:08]dt then da / dt tanθ cannot be said to be equal to direct.

[00:12:12]Instead of perpendicular/base, you can say da/dt.

[00:12:15]What can I say? Can speak da/dt.

[00:12:18]Archana Prajapati Most welcome Archana baby girl. Ok? You are most welcome.

[00:12:25]So here it is, so understand da / what can we write? You can write dt. Ok? There should be no problem. And especially it should be that you tan theta is equal to perpendicular/base. So d / dt is the angle here, but whatever angle you take for tan theta, you will have to take that angle as positive.

[00:12:47]What will I have to take? Positive. There will always be talk about this forward angle. There will be talk of positive angle. Isn't it? Positive angle, whatever angle we take, we will take the next one. Ok? If this is given anything, we have to take the front angle. Are you getting the point? The rear angle is not to be taken. These many things should be remembered.

[00:13:14]Correct? Like what happens now? This was for the reactant. Who was it for?

[00:13:19]Reactants.

[00:13:21]What was the reactants for?

[00:13:26]Agent factor. Who could this be for?

[00:13:34]This can happen for the product also.

[00:13:40]What do we call this product?

[00:13:43]product. This can also be for the product.

[00:13:47]Now how will this graph of the product be made?

[00:13:50]Look carefully how this product graph is formed? The product is being made like this only.

[00:13:56]Ok? So the product is being made in this manner.

[00:13:58]So suppose from this point what do we draw?

[00:14:04]A line drawn tangent. So what do we do? This angle should not be taken.

[00:14:10]We will not take this angle but will take this angle.

[00:14:13]So this positive angle will have to be taken towards the front.

[00:14:20]So, whose graph is this actually? of the product. So the product in this is this product. So whatever happens here, whose product it is, should we write it here? dp dp / dt This is a graph between product concentration and time. The graph is between the concentration of the product and time.

[00:14:42]Ok? Who is Archana Bachchi?

[00:14:45]Why are you saying goodbye? dp/dt ok? So what will we do with this? We also need to know its slope, its slope will also be equal to tanθ.

[00:14:56]and tanθ equals perpendicular/base. So what is a perpendicular thing? dp and this dt so what can we write? dp / what will you write? All this will be written as dt. So it is very important for you to write this and it is also very important to understand it. Ok? No problem sir, no problem.

[00:15:15]Come on, let's move forward.

[00:15:17]You should know which angle to take.

[00:15:20]Ok? Along with the angle, there are many more questions too. We will also consider these questions and try to answer them.

[00:15:27]Ok?

[00:15:29]Now even before this we may get a lot of questions.

[00:15:32]Like one more question has been given earlier. Let's do two questions first.

[00:15:36]Then we will move forward. So here the first question given to you, what is the first question given to you? You must be clearly seeing that this is the first question, understand it carefully. This first question, okay, oh my god, baby Archana, go ahead, okay, then read it now, but then we feel like offline, you can see the class, okay, so what is it saying here, it is saying that reaction 2A is saying that for reaction 2a + 4C, write the expression for the instantaneous rate of the reaction. So what's the one thing here?

[00:16:32]Write the expression. So let's take the reaction here, 2a + 3b [sound of clearing throat] forming 4C. So let's write the expression for its instantaneous rate of reaction. So its expression means now look here instantaneous, we will write it as instantaneous r o r instantaneous rate of reaction. So what can we write about this? - 1/2 of dA / dT is equal to +3 here, that is, 3b, so here minus 1/3 of dB / dT, then after that it is equal to 4, so plus +1 4 dC / dT dC / dT, so what is the thing here? This is the expression you get.

[00:17:33]I have written this expression for the rate of a typical reaction.

[00:17:37]Ok? Wrote this. So saying if dc / dt is saying dc / dt is so many meters per second.

[00:17:47]Ok? Then what is the value of da - dt?

[00:17:53]So look here what is Sandrum instantaneous R1 equal to?

[00:18:02]I would like to take this here. I would like to take it to its value. I would like to take it.

[00:18:07]a brother plus 1/4 is here and then after that it is written dc / dt so I will do this + 1/4 dc / dt what is the value of this?

[00:18:27]What is the value of dc / dt? The value of dc/dt is given as 4 * 10 to the power minus two, okay, and this four to four will cancel out, so 10 to the power minus two meters per second is given. This is the instantaneous rate of reaction. So its value is 10 to the power -2, so this is the instantaneous rate of the reaction, so this is the instantaneous rate of the reaction, so what is he asking, he is asking what will be the value of da / dt - da / dt, so let's not do anything, the same rate of corrosion reaction, instantaneous r or instantaneous rate of reaction equal, now we will write this, now what will we write with this, if we write this, then we will write minus 1/2 da / dt, so minus 1/2, so okay. da is also fine. dt is also fine. So what is the instantaneous rate of reaction? 10 to the power minus two is the result. So this is 10 to the power minus two.

[00:19:47]So let's write this to the power of 10 minus two.

[00:19:49]Ok? There is no problem. Now multiply it here. So this will become da / dt equal to what will it be - 2 * 10 to the power minus 2 -2 * 10 to the power -2, this will also become meter per second, okay this will also become okay, so what will come, this will come, Rolex Ashish ji is saying sir there is a mistake there. Tell me Ashish Babu, where did I make a mistake?

[00:20:36]Tell me it is three.

[00:20:49]This minus may continue in the future also.

[00:20:52]Here we are thinking that if we write minus here then you can also write it like this.

[00:20:56]This minus can be written whether it is written here or there. So - da / dt equals what? 2 * 10 to the power minus 2 meters per second. Like this is given, whereas we write mole liter inverse second inverse like this.

[00:21:13]Ok?

[00:21:22]Let's go next.

[00:21:25]Tell me where? Only then will the work be done, Babu.

[00:21:28]Let's move on to the next one.

[00:21:32]We, we, life is a beautiful journey, who knows what will happen tomorrow here, who knows what will happen tomorrow here, are you understanding it, let's move ahead, brothers, let's move ahead. Shall we go ahead? Shall we move ahead?

[00:22:24]Ok. Clear Igum's Igum looks like it's clouded over.

[00:22:33]Some kajal has spread on the eyes. And who is asking this question? He has come forward.

[00:22:43]Tell me quickly, can this be the answer to the question or not?

[00:22:49]My brother, can you ask questions or not?

[00:22:54]Because let's move ahead. It should be put on.

[00:22:57]Let's look at what's being said here, talking about concentration changes. He is saying, brother, what is this equation? Nitrogen and here 3H23 is hydrogen and 2NH3 is.

[00:23:12]So I am saying that let me tell you sir how will this be applied? Try it and show me.

[00:23:19]So what's the point of this first?

[00:23:22]Write down the instantaneous rate of reaction. Write down the instantaneous ROR.

[00:23:24]Whatever he gives, write it down. Minus 1 / 1 of dn2 / dt = - 1 / 3 of dh2 / dt = + 1/2 of dnh3 / dt OK? What have we written to this? I wrote this and that. what is written?

[00:23:51]What can we easily write this as? This can be very easily written as instantaneous rate of reaction.

[00:23:59]Come on Bajrangbali good morning Babu good morning good morning that is the name of the Lord, okay you are taking his name, the biggest thing is okay, so you are saying that the rate of extinction of hydrogen, so brother, you can see here that the rate of extinction of hydrogen, if we talk about ds2 / dt, if its rate of extinction was in minus then what would you write? 1.5 What should I write here? 1.5 * 10 to the power is -4 meters per second.

[00:24:40]Then find the rate of disappearance of nitrogen.

[00:24:45]Then find the rate of disappearance of nitrogen.

[00:24:48]So I can write it this way.

[00:24:50]ds2 / dt = - 1.5 * 10 to the power of -4 meters per second. That's why I have to write this the way I wrote it, that this is the extinction rate. The sign is minus, meaning it is becoming extinct. What is happening?

[00:25:09]becoming extinct.

[00:25:15]Okay, okay, you are not a Babu, you are a sister. Okay, sorry dear girl, now we had a little idea about who you are, right? If you are new girl, then please like, subscribe and share the channel, right?

[00:25:30]Please, okay dear, it is simple here, what are we applying, we can put the minus here also because if you write the minus here in minus, it is still in minus, if you write it here, the value will remain in minus only, so it is saying that for the extinction of nitrogen, first of all, the instantaneous rate of reaction is written. Write down the rate of the instantaneous reaction.

[00:25:49]Instantaneous Rate of Reaction Instantaneous r o r Instantaneous Rate of Reaction is the rate of the reaction relative to nitrogen.

[00:25:59]So here we bring it first what will we write with this -1 / 1?

[00:26:06]dn2 / dt so tell me here that if it is -1 / 1 then what is its value of dn2 / dt? Its value is given by the rate of dissociation of hydrogen.

[00:26:22]O Ho DH2 Rate of Dissociation of Hydrogen Rate of Dissociation of Hydrogen What is the rate of dissociation of hydrogen?

[00:26:47]If we look from here and write this equation, then take it -1 / what will it be? It will become 3. s2 / dt will become -1 / 3 * ds2 / dt What is the value of ds2 / dt? Minus 1.5 * 10 to the power minus 4 So here the minus and minus is over. It's plus. 3 * 5 15 0.5 * 10 to the power minus 4 means you will write this as 5 * 10 to the power What can you write as 5 * 10 to the power? -5 ok? Meters per second. This is your instantaneous reaction rate.

[00:27:27]Instantaneous rate of reaction. What is? The velocity of an instantaneous reaction. This is your instantaneous reaction. What is it? There is velocity.

[00:27:40]Okay Vinita Vinita most welcome dear child if your name is Vinita then okay you are most welcome come on what did you write here, calculate the rate of instantaneous reaction means the rate of instantaneous reaction of 5 * 10 see the decimal point was 0, we will bring the decimal here that means minus one will increase in it, now you should also know calculations to this extent okay second thing what is happening here my dear child look carefully here what is it asking, it was asking the rate of extinction sound of hydrogen, now it is asking the rate of extinction sound of nitrogen so now we have to take nitrogen so instantaneous rate of reaction take instantaneous rate of extinction sound of rho so what is the equation of nitrogen -1 / 1 dn2 by what to write dt so what is our instantaneous rate of reaction 5 * 10 to the power minus 5 so here is minus 1 / 1 dn2 / dt so dn2 / dt now we can write it like this what is it That dn2 / dt = - this is going to be 5 * 10 to the power minus 5 meters per second to the velocity.

[00:29:07]Ok?

[00:29:12]Ok? Mole liter inverse, second in comes up so second will be inverse. Correct?

[00:29:18]Salutations at the feet of Guru Ji. Most welcome baby girl Khushboo. You will be beaten a lot. Where do you live? Fragrance.

[00:29:27]Ok. So what's the point here? Minus 5 * 10 to the power minus 5. It is clear. Let go.

[00:29:34]Now what is that and then after that, I had given this question in this. Then this was the first question, so we found out that the rate of reaction against nitrogen is going to be -5 * 10 to the power -5.

[00:29:49]This is it. Are you getting the point? Oh, okay. Milk 20 kg each, blessings to you. Ok? Now what is there here?

[00:29:58]Sir, blessings are also measured in kilos. And what will be the instantaneous rate of formation of NH3 in the above reaction? So the third question is here, the second one has been asked here that the rate of formation of ammonia in this means now from here the instantaneous rate of reaction, now equate it with ammonia. What is the instantaneous rate of reaction Eq +1/2 of DNH3 by? dt then what is given in instantaneous rate of reaction?

[00:30:37]Instantaneous rate of reaction is 5 * 10 -5, so here we will write 5 * 10 minus 5, now 5 * 10 power minus 5, is this correct?

[00:30:53]Ok? 5 * 10 power -5 so what is the +1/ thing here? 2 So dns / dt is to find its value.

[00:31:03]So this becomes dns 3 / dt, so it will be multiplied by five.

[00:31:11]What happens if 5 * 2 is 10? If we do dnh3 / dt then what will happen to 5 * 2?

[00:31:21]10 so 5 * 2 to the power of 10 * 10 is minus 5, okay? Here it is, here it is.

[00:31:41]This is the value, is it clear?

[00:31:47]Nitish ji Ayush Pandey Hi Nitish ji good morning Babu and please tell us in the comments where you are from.

[00:31:57]Where from you Ayush Pandey ji or Nitesh ji and Khushboo already know.

[00:32:05]Please tell me where you are from. Abhishek Saini ji Abhishek Saini good morning Babu. Good Morning. I hope you all are well.

[00:32:14]Ok. Tanika, tell me where are you guys from? Please tell me where are you from? Where are you from dear student? Please do tell.

[00:32:25]So this was your calculation according to the questions.

[00:32:28]Ok?

[00:32:38]Archana is a Jain people.

[00:32:41]And brothers, where are you all from? Nitish ji told a child. Nitesh ji explained it very well.

[00:32:50]Told my locations.

[00:32:54]Ok. You are most welcome. If you all are new to the channels, my dear children, then let me tell you that this is the third lesson of Physical Chemistry of 12th. UP Ballia Abhishek Sahni ji is saying sir from UP Ballia. I am not in Ballia, UP, I am in Ballia, my maternal uncle's house is in Ballia, it is fine, Madhu is in Ballia, most welcome baby, Madhu is saying sir, I am a new student, most welcome Madhu baby, if you are a new student then please like, subscribe, share the channel because if you have any problem in Chemistry then I am, I am always with you. I am always standing with you children. And I will teach you the entire chemistry. You will get all the lectures.

[00:33:49]Go to the playlist and check it out.

[00:33:51]Go to the live section and check it out. Three chapters, the third one is going on from the beginning, so you guys can get all of them. Okay, right?

[00:34:06]Yes. It is in UP. Ok. There is Mau and Ballia in UP. Okay Abhishek Sahni ji, please like, subscribe and share the channel, my dear student Abhishek Babu, you are also saying Ayush Pandey, Ayush Pandey, most welcome Madhu, sir, we are from Bihar. So you are also welcome dear girl and the people of Bihar too. Bihar is no different. Ok?

[00:34:36]You guys are neighbors. What is a neighbor? It is in a separate room of the house. Ok? So these things remain.

[00:34:50]These are the questions you have to ask. Ok?

[00:34:56]Yes. Ok. Thank you very much Babu. If you are subscribing to the channel then I will be ready for you and then you can keep reading.

[00:35:04]Ok?

[00:35:07]We are from UP. In UP, that too in Mau district 54 district. He is from UP 54 i.e. District Mau which is adjacent to Ballia. Ok? And then if you go from Ballia then Bihar is adjacent to you.

[00:35:21]Okay kids?

[00:35:25]Nitesh ji B said, Sir, I also did it.

[00:35:28]Most welcome Babu, most welcome, everyone is heartily welcome.

[00:35:34]Look here it is saying that this is a complex reaction. For 5Br- Br3 and 6H+ N3Br2 3H2O, give the relation between the rate of disappearance of Br and the rate of formation of Br2. Isn't it?

[00:35:54]Ok?

[00:35:56]So what's the point here? What do you see, the equation given is 5Br - Br 3- 6H plus and then this is going to be 3Br2, look carefully. 3Br2 + 3H2O, right? If you see this equation then look at it like this. Then you immediately write down the instantaneous rate of reaction.

[00:36:23]Instantaneous R or Instantaneous Rate of Reaction Whatever is in front of the coefficient is the reactant. Those on the other side of the arrow are in plus. The ones here are in minus.

[00:36:32]That means if there is reactant then it will decrease in minus. If it is a product then perhaps you should know that it will definitely grow. So I am saying 5 is written. So 5, when it is already written, what can I write in its place?

[00:36:44]What can I write about -1/? 5 so I can write this as dbr - / dt equal now nothing is written here bro so please write 1 / 1 of minus what will I write 1 / 1 of minus d will write bro3 - / dt sir ok I have written this also I will write this as 1 / 6 of minus dh plus ion this is d 1/6 of minus what will I write d h+ ion by what will I write dt equal plus what will I write plus +1 3 dr2 / dt I can make this in brackets on all of them.

[00:37:51]You make it on everything. Ok?

[00:37:54]Plus 1/3 of dh2o / dt so what is this saying? First of all, I want you to understand this. What is the connection between them? You have written this.

[00:38:10]Ok? You wrote this. Now he is asking about the relationship in this. He is saying, brother tell me the question.

[00:38:20]What is the relationship between the rate of Br- and the rate of formation of Br2? So what is the relationship between these? You should understand that Br- is Br- and the formation of Br2 is here. Where did you go? Br2 So now if we look at this relation, what is their rate? So this is 1/5 of minus.

[00:38:42]dbr can be minus upon dt and in relation to them they write plus plus 1 / 3 what do they write br2 / dt this is this is the relation what is this their relation if seen then what is their relation okay so this is the relation between them -1 / 5 dbr - dt + 1 / 3 dr2 / dt what is this between them? This is their relationship. So now, apart from the relationship, what will we move forward with? The next topic in this is this relationship. Now again it's saying that if now looking here it's saying if the rate of dissociation of H+ ion is x mole liter inverse second inverse. x mole is saying. So he is saying, look carefully.

[00:39:42]What will be the rate of extinction of Br2? You can simply remove it.

[00:39:45]There is no problem. Come here.

[00:39:47]So instead of X, if I say here, suppose I have given the price of X. Suppose here we should give value in place of x. Ok? No problem. Only x is given. We will assume some value there. So let's get to the instantaneous rate of reaction first. Instantaneous velocity instantaneous rate of reaction is equal to what instantaneous rate of reaction is and what will this instantaneous rate of reaction be equal to? Who are you asking? is saying that the rate of dissociation of hydrogen ion is or the rate of dissociation of hydrogen ion is given. First thing to remember is to know the rate of dissociation of hydrogen ion. So if I write hydrogen ion here, then dh+ ion by dt, now its rate of extinction is x mole liter inverse second inverse, so if this x mole is the rate of extinction, then what will be put here? It will become minus. So what will happen here now? If I say that the rate of extinction of hydrogen is given here, then this is the rate of extinction of hydrogen.

[00:40:58]So let's come to instantaneous rate of reaction. What will be the instantaneous rate of reaction is equal to? Instantaneous rate of reaction equal to this will raise this will come to hydrogen. Where will you come from here? If we come near hydrogen, then it is hydrogen, so we will keep - 1/6 of it, okay and we will write dh+ upon what will we write dt, so 1/6 of it and * dh + ion / dt value is given, x mole of minus is given, it is x mole, right, how much of minus is given, this is given, minus x of minus, this becomes x of minus.

[00:41:44]So since it was already given here x mole liter inverse second inverse, what do we have to do now? What will happen to minus and minus? It will be a plus. So x/6 x/6 will become mole mole liter inverse second inverse. This is your instantaneous rate of reaction. This became the speed of the instantaneous reaction.

[00:42:13]What has happened? Instantaneous reaction velocity. When the rate of the instantaneous reaction is this, then from here it is asked directly, what will be the rate of formation of Br2? So where did Br2 come in? Br2 Then you pick it up directly.

[00:42:28]Relate the instantaneous rate of reaction to Br2. So write down the instantaneous rate of reaction. What will you write ROR equal to? What will you write as instantaneous rate of reaction Eq + ka 1 /?

[00:42:46]What will you write plus 1/3 dbr2 by? dt dbr2 / dt. Are you understanding the point of Plus?

[00:42:52]What will you write for plus? Plus 1/3 of dbr2 /dt so what is the instantaneous rate of reaction you have derived? This is what I have brought x up 6 x/6, the value of instantaneous rate of reaction is what I had come up with, so instead of this x / 6, I am saying that now if it is multiplied by three here then it will become dbr2 / dt = 3, so here what will be 3x by, it will become 6 and what will be 3 * 1 = 3 3 2na, it will become 6, so I feel that x/ 2 is coming. x/ 2 3 2 6 x/2 Now its coming to mole liter inverse second inverse. So what is the rate of formation of Br2 here?

[00:43:53]x/2 mole liter inverse second inverse This is the rate of formation.

[00:44:12]Ok? So x mole means just given here. x moles mean nothing dear child. Here a digit has been given that you have to tell in place of x, you can write and put two or three whichever is given here in the question. There is nothing much for you to be afraid of in this. Someone has already given this x mole so that you can solve the problem. If you give the value of x moles then you can apply it. No problem. Is it okay Babu? x can be anything in place of mole. So it has been given because it is a variable. Ok?

[00:44:51]So let's move forward. So, do not forget these questions that you have to ask.

[00:44:56]Ok? And ask their question.

[00:45:00]Like this is also a question. You can also ask this question. What will be the rate of weight of into five at that instant? So, it is your job to answer all these questions, dear student. Ok?

[00:45:14]So remember to ask questions and understand.

[00:45:18]Correct? We move forward. There are still some things left to be done which we will do.

[00:45:27]we we're okay. Come on, come.

[00:45:37]We ask questions. Ok? If I am saying children, watch carefully. If I'm saying that there's a reaction a / b is converting from a. Where are you going? is converting from a to product.

[00:45:53]And what do you do for that? You have given some graph wise questions and some such questions.

[00:46:03]Ok? In which concentration has been given here also.

[00:46:14]Ok? Now I think that these concentrations here are time here.

[00:46:21]Here let us assume that a is da and relative to what is it calculated? dt k. So I know how to find the place of da / dt.

[00:46:30]So what can I say about what happens in the beginning? This concentration is in moles per liter per mole of DA.

[00:46:42]Here I take it that this will be the concentration of anything in moles per liter. So what is one mole of A per liter? The concentration is given here. So whatever the initial concentration might have been here, the concentration of the reactant is decreasing from here. So whatever the initial concentration might have been, I am calling it A1. Ok? Later the concentration has decreased, the remaining concentration means the concentration has decreased to a2 so the initial time here must have been t1, later it must have come from here to here, it must have gone t2 so this is the only formula that you should understand to find the slope sometimes you may be asked to find the slope, you can also ask to find the rate, there is no problem, so the instantaneous rate of reaction is instantaneous r or r, if we leave aside the instantaneous rate of reaction, if I talk about the slope, what do we call the slope, the slope is equal to tan theta, children it is equal to tan theta and here what are we getting tan theta, what are we getting tan theta, this is a and from here I can say da / what are we getting, we are getting dt, so this will be the reactant, so obviously we will put a minus because it is decreasing, so we can just put a minus for the concentration. And what can I write in place of de? a2 - a1 and instead I can write t2 - t1 okay? So if I have been given such a question then please I can use it and ask the question. Ok? And what to apply? Now we have to understand that I will be given a question, how will we apply it to it, remember this also Sir Jai Shri Ram Jai Shri Ram Babu Jai Shri Ram Okay Nasi ji good morning good morning all of you dear Okay to all the people who are there, good morning to all of you Okay so the concentration that I have sloped here tan theta = d / dt this up, here questions are made for concentration change and I am also making you ask those questions, suppose I can make you ask the questions.

[00:48:57]Like let us ask a question. Speak and write. He is saying that brother, look here there is a question.

[00:49:08]Question number one is a question in a way.

[00:49:11]Then we will do it further also. What is this question? N2 + 3H2 forming 2NH3 This is ammonia being formed. Ok? Now ammonia is being produced here. So we will see. Now it's saying look, find the rate of the reaction.

[00:49:38]Find the rate of the reaction.

[00:49:42]What is the other person saying? The second one is saying that the rate of extinction of nitrogen, the rate of extinction of nitrogen, the rate of extinction of nitrogen, so the rate of extinction of nitrogen also and what do I plot in the graph, so what do we get in this crop, okay, here I have given the concentration 10, then it has come down from that, it has become six, then after that, the concentration of which is given here is hydrogen, hydrogen has been given, who has given it in moles per liter, its concentration is in hydrogen moles per liter. There is time here.

[00:50:50]Time is here. And what have you given in this time? Two and four. From 2 seconds to how many seconds? Up to 4 seconds. So now we have to find its equivalent. Ok?

[00:51:04]No problem sir. No problem. So these things have been given. Correct. So what will we do now? You will see this slope.

[00:51:14]What would slope slope is equal to? will be tan theta. And tan theta, do you know what that is?

[00:51:21]What is perpendicular divided by? Base. Ok? perpendicular/base.

[00:51:24]So tan theta equals perpendicular / base.

[00:51:26]What can we write here that means?

[00:51:29]See, it is simple.

[00:51:33]tanθ for equal concentrations. Just like I used up here. I used this thing above. Same slope is equal to this slope tan theta da / dt, given that we have to take the concentration of hydrogen ion, so we can take the concentration of hydrogen ion, let's take now what is the thing here, so if I write it as dh2 / dt, then the later concentration of hydrogen ion, if I compare it with a2 - a1, it has the same concentration, what can I write for it, concentration a2 - a1 and t2- minus, what can I write for it? P1 I am writing that as per my convenience.

[00:52:12]So what is it to me? How much is A2 A2? six. So here I will write ch. What should I write for the minus? 10 Then what comes after that? T2 What should I write? 4 minus 2 So what am I getting here? 6 out of 10 is getting minus 4. Minus 4 up to 2 so 2 * 2 is 4 total minus 2 mole liters inverse second inverse, this is what I am getting 2 mole liters inverse second inverse. This much has come.

[00:52:46]So tell me this simple way to write its average, sorry, instantaneous, instantaneous rate of reaction is equal, what can I write?

[00:52:56]What can I write minus 1/1 dn2/?

[00:52:59]d2 and then equal what can I write this?

[00:53:02]+1 / 3 dh2 / What can I write? d2 dt and then after that equal cannot be plus here, right.

[00:53:13]How can you plus here? Are you mad sir? No sir. No equal minus 1/3 because the reactant can only have a plus in front of the product. Yes.

[00:53:24]Product 1/2 DNH3 / What can you write?

[00:53:28]DNH3 / DT ok? Ok? DNH3 What can I write by? You can write dt. Ok?

[00:53:34]Is it clear? Yes sir. If that is clear then we move ahead. Let's see.

[00:53:40]So what? First come the instantaneous rate of reaction. Instantaneous rate of reaction. We have talked about instantaneous rate of reaction. The velocity of the reaction has been discussed. So we have talked about the speed of the reaction. So come on. Where is it about whom? A. We, we, what else did we bring into the reaction?

[00:54:05]ds2 / dt So ds2 / dt ds2 / dt This has to be raised.

[00:54:10]What will I have to write -1 / 3 ds2 by? dt will have to be written. So what is the value of - 1/3 ds2 / dt given?

[00:54:22]What is its value that we have calculated?

[00:54:25]We found its value, what is its value you found? If two minus two is two, what will happen to minus and minus? It will be a plus. So it will become 2/3 mole liter inverse second inverse. Ok?

[00:54:45]So here's what happened to you? Here is the instantaneous rate of reaction. 2/3 mole liter inverse second inverse.

[00:54:54]Ok? Did you understand or not? Now what is there here? We move forward.

[00:54:59]Then I will explain it to you. Ok?

[00:55:02]Then we explain what will happen. Correct?

[00:55:05]Ahead. Now what is in question here? Instantaneous rate of reaction once released. Once this is removed, it will make a lot of your work easier. is telling the rate of nitrogen extinction. Okay, of course.

[00:55:15]So instantaneous rate of reaction equal to rate of disappearance of nitrogen, right? So where is the nitrogen equation? Pick it up with this. Let us take - 1 / 1 dl2 / dt. So what is the instantaneous rate of reaction? 2/3 2/3 minus 1 / 1 dn2 / dt So what will the total dn2 / dt be equal to? 2/3 of minus 2/3 moles is liters inverse second inverse.

[00:56:02]Ok? So this should remain. Is it clear?

[00:56:06]Is it clear?

[00:56:09]We are yes clear. So such questions should be asked till here.

[00:56:18]When you ask questions in this way, your clearance will increase. It will become clear how you are able to invest.

[00:56:26]Those things should be within you. Ok? So right now I am giving you the questions one by one.

[00:56:31]You can apply it on this also. Ok? Please ask a question on this also. Ok? There is no problem. Sir, there is no problem. Look what is the question? It comes from asking questions. If you sit with a pen and paper and note down that thing, then by noting down your understanding gradually increases. And when your understanding gradually increases, then you can also solve the questions by looking at them.

[00:56:52]These things should remain. Now you will simply understand that if we just look at it and write it down, it is not going to come. You will have to work a little hard. You will have to understand. You will have to devote time to studies. Dua student, are you understanding the matter or not? Yes sir, I understand.

[00:57:06]Ok. You should also come.

[00:57:08]I am giving you one question as homework.

[00:57:10]Please do this dear. Ok? So I am also giving you one question homework.

[00:57:15]Correct?

[00:57:18]Watch 2N2O5 convert into 4NO2 + O2. So its concentration is also given in this 16 + 6, time is given in this 6 10 6 and 10 seconds, okay, so whose reaction is this, it is okay to remember this much. Given here is N2O5 in moles per litre. In moles per liter and here if we talk about time then it is in time and second.

[00:58:18]So, the only thing you have to do while asking questions in this is that you will ask the first question in this, find the rate of the reaction. Instantaneous velocity. Ok? What is the second one? I will ask you another question. Rate of formation of O2 Rate of formation of O2.

[00:58:51]rate of formation. The third one is the rate of formation of NO2. The rate of formation of NO2. Ok? The rate of formation of NO2. Ok? So there are so many questions. You have to ask these questions.

[00:59:11]Okay kids? Tomorrow's topic will be factors affecting the rate of reaction. So you remember all these things.

[00:59:18]Whatever questions I am asking you in today's session are very important questions.

[00:59:24]Ok? So please learn whatever is being taught. Keep remembering together. Is it okay my dear child? So remember the question that was given and also the one that you have asked.

[00:59:38]You will have to pay attention to all the questions. So let's go.

[00:59:40]Jai Hind Vande Mataram. Do n't forget to like, subscribe and share the channel.

[00:59:44]Please do like, do subscribe and do share this video. Jai Hind, Vande Mataram.