To solve the equation X^X = 16, first test integer values to determine that the solution lies between 2 and 3 (since 2^2 = 4 < 16 and 3^3 = 27 > 16). Then apply the natural logarithm to both sides to get X·ln(X) = ln(16). Using the property that any number A can be written as e^(ln(A)), rewrite the equation as ln(X)·e^(ln(X)) = ln(16). Apply the Lambert W function, which satisfies W(z)·e^(W(z)) = z, to obtain ln(X) = W(ln(16)). Finally, exponentiate both sides to find X = e^(W(ln(16))), which equals approximately 2.74536802357.
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Harvard University Entrance Exam Question | Can you solve ?Added:
Hello, welcome back once again. Today we're going to solve the following given interesting equation.
X raised to the power of X is equal to 16. In this video, we're going to find the value of X that will satisfy this equation. So let's get started.
Now, let us find out if X is an integer.
So if X is equal to 1, we get 1 raised to the power of 1. This is equal to 1, which is less than the right hand side.
If X is equal to 2, we get 2 raised to the power of 2, which is equal to 4.
This is less than the right hand side.
If X is equal to 3, we get 3 raised to the power of 3, which is equal to 27.
This is greater than the right hand side.
Now we can see from here our equality sign change, right? From less than to greater than. So it tells us that our solution lies between 2 and 3.
Hence, we say 2 is less than X and X is less than 3. Awesome.
Now here we have X to the power of X is equal to 16.
Let us ln both sides. We get the ln of X to the power of X is equal to the ln of 16. Use the power rule of logarithm. This becomes X times ln of X, which is equal to ln of 16.
Now use this following property. A can be written in the form E raised to the power of ln of A.
So therefore here we have ln of X then multiplied by E raised to the power of ln of X. So this is equal to ln of 16.
Now we can use the Lambert W function on both sides of this equation.
So, this is the Lambert W function.
So, it has a very nice property. The W of K times E raised to the power of K is equal to K.
With this property, the left-hand side simplifies nicely to ln of X, which is equal to the W of ln of 16.
Now, from here we're going to exponentiate both sides using the base E.
So, here this will be E to the power of ln of X and here E raised to the power of the W of ln of 16. So, this both get cancelled. So, here we have X is equal to E raised to the power of the W of ln of 16.
So, here this will give us our correct value for X.
That is X is approximately equal to 2.
745 368 023 57.
So, this right here is our correct answer.
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