B.SC. SEMESTER-4th CHEMISTRY IMPORTANT QUESTION 2026

[00:00:00]Hello friends, welcome to another amazing video of ours. So son, after a lot of demand from all of you, today we have brought a video for you.

[00:00:07]Whose video is it going to be? Son, the B.Sc. Semester 4 subject is going to be Chemistry.

[00:00:14]Chemistry is the subject of both Biology and Mathematics. So son, you will get to see all the questions in this video.

[00:00:20]I give you this 100% guarantee that if you watch this video and leave, you do n't need to read anything else. But you have to watch this video but you have to watch it completely.

[00:00:28]Most of your questions have been covered in this video.

[00:00:33]All the important questions from the point of view of your exam have been covered.

[00:00:35]As you know, the special thing about our video is that you will get to see every paper in both Hindi and English.

[00:00:40]That means bilingual will be available. Along with this, you will also get to see most of the answers in the video.

[00:00:47]You can look at those who don't have it. Is it alright son? Let's start the video without any delay.

[00:00:51]What do you have to do now? First of all, WhatsApp has provided its own scanner.

[00:00:55]So take a screenshot of it from here and join it. Is it alright son? Besides, if you face any problem, your brother is ready to help you.

[00:01:04]Ok? You can DM me here.

[00:01:06]Let's start the video without any delay son. First of all you know, son section A comes to you. Ok? What will come in section A? You will get 10 questions in Section A.

[00:01:16]This question is of two marks.

[00:01:17]So this is section A, it will be of 20 marks for you.

[00:01:19]What will we do after seeing it now?

[00:01:21]Because if we speak in both Hindi and English, it will take a lot of time and you all know this because you are the ones who watch the video. You don't even watch the entire video.

[00:01:28]Ok? So the English medium students will quickly watch it together.

[00:01:31]I will tell you in Hindi.

[00:01:33]First variant question, son, all these are important questions from the examination point of view.

[00:01:37]So if you do not want to read anything else then these are the questions that I am telling you, in this video there will be hardly 202 minutes of video, so you have to watch it completely, do not be careless in it, then you say that sir, you do not know the questions, then you do not watch the complete video, after watching the starting 510 questions, okay, this should not happen, son, you will watch the complete video, then see it completely, first what questions are coming and what are not coming, what is valence bond theory, write its limitations, what is valence bond theory, VBT, write its limitations, son, there are going to be very varied questions, in the first chapter of VBT, most of the things are only two things.

[00:02:09]VBT & CFT.

[00:02:12]Ok? Valence Bond Theory and Crystal Field Theory. Just watch it once along with the English medium ones.

[00:02:18]Take a screenshot of it. I will tell you quickly in Hindi.

[00:02:20]Ok?

[00:02:22]According to VBT Poling, Poling is the name of the scientist. The ligand donates its lone pair of electrons to the vacant hybrid orbital of the metal ion to form a coordination bond. What are the metal ion hybridizations according to the number and geometry of ligands? sp3 becomes d2sp2 dsp2, sp3 d2 and d2sp3 etc. What shapes can the complex take? It can be tetragonal, square planar and octahedral. That magnetic behavior means which one is paramagnetic, which one is diamagnetic and it tells you which one, so what do you have son?

[00:02:59]Diamagnetic and which one do you have?

[00:03:01]is paramagnetic. Ok? Next, son, from whom do you get to know all this? VBT shows hybridization.

[00:03:08]Their geometry is revealed. Ok? And the magnetic behavior is detected by VBT. What could be its limitations? This does not explain the color of the packages.

[00:03:17]Firstly, it does not explain the different magnetic moments in complexes with the same coordination number and it considers the bond to be only covalent. It also ignores the effect of the ligand field above the D orbitals. It only gives a quantitative measure of bond strength and cannot explain the electronic absorption properties in the spectrum.

[00:03:36]Son, this was the first very important question. Son, this is a 100% likely question. Ok? Those questions are covered for you.

[00:03:44]Look at the second question, son. Crystal field theory is what I called CFT.

[00:03:47]In short it is called beta CFT.

[00:03:50]What is crystal field theory? And how is it different from VBT? What is Crystal Field Theory? What is CFT and how does it differ from VBT? Those who are in English medium should watch it once along with their son.

[00:04:01]Ok? I will tell you in Hindi medium.

[00:04:03]Look first up is CFT. What is CFT?

[00:04:13]CFT considers the metal-ligand bond to be completely electrostatic ionic. where the ligands are considered as point negative charges. Which generates an electric field around the metal ion.

[00:04:24]This field splits the equal d orbitals into different energy levels.

[00:04:29]Like octahedral region has T2G and EG. Absolutely. And this cleavage pattern also explains the color magnetism and stability of the delta and delta T complexes. This happens to us, son, CFT. Ok?

[00:04:43]Whatever energy levels there are, it divides them into two things. One is T2G and the other is EG and it also tells about the colour, magnetism and stability of the packages.

[00:04:50]Now see what is the difference between the two.

[00:04:57]Look at the difference between the two, son.

[00:04:59]What is the difference from VBT? VBT considers covalent bonding by hybrid orbitals.

[00:05:05]Ok? and explains geometry and magnetism.

[00:05:07]But I cannot explain the color.

[00:05:09]Who? VBT. Whereas CFT considers electrostatic interactions.

[00:05:12]And d orbital splitting explains the colour and magnetic properties quantitatively.

[00:05:18]But what does the covalent nature of the metal-ligand bond do? Ignores it. which was later improved by ligand field theory.

[00:05:25]So what is the difference between most of it? That VBT is not able to tell the colour and this one is able to tell the colour. Ok? Now let us see the next variant, the question you have is question number three.

[00:05:37]Question number three is with us, Beta Curie and Neel Taap. Define Curie temperature and Neel temperature. What are they? along with e n effective atomic number.

[00:06:00]Tell me which is the effective atomic number variant. Ok? Let's see, let the English medium people see it quickly.

[00:06:05]Take a screenshot as well. Look, what is Curie temperature, son?

[00:06:10]Curie temperature is the temperature above which a ferromagnetic substance loses its spontaneous magnetism and becomes paramagnetic.

[00:06:19]Because thermal energy disorganizes the observed magnetic domains. Ok? So this is our Curie heat.

[00:06:26]The temperature above which a ferromagnetic substance automatically loses its magnetism and turns into what?

[00:06:33]In paramagnetic. So we call this Curie heat. That's right. What is blue heat? The temperature above which an antiferromagnetic substance becomes paramagnetic. Look, there is not much difference between the two. What is the difference? That in the Curie temperature, there is iron magnetic material, in which does it get magnetized? In paramagnetic.

[00:06:50]Ok? And what does the antiferromagnetic substance in it turn into?

[00:06:55]In paramagnetic. That's the only difference. Because adjacent magnetic moments have opposite parallel alignment. He breaks down.

[00:07:00]Because of this. Now look at your son EN.

[00:07:03]What is EN? In the complex proposed by Sijwick, the central metal ion is The total number of electrons after adding the electrons donated by the ligands around the central metal ion is called its effective atomic number. The atomic number of these metals can be calculated by taking the oxidation state of the metal plus two times the number of ligands and from this for a codon.

[00:07:30]Whom? Many stable complexes also follow the EA N rule. Whose EM means EN sorry, effective atomic number is equal to the atomic number of the nearest noble gas.

[00:07:45]18 electron rule. That's right, son. Let's look forward to our next one.

[00:07:53]Question number four. Son, someone will definitely ask you this type of question.

[00:07:57]Look, he will give you many and will ask which ones are hard acids, which are soft acids, which are hard alkalis and which are soft alkalis.

[00:08:05]Son, this paper has been made very simply, keep in mind that you have to read this paper 100%. The students who see my paper know how many questions come in my paper and how many do not come, so this has been made very carefully, the paper has been made after thinking carefully, what kind of questions will you see, you will get to see 100% questions, keep in mind that you should not take the paper lightly, you have to read the paper and then go, now look at it, first hard acid. Ok? Which is called hard acid. See what harsh acids can be present inside it?

[00:08:35]Hard acids I have one Be2+ one Na+ one CO2 one GaCl3.

[00:08:42]Ok? So, who is this son who is with us? Hard acid. Ok? Small charges, high charge density and low polarity are not easily oxidised. Son, what dead acids have I got?

[00:08:57]Look at the dead acids, son, Pd2+ Ag+ BH3 and Al AlH3, okay, these are the mild acids I have. hard bases look hard bases OH- okay? And let's look at mild alkalis.

[00:09:19]H- Br- and CN- and there is a boundary which we call son a border line. Ok? We have that NO2 - so we have this.

[00:09:27]You can see these. Let's move on to question number five. That's right, son.

[00:09:34]Question number five. He is the most important brother. HSAB principles.

[00:09:45]This is the subsaint. This is your unit number question from seconds. HS HSAB Principles.

[00:09:50]Ok? So what is the full form of HSAB, son? Hard Soft Acid Base Hard Soft Acid Base The video may be long but son you have to watch it completely carefully, I am telling you in advance that you have to watch the video completely before the exam, okay what is hard soft acid base theory and write its drawbacks, HSAB theory, English medium students can watch it along with it, I will tell you in Hindi, watch it quickly son, HSAB theory, HSAB theory, hard soft acid base, according to Pearson, hard acids like to bind with hard bases and soft acids like to bind with soft bases.

[00:10:33]that is, forming bonds that lead to more stable complex products. Hard species are small, high-charge, low polarity.

[00:10:43]Soft species are those with very low charge.

[00:10:46]Ok? Sorry, the hard ones are small species, they are small, have high charge and low polarity. Whereas the species which are soft are larger, have less charge and have more polarity.

[00:10:57]So this is what we have with the HSAB theory. This same question can be asked to you in the higher exam as well as in the 10 mark exam. So you prepare it that way. It is very important son. HSAB principles to keep in mind.

[00:11:09]HSAB Theory 100% You will see this question in your exam. You can get a bigger one too. Brother, take care of the one with number 10 also.

[00:11:15]Limitations It is qualitative and not quantitative.

[00:11:20]Cannot even accurately predict the permanent constant. Hardness or softness is not clearly defined either.

[00:11:24]It does not take into account steric and solvent effects and fails in reactions where kinetic factors dominate thermodynamic rigidity adjustments.

[00:11:35]Look at question number six, son.

[00:11:37]Question number six: What do you have? This is going to be a question from your unit number four.

[00:11:42]What is meant by order and molecularity of reaction? I have also studied in class 12th.

[00:11:47]Define zero order reaction with examples.

[00:11:50]Sorry son, there will be a Piso reaction in this. Take care in this, take care in your place. Ok? This mistake has been written because you have written a PCDO reaction in it which we call pseudo order reaction. Brother, read this pseudo category.

[00:12:06]Ok? Pseudo-order reaction.

[00:12:12]Read this pseudo order reaction. First of all, what is meant by order and molecularity of reaction? Order of reaction: The order of reaction is the sum of the powers of the concentration terms in the experimentally determined rate law.

[00:12:30]It is an experimental quantity.

[00:12:34]Zero can be either negative or integer.

[00:12:37]Which son? Category. Quotient can be zero, can be a fraction and can also be an integer. Look up molecularity. It is the number of reactant molecules, atoms, or ions that collide together to carry out a reaction in an elementary step.

[00:12:50]It is always of the order of an integer and is a theoretical concept. It is meaningful only for elementary reactions.

[00:12:57]Ok? Okay, now that we have taken the zero order reaction, we can study it but you have to study the pseudo order reaction. This is called PCoration.

[00:13:05]The reaction whose velocity is independent of the concentration of reactants and whose rate is proportional to the concentration of reactants raised to the zeroth power. You just take care. Ok? Zero order is proportional to the zero power.

[00:13:16]In the first order it is proportional to the first power and in the second order it is proportional to the second power. That's the only difference. Examples are the decomposition of gaseous ammonium on a hot platinum surface or the photochemical reaction of H2 and Cl2.

[00:13:32]Ok? All these can be examples of this.

[00:13:34]Next son, very important question.

[00:13:38]Explain the difference between paramagnetic, ferromagnetic and diamagnetic. That means I have to tell you, son, what are paramagnetic, ferromagnetic and diamagnetic substances? What could be the difference between these three? Now suppose one can ask a direct question.

[00:13:47]Now if you don't ask directly then you have a lot of compounds. Ok? Now son will ask as these compounds.

[00:13:52]Like this is it and I just read VBT.

[00:13:55]In VBT, we used to teach one thing, VBT tells about nature.

[00:13:59]Describes magnetic nature. So, on the basis of VBT, explain that it is diamagnetic.

[00:14:03]Whereas it is magnetic. Either he will ask you a direct question or he will not ask you a direct question. So in this type it will tell you two compounds and ask whether this is magnetic or this is diamagnetic. Why? Ok?

[00:14:11]The concept will seem the same. Be careful in all questions.

[00:14:13]Such questions will come that the concept will seem to be the same in all. So you take a look at it, if someone asks the same question then you have to apply the same concept. But before that you should know what paramagnetic, ferromagnetic and diamagnetic actually are? Isn't it? So see, English medium people can watch it together. Let me tell you in Hindi. Look son diamagnetic first of all. All electrons are paired inside the diamagnet.

[00:14:35]Take this meaning of coupled. Ok? There will be two electrons inside a box, both paired. It does not have a permanent magnetic moment and is also slightly repelled by an external magnetic field.

[00:14:47]What happens in paramagnetic, son? There are unpaired electrons. Here, this unpaired electron has become one electron. Ok?

[00:14:53]Light is attracted by a magnetic field and when the field is removed the magnetism becomes It ends in this.

[00:14:59]What is iron magnetic material, son? Unpaired. Now how will we know the effect? Like this is a compound.

[00:15:05]Find out its electronic configuration. Ok?

[00:15:07]What if this happens?

[00:15:09]All the electrons are there, that means all the orbitals are filled. Any electron does not remain unpaired, then which one will I have? Diamagnetic. And if an electron is in it what remains?

[00:15:20]remains unpaired then which will happen? Paramagnetic.

[00:15:23]Unpaired electrons align spontaneously and cooperatively into spin domains.

[00:15:28]Due to which strong permanent magnetism is produced. Which remains even after removing the area. Is it okay son? Now look at this question. Like K4C6 and K4F FeF6, it is kept with us. Both contain Fe2+.

[00:15:43]Ok.

[00:15:46]CN is that strong field legend. This causes pairing of electrons in the inner d orbitals. That means Fe2+ undergoes D2s3 hybridization. No unpaired electrons remain in it. So how did this happen? Diamagnetic. Whereas F is a weak field Legendre. Ok? It does not force pairing and Fe2+ does sp3d2 hybridization i.e. outer orbital complex and four unpaired electrons remain in d3d, hence how is it paramagnetic, you have to keep only one concept in mind that which one has electrons, son, if they remain unpaired then which one will be paramagnetic and the one in which the electrons are paired, which one will be diamagnetic, okay, let's move ahead son, next, you guys see question number eight, this is ours, son, question from unit number three, is formic acid more acidic than acetic acid, why do you know acetic acid CH3COOH, okay, it has been said that compared to acetic acid, this one is acetic acid and this one is formic acid HCOOH, formic acid which is found in the sting of red ant, this one is okay, son, let's see why it happens, now we have formic acid from the carboxylic carbon of HCOH Only one hydrogen atom is attached. Whereas acetic acid CH3COH has an electron donating +i effect i.e. methyl group. You can see it here.

[00:17:19]And the +I of CH3 pushes the effective electron density onto the carbosilicate which destabilizes the conjugate base and makes it a weak acid. This is because forbic acid does not have this destabilizing plus I group because you do not see any CH3 group in it. Its conjugate base formate ion is more stable.

[00:17:39]Due to which it cannot ionize easily and what more happens son? It is more acidic. take care brother. Ok? so take care. Formic acid is more acidic than acetic acid, in which the more CH3 groups increase, the more it will remain, what will happen, son, less acidic, okay, next very important question, what is RNS theory and how does temperature affect the rate of reaction, see son, what is RNS theory, how does temperature affect the rate of reaction, those who are in English medium can see it together, I will tell you quickly in Hindi, okay, see son, this is the Rhenius equation, what do you have, son, k = a e to the power minus e ert, this is it, son, okay, rate constant is k, we write temperature as T. The activation energy is beta ea and is related to the frequency or pre-variable exponential coefficient a. According to this, only those molecules are able to react on collision whose activation energy is greater than the activation energy.

[00:18:49]So this is the rule of RNS with us, son.

[00:18:54]Now let us look at the temperature.

[00:18:56]How does this temperature affect the rate of reaction? Son, keep in mind that as the temperature increases, more molecules are able to gain energy ea > according to Maxwell volt-force distribution.

[00:19:07]Ok? Meaning, we can get more active energy.

[00:19:09]Therefore, the active energy per unit is called ea.

[00:19:12]Hence, there are more effective collisions per unit time period and the velocity constant, K, varies exponentially with T.

[00:19:20]Generally, what happens to the reaction rate approximately with a 10% increase in temperature, say 10°C? You get double the amount. This means that with an increase of 10°C in normal temperature, the speed almost doubles. Son, look at the last question.

[00:19:38]Ok? Look around you, what is the last question? Now let us look at the last question of our section one.

[00:19:46]Write a comment on Michaelis Menton mechanism. I have a question from unit number four.

[00:19:49]Write a note on Michaelis Menton mechanism. Look at the Michaelis Menton mechanism which explains the kinetics of enzyme catalyzed reactions. The enzyme combines reversibly with the substrate to form the enzyme-substrate complex ES, which then breaks down to give the product P, and the enzyme is regenerated. This is how something like E plus A happens. Here also a reversible reaction takes place and ES is formed. Then who is formed from es again, son?

[00:20:20]Applying e + p and approximation from steady state, we get Michaelis Menton equation.

[00:20:28]You get this. Where vmax is the maximum rate of velocity.

[00:20:32]km, he has active concentration.

[00:20:35]v = v max / 2. and at low s the reaction is first order with respect to the substrate.

[00:20:40]And whose reaction is it at high As, son? It is of zero order. Let me tell you once again. To join your WhatsApp channel, the link to join this WhatsApp channel has been given above, son, what QR have you given, you can join from there, along with this, if you face any problem, you can DM here.

[00:21:04]Now let us see son, pay attention to section B, it is very important, see all the questions, even if you get two questions in the unit. Ok? If one extra question is being asked then tell me the extra one. There is no problem with that.

[00:21:16]If one more question is being asked then you can tell me the extra question. There is no problem in that. I can tell you what you mean, extra. Ok? If you read one question, you will not face any problem. If you read one extra question, you will not face any problem. My only aim is that your paper should be very good.

[00:21:30]Ok?

[00:21:32]You have to read and answer all the important questions.

[00:21:34]Look son, first question right short note. What do I have to write about? Magnetic Succeedability.

[00:21:41]Ok? This is called magnetic sensitivity, son.

[00:21:45]Not sensitivity, it will come like this, magnetic sensitivity and this is what we call son, what do we call cooperative magnetism, son, this is what we call cooperative magnetism, that's right, okay, next second, look son, second, we have LS coupling variant, son, this LS coupling, with this, this question can be asked to you, third, I have given some IUPEC names, son, okay, what do you have to write for these?

[00:22:15]You have to write the IUPEC name. Ok?

[00:22:18]You have to write the IUPEC names of these three.

[00:22:22]Can you guys write? Hey yes or no?

[00:22:26]So you have to write the typical names of these three also.

[00:22:29]Ok?

[00:22:38]Let us move on to the next question.

[00:22:43]Now you know son, you have to attempt four questions in section B.

[00:22:45]One question is worth 10 marks and section B is worth 40 marks.

[00:22:47]But sir, how can I ask four questions?

[00:22:49]Two questions are being asked from one unit.

[00:22:51]Look son, like this question you have got this and by applying it you have got this question.

[00:22:56]Now you have to do only one question out of these two.

[00:22:57]Either do the above or do the below. Is that okay? Look look son, explain the geometry and magnetic properties of the following transition metal complexes on the basis of VBT. Explain the geometric magnetic properties of following transition metal complexes on the basis of their vibrancy. Whatever they have given you, you have to tell me its geometry, what do you have to tell me about it, son? The structure has to be explained. Ok? How are they? Secondly, I want to tell you about the magnetic properties of all four of them.

[00:23:31]Ok? Because they are small. All you have to do is look at the electronic configuration and that tells you its geometry and its magnetic properties. Next, see son, what questions do you have from unit number second? First very important question.

[00:23:46]Draw the Latimer diagram for CO2 from the following data. They have given the figures with them. I have given these.

[00:23:52]Ok? You have a Latimer diagram, son.

[00:23:54]You have to make that. Which diagram son?

[00:23:56]Latimer. Take care.

[00:23:59]So you have Frost and you have Latimer. So which one is important for you? Latimer. Is it okay son? Next, don't look at this, you will learn to make this. Suppose some value changes in it also. The next one uses his brain a little. So it also changes some values, so you should learn how to make it or how to make it. Ok? So you can change it and write it down. Look next, son. Write the characteristics of hard and soft acids and bases.

[00:24:24]Write the characteristics of hard and soft acids and bases. Ok?

[00:24:31]Next, what else can I ask you, son? Look, tell me what you want to tell me son? First of all, I want to tell you that H2O is more stable than H2O2. Why? Why is H2O more stable than H2O2?

[00:24:48]What do you want to tell me next, son? HGO or HGO is soluble in HCL. Whereas HgS is soluble in HCl. Why does this happen? You have to tell this inside it also. That's right, son.

[00:25:05]You see next. Let's see this in English once.

[00:25:08]What did you say, son? HgO is soluble in HCl while Hgs is insoluble in HCl? Let's see question number three, son. It is LiLiLi, son, which means it is lithium iodide. Keep this in mind that LiI gets hydrolyzed easily, whereas LiF is called lithium fluorine fluoride, right?

[00:25:34]Why not? You have to tell yourself this, son. Question number four: See, son, CH3I is called methyl iodide, right? Or it is called methane hydride, and it is more stable than methane chloride, why?

[00:25:49]Question number five: CA and Mg: Calcium and magnesium are found in the form of carbonates in nature.

[00:25:54]Whereas CO and Ag are found in the form of sulphides.

[00:25:57]Why does this happen? So all these variants are going to have questions.

[00:26:02]Whatever questions are asked in Chemistry, they will be asked to you in parts, son. You should also keep this in mind.

[00:26:05]In Chemistry you will be asked questions only in parts. Unit number because it is not a big question in chemistry.

[00:26:10]So watch from unit number three, son. Look at the variant first question, son.

[00:26:18]First you have to write the following reactions because in your third unit you have only reactions.

[00:26:23]Alcohol sorry in that you have one so aldehyde ketone and carboxylic acid.

[00:26:30]Ok? So the question is, what reactions do you have? First we have aldol condensation class 12th. All are from class 12th. Benzone condensation.

[00:26:38]Benzoin condensation. Next I have Haleh Hollard. This is son Hale, right?

[00:26:46]Hellard Jess reaction next Berwicker oxidation or Berwicker oxidation and this is what I have son Rosen Mund Rosen Mund reaction okay these are the reactions I have. Look ahead son, let's see the next one.

[00:27:06]Well, isn't that one written in it? There was one more thing in this, son, you have Mirvine Mirvine Pondrof Worli Abchayan, you have to see this also. Ok?

[00:27:32]Now let us see the next question, son, what can you ask about the unit number and its third question? And look son, you have some reaction given. Ok? These are some of the reactions I have given. So they have to write that their product is the final product.

[00:27:47]I have already written it, son. I have already written it. I have written all the reactions to you. Look son, you have given the first reaction. CHO's reaction is happening, son. In whose presence is this happening with CHO, son? This presence is given. This is happening in the presence of concentrated NaOH. And what is the final product that I am getting, son?

[00:28:10]This is the answer of CH3OH and CH3COO. This is the answer to it.

[00:28:13]Next we have the son cyclopentane.

[00:28:16]Now see how it is being made? It is being made something like this. If it is pentane then it is a simple matter. Take this one with five arms. This is beta cyclopentane. It is reacting with beta CF3COH. What are you doing son? It will become something like this to me. Let me tell you the answer to the second one. Here, I will have it ready. Ok? Its name is beta lactone. What is his name?

[00:28:45]Lactones. Look at the third one, whatever you are getting from us, we are providing you that much.

[00:28:50]Ok? So you also try to understand a little. And all the students who have joined our channel for the first time should subscribe to the channel now because there are many students who watch the videos but do not subscribe to the channel. Which of your money is involved in this, brother? We are not taking any money, right?

[00:29:05]We think that let us help the students as much as we can.

[00:29:10]Okay friends? So a small request to all of you, consider me your elder brother and younger brother and please subscribe to any channel.

[00:29:18]The third one, son, has 24, right?

[00:29:24]Yes, this one has this structure. Ok? Whose reaction is this? Dilute with NaOH. What else is happening, son? Something like this will be made. Look, I'll show you how to make it. I am doing the third one. Keep this in mind that whatever you note, you can note it along with it, even if it will be made in the third one. This is oxygen here and this will be formed in the third one here. That's right, son. Make a note of it as well, let me delete it here then.

[00:29:50]Let's look further then. I will quickly delete it once. Let's see the fourth one later.

[00:30:03]Look son, now let's watch the fourth one once.

[00:30:05]Look who's reacting to me in the fourth one.

[00:30:07]In the fourth one, I have some kind of compound, son.

[00:30:17]I have this type of compound. Ok? It means benzene. Along with this there is CH here. The double bold is CH and here it is CHO. With whom is the son reacting? With NaOH. This is written.

[00:30:31]Ok? And what are you making, son? I have some kind of compound like this forming. First of all, phenol is being formed, son.

[00:30:40]I have ate with it CHO and a compound is being formed with it, son.

[00:30:48]I have the compound CH3 and CHO formed.

[00:30:52]Ok? Next question number five. Look son, do it quickly. Let's see five.

[00:31:00]Look son, what's happening in Five?

[00:31:02]I have this compound in five. It is something like this, it has OH on it. I have two compounds being formed in this.

[00:31:12]One is para hydroxy and one is being made by me, son, para hydroxy benzoyl alcohol. I have one being made and hydroxy benzoyl alcohol. So I have two of these being made.

[00:31:23]Ok? Let's talk about unit number four.

[00:31:26]Derive the first break equation which happens to be 2dsinθ = nπ and discuss its applications in the study of crystal structure. Derive the break equation 2dsinθ = n lλ and discuss the application in the study of crystal structure. Ok? I have this. Next question. See you next, son. What more can one ask for in this?

[00:31:53]Describe the powder method and the iron method or as it is called, the Lau method for determining the crystal structure.

[00:31:56]Describe the powder method and Laue method for determining crystal structure.

[00:32:01]Look ahead son, what other questions can you have next? Prove that the half-life of a second order reaction is inversely proportional to the initial concentration. Prove that the half-life of a second-order reaction is inversely proportional to the initial concentration. Next, plane of symmetry, symmetry X. What do you understand by centre of symmetry?

[00:32:23]Find the Miller indices for the following faces. Look son, let me write down for you which panels are there, right? It's probably not written in it. Let me tell you. If you have an index, then this is a very important and very simple question.

[00:32:35]This is the Miller index finder. Ok?

[00:32:38]First of all, I have this 2a alphac. I have a second, son, look at the 2a ratio, it is not very hard.

[00:32:50]Ratio minus 3b is minus 3. We reciprocate it and then divide what we get in the denominator by what we get in the denominator. It's just simple. Isn't it? So this is not such a hard thing. You can watch it comfortably. First of all let's do its reciprocal. Then what does the same thing that comes in the denominator do to everyone? Let's divide it. And if there is a minus sign, then we put it on top of it like this, like this 3 c / 2, so what do you have to find out from these three, son? Miller indices are to be found. This is a very important question.

[00:33:25]This Miller index brother. Take care of this. Next C section is here son. Now you all can be carefree about C section. Because if you have studied B section carefully then you can do C section easily. You have to attempt any two questions out of four.

[00:33:39]How many marks will you get for one question? Of 20 marks. So how many marks do you have son? Of 40 marks. Which one? Section C. First variant question from first unit.

[00:33:49]Explain linkage isomerism. Explain linkage isomerism. That's right, son. I have got this, son.

[00:33:54]Question number one. Let's see next.

[00:33:56]Look next, son.

[00:34:00]What can you have next?

[00:34:08]Explain the crystal field splitting of d orbitals for octahedral complexes.

[00:34:09]Explain the crystal field splitting of d orbitals for octahedral complexes. Look at the third question, son, because you know it is a question of 20 marks and will not come in one part. Ok? Third look, explain. What do I need to explain?

[00:34:21]K3 FeF63 - is paramagnetic. While these are diamagnetic. I told you this can change.

[00:34:26]But he will come. It has unpaired electrons in it. Now you understand son, you can tell that it contains unpaired electrons. Because of this it is paramagnetic and does not contain unpaired electrons. All the electrons in it are paired. Hence it is diamagnetic. This is the answer to it. Ok? Next is K4. This MNC6 is paramagnetic, what is it like?

[00:34:45]Diamagnetic. It's the same thing, son.

[00:34:47]Why? Because what does it contain? There are unpaired electrons. Hence paramagnetic and does not contain unpaired electrons.

[00:34:52]So what is it? It is diamagnetic. Next question number 2nd. Write a note on covalency.

[00:34:59]Write a note on covalency. Ok?

[00:35:01]Co-valency will not come son. In its place will come symbiosis. Be careful what will come?

[00:35:08]Write a note on symbiosis. Look next.

[00:35:14]Explain the relation between hardness and softness with electronegativity. What is its relation to that?

[00:35:17]Explain the relationship between hardness, softness and electronegativity. You have to tell yourself the relation between hardness and sweetness and electronegativity.

[00:35:26]Look at the third variant, son, what is the question? Differentiate between acids and bases according to Bronsted, Lowry, Lux, Flood and Lewis theories.

[00:35:36]Who has to differentiate themselves? Acid and base. On whose basis? Bronstad Lowry, Lux Flood and Lewis Concept or we call it Son Lewis Concept. Ok? The third question is of 20 marks. Your reaction will be asked, son. You should definitely keep this in mind.

[00:35:51]You guys should memorize these reactions that I am telling you and go away. First is Clementine reduction, it is very simple. WF Christner Uns Dieker reaction, estfigation reaction and Claisen condensation.

[00:36:01]Ok? That is, Claisen condensation. That's right, son. Next look at Claisen-Schmidt reaction, Witting reaction, Haloform reaction, Tishyako reaction, this or even Tishya is called many times. Parkin reaction and Nomengel reaction. Is it okay son? I have it with me.

[00:36:18]One comes to his son inside it Markonikoff rule. So you should already know the Markonikoff rule.

[00:36:24]See the last question, son, it is a variant.

[00:36:27]Explain that all crystals are anisotropic while cubic crystals are isotropic.

[00:36:31]Explain why all crystals are anisotropic while cubic crystals are isotropic. It's okay son, you have it. This is going to be your next question. Let us talk about the next question, son, which is going to be the last question of your section, which is your unit four. You have to tell yourself what is the difference in the crystal structure of NaCl and KCl. What is the difference between the crystal structure of NaCl and KCl? Look at the third question, son.

[00:37:02]What is the difference between a three-dimensional conductor and a unit cell? What is the difference between a specification and a unit cell? Last.

[00:37:10]What is the difference between zero and first and second order reactions? You have to tell yourself this.

[00:37:13]What is meant by zero order, first order and second order? I told you that the concentration of the reactant is proportional to its first order. That first order is proportional to the zero order.

[00:37:22]That is zero order and the one which is proportional to two order, we call it third order reaction, son.

[00:37:29]I hope you liked the video.

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[00:37:58]See you in the next video. Till then Jai Hind Jai Bharat.