UGTRB MATHS FOURIER SINE SERIES EASY TRICKS

[00:00:00]UGC TRB notification anytime annual planner buddy TRB love UGC TRB kind of notification where you get it ready.

[00:00:12]Number of PR Max Academy love UGC TRB examinations online mode coaching credit to come after classes at the chrome live classes with them live with the pin with under classes and you are recording a particular unit test half unit test model examination previous years questions and discussions shortcuts and tricks and everything include of them 10,000 plus MCQs only test series volume material hard copy courier for you to work number of PR Max Academy love UGC TRB love you TRC for you to come 94 members clear money to come and the details of show money to come admissions by the interested at the contact money thank you.

[00:00:55]TRB examinations prepare money to come mathematics major friends color video with them previous years cater than one question one of the syllabus love unit four vector calculus and four year series four year transforms either love four year series love sign series love and the question cater to come fourth unit love cater to come find a sign series for f of x is equal to c interval zero comma five cater to come one government competitive examination time saving technique number of volume in the problem of part of one and a year question send you back home option B in the solution you have the I mean now f of x as equal to one constant c cater to come can be part of constant c final answer love volume so c love the option you have to eliminate money to come and then the constant c can be part of denominator club volume numerator love the volume so B and D in the render love the answer and sign series la one odd sign 1 x sign 3 x sign 5 x pattern problem I believe not 2 x 4 x 6 x in the mighty problem. What is it 1 x at the 2 x 3 x What is it odd multiples la 1 1 3 5 up here So, option B in the mighty problem by the city the exam hall la in the problem type in the mighty la and the time la in the work on work on problem and easy and a trick C can be the question la in the mighty problem and the numerator 1 x 3 x 5 x in the pattern la in the problem all of the option B in the solution if I in the problem in the direct in the mighty problem I'm going to sign series get it done 4 year sign series in a formula sigma n is equal to 1 to infinity B N sign N X in the 4 year sign series in the formula in the B N calculate problem in the double 0 comma 5 in the mighty problem 4 year sign series la 0 comma 5 in the double la B N in the formula 2 by 5 integral 0 to 5 f of x sign N X D X in the f of x question la C in the mansion in the mighty problem I do or constant la x in the mighty problem integration in the mighty problem sign N X in the mighty problem in the mighty problem minus cos N X by N in the mighty problem lower limit 0 upper limit 5 So, B N in the mighty problem 2 C by 5 upper limit X by 4 problem So, minus cos n pi lower limit for the minus into minus plus cos zero one plus one by n So, denominator common here.

[00:04:12]2 c by pi n minus cos n pi plus one one minus cos n pi cos n pi minus one the whole power n and cos n pi but it should be n odd multiples of pi cos one more minus one more room even multiples of pi cos plus one more room and I sold minus one the whole power n general cos n pi you can minus one the whole power n n odd number minus one more room number minus one the whole power n and n equal if in the b n random calculate which column n odd number in the b n value in the room n even in the room in the b n value in the room n in the minus one the whole power n value small room plus or minus one in the room if a plus one more room even value in the room in the room a minus one the whole power n plus one more room one minus one zero in the room b n full of zero in the room n even in the room in the room in the b n in the room in the room in the room n suffix n b n suffix odd value one more n g n equal more room in the minus one the whole power n minus one more room more room in the room in the room in the room in the room in the room plus one more room one plus one two in the room already one two c in the room a four c by pi n in the b n in the room by pi n either b n or the value n or I become Buddha.

[00:05:54]Number four year science series April and April 4 on.

[00:05:58]And the formula Sigma n is equal to 1 to infinity and it will learn.

[00:06:02]Other Sigma n is equal to 1 3 The odd values are for the word summation. Plus another summation Sigma n is equal to 2 4 6 and it will go with it.

[00:06:12]B n sine n x and the word for year sine series and up which it will learn.

[00:06:17]Second layer could be n value and the even values for the full of zero.

[00:06:22]Odd values for the word number can one that it be n good.

[00:06:25]4c by pi n The 4c by pi or constant n in the term now. In the summation layer n in the term constant. So 4c by pi n number really it will turn on. We will number can I become now?

[00:06:41]Sigma n is equal to 1 3 5 it will be getting it will come. Sine n x by n Sine n x by n and all the summation full of zero error.

[00:06:50]If you need a summation express for now.

[00:06:53]Sine 1 x by 1 plus sine 3 x by 3 plus sine 5 x by 5 it will be getting it will come with a 4c by pi it will come in the option B layer it will come. But it will order more work out for now and now.

[00:07:04]Question about the word and they final answer layer. Constant C word and all the option A will remove for now and now. And the constant C denominator layer for the word for now and now.

[00:07:15]Option C remove for now and now. If a B D layer B layer the word n x 3 x 5 x and it will take and the odd multiples for the word and it will go with it. So that is the answer now easy number guess for now and now. The word time saving technique.