To solve the equation x³ = 8⁻¹, first rewrite it as x³ = 1/8, then express 1/8 as (1/2)³ to apply the difference of cubes formula a³ - b³ = (a - b)(a² + ab + b²), yielding (x - 1/2)(x² + x/2 + 1/4) = 0. The first solution is x = 1/2, while the quadratic factor x² + x/2 + 1/4 = 0 is solved using the quadratic formula, giving complex solutions x = -1/2 ± (i√3)/4.
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Olympiad Mathematics | Indian | Can You Solve This?Added:
Okay, if you're ready, let's provide the complete solution to this problem very quickly.
We have x to the^ 3 to be = 8 to the^ of -1.
Now we are having three solutions from here. We're going to have three solutions because of the power of three.
Now here is what we should do. This is x to the^ 3 = 8 ^ -1 is the same as 1 / 8.
Okay. And then from here we are going to express 1 / 8 in the power of three.
Okay. That's very possible. So write x ^ 3 to be equal to um from here we can write um 1 / 8 as 1 / 2 to the power of 3.
Yes. Okay. So this is very very possible because 1 to the^ 3 is 1. 2 to the^ 3 is 8. Now bring this to the left hand side as you have x ^ 3 - 1 / 2 to the same power 3 equals z.
So at this point you just apply your difference of two cubes.
Yes. And it says that a cub - b cub is equal to a - b * a 2 + a b + b 2.
Yes, this is what it is. So that our a is going to be x. Then our b is going to be 1 / 2. This will be in the first bracket. Then in the second bracket a 2 will turn to x².
Then + a. A is still x right. Then multiply by b which is 1 / 2.
Then + b 2 and that is going to be 1 / 2. You know this will be squared.
Okay. Let me turn this.
Okay. So, this is it.
And um we're going to equate everything here to zero.
Yes. Everything will be equated to zero.
So, now we have our x - 1 / 2 one of the factors. Then from here we have x² and then x * 1 / 2. that will give us um x / 2 + 1 / 2^ 2 will give 1 / 4.
Okay. So this is equal to zero.
From here what do we do? Let's um okay I think it's okay for us. We can apply our zero product rule already so that either this is equal to z or this is equal to z. So let me pick this. I'll come back to this one after x - 1 / 2 = 0.
And this means that x = 0 + 1 / 2 and that is 1 / 2. So we have our value of x already to be 1 / 2.
But then I'm going to pick out this equation and then we'll solve it.
Okay. So, here it is. And remember that this is still a quadratic equation. Yes, even if we having fractions, it is a quadratic equation. And we can clear out the fractions. How do you do that? The LCM of everything is four. So, multiply four by all the terms. 4 * x 2 that will give us 4 x^ 2 + 4 * x / 2 that will give 2 x. Yes. Then 4 * 1 / 4 will give 1 which is equal to 4 * 0 and is 0.
So from here now we have 4 x².
Okay. I think we already have what we want.
Yes, this is already our quadratic equation and we are going to solve it.
Let me remove this. We're going to solve this formula using our quadratic um we're going to solve this equation using our quadratic formula that says x = - b + or minus we have the square root of b^ 2 - 4 a c all over 2 * a.
Now what is our a? Our a is 4. Our b is 2 and then c is 1. a is a coefficient of x².
b is a coefficient of x and c is a constant. So we're going to put the three of them into the formula.
So our x will now be -4 + or minus we have b ^ 2 which will be 4. Okay.
What is our b? b is 2. So we write 2^ 2 there. Then - 4 * 4 * 4 cuz a is 4 then * 1 c is 1 and all of this is over 2 * 4 since a is 4.
So our x will now be -4 plus or minus we have 4 - 16 4 - 16 and it's all over 8.
From here we have x to be -4 plus or minus the square root of 4 - 16 is -2.
So this is all over 8. Now let us um work on root -12.
Let's work on that root. So that x will be -4 + or minus square<unk> of 12 *<unk> of -1.
So that if you multiply both of them you have roo<unk> -12 all over 8. Now to go on with what we have our x will be -4 plus or minus square root of 4 * 12 is 4 * 3.
Then square root of -1 is i and all of this is over 8. Okay. So from here now we can continue to get x = -4 + or minus square root of 4 is 2 2 * i that will be 2 i then we have <unk>3 as we divide all of this by 8.
Okay. Now let's break it very quickly.
Okay. So we break it down to get -4 / 8 + or minus we have 2 I <unk>3 / 8. So what are we saying that x is = -1 / 2 plus or minus um 1 / 4. By the way that should be I yes I over 4. Then we have <unk>3 and this is a two in one kind of solution. So to get the full solution together we have x to be 1 / 2 if you remember. So this is our first solution.
Then the second x2 is - 1 / 2 + i / 4 <unk>3. This is the second. Then the third is -1 / 2 - i / 4 <unk>3.
So these three are the solutions to the equation. Thank you for watching.
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