This session is a masterclass in exam-oriented pragmatism, distilling complex physics into a high-speed survival guide for competitive success. It perfectly balances conceptual clarity with the brutal efficiency required to conquer the NEET marathon.
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NEET 2026 Physics 🔥 Top 100 Most Expected PYQs | Questions & Answers 💯Added:
Morning. Good morning.
Good morning everyone.
Am I audible?
Am I audible?
Good morning manusa. Good morning Chundraala.
Good morning Niha. Nisara Shashi Padmanab.
Yes.
Fine.
Shall we start?
Shall we start?
Start man.
Yes. Okay. Now let's get started. So session top 100 PQ most expected questions discuss. It is not only about you know only PQS PQ most expected questions.
Okay. Now right so duration of the class. Okay. So duration of the class 2 to 3 hours. Okay. 2 to 3 hours 100 questions discuss. Okay. Right.
So today's topic is top 100 PQS m most expected questions for your NE 2026.
Okay. So let's get started with the very first question. Okay. So try to answer these questions. Okay. The question is an electric dipole with a dipole moment<unk> into 10^ - 6 kum is aligned with direction of uniform electric field of a magnitude 4 into 10^ 5 Newton per kum. The dipole is then rotated through an angle of 60° with respect to electric field. The change in a potential energy of the dipole. Okay. So change in potential energy. So first of all change in potential energy is nothing but work done only. Okay. So indirectly they're asking about work done.
Okay. Then sir it can be written as minus P the bracket of that is a cos theta_1 the cos theta cos theta 2 minus cos theta 1. Okay. And values. Okay. So values substitute. So change in potential energy that is equals to the dipole moment it is a five that is minus 5 into 10^ - 6 and electric field electric field that is 4 into 10^ 5. Okay. So bracket of the cos theta aligned with the direction of electric field. So it is theta_1 is equals to 0 and next to theta_2 is equ= to 60°. Okay. So that is 60° so minus cos 0.
Okay. Yes sir. So delta is equals to minus.
So that is 10^ - okay. So that is into so cos 60 that is 1 by 2 and cos 0 that is equals to 1.
Okay. So deltaU that is equals to minus 10 -1 into 20 that is 2 and LCM that is -1 by 2. Okay. So yes so change in potential energy minus of minus plus 2 two get cancel. So one jol is the right answer. Okay. So one jol is the right answer. Okay. So option D is the right answer. Okay. So option D that is one jol is the right answer.
Very good. Now let's move on to the next question. Next question. A ball of mass 0.5 kg is a drop free fall from a height of 40 m. The ball hits the ground and raises to the height of 10 m. The impulse imparted to the ball during its collision with the ground.
Okay.
impulse. Impulse is nothing but the change in momentum. Okay. So change in momentum into delta V change in momentum in terms of impulse into it.
Right? First initial momentum. So that is initial momentum m into u. Okay. So m into v. So let me write as v1. Okay. So this is p2us p1.
Okay. So p2us p1. I'll be writing p1 as m into v1. M1 into v1. So we have equation. So v² that is equals to u² + 2 a. S. So right. So v² v² that is equals to u square free drop that is clear. Next one.
So 2 into g value into h. Okay. Yes sir.
So v² that is equals s v is equals to un 2 gh. Okay. Yes sir. V1 2 into 9.8 8 into high test that is a 40.
Okay. So 40. So V_sub_1 value simplification. Okay. So V_sub1 value that is simplification.
Okay. So simplification. So that is uh 2 into 9.8 into 40. Okay. So that is 784 28. Okay. Yes sir. This is 28 m/s.
Sir V1 therefore momentum initial momentum is so it is m1 into v_sub_1 so p1 that is equals to m1 value so it is 0.5 into 28 so p1 that is equals to okay so into 0.5 so 14 okay sir p2 okay so v2 so v_sub2 that is equals to sir it is 2 * of gh2 Okay. So this is H1. So this is H2. Okay. Yes sir. So V_sub_2 that is equals to unders² it is 2 into 9.8 into height that is a 10. Okay. So V_sub_2 that is equals to Okay. So V_sub_2 that is equals to 2 into 9.8 into So that is a 10. So that is 196. 196 square root that is a 14. Okay. So 14 m/s. Okay. So 14 m/s.
Fine. So P2 that is M_sub_2 into V2.
Okay. Yes sir. So P2 okay so that is the P2. So that is equals to M2 values you know M1 value M2 value same mass.
Okay. So same so that is 0.5. Okay. So 0.5 and velocity that is a 14. Half of the 14 that is the seven. So 7 Newton second.
Okay. So 7 Newton second. Okay. So 7 Newton second and change in momentum is impulse is nothing but the change in momentum that is nothing but it is P2 minus P1. Okay. The P2 is it is a seven minus of it is a positive.
Okay.
So 14 I that is equals to 21.
Okay. So 21 Newton second. Okay. So 21 Newton second. Okay. So 21 Newton second that is option C. Okay. So option C is the right answer. Okay. So option C is the right answer.
Option D that is wrong. P1. Okay. So P1.
Okay. Now is that clear for everybody?
Clear option.
So change in momentum impulse. Okay.
Fine.
Yes.
Clear.
Yes. Okay. So, try to answer this question. Yes. Answer.
Any answer.
Okay. Right. The question is the kinetic energies of two similar cars A and B are 100 joule and 225 joule respectively. On applying brakes a car A stops 100 m and car B stops 150 15 uh sorry500 m. If FA and FB are the forces applied by the brakes on a car A and car B respectively then ratio of FA and FB find right.
What is the relation? We can use work energy. Okay. So what is the work energy becomes okay because final falsinetic energy?
Yes sir.
change in energy because coming to the rest okay value into you know displacement so distance x s value so that is equals to ka value And next one FB value and SB value. So that is equals to KB value learning FA and FB. Okay. So F A divided by FB.
Okay. So F A divided by FB. So into S A divided by SB. Okay. So SA divided by SB. Okay. So that is SA divided by SB.
So that is equals to K A divided by KB.
Okay sir. And next F A divided by FB.
Okay. Say f a divided by fb that is equals to okay into okay into yes a car a stops is to 1,000 and 1,500 okay so it is 1,500 that is equals to kinetic energy of a that is 100 and 225 okay yes sir observe two get cancel 0 get cancel okay yes so F A divided by FBI 15 into 10 that is 150 divided by 225.
Okay. Yes sir.
So 15 in the divide. Yes sir. 15 sir it is a 10. Okay. So 15 that is a 10. And what about 225? 225 that is a 15. and okay so that is 2x3 okay so 2x3 is the right answer okay so 2x3 okay so 2x3 is the right answer fid fb that is 2 by3 okay so that is 2 divided by 3 that is option D so option D is the right answer very good now let's move to the next question okay so next question okay so next question tumba students okay so tumba students The current passing through the battery in a given circuit is okay.
Right.
Okay.
Okay.
It looks like a stone bridge. So five resistors bridge.
Okay. So this is 6 ohm and this one as a R1 and this is R2 and this is R3 and this is R4. Okay. Right. So this is R1 and this is R2 and this is R3 and this is R4.
Yes sir.
By watching this. Okay. So wheat stone bridge. Okay. So wheat stone bridge. So it is R1 / R2. So that is equals to R3 / R4. E concept it is 5 / 3. Okay. So let's consider this is R1 and this is R2 and this is R3 and this is R4. Okay. Yes sir.
It is 2.5 divided by 1.5.
Okay. R1 that is equals to R1 R2. So that is equals to R3 / R4. Okay. So 5x3 5x3 it is a stone bridge. We st you can eliminate this one. Okay. So you can eliminate this one.
Remove. Okay. So remove what is the combination? A C.
What is the combination? A C that is a serious combination. F D that is also serious combination. Okay.
Okay.
Okay.
So, so combination.
Okay. So, for a better understanding.
Okay. Right.
Okay.
Okay. Right.
Okay.
Okay.
Okay. So that is the 3 + 5. Okay. So that is 3 + 5 that is equals to 8 ohms.
And the next one it is 2.5.
Okay. So 2.5 plus. So that is 1.5 it is 3 four. Okay. So 4 ohm and again it is a par combination right. So first as it is.
Okay. So 1.5 ohms. Okay. And it is 5.5 ohms. Right.
So it is a 1.3 ohm right? Yes sir. 5 fine. So circuit is reduced to this one. Okay. So circuit is red to this one is a combination. Okay.
combination.
Okay.
You can consider it RP that is equals.
Okay. So that is RP.
So par combination that is resistance in a par combination 8 into 4 divided by 8 + 4. So RP that is equals to so 8 into 4 / 12.
Okay. So that is 8 / 3 ohms. Okay. So 8 / 3 ohms. Okay.
Yes sir.
So you know passing in a direction have a single path. So therefore it is serious combination. Okay. So total resistance. Okay. So total resistance it is 1x3 and it is 8x3 plus it is 1.5.
Okay. Okay. So 1.5 s 3x2. Okay. So that is 3x2. Okay. So this can be written as 3x2. Okay. So 3x2 ohm it is 11 by2 ohms. Okay. Yes sir. Sir it is 11 by2 ohms. So total resistance that is equals to it is 9 / 3 plus 14id 2 right? Yes sir. And it is.
Okay. So total resistance sir it is a 10 ohm. Okay. So total resistance 10 ohm and further simplification. Okay.
S total current. Okay. So total current is two. Okay.
Current passing through the battery.
Okay. So current passing through the battery that is V / R. So V is a five and R is a 10. So that is 1 by 2 ampere.
The 0.5 amp. Okay. So total current so that is 0.5. Option D option D is the right answer. Okay. Option D is the right answer.
So that is option D. Okay. So option D is the right answer. Okay. So option D is the right answer.
Very good. Next one.
So this is this question is from wave optics. Okay.
Right. The question is two monochromatic light wave of amplitude three 3 a that is amplitude three times amplitude and two times of amplitude 3 a and 2 a interfering at a point have a phase difference of 60° the intensity at okay the intensity at that point will be proportional to okay so intensity okay so that is intensity is directly proportional 2 amplitude square. Okay. So that is amplitude square right? Yes sir.
Amplitude resultant it is resultant amplitude is nothing but that is r². Okay. It is r². So it is a1 square + a2 squ + 2 * of a1 a2. So that is a cos 5 right. Yes sir. So r² that is equals to a 1 + error. So it is a 3.
Okay. So that is a 3 a square + 2 a² + 2 * okay. So that is the 3 a and that is a 2 a and cos 60°. Okay. So that is a cos 60° and r² that is equals to okay.
So that is 9 a² and 4 a² + r. Okay. So r. So 2 into r a² into cos 60 it is 1x2 e 1x2 1x2 get cancel it is r² that is equals 6 + 19 19 a square I is directly proportional to the resultant amplitude square that is equals to 19 a² so this is the option D again so option D That is option D.
Very good. Now let's move on to the next question. Okay. So next question. Yes.
Answer.
The question is a lens of a large focal length and large aperture is the best suited as object of objective of an astronomical telescope. Since Astronomical telescope. Okay.
There are multiple reasons that is a large quality visibility of image quality visibility clear that is the first thing and the next one large area infinite so large so that more bright image will be formed better and the large aperture provides a better resolution lens of a large focal length and large.
Okay. So that is the reason. So that is option.
So D a large aperture contributes to the quality and visibility of the images.
That is correct. A large area of the objective ensures a better light gathering power. Yes, that is also correct. And option C that is a large aperture provides a better resolution.
That is also correct. So therefore all of the above. So all of the above that is option D. Okay. So very good. Now let's move on to the next question.
Okay. So next question. In some appropriate unit time t and a position x relation of a moving particle is given by t is equ= to x² + x. The acceleration of the particle is okay. Acceleration of the particle. Okay.
that is x² + x with respect to time. Okay. So that is a differentiate with respect to time it is dt / dt. Okay. So that is dt / dt and it is 2x into dx / dt. So plus it is a dx / dt. left hand side it is a 1 and this is a 2x + 1 into dx / dt. Yes. So 1 that is equ= to 2x + 1. So dx divided by dt it is a speed of velocity and velocity that is equals to 1 / 2x + 1.
Okay. So 2x + 1 2x + 1 - power - 1 is a function of a position not a time.
acceleration that is equals to v into dv / dx. Okay. Yes sir. So v as it is dv differentiation of s it is minus1 sir it is a 2x + 1 minus of -1us into that is 2. Okay. Yes sir. Sir acceleration that is equals to okay. So acceleration that is equals to sir it is -2. Okay. - 1 into 2 that is - 2 and the v value it is 1 2 x + 1 2x + 1 therefore it is a 2x + 1 okay so into so that is a 2x + 1 all square so a that is equals okay so a that is equals to so it is minus 2 so it is a 2x + 1 okay sub power 3 okay power 3 -2 1 2 x + 1. Okay. So that is option D.
Okay. So option D is the right answer.
Option D is the right answer. Option 2 X. Okay. So 2X + Okay. So 2x + 1 x + 2 x + one normal. Okay. So simple mistakes. Okay. Now let's move on to the next question. Okay. So next question.
Yes. Try to solve this question. The question is in the given circuit the resonant frequency is resonant frequency. Okay. So resonant frequency we know that. So f that is equals to sir it is a 2 pi under square root l into c.
Yes sir. So frequency that is equals to 1 divided by s it is a 2 pi under square root valus 3 into it 20 into 10 - 6 okay yes sir. So frequency that is equals to 1 / 2 pi so 20 into 5 to 20 into 0.5 that is 10 10 - 9 that is 10^ 8 10 it is 10us 4 so simplification it is you know 1 / 6.28 3.14 into 2 that is 6.28 28 sir 0.1592 so 35 into it is 10^ + 4 so resonant frequency that is equals to 1 2 3 4 okay so 15 92 Hz okay so 92 Hz okay so 15 92 Hz that is option C right so that is option C is the right answer okay so option C is the right answer option C is the right Answer option D that is wrong. Okay. So that is wrong answer.
Next one. Next question.
Next question. A disk is a placed on a surface of a pawn which has a refractive index 5x3. A source of a light. Okay. So a source full stop.
Huh. A source of light is placed 4 m below the surface of the liquid. The minimum radius of a disc will be so light is not coming out. So radius of the disc. Okay. So radius of the disc.
So we have a formula. So that is radius of a disc that is equals to h. So divided by square mu² minus one. Okay. Yes sir.
So r that is equals to h value. So sir h value that is a four and that is under square root refractive index it is a 5x3. Okay. 5x 3 - 1. Okay. So that is a four.
So four that is under square root it is divided by minus one. Okay. So r that is equals to 4. So divided by 25 - 9. So divided by 25. Okay. So 4 / under square root. So it is 16 divided by 25. Okay. So 16 divided by 25. So four into it is a four.
So that is four. Okay.
25.
Okay. So this is okay. So okay 9 fine. Yes sir. So 4 / 4 / 3. So okay it is 3 m.
So 3 m option B. So option B is the right answer. That is option B is the right answer.
16% answer 66 option gone. Gone case.
Okay. So that is option B is the right answer. Okay. Next one.
Next one. Fine. Next question. Bigger.
Bigger.
Answer M. D broadly wavelength of an electron orbiting in an N= to2 state of hydrogen atom is a close to.
So according to the quantization okay so according to the quantization rule okay hypothes you have a formula it is l= n h / 2 it is 2 pi rn so that is equals to n lambda s it is equals to 2 okay so that is 2 pi sir it is i2 that is 2 into lambda so 22 get cancel. So pi into R2. So that is equals to lambda and R2 value.
So R that is equals to N². Okay. So R N² R N². Okay. So R2 R 0.052. Okay. So 0.052 into sin square it is a 2 square. Okay.
So s R2 that is equals to 0.052 052 into 4. Okay. So 0.052 into 4. So that is so I2 value that is 0.208.
Okay. So that is nanometer.
Okay. So nanometer. Fine. Yes sir. I now substitute that lambda that is equals to it is 3.14 into that is 0 208 and lambda that is equals to start into 3.14 so that is 0.65 65 31 nanometer. Okay. Yes sir. So this is the wavelength. Okay. So 0.65 0.65.
So approximate value that is option D.
And nearest value nearest value that is 0.67 nearest value. Okay. Now so that is option D. So option D is the right answer.
What is the problem you are facing?
Okay.
Fine. The question an electromagnetic wave is the traveling in X direction with electric field vectors given by EY that is equals to E sin K X minus omega T JCAP. Okay. So that is a JCAP. Okay. So JCAP the correct expression for a magnetic field.
Okay.
So it is E cross B. Okay. So that is E cross B into V vector.
Electromagnetic wave is traveling in X direction. X direction ICAP and electric field vector is given by that is a JCAP. Okay. So that is a JCap vector unit vector.
So J cross K. Okay. So J cross K value vector. Okay. So elimination option option D and option B opposite. So right answer that is option D. So option D that is BZ okay so Bz that is equals to B so it is a sine of it is a kx minus omega t okay so okay so k bz okay so bz can be written as it is a divided by c so sin of kx minus omega t that is a kcap okay So that is option D is the right answer. Okay. So option D is the right answer.
Okay. Uh lead lid.
Samanasa, Spandana, Chandraala, Padmanab, Animation, Ki, Priu, Vishuanat, Vinatkumar, RPG, Ga, Dhanash, Natraj, Ajitkumar, Shiva, Shivat Mika, Jaram, Nisara, Rada, Shashi, Vir A and Kala go kala patil okay so let's move on to the next question yes e question answer okay question answer to an AC power supply of a 220 volt at a 50 Hz a resistor of a 200 a resistor of a 20 ohm resistor okay sir and capacitor reactor so that is X C and inductor reactance so that is XL are connected in a series.
Okay. the corresponding current in the circuit and the phase angle between the current and voltage is respective.
What is the formula combination V / Z and what about Z is underscore R² + XL - X² okay yes so Z that is equals to underscore R² value there it is 20 square plus XL value there it is 45 minus XC value that is a 25 square okay so Z that is equals to understo plus say 45 - 2500 that is 2020 20 that is a 400 and 200 that is 2002 okay so 2002 ohms okay so 200 okay sir it is 2 * 400 s it is 20 okay so 200 so that is 20 Okay. So 20.
So that is equals to that is 20 20<unk>2.
So current that is equals to V sir it is 220. So divided by sir it is 20 into <unk>2. Okay. So 20 into <unk>2. Okay sir. So I is equals to 10 1 get cancel 11 / 2<unk>2.
So I that is equals. Okay.
112 0.77.
Okay. Yes. So 11 into 0.707.
Okay. So I that is equals to 7.77 amp. Okay. Elimination elimination.
And 7.8.
So C answer and so phase angle. Okay. So phase angle. Okay. So phase goes. So we have a tan pi that is XL minus XC divided by R. Okay. Yes sir. So tan five that is equals to Excel value. Excel value that is a 45. XC value that is 25.
So resistance value that is a 20. So 20 divided by 20. So that is equals to 1.
So tan is a 45° or is by4 answer. Okay. So 45 by 4.
Okay. Yes. So that is option D is the right answer. Okay. So that is option D is the right answer.
Option D is the right answer. Very good.
Now let's move on to the next one. Next question. Ready? Next question is which of the following option represent the variation of photoelect electric current with a property of a light shown on the x-axis and photocurren electric it is depends upon only on intensity of light. Okay. So frequency.
Okay. So frequency waveg it is depends only on intensity. intensity.
Okay.
And so electric as intensity increases. Okay.
So as intensity is increases direct.
So therefore it is constant therefore wrong. So only one correct that is option A. Okay. So option A correct.
Okay. So that is option C.
A only okay so A only C photoelectric current is independent of frequency and the next one intensity of light intensity of a light is directly proportional to the you know intensity of light. Okay. So photo electric current is directly proportional to the photo nothing but photoelectric current is directly proportional to the intensity of light.
Okay. So that is option C. Okay. So, option C.
Next one. Next question. Next question.
A pipe open at a both ends. Okay. So, when a pipe open at a both ends has a fundamental frequency. Okay. It is a open pipe. Okay. So, this is a open pipe. The pipe is now dipped vertical in a water drum to the half of its length.
Okay. So close.
Okay. Now in a water drum to half of it is equals to L2. Okay. The fundamental frequency of the air column is now equal to. So first no delay okay frequency of open okay so that is given by NV / 2 * of L okay now yes sir fundamental it is f_sub_1 that is equals okay fundamental already so therefore f so that is equals 1 v / 2 l okay yes sir so this is the frequency Open. Okay. So, open pipe. Now it is a dipped closed pipe. Okay. So, closed pipe fn. Okay. So, for a closed pipe.
Okay. So, for a closed pipe, what is the frequency? Okay. So, for a closed pipe.
Okay. So, for a closed pipe, so it is fn that is equals to so it is a 2 n minus one. Okay. So vid * frequency. So f_sub_1 that is equals to it is 1 into v / 4 into ldx2.
Okay. So v / 2 l. Okay. So f dash that is equals to v / 2 l it is f. Okay. So that is f. Okay. Okay. So that is option D is the right answer. Okay. So option D is the right answer. You got my point.
So that is option D is the right answer.
So option D is the right answer.
So next question. Yes. Question. Two identical point identical point masses P and Q suspended from a two separate massless spring constant K1 and K2 respectively oscillates vertically. If their maximum speed are same, the ratio aq divided by a of the amplitude aq of a mass q and the amplitude a condition max right? Yes sir. Spring constant related it is time period.
Okay. So time period sir v maximum that is equals to time period. Okay. So that is 2 pi / t. Okay.
So 2 pi / t that is equals to a and v maximum. So that is equals to so that is 2 pi time period so it is 2 pi under square root okay so under square root that is m / k okay so into a right yes sir so 2 pi 2 pi get cancel okay so 2 pi 2 pi get cancel as v maximum so that is equals to under k / k / m into a okay so 2 pi 2 get Okay.
So, V_sub_1 that is equals to V_sub_2.
So, V_sub_1 that is equals to V_sub_2.
Okay.
V_sub_1.
So that is under squared that is K1 divided by M identical identical point masses. Okay. So let me write it as m1 into a amplitude of 1 p. Okay sir. Next one under square root k2 divided by m_sub_2 into aq. Okay. Right sir it is aq / a. Okay. So aq divided a.
Okay. say a divided by a socore k1id m1 m_sub_2 / okay so it is k2 okay identical masses okay so mass masses are identical identical get cancel okay so m2 m1 get cancel aqid a so that is equals to under root It is it is a k1 divided by k2. So this is the required solution. Okay. So underscore root k1 divided by k2. Okay.
Underscore it. So k1 divided by k2. So that is option B is the right answer.
Okay. So option B is the right answer 27%.
Next one. Answer m answer my no. The output y of the given logic implementation. Okay. This implementation is a similar to that similar to the output of an an or a gate identif Okay.
Right.
So that is bar complement.
Okay.
A and B.
Okay. Yes sir.
Okay. and okay so again it is and sir that is equals to a + b okay into okay so that is a b bar okay a b bar okay right sir and simplification a dot okay so a dot b so that is bar and this is also bar okay so into okay so a bar Okay. So it is a plus. Okay. So a plus. Okay. So a + b. Okay. So a plus a bar and this is also bar. Okay. So sir it is a okay. So that is a okay into either it is a bar plus b bar. Right.
Yes sir. And simplification complement. Okay. So compliment it is a a b. Okay. So a + b bar a b. Okay. So simplification.
So it is simplification. Okay. So simplification that is. Okay. So that is a gate. Simplification you will get a ngate. Okay. So simplification you'll get a nate. Okay. So that is a Nate.
Very good. So that is a Nate.
simplification. Okay. So that is a Nate that is option B.
Very good. Now let's move on to the next one. Answer. The question is a physical quantity P is related to four observations A, B, C and D as follows. P is equals to A power 3 B power 2 divided by C power C into under root D. The percentage error of a measurement in A, B, C and D are 1% to 3% 2% 4% respectively. The percentage error in a quantity P is okay. So percentage okay so percentage so first it is a P that is equals to okay so that is a P that is equals to it is a power 3 and B power 2 all divided by set is a C under root D. So this is what we they have given. Okay. Simplification it is a power 3 and b 2. So all divided by c and d power 1 by 2. Okay. Yes sir.
Fine. You know percent error. So that is equals to it is a three power that is three and this is the delta a divided by a into 100%.
Okay. So 100%. Okay. So this is one and the next one plus B. Power there it is two and that is delta B divided by B.
Okay. So into 100%.
Okay sir. So plus power C power that means it is a one and this is a delta C divided by C into 100%.
Okay. So that is plus C and D that is power is there. So it is 1x2. Okay. So that is 1x2 and this is delta d sir divided by d into 100%. Okay. Yes sir.
And substituting the values sir three in place of a what we have that is 1%.
Okay. So 1%. Suppus 2 b d it is a 3%.
Okay. So plus 1 into c c d it is a 2%.
Okay. And the last one that is 1 by 2 and d rest d to the set that is a 4%.
Okay. And next sir 3% plus 6% and plus 2% plus 2%. Okay so that is a plus 2%.
Yes sir% okay so that is 13%. Okay so that is the 13%. Okay so 13% that is option yeah option A is the right answer. Okay so option A is the right answer. Very good. Now let's move on to the next one. Okay students question the question is the sun rotates around its center identify center. Okay. So rotates around its center once in 27 days. What will be the period of revolution? If the sun we are expand to the twice. Okay. So to the twice. Okay. to the twice. It's a you know a present radius without any external influence. Assume the sun to be sphere of uniform density. Okay. Uniform density.
And next one.
Okay.
Okay. So what parameter is a constant? What parameter is a constant? Sir is a momentum. Okay.
So momentum moment of inertia that it is a 2 / 5 am I right? So 2 divided by 5 and next. Okay. So next con that is M R². Okay. Say M R². Okay. Yes sir. And let me cancel this is I1 and this is the I2. So that is 2 / 5 it is as it is because it is a uniform density. Okay. So R² it is twice. So that is 2 R². So I2 that is equals to added. So 4 * of 2 / 5 is M R². Okay.
Yes sir. So I2 that is equals to 4 * I1.
Okay sir. So moment of inertia E formula.
And the next one angular momentum. Okay.
So angular momentum. Okay. So angular momentum is a constant. Okay. So angular momentum is a constant. Okay. So angular momentum is a constant. Angular momentum. Sir L= M V into Right.
Yes sir. So it is L1 that is equals to L2 right body not a particle. Okay. So it is rigid body. Okay. So body I into it is I omega 1. So I2 so that is omega 2 and we know that. Okay. So we know that sir I1 that is equals to omega that is 2<unk>i / t1 and this is i2 into that is 2 pi divided by omega that is t2. Okay. So that is t2 fine. Yes sir. So 2 pi and 2 pi get cancel and i1 value. Okay. So i1 value is so i1 value. So i1 value relation.
Okay. So that is i1 value that is the four. Okay. So sorry this is i1 value.
So divided by T1 T1 value is there T1 value that is 27 days. Okay. So that is equals to I2 value is 4 * of I1. Okay.
So divided by T2 T2 I1 I1 get cancel T2 that is equals to 27 into 4. Okay. So TS2 that is equals to okay. Okay. So 108. So T2 that is equals to 108 days. Okay. 108 days. That is option B. Okay. So option B is the right answer.
Clear? Yes. That is option B is the right answer. Okay. So 108.
Right. So next one you question. The radius of the Martian orbit around the sun is about four times of radius of of the orbit of Mercury.
The Martian year is 687 earth days. Then which of the following is the length of one year on a mercury.
So comparison start. So comparison start that is radius of mercury. Okay.
Martian. So that is equals to 4* of radius of you know mercury. Mercury mercury. Okay.
Next one that is next one Martian year.
Okay. So Martian year. So that is Martian year as to 687 days. Compare.
Okay. 687 days. Then which of the following is a length of 1 year in a length of one year on a Mercury? Mercury that is t G H. Okay. Yes sir. And from law of time period. Okay. So gravitational law of time period. Okay.
So period of time it is a t² is directly proportional to the rq. Okay. Yes sir.
It is gh. Okay. So that is g hg div / t of that is m. So whole square. Okay. So that is square. So that is equals to r c rq. So it is r gh.
Okay. So r gh. Okay. So R GH divided by RM. Okay. So power three. Okay. Yes sir.
And T GH. Okay. So because Mercury time and Martian time per it is 6 687.
Okay. So all square that is equals to it is R G. So divided by RM value it is 4 R GH. Okay. So R HG. So power three. Okay.
It's a power three and hg RG get cancel.
So it is 1 / 4 power 3.
Okay. So 64 and T hg so divided by 687.
Okay.
So now so TGH that is equals to 8 687 divided by 8. Okay. So sir 687 divided by 8.
So that is 85 point. Okay. So that is 85.
Okay. So that is 85.87.
Okay. So 85.87.
So it is okay. So 85.87 nearest value of the so it is option C 88. Okay. So option C is the right answer. Okay. So option C is the right answer. Clear? So that is option C is the right answer.
Now let's move on to the next one. Okay.
So next one go. Yes. Next question. A wire of resistance. Okay. So wire of resistance. A wire of resistance R is a cut into eight equal pieces. From these pieces two equivalent resistance are made by adding four of these together in a parallel. Then these two are sets in a okay sets are added in a series. Then net effective resistance of the combination is okay.
So let's say this is one wire of length L. Okay. So of length L and area of a cross-section resistance of this length resistance of length this is equals to row L divid.
So that means resistance is directly proportional to the length. Correct. Now cut into eight equal places. Okay. Okay.
So now cut into eight equal pieces. Okay. So equal pieces.
Okay. So equal pieces. Yes sir.
L that is equals to L / 8. Therefore Rash it is R / 8. Okay. Right.
Each. Okay. So this is for each each length. Okay. So that is for each length from these pieces. Two equivalent resistance are made by adding four of these together in a par. Okay. So par four. Okay. So par combination par combination that is equals to r divided by it is r - p. So that is equals to r dash divided by n2 s2 made by the adding four together.
Okay. So that is a four. Okay.
R / 8 already 4 into 8 and okay so that is 32 right? Yes sir. and Okay.
Okay.
Okay.
The one resistor.
So one resistor.
So one resistor.
So one resistor. Okay. So this is R dash R dash R dash R dash R dash. Okay.
Yes sir. In a same way. So it is R dash and R dash and this is R dash and this is also R dash. Okay. So and what is the effective resistance?
Still it is you know it is you know par combination only identical resistance. So okay so RPA okay so this is total resistance okay so total resistance equivalent resistance so that is RP okay so that is so it is already combination RP okay so that is RP- divided by okay so RP- divided by okay so par combination okay so par combination Okay. So, yes sir.
Okay. Yes sir.
So okay. So 8 all are all all four connected you know 8 8 4 8 4 32 in the same way.
Okay so R / 32. Okay. So I divided by 32.
So first from these two pieces two equivalent resistance are made adding.
Okay. So by adding four of each together so then these two sets are added in a series. Okay. So sets in a series 4. Okay. So done done. Okay. Okay.
Okay.
Okay. So, so first.
Okay.
Okay.
Okay. Ether.
Okay. Right.
RX 82 it is R by 8 and two it is RX 8 and this is also R by 8. Okay. Yes sir. And two sets. Okay. So two sets.
Okay. So two sets R par. Okay. R par it is R by 8. Okay divided by N times. Okay. It is R number of register.
Okay.
Okay. Right sir series connect. Okay.
Yes sir.
So four.
Okay. Say to sir R 8. Okay. So R by 8.
So R by 8. So R by 8. Okay. Yes sir. So it is R by 8. And this is also RX 8. And this is also Rx by 8. Okay. So RX 8 and this is also RX 8. Correct. So RX 8 RX RX 8. Okay. Now 32 series combination.
So series combination.
So it is R / 32. So plus R / 32. S it is a 2 R / 32. and R series that is equals to R / 16. Okay, so R / 16. Okay, so R divided by 16 is the right answer. Okay, so R divided by 16 that is option A.
Okay, so option A is the right answer.
Very good. Now let's move on to the next one. Okay, so next question. Next question is a photon and an electron mass M have the same energy E. The ratio of that is wavelength of photon and wavelength of electron dy wavelength is where is the speed of light. Okay. And first photon concentration. Okay. So photon okay lambda right wavelength of photon that is equals to hid.
Okay. And electron electgength of electron that is equals to particle.
Particle it is hid.
Okay. Right sir. Ratio wavelength of photon divided by wavelength of electron. The wavelength of photon hid okay so that is into okay reciprocal okay so reciprocal to s it is h so underscore sir it is 2 * of m into e okay right so h get cancel okay so it is 2 * of m eid e² okay so e² so e and e get cancel okay so e and e get cancel. So lambda p / lambda e. So that is equals to c under root that is a 2 m divided by e.
So this is the required solution. Okay.
So this is the required solution. 2 m / e.
So option a. So option a is the right answer. Okay. So option a is the right answer. Very good. Now let's move on to the next one. Next question. An electron. Okay. So an electron mass in mass 9 into 10^ - 31 kg and a charge 1.6 into 10 - 19 kum moving with a speed that is C divided by 100 where is the speed of light is injected into the magnetic field B vector of a magnitude 9 into 10^ -4 Tesla perpendicular to its direction of the motion. We wish to apply an uniform electric field E together with a magnetic field so that the electron does not deflect. Electron does not defect.
Okay. So does not deflect. Okay. So deflect does not deflect from its path where combination.
So elect whences are equal forces are equal.
So E divided by B. Okay. So that is equals to V. Okay. So E value. Okay. So E that is equals to B value B value that is 9 into 10^ minus 4. Okay. So that is equals to C divided. Okay.
Sir it is C divided by 100 right? Yes sir. C divided by 100. C divided by 100 and rest it is 3 into 10^ 8 divided by 100. Okay sir. So E that is equals to 3 into 10 you know 6 into 9 into 10 - 4.
Okay. Yes sir. So E that is equals to into 10^ 2. Okay. So old meter. Okay. So meter volt per meter volt per meter okay so that is per meter so E not that is equals to 27 into 10^2 okay so that is E is a perpendicular to the magnitive field it's a magnitude is 27 into 10^ 2 old per meter that is option D okay so option D is the right answer okay so option D is the right answer option D is the right answer okay so option D is the right answer so Okay. So, animation ki andab and okay so top 20 and this is the top 30.
Fine. Okay. Now let's move on to the next one. So next question. Next question. The electric field in a plane electromagnetic wave is given by Ez that that is equals to 60 cos 5x + 1.5 into 10^ 90 per meter. Then expression for the corresponding magnetic field.
So EZ Okay. So EZ. Okay. So E.
So vector E cross B that is equals to C vector. Okay. Right.
Kap. Okay. So that is keyap. Okay. So E cross B. Okay. is E cross B that is equals to C vector and sir it is a JCAP the cross KCAP so that is equals to ICAP cory process okay so KCAP okay so I cap and this is a JCAP okay so this is JCAP but an electric field in a plain electrom wave is given by okay that is a 5x the particle is moving moving along x-axis. Okay. So particle is moving along x-axis. Okay.
So moving along xaxis xaxis. So you cannot write this one. Okay.
Iap that equals to kcap and j cross.
Okay. So that is equals to iap. Okay.
and kcap.
Okay. So, kcap i. So that is equals to jcap.
Okay. Soap.
So that means that yaxis.
Yes sir. So yaxis fine. So therefore eliminated. Okay.
And next sir, okay. So cos 5x. Okay. Cos 5x. Okay. So 1.5.
And we have to find out this you know B.
Okay. So B value B value that is E / C. Okay. Say E value 16. Okay. assigned a C value that is 3 into 10^ 8 it is 20 into 10^ - 8 okay so further simplification it is 2 into 10^ - 7 okay so 2 into 10^ - 7 2 into 10 - 7 so 2 into 10 - 7 yes so that is option C elimination method okay done okay okay now so that is option C is the right answer okay Option C is the right answer. Now let's move on to the next question. Next question.
A body weighs 48 Newton on a surface of earth. The gravitational force experienced by the body due to the earth at a height equal to 1/3 of a radius of the earth from its surface.
Weight of the body on the surface of earth. Okay. So weight of the body. So normal m. Okay. Right. So weight of the body on the surface of earth that means m g mass change. So what is the value?
So it is a 48. Okay. So that is 48 and the gravitational force experienced by the body due to the earth at a height equal to 1/3 of radius. So that means of radius. So r.
Okay. So now 500 when height is greater than 500 km we have a formula so that is gh that is equals to g s 1 divided by 1 + h / r all square and this is g sided by so 1 + h value it is r by so 3 r so all square okay yes sir and G S that is equals to R R get cancel 3² okay yes sir so this is 9 G S divided by 4 that is a 16 okay so 16 okay mg so that is equals to so 9 divided by 16 mg yes okay mghal s mg MG MGH value. Okay. So that is WH.
So that is 9 divided by 16 into W. Yes.
S. Okay. Yes sir. So height it is 9 / 16 and surface it is 48. Okay. Yes sir.
Okay. So 27 Newton. Okay. So that is 27 Newton. Right. 27 Newton. That is option D. Option D is the right answer. Okay.
So, option D is the right answer. Very good. Now, let's move on to the next one. Okay. So, next two question. An unpolarized light beam traveling in a air is incident on a medium of refractive index 1.73 at a bster angle.
Okay. That is refractive index and we know that ang light falls on a you know surface reflected completely and refracted partially polarized but what angle that is the brewster angle okay so that is aster angle so that is tan theta so that is equals to mu so that tan theta that is equals to mu value is to 1.73 say 1.73 root Yes sir. Therefore angle sir 60° 60° both reflected and transmitted light are perfectly polarized. No transmitted light is completely polarized. No reflected ray reflected light is completely polarized and angle of the reflection is close to the 60°. Okay.
Reflected uh reflected light is partially ill. So option C is the right answer. Okay. So option C is the right answer. Okay. So that is option C is the right answer. You got my point? Okay.
Now, now so that is option C is the right answer.
Okay. Now let's move on to the next one.
2 ampere. Okay. So that is 2 ampere current is a flowing through two different small circular copper coils having a radi ratio 1 is to2 the ratio of the respective magnetic moments will be magnetic moment number of direct so I directly proportional to the area. Okay.
So directly proportional to the area that is nothing but p<unk> r² right. So pi is also constant. So magnetic moment is directly proportional to the r².
Therefore m1 / m_sub_2. So that is equals to r1 / r2. So square. Okay. So ratio of radi. So that is 1 is to2 that is 1x2 square. So it is 1x4.
Okay. So that is 1x4. Okay. So that is 1x4. So that is 1x4. 1x4 that is option C. The ratio of the respective magnetic moments R. Okay. Right. So that is 1x4.
So option C is the right answer. Okay.
So option C is the right answer.
Right? So next one. Next two question delay.
Two ordinary satellites are revolving around the earth in a same elliptical orbit. Which of the following quantities is conserved?
satellite are revoling around the earth in a same velocity semi ais velocity cannot be same. So angular velocity. So angular velocity it is depends upon you know r that is you know distance from the semi-oraxis also depends upon velocity it is also changes and angular momentum as gravitational force central force. So central force is angular momentum is a constant. Okay so therefore angular momentum is a conant reason. Okay. So torque that is equals to DL divided by DT and is zero. So DL divided by DT and L is equals to constant the angular momentum. Okay. So that is option C. Okay. So that is option C is the right answer. Okay. So option C is the right answer.
Okay. Now let's move on to the next one.
Yes. No delay. Given below are two statements. One is labeled as assertion and other is labeled as a reason. R assertion. Okay. So assertion statement.
Assertion statement. The potential at any axial point at a 2 m distance from the center of the dipole of the dipole moment vector P of magnitude. Okay. So P of magnitude. Okay. So P of magnitude 4 into 10 - 6 K is plus or - 9 into 10 3.
Okay.
Reason reason it is v= to plus or minus 2p 4 pi epil r² where r is the distance of any axel point situated at 2 m from the center of the dipole in the light of the above statements is choose the correct answer from the option below is wrong statement. Okay. So reason wrong statement.
So reason is a false. Okay. So reason is a false. Okay. So reason is a false correct reason is a true eliminated and both are correct eliminated. And both reasons and are true eliminated. So remaining answer A is a true and B is a false. I mean reason is a false. Okay.
Okay. So pro potential due to dipole. So it is a KP divided by cos theta divided by r².
Okay. Yes sir. And this is a plus or minus k value is 2. So it is 9 into 10^ 9 and p value is to there p value that is 4 into 10^ - 6. Okay. So kp and divided by that is 2². Okay. So 2² cos 0 that is equals to 1. Okay. So that is= 180= that is a + 1 and theta= 180°us one plus or minus one okay right so either get cancel so 9 into 10^ 3 okay so 9 into 10^ 3 so old yes so therefore assertion is true but the reason is a false that is option B so option B is the right answer okay so option B is the right answer. Okay.
Now let's move on to the next question.
Okay. So next question. Next question.
The mass of the planet is 110th of that.
Okay. 110th that of the earth. It's a diameter is half of the earth. The acceleration due to gravity on the planet is okay. So the acceleration due to earth is given by it is gme so divided by radius of earth. Okay. So the value is 9.8 m/s squared. Am I right?
Yes sir. And Okay.
Mass of the planet. Okay. Acceleration due to gravity of the planet. That is MP divided by RP. Okay. MP divided by RP.
So that is G mass of the planet s of mass of the earth. Okay sir. So divided by RP that is diameter of radius. Okay. So radius of planet is also off. Okay sir. So it is a GP that is equals to it is G M E all divided by 10. Okay. So 10 right. So that is R E. So divided by 2.
Okay. So R that is R square. Sorry this is R². Okay. So this is R². the R square that is the four. Okay. Right sir. So 4 / 10 that is G E.
So 4 into 9.8.
So divided by 10. Okay. So precise values 3.92 GP that is equals to 3 98.
Okay. So 92. Okay. So 92. So m/s square.
Okay. So that is GP value. Okay. is a three point fine so 3.92 3.92 that is option C is the right answer till I concentrate my delay so option C is the right answer very good now let's move on to the next question yes next question at any instant of a time t the displacement of any particle is given by 2t minus 1 unit under the influence of a force of 5 Newton. The value of the value of instantaneous power. Okay. So first of all instantaneous power formula sir it is a DW divided by Okay. So that is a DW divided by DT. Okay sir. So W it is a force into disment right? Force into disment force. Okay. So forces pass it is a pi displacement displacement that is a 2t minus one. So work done that is equals to that is a 10 t minus one. Okay. So 10 t that is - 5. Okay. So now differentiate with respect to time it is a 10 into 1 that is equals to 0 that means that is 10 10 units. Okay. 10 units. Okay. So right answer that is 10 units. So that is option D. Okay. So option D is the right answer.
Next one. Next one. The question is a particle moving with a uniform speed in a circular path. Circular path.
Okay. So that is the particle moving in a circular path. Constant acceleration.
No variable because the direction keep on changes. Constant velocity. Wrong.
Keep on changes. It's a direction. Next one. Varying velocity and varying acceleration. That is true.
So that is option C. Okay. So that is option C is the right answer. This is also wrong. Get a point. Okay. So that is option C is the right answer. Okay.
So option C is the right answer. Next question.
Yes.
The question is match list one with the list two. Choose the correct answer from the options given below. So diamagnet it is a diiamagnet parag and ferroagnet.
Okay. So magnetic susceptibility negative negative magnet is negative and small. Okay. So negative and small a is matching with two. Next one feromagnet magnet suscept it is much much much more than one. So that is three is matching and camagnet.
Okay. So paramagnet the value is small. Okay. So small.
Okay. So where is small and that is a four and non-magnet that is suscept susceptibility that is zero. Okay. So zero that is one. So 2 3 4 1. Okay. So 2 3 4 1 2 and two in the start you can eliminate. So two in the start three one in the start four and one. Therefore it is option D.
Okay. So option D is the right answer.
Okay. So option D is the right answer.
Okay. So option D is the right answer.
Now let's move on to the next one. In an ideal transformer the turns ratio is NP divided by NS. Okay. So that is equals to 1x2. The ratio of VS divided VS is to VP that is the voltage across secondary call across primary call is equal to. So ideal transformer okay transformer sir it is the V S divided by VP. So that is equals to NS / NP. Okay. So NS value it is a two corresponding val. Okay. So that is two divided by 1. Okay. So 2 is to one. Okay. So that is a 2 is to one.
That is option A. So option A is the right answer. Okay. So option A is the right answer. Okay. So that is option A is the right answer. Okay. So S answer option A is the right answer.
Okay. Now let's move on to the next question. Next question.
Next question. A tightly wound 100 turns coil of a radius radius 10 cm carries a current of 7 ampere. The magnitude of the magnetic field at the center of the coil is okay. So magnetic field due to circular coil. So it is given by mu not n i divided by 2 * of r. Okay. Yes sir. The b that is equals to mu not value is 2. So it is a 4 pi into 10^ - 7 into n value it is 100 and current that is 7 to divided by 2 into r r value that is 10 so 10 cm right so yes sir so 10 cm that is 10^us 2 okay so simplification okay so simplification that is so 3.9 okay so 3.96 into 10^us 3 tesla Okay. Okay. So, four four. Okay. So, four.
Okay. So, cancel.
So, 223 and that is you know almost 4.4. Okay. So, that is 4 96. Okay. So, 4.96 into 10^ 3 Tesla. So, that is equals to sir it is a 4.4 milll. Okay. So, 4.4 four mele Tesla okay so 4.4 and four. Okay. So that is the option B.
So it is a 4 into 3.14. Okay. So into 100 into 7. Okay. Right sir. So divided by 2 divided by 10 439. Okay. So 4.39. Okay. So 4.39. Okay.
Set is a 4.39.
Finally - okay so 10 - 5 that is true 10^ minus okay so that is option B is the right answer right so next question next question in the following circuit the equivalent capacitor between terminal A and B So direct.
Okay.
Answer two 2 microfarad. If you want me to solve either ratio either ratio same 1 microfarad 1 microfarad therefore you remove this and what is the value of this one is it it is a series combination series combination.
So you can consider C1 into C2 divided by C1 + C2 for CID.
Okay. So 2 / 2. So that is equals to 1 microfarad. Okay.
Now they are in a combination.
Okay. So 1 microfarad and this is also 1 microfarad. Okay. So this one and this one C equivalent. So par combination 1 + 1 that is equals to 2 microfarad.
So instead of solving all these you know steps individual values equal. Okay. So individual values equal. So therefore option D answer.
Now let's move on to the next question.
Yes.
The question in the in the above diagram under a strong bar magnet is moving towards the solenoid 2 from solenoid one. This is solenoid one. This is solenate 2. The direction of induced current in a solenoid one and the solenoid 2 respectively or through the direction as bar magnet is moving. Okay. So bar magnet is moving away. So deflection towards right hand side.
Okay. So deflection towards right hand side using lens law. Okay.
It is always opposed.
Okay.
Okay. So that is A to B. Okay. So A to B. Okay. Say A to B because it acts as a south pole as it is moving clockwise.
Sir it is if it is south pole it is also south pole. South Pole clockwise. So clockwise. Okay. So clockwise therefore D2 C. Okay. So D2 C. Okay. So D2 C. So A to B. A to B. A to B. A to B and D to C.
Okay. So A to B and D to C. That is option D. So option D is the right answer. Okay. So option D is the right answer. Very good. Now let's move on to the next one. So next question. Next question is the maximum elongation.
Okay. that is the maximum elongation of a steel wire of 1 m. So length if the elastic limit of a steel and its modus respectively are 8 into 10^ 8 Newton per me square and 2 into 10 11 m square stress is nothing but elastic limit that is 8 into 10^ 8. So modulus modulus that is the 2 into 10^ 11 it is 4 into 10^ minus 3. Okay. So 4 into 10us 3 and so strain that is equals to change in length divided by length change in length nothing but elongation elongation.
So that is epsilon into epsilon value.
It is 4 into 10^us 3 into 1 m. Okay.
Direct delta that is equals to 4 mm.
Okay. So 4 mm. Okay. So that is a 4 mm.
Option D. Okay. So option D is the right answer. Okay. So option D is the right answer.
Option D is the right answer. Okay. Now let's move on to the next question.
Okay. So the question is a wheel of bullock cart is the rolling on a level road as shown in the figure below. If the if it's a linear velocity linear speed is the V in a direction shown which one of the following option is correct P and Q are the any highest point. Okay so highest point ground lowest point highest and lowest point on the wheel respectively. Third speedomet and radius of okay so this is r so total distance r velocity of p. Okay so first that is omega into r that is zero sir. So velocity at a Q that is equals to zero sir and velocity at you know Omega into R. Okay now so that is nothing but V. Okay. Yes sir. Omega V at a point omega into that is R into R that is 2 R.
Okay. So that is 2 R. So 2 * of omega into R. Okay. So VP that is equals to 2 * of V.
Okay. So VP that is equals to 2 V. Okay.
So that is the both points wrong. Point P move faster. Okay. So point P move faster than point Q. Yes. This is valid reason. The both the points P equal.
Okay. So both the points P and Q move with the equal speed. Wrong. Point P has a zero speed. No point O that is center one has a speed zero. The point move point P moves slower than Q. E wrong.
Okay. So right answer. So that is option A. Okay. So that is option A is the right answer. Okay. So option A is the right answer. Okay. Now let's move on to the next question. Okay. So next question. Next question. An unpolarized light beam strikes the glass surface at a brster angle. Then already reflected light and transmitted light partially.
So the refra refracted ray will be completely polarized. No, both reflected and refracted light will be completely polarized. No, the reflected light will be completely polarized but refracted light will be partially polarized. Yes, that is right answer.
Okay, so that is option C. Okay, so that is option C is the right answer. Okay, right sir. Next one. So next question.
In a verier calipers n + one division of a scale coincide with n divisions of main scale. If one msd represents 0.1 mm. Okay. So 0.1 mm the verier constant is okay. So first thing number of warer scale division. Okay. So verier scale division that is equals to coincident division of msd. Okay. So msd right? Yes sir. main scale division.
Okay. Now, so 1 MSD that is equals to Okay. So 1 MSD about 1 V SD. So that is equals to N / that is N + 1 MSD. Okay sir. Fine conant. Okay. So one conant that is equals to 1 MSD so minus 1 VSD. Okay. So that is 1 V SD 1 MSD. So that is equals to 1 BSD value is set as N + 1 into MSD. Okay. So MSD conant. So 1 MSD conant. So 1 - N / N + 1. Okay. So 1 MSD the bracket of N + 1 - NID + 1. Okay. Yes sir. + 1 - n plus n and minus n get cancel one constant that is equals okay so one constant that is equals to so is 1 msd that is equals to into third is 1 divid n + 1 okay so n + 1 right so n + one okay so that is n + one and what is the value of one msd value s 1 md value that is equals to 0.1 into 10 power minus - 3 m. Okay. So divided by 1 n + 1. Okay. Right. Yes. So 1 cal I mean that is equals to 10 cm. So 0.01 into 10^ minus 2. Okay. M. So that is n + 1. Okay. And 0.01 it is 1us.
Yes sir.
So divided by n + one. Okay. Right. So that is equals to it is 100 n + 1. Okay. So cm. Okay. So one constant. So that is 1 divided by okay 100.
Okay.
So that is option A is the right answer.
Okay. So option A is the right answer.
Next question. Next question.
com.
Okay.
Okay.
Fine.
Next one. A bob is weird in a horizontal plane by means of a string with initial speed of omega rpm that is rotation per minute.
The tension in the string if the speed becomes a 2 omega while keeping the same radius the tension in the string a okay so first of all tension in the string is nothing but it is a type of force mv² / r mv / r into that is omega square and r² okay so yes r get cancel so tension that is equals to m omega square r okay sir mass is constant and r is also okay by keeping the same radius.
So therefore t is directly proportional to omega square right? Yes sir.
T1. Okay. So T1 directly proportional to omega. Okay. Yes sir. Omega square and T2. So that is directly proportional to Okay. So directly proportional to omega -ash². Okay. So omega -ash it is 2 * by means that tension in the string is a t.
If the speed becomes a 2 * of omega.
Okay. So that is 2 * of omega. So it is t2 that is directly proportional to that is 2 omega square. Okay. So that is nothing but s is 4 omega square. Okay.
Right sir ratio. Okay. So t2 divided by t1. Okay. So that is equals to 4 omega square omega square. So t2 that is equals to okay. So t1 t1 t. Okay. So 4 t. Okay. Omega square omega square get cancel. Okay. So 4t. So that is option A.
Clear.
Right. So that is option A. Option A is the right answer. Okay. Right. So let's move on to the next question. Yes.
Hello. The thermodynamic system is taken through the cycle A B C D E A. The work done by the gas along the path BC. Okay.
So path BC.
Okay. BC volume.
So work done that is nothing but P into DV. Okay. Change in volume that is zero.
So therefore work done is equals to Z.
Okay. So work done that is equals to Z.
Okay. So that is work done that is equals to zero. Option D. Okay. So option D is the right answer. Okay. So option D is the right answer.
Answer ma. Next question.
So next question.
The output of the given logic gate is similar to the output of. Okay. So this is a bar and this is b bar and this is a bar plus b bar all bar. So y that is equals to dot it is double bar and double complement. So that is a so it is and okay so and gate. So that is option c and gate right double complement and gate. Okay. So and gate that is option C.
Next one.
Yes, two bodies A and B of the same mass under goes completely inelastic collision. Okay, so inelastic collision.
Okay, the body A moves with a velocity U V1 and while body B is at rest before the collision. Okay, so that means it is a U1 value. Okay, so this is U1 value and this is the U2 value. The velocity of the system after the collision is a V2. The ratio of V_sub_1 is to V2 is under. Okay. First of all, the inelastic collision final velocity that is m1 u1 plus m_sub_2 u2 the all divided by m_sub_1 + m2. Okay. Yes sir. So v that is equals final velocity the velocity of the system after the collision v2 and m and initial velocity is 2 it is v1 and m and it is rest okay divided by m1 + m2 it is m that is m okay v1 so divided by 2 m okay okay so m get cancel. So it is m1 divided by 2 and v_sub_1 is to v_sub_2 right? Yes sir.
V_sub1 is to v2 2 divided by 1 that is 2 is to 1. So 2 is to 1 that is option a.
Okay. So option a is the right answer.
Okay. So option a is the right answer.
So option a is the right answer. Next question. Next question.
A horizontal force 10 newton is applied to a block e. Okay, as shown in the figure, the mass of the block A and B 2 kg and 3 kg respectively. Okay, so 3 kg.
Okay, so 3 kg respectively. The blocks slide over a frictionless surface. The force exerted on a exerted by block A and a block B. Okay, so block force exert. Okay, forceal reaction. Okay. So normal reactional reaction first.
So total force divided by total mass.
Total force that is 10. And total mass that is 2 + 3 that is equals to 10 divided by 5. So acceleration that is equals to 2. So that is a m/s squared.
Okay. So that is a m/s squared. Okay. So 2 m/s square.
So that is mass pushed. Okay. So that is a mass pushed. Okay. So mass is pushed.
Okay. So mass is pushed. So into acceleration. Okay. So n that is equals to. Okay. So block a mass that is a 3 kg. Okay. So that is 3 kg acceleration is to 2. So normal reaction that is equals to 6 newton. Okay. So 6 newton.
Okay. So normal reaction is to 6 Newton.
That is option B. Okay. So option B is the right answer.
Clear?
Okay. Exam revision last minute revision. Okay. So I I don't have any idea regarding chemistry. Okay. Right.
So that is option B is the right answer.
Okay. So option B is the right answer.
Next one. So next one. Yes. Next one.
That is if x equ= to 5 sin of pi t +<unk> by 3 m represent the motion of a particle executing simple harmonic motion. The amplitude and time period of the motion respectively. This is in terms of x = to a sin of omega t + 5. Correct? Yes sir. Amplitude already s 5 m.
So 5 m cm. Okay.
Omega divided by 2 omega value it is a pi. Okay. So that is 2 pi / omega and 2 pi that is equals to omega val it is a pi. Pi pi get cancel. So t is equals to 2 seconds. Okay. So t is equals to 2 second.
Option a. Okay. is a 5 m and 2 m that is option A is the right answer. Okay. So option A is the right answer. Very good.
Now let's move on to the next one. Okay.
So next question ready. Next question.
In the given circuit the peak voltage across CL and R that is capacitor, inductor and resistant resistor are 30 volt, 110 volt and 60 volt respectively.
The RMS value of applied voltages. Okay.
So applied voltage. Okay.
Okay.
Sir peak volage first peak voltage find okay so V that is equals to sir V R² so plus V L minus VC all² okay yes sir and next okay so next to V so that is equals to under square root okay so V R S it is a 60 and V L there so it is 110 and C there it is 30 okay so yes so we not that is equals to it is 3600 plus it is 80 okay so 6400 it is the 10,000 okay so 10 okay 100 so 36 and 100 and it is 100 okay so 100 we are a mess okay so we are a mess so that is V / <unk>2 0.707 into 100 volt. Okay. So we are a mess.
So that is equals to 70.7. Okay. So 70.7 volt.
Option C.
Okay. So option C is the right answer.
Okay. So option C is the right answer.
Next question. Next question.
Yes.
A thin spherical shell is charged by some source. The potential difference between the two point points C and P.
Okay. So this is C and P shown. Okay. So potential difference that is work done. Okay. So work done.
Okay.
Right. Yes sir.
potential potential difference.
So potential difference and so delta V that is equals to KQ. Okay. So divided by R. Okay.
So potential gradient potential potential constant. So therefore delta V that is zero. Okay. So potential difference that is equals to Z. Okay. So that is potential difference between two points that is zero. Option C. Okay. So option C is the right answer. Okay. So option C is the right answer.
Right. So next question. Yes. Answer.
The question is if C is the velocity of a light in a free space, the correct statements about a photon among the following are. So these are the properties of a photons. Okay. So first one energy of the photon that is H E is equals to H new. The velocity of photon that is a C. That is also right.
Momentum photon this is also correct. H new divided by C. Okay. And next one in photon electron collision. Okay. Okay.
So that is HC divided by lambda. Once again E is equals to HSC divided by lambda.
Okay. Right sir. So E that is equals to sub PC. Okay. So that is a PC. Okay. So PC. So P is equals to E / C C and H new divided by C. Yes, this is correct. And the next one in electron photon electron collision both electrical total energy and total momentum are conserved. Yes.
And photon possess a positive charge is wrong. Electrically neutral. Okay. So therefore a b c correct e wrong. Okay.
So a b c d only. Okay. So a b c d only.
So okay. So e wrong ether wrong. Ether wrong. So right answer that is option a.
Okay. Right. Right. So now let's move on to the next one. Yes. Next question.
Option A.
Next question. Next question.
Given below are two statements.
Statement one, atoms are electrically neutral as they contain equal number of positive and negative charge. Yes, this is statement right. And the second statement, atoms of each element are stable. Okay. So stable and emits their characteristic spectrum.
Wrong. unstable atoms. So unstable atoms.
Okay. So stable atoms. So they do not you know emit the character their characteristic spectrum. Okay. So therefore so statement one is correct.
Okay. Statement one is correct but statement two is wrong. Statement one is correct and statement two is incorrect.
Okay. So that is option B.
Next one.
Terminal voltage. Okay. the terminal voltage short break.
So 15 minutes Audio, welcome, welcome, welcome, welcome. Okay, so let's get started.
The question is the terminal voltage of a battery whose emf is a 10 volt and internal resistance 1 ohm when connected through external resistance of 4 ohm as shown in the figure. Now find terminal voltage. Okay. So terminal voltage what is the formula I into R? Yes sir. I so therefore we have to find out I first.
Okay.
So R + R E value is to this it is a 10 and external resistor is to this it is a 4 + 1. Okay. So that is a 2 amp and s it is 2 into so that is a four it is a 8 vol.
Okay so that is 8 volt. Fine. So that is option B.
Next question.
So next question.
If the monochromatic source in double expment is replaced by white light then instead of a single color.
Okay. So there will be a central dark fringe ala and will be a central bright white fringes surrounded by few colored fringes. Okay. So that is so that is option sub. So that is option B is the right answer. Okay. So option B is the right answer. Very good. Now let's move on to the next one. The question is a logic circuit provides the output Y as per the following to the table. The expression for the output y is simple.
So first y= 1.
So first= so therefore it is not right. and B 0 1 0 1 0. Yes, this is right answer. Okay, simple already and so 0 0 0 1 0 1. So therefore it is also wrong. So right answer that is option B bar. Okay. Right. Very good. So that is option B.
Now let's move on to the next one. Next question. The quantity which have the same dimensions as those of solid angle.
Solid angle dimensions. So dimension solid angle it is the dimensionless.
Okay. So solid angle plane angle these are you know dimensionless quantities dimensions but dimensions. Okay. So stress dimensions.
Therefore it is not a dimensionless quantity. It is a dimensional quantity.
So not possible strain angle. Yes, that is possible.
So both are dimensionless. Okay. Now clear. So that is option D.
Option D is the right answer. Okay. So option D is the right answer. Next one.
So next question. the graph which shows the variation of 1 divided by lambda square and it's a kinetic energy E where lambda is the D brogly wavelength of a free particle. Okay. So free particle so D broadly wavelength H divided by under square root 2 M. Okay. So that is 2 M E. Okay. So squaring on both side.
Okay. H / H² / 2 M E H² M so constant so that is inversely proportional to E. So directly proportional 1 / lambda square is directly proportional to straight line. Okay. So straight line straight line that is option D lambda square e that is 1 lambda square relation that is a straight line because it is directly proportional 1 divided by lambda directly proportional to directly proportional that is option D okay now let's move on to the next question next question you know the magnetic flux linked with the coil varies as a flux that is equals to 3t² + 4t + 9 the magnit EMF induced that is T is equals to Z.
So EMF that is equals to D5 / DT so that is equals it is 60 it is a + 4 and at T is equals to okay at T is equals to 2 seconds so E is equals to 12 + 4 E= to 16.
Okay so 16 that is option B. Okay. So option B is the right answer.
Okay. So this is 6 + 4 into that 6. So plus 4 that is 16.
Okay. So that is option B is the right answer. Okay. So option B is the right answer. Okay. Now let's move on to the next one. Next question. Which of the following is the correct regarding electric charge?
Electric charge regarding.
Okay. So first one if a body having positive charge that is shortage of electron that is right statement. And second one if a body having negative charge that is excess of electron that is also right statement. The minimum charge a body can have that is plus or - 1.6 into 10^ - 19 kum. Yeah that is also right. So therefore option D that is all of the above. Okay. So all of the above right. So that is D is the right answer.
Okay. So option D is the right answer.
You got my point? Okay. Now let's move on to the next question.
A small telescope has a objective focal length 140 cm and eyepiece of a focal length 5 cm. The magnifying power of a telescope telescope. Okay. So telescope the magnifying power. So focal length of objective lens and a focal length of five lens is to 140 / 5.
Okay. So 28.
Okay. So 28 that is option A. Okay. Now so option A is the right answer.
So option A is the right answer. Option D that is wrong. And the next one hello two heaters A and B have a power rating 1 kilowatt and 2 kilowatt respectively. Those two are first connected in series then par to fix the power source. The ratio of power output for those two cases. First series.
So series I sir it is a P1 + P2 so that is equals to 1 + okay so 1 + 2 that is equals to 3 okay so that is three and the next one par so it is a P1 into P2 so divided by P1 + P2 s 1 into 2 that is 1 + 2 so that is equals to 2x3 okay yes sir the ratio of power output of these PS S. Okay. So that is a PS. Okay. So sorry P. So this is the par combination and this is series combination. Okay. So PS divided by P power. So that is nothing but PS is 2. So it is the 2x3.
So power that is three. Yes. 2x 9. Okay.
So 2x 9.
Okay. So 2 is to 9. Okay. So that is the 2 is to 9. Right. So that is option A.
Okay. So option A is the right answer.
Very good. Now let's move on to the next question.
For a uh a force defined by F is equals to alpha t² plus bt plus beta t acts on a particle at a given time t. The factor which dimensionless okay the factor which is dimensionless. If alpha and beta are constant simple homogenity equation homogenity principle that is alpha t² and alpha that is f / t². Okay sir. Next one sir it is f that is equals to beta t and t that is equals to f / okay. So beta so beta that is equals to f divided by t. Okay. Yes sir. So alpha that is equals to beta. So divided by t. Okay.
Yes. So dantity alsity or multip beta divided by alpha t that is equals to 1.
Okay. So both are correct answers. Okay.
Options first. Okay. The first one alpha tid beta that is equals to 1 and beta divided by so beta. Yeah, that is alpha t divided by beta that is equals to 1.
Okay, that is option A.
Option A is the right answer. Very good.
Next question. Next question.
10 microfarad capacitor is connected to a two 210 volt and 50 Hz source as shown in the figure. The peak current in the circuit is nearly peak current. Okay. So first RMS current. Okay. RMS. So I RMS.
Okay. I RMS that is equals to sir V / that is X C so V divided by sir so it is a 2 pi FC into V okay so I RMS so that is equals to so 2 pi into 50 into 10 okay into 10^ - 6 into V that is 210 okay so IMS okay so IMS IMS MS sir it is uh so 2 into 3.14 into 50 into 10 okay into 10 into 210 so that is uh 6 5 9 okay so 6 5 9 400 okay into 10 power - 6 okay so that means it is 6.59 ampere But I okay so I not so therefore that is <unk>2 into IMS okay so so divided by 1 2 3 4 5 6 so that is 6.59 divided by into so that is 1.414 414. It's like the 9.31. Okay. So 9.31 ampere. Okay. So 9.31 ampere. So 9.31. Okay. So that is 0.
Okay. Okay. Okay. Okay.
So that is 0.6594.
Okay. 0.931.
Okay. So that is 0.93. Okay. That is 0.93. That is option A. So option A is the right answer. So option A is the right answer. Very good. Now let's move on to the next one. Next question.
The property the property of property which is not. Okay. So the property which is not of electromagnetic wave traveling in a free space. Okay.
The energy density in electric field is equal to the energy density in a magnetic field. That is correct property. They travel with a speed is equivalent to C. Okay. So that is also right statement. They originate from a charges moving with a uniform speed.
Okay. So uniform speed in they transverse in nature. Yes, that is true.
Originate. Okay. They originate from a charges moving with variable speed.
Okay.
Okay. So that is option C.
Option C is the right answer. Okay. So next next question.
A parall plate capacitor is charged by connecting it to a battery through the resistor. If I is the current in the circuit then gap between the plates is then the gap between the plates.
Displacement current and displacement current conduction current both are in a same direction and magnet wise both are equal. Okay.
The displacement current of a magnet is equal to the current flow in the same direction as I and displacement of the current magnet equal to the flow of current in a direction opposite. No, the displacement current of a magnet is greater. So there is no current at all.
Wrong. Okay. So right answer.
So that is option A. Okay. So that is option A is the right answer. Okay. So option A is the right answer. Now let's move on to the next one.
So the error in the measurement which arise due to unpredictable fluctuation unpredictable and random. Okay. So that is a random one that's that is random errors. Okay. So that is option C.
Okay. Now let's move on to the next one.
So a metal wire has a mass 0.4 plus or - 0.002 g radius 0.3 plus or - 0.001 mm and length 5 plus or - 0.02 02 cm the maximum possible percentage error in the measurement of density will be okay. So density normal s density that is given by so mass per unit one so mass as it is and pi r² l because it is a wire okay yes sir density percent so that is equals to so density of a mass divided by mass into 100%.
Okay.
So it is delta R / R into 100%. Okay sir.
Therefore keep it as it is. So L into 100%. Okay. Yes sir. And compare delta M it is 0.4 divided by 0.00.2.
Okay. into 100%.
Okay. Yes sir. So plus 2 into is R. So that is delta R 0.001 that is divided by 0.3. Okay. So into 100%.
Okay. So plus delta L that is 0.02 divided by 5 into 100%.
Okay. Yes sir. So simplification sir it is 0.4 0.4 4 divided by 0.02 into 0.4. Okay. So divided by 0.002.
So 200. Okay. So 200%. Okay. Already percent right. Oh.
Okay. So that is 0.00.2 divided by 0.4.
So 0.00.2.
So divided by 0.4 into 100.5.
Okay. So that is 0.5 check. Yes sir. 02 divided by 0 4. Okay. 0.4.
Okay. Say into 100 to 0.5 percentage plus it is 0.001 divided by 0.3.
Okay. Say into okay say into 100 okay say into 100 into two 0.67 okay so 0.67%.
Plus so it is 0.02 divided by 5 into 100. So that is 0.4.
Okay. So that is 0.4%. Okay. So overall so plus 0.67 67 plus that is 0.5. So that is 0 1.57 percentage and round off mid 0 1.6 percentage. Okay. So that is 1.6 percentage. 1.6 option B. Okay. So option B is the right answer. Okay. So option B is the right answer.
Let's move on to the next one. The net magnetic flux. Okay. So net magnetic flux through any closed surface is zero.
Okay. So that is zero only according to you know goss law of electromagnetism.
Okay. So law of magnetism z inward flux that is equals to outward flux that is equals to zero. Okay. That is option B. Option option D.
Now let's move on to the next one. Okay.
So next question. Yes. Hello.
The question is in a series LCR circuit the inductance L is equals to 10 mhry and capacitor is equals to 1 microfarad and resistance R is equals to 100 ohm. The frequency at which resonance occurs. Okay.
It is F that is equals to 1 / 2 pi into LC. So 1 divided by 2 pi under L L there it is 10 into mill that is 10us 3. Okay.
So into L that is equals to 1 into 10^ - 6. Okay. So frequency that is equals to 1 / 2 pi into 10^ 8 10 - 4. Okay. So 10^ - 4 and 1 / okay. So 1 / 6.28.
Okay. 0.1592.
Okay. So 1592 into 10^ 4. Okay. So final it is 1.592 kilo. Okay.
Okay. So 1.592. Okay. So 1.592 1.592 1.592 kohz. Okay. So that is option C.
Okay. Right. Yes sir. So that is option C. Option C is the right answer. Okay.
So option C is the right answer. Answer wrong. Next question.
Next question. An iron rod of a length L and the magnetic moment M is a bent in the form of semicircle. Now it's a magnetic moment is okay. So resultant magnetic moment that is equals to sir it is a 2m divided by theta and sin of theta by 2. Okay. Yes sir. So m ddash that is equals to 2 m. Okay. So what about theta that is semicircle ala? So semicircle that is a pi and sine that is a<unk> by2. Okay. So that is<unk> by 2.
So it is 1. So 2 m /<unk> okay. So 2 m / pi. Okay. So 2 m divided by pi. That is option B. Okay. So option B is the right answer. Option B is the right answer.
Now let's move on to the next one. So next next yes direct answer though.
Magnetic intensity for axial point due to a short bar magnet of the magnetic moment M is given by magnetic intensity on a pointial point electric E that is equals to 2 KP R that is equals to 2 * of M okay and M B / that is R T. Okay. So that is a DQ.
Okay. So M okay.
Okay. So D² D square.
So right answer for this question that is option C 2 1 2. Okay. So cancel that is option C is the right answer. Okay first D cancel that is DQ D square R is okay now that is option C is the right answer. Okay. So option C is the right answer. Now let's move on to the next one. Okay. So next question. A uniform string of a length L and mass M is a fixed at both ends under the tension T.
then can vibrate with the frequency given by the formula. So what is the formula? So fundamental frequency as normal fn= to n / 2.
So let's consider n= to 1. So f that is equals to s v / 2. Okay. So where v is equals to 1 divid 2 l and this is the tension per unit mass. Okay. So per unit mass and further simplification that is 2 L².
So T and then mass per unit length.
Okay. So mass per unit length. Okay. And so F that is equals to 1 / 2 and TL / M L². Okay. So L l get cancel. So that is 1 / 2. So that is T / M. Okay. So T / M.
Okay. So T / M. M into L. Okay. So so this is the required solution that is F that is equals to 1x2 1x2 L value there.
So T divided by ML that is option A.
Okay. So that is option A. Okay. So that is option A is the right answer.
Okay. So option A is the right answer.
Okay. Right. Yes sir. So option A is the right answer.
Now let's move on to the next question.
Okay. So next question. The work done by an ideal gas along cyclic path L M N O.
Okay. So L M M N O L. So work done the area enclosed by the loop. Okay. So area enclosed by the loop. Okay. So that is W. So cyclic process. Yes sir. Cyclic process this is positive area under that. So it is length into breadth.
Okay. So that is a V and breadth that is also P. Okay. So therefore it is a PV.
Okay. So that is a PV. So PV that is the right answer. That is option A. Okay. So option A is the right answer. Okay. So option A is the right answer. Option A is the right answer. Okay. Now let's move on to the next question. Next question. Water flowing through a non-uniform radius tube of if ratio of the radius of entry and exit are 3 is to2 then the ratio of velocities of entering and exit will be okay. So velocity and we know that the relation between radius diameter sir v_sub_1 divided by v_sub_2. Okay. So v_sub_1 divided by v_sub_2. So that is equals to r2 / r1 the whole square.
Okay. Yes sir. Ration sir it is 2x3. Yeah it is R1 R1 is to R2. Okay. So this is R1 R2. Now R2 is to R1. Okay. R2 is the 2 / 3 all square. Okay. So this is a 4 / 9. Okay.
So that is a 4 / 9. Okay. So that is a 4 / 9. Okay. So 4 / 9. Okay. Done. Okay.
Now so option A is the right answer.
Very good. Now let's move on to the next question. Okay. So next question.
Anyway, the access of pressure. Okay.
The excess pressure inside the liquid bubble. Okay. Soap bubble. Liquid bubble. Okay.
Right. So that is a liquid bubble not soap bubble. Liquid bubble that is excess pressure 2t / r soap bubble 40id r. Okay. Now so that is option a. Option a. Very good. Now let's move on to the next one. Okay. So next question. Next question. Gravitational force between two masses at a distance d apart is a 6 Newton. Okay, if these masses are taken to the moon and kept at the same separation condition, same separation, then the force between them will become F= to G. M1 M2 divided by D² R² masses are same. G is a constant. Universal gravitational constant G is constant. M1 M2 also constant, D is also constant.
Therefore force remains same to 6 Newton. So that is option D. Okay. is option D.
Next question. Next question. A body of a mass is 60 g experience a gravitational force of 3 Newton when placed at a particular point. The magnitude of the gravitational field intensity at that point. Okay. So gravitational field intensity gravitational field intensity. So gravitational field intensity that is equals to force per unit mass. Okay. So force three and mass 60 g. Okay. So 60 g 10^ - 3 it is 3 into 10^ 3. Okay. So divided by 60 it is 3,000. Okay. So that is 3,000 divided by 60. So 10 get cancel.
So that is a 50. Okay. So 50 is the right answer. Okay. So 50 50 Newton per k. Okay. So that is a 50 newton per k.
That is option B.
Next question.
Yes. A body is a word in a horizontal circle of radius 20 cm. It has an angular velocity of 10 radians/s. What is its linear velocity at any point in its circular path? So relation between angular velocity and linear velocity that is omega into r. Okay. So omega to there it is a 10 and r that is 20. So therefore it is h 10 cm. So 20 cm. Okay.
So it is 2 m/s. Okay. 2 m/s.
Okay. So that is 2 m/s. Okay. So that is 2 m/s. That is option D. 2 m/s. Option D is the right answer. Okay.
Option D is the right answer.
Next one.
Two objects of a mass 10 kg and 20 kg respectively are connected to a two ends of the rigid rod of a length 10 m with a negligible mass. the distance of the center of a mass of the system from the 20 kg of mass. Okay. So 20 x2. Okay. So x2 value.
Okay. So x2 that is equals to m1id m1 + m2. Okay. So m1 + m2 divided by total distance d. Okay. So x2 that is equals to m1 value. Sir it is a 10 and this is 10 + 20 in total distance is there sir distance that is the 10 m okay so x2 that is equals to okay so that is 10 so divided by 30 into 10 okay yes sir so 1 0 1 0 get cancel that is the 10 divided by 3 so mters okay so 10 divided by 3 m okay so that is option A is the right answer okay so option A is the right answer Mt right. Now let's move on to the next one. Next question. The shell explodes and many pieces fly off in a different direction. Which of the following conserved? Okay. Explodes under internal force not external force. Okay. So that is internal force. Internal force explode there is no external force that means external force is zero. Relation between F and DPT F is that is the momentum is a constant.
Okay. So momentum is a conserved that is option B. Okay. So that is option B.
So next question.
A force 10 newton displaces an object by 10 m. If the work done is a 50 jou then the direction of a force makes an angle with the displacement.
So work done that is equals to fs cos theta. So right so w work done that is a 50 jou and force it is a 10 and displacement that is a 10. Okay so that is equals to cos theta 10 cancel. So 5 divided by 10 that is equals to 1 by 2.
So that is equals to cos theta and theta is equals to 60°. Okay. 60° right answer. Okay. So that is option C. Okay.
Now let's move on to the next one. Which of the following statement true? Yeah.
Work done by conservative forces. Okay.
So conservative forces.
It does not depends on a path. Yes. It depends upon only on initial and final state. Initial and final position. And the next one it is equal to the difference of initial and final potential energy. Yes, that is true.
Okay. And the next one it can be recovered completely because it is a conservative force again and all of the above. Okay. So all of the above that is option D. Okay. So option D. Next question. A body under the action of force. Okay. A body under the action of force F is equals to 6 Icap - 8 JCAP plus 10 KP acquires an acceleration 1 m/s squared. The mass mass not really mass another scalar quantity. Let's convert this one into scalar that is a force that is equals to under square root cofficient of Icap that is 6 square and coicient of JCAP that is - 8 square and that is 10 whole square okay yes sir force that is equals to yes okay so that means it is 200 okay so that is 200 E 200 it is under square root it is 2 into 100 okay yes sir so force that is equals to 10 <unk>2.
Okay. Yes sir.
Force divided by acceleration. Force is 10 <unk>2 and 1 acceleration is to 1. So therefore 10 <unk>2 so kg. Okay. So that is 10 <unk>2 kg. Okay. So that is 10 <unk>2 kg.
So 10 <unk>2 kg. That is option C. Okay.
So option C is the right answer. Next one. the tension t2 for the system as shown in the figure. Okay. So, acceleration to zero. Okay. So, acceleration and same as you know previous one. Okay. So, you know in the same way in the string that is t2. Okay. So, tension in the string that is t2. masses pushed and hold this two it is 2 + 3 okay so 2 + 3 into g value is there so it is g acceleration due to gravity zero okay so t2 that is equals to 5 into 10 to t2 that is equals to 50 newton okay so that is a 50 newton okay so that is a 50 newton so that is a 50 newton option C okay now right so next question which pair of the following forces will never gives the resultant of force that is 2.
Okay. Range magnitude of resultant vector it is a minus b and a + b. Yes siral.
Okay.
The first difference is z. Okay. So total sum four 0 to 4 0 1 2 3 4. Yes sir. And one and one sum is two and difference is zero. Yes two there. And sum is four and difference is two. Yes two there. And sum is five and difference is three. 3 4 5 two.
Therefore write we'll never give a two as a resultant vector. That is that is option D. Okay.
Uh right. Next two question. Next two question. A ball is projected with the velocity 10 m/s at an angle 60° with the vert with the vertical direction test.
Sir 30° with a horizontal. Okay.
Okay. So horizontal it's a speed at the highest point of it trajectory. Okay.
highest point. So only ux that is equals to vx that is equals to u cos theta.
Okay. So that is 10 and cos 30°. Okay.
So that is cos 30° and 10 that is equals to cos 30. So it is 1 <unk>3x 1. Okay.
So roo<unk>3x2. So that means 5<unk>3 speed is to 5<unk>3 m/s. Okay. So 5<unk>3 m/s.
Fine. So 5 <unk>3. Okay. is 5 <unk>3 m/s. Next one ratio ratio. Okay. So this is the ratio of nuclear radius.
So it is r1 divided by r2. So that is a1 sub power 1x3 and a2 so power 1x3. Okay.
So a1 that is 27. Okay. So power 1x 3 either sir it is 64 power 1x3. Yes. So it is the three and this is the four. So 3x 4 3 is to 4. Okay. So that is option B. Done. Next one. The total energy of electron in the third orbit. Okay. So third orbit. So E N that is equals to -3.6 divided by N square. Okay. So -3.6 / 3².
So that means 13.6 divided by 9. Okay.
Okay. So, EN that is equals to - 1.51 electron volt. Okay.
Right. So, that is - 1.51 electron volt.
That is option B.
Okay. Now, let's move on to the Okay.
So, this is three verb. Okay. So, three.
Next question.
The energy gap of an LED is a 2.4 electron volt. When LEDs are switched on the momentum of emitted photo photons.
So E is equals to HS divided by lambda.
So that is equals to it is P. Okay. P and momentum E divided by C. So E value it is 2.4 elect therefore 1.6 into 10 - 19.
So all divided by 3 into 10^ 8. Okay.
and P that is equals to okay so 1.28 into 10^ -27 kg m/s okay so that is 1.28 okay so 1.28 to it.
That is option A. Option A is the right answer. Okay. Now let's move on to the next one. Yes. Homework lastuss.
Okay. So answer will be this one. Okay.
So answer will be this one.
It is N2 minus N1 U that is equals to N2 - N1 / R formula. Okay. Now right.
Huh?
animation you only block. Okay. You only block them. Okay.
Right. So, next one. A multimeter reads a voltage of certain AC source 100 volt.
What is the peak value? Okay. So, peak.
So, V RMS. So, that is equals to V. So, divided by <unk>27 into V. So, V. So V root into Vrms. Okay. So amter sorry multimeter reads that is a V RMS that is one it is 1.414.
So into that is 100. So finally it is 141.4.
Okay. So 141.4 that is option C. Okay. So option C is the right answer. Right. Now let's move on to the next one. In a series LCR.
Okay. This is series LCR. R is equals to 300 ohm. L is equ= to 0.9 Henry and C is equ= to 2 microfarad and omega is,000.
Then impedance. Okay. So impedance s impedance that is equals to unders² r² + okay. So r² and xlus x c. Okay. So r value and that is omega into l. So omega into sir omega that is 1,000 into 0.9. So that means it is 900. Okay. So 900 ohms. Fine. Yes sir. Excel that is equals. Okay. So XL that is equals to and X. X that is equals to 1 / omega C.
Say it is 2. Okay. So 2 omega,000.
Yes sir. 1,000 into L L value L C value sir it is a 2 micro okay so 2 micro 300 that is a 500 okay so 500 ohms and Z that is equals to it is 9 followed by 0 plus so 9 - 4 that is 16 okay so that is 16000 okay yes sir so that indicates that is 2500 0. Fine. So Z is equals to So 5000 that is 500 ohm. Okay. So 500 ohm is the right answer option B. Okay. Done. Okay.
Now let's move on to the next question.
Okay. So next question.
Next question. A square loop of a side 2 m lies in a YZ plane. Okay. So Y plane area vector it is area that isap.
Okay. Plain reason having a magnetic field B= IP. Okay. So magnetic flux.
Okay. So magnetic flux that is equals to sir B vector into A vector. Okay. Right sir. The flux that is equals to B vector that is 5 Icapus 3 Jcap. So - 4 cap 4 KCAP. Okay. Yes sir. Into a A and that is a 2 square.
Okay. Because it is the side matra.
Okay. square that is I 20. Okay. So 20.
Okay. I it is only along Y Z plane. That is option C. Next one. Needle N1, N2 and N3 are made up of feromagnet paramagnet and diamagnet substances respectively. A magnet when brought close to them will be N1 N2. N1 has a magnet strong attractive property strong attract all three attract strongly N2 weakly and ripple N3. Yes, this is right statement.
Attract one strongly attract one and N2 strongly. So therefore right answer that is option P.
Ferroagnetic substance strongly attracted and paramagnetic weakly attracted whereas diiamagnet weakly ripple. Okay. Now let's move on to the next one. The equation of a progressive wave for a wire is y is equals to sin of pi. Okay. So that is sin of pi by 2 8 t minus x / 8. Okay. So velocity of the wave. Okay.
The velocity of a wave that is equals to omega / k omega omega into t that is<unk> /<unk> 8 / 2. Okay. Yes sir. And k value that is a kx. Okay. So pi divided by uh 16. Okay. Right sir. So pi pi get cancel enter.
Okay. Okay. So 8 into 8 that is equals to 64. 64 and 64 cm along xus right answer that is option that is moving along xaxis okay moving along negative xaxis okay now let's move on to the next one at what temperature does the temperature in a fah r equalize okay so equalize the The first one Celsius. Okay. So, C divided by 100 and Fahrenheit. F - 32 divided by So, that is 180. Okay. So, equalize. Okay. Equalize. Let me consider this is X. Okay. So, let me X and this is 10 get cancel and this is X - 32. So, divided by 18. Okay. So, okay. So, that is 9 X that is equals to 5x - 160. Okay. And this becomes a 4x that is equals to - 160 and x = -40.
Okay. So that is -40 is the right answer. Okay. So option A.
Okay. Now let's move on to the next one.
Yes. A body on the surface.
Okay.
Okay. Same question.
Right. Next one.
A uniform force that is 3 ICAP plus JCAP Newton acts on a particle of a mass 2 kg. Hence the particle is displaced from position 2 ICAP plus KCAP meter to the position 4 ICAP + 3 JCAP minus KCAP meter. Work done by the force. Okay. So work done by the force vector quantity.
Okay. So vector quantity so force into displacement. Okay. So force into displacement disment. So therefore sub final position minus initial position.
Okay. So that is equals to 4 ICAP. So + 3 JCAP minus KCAP. Okay. Yes sir. And minus 2 ICAP minus KCAP. Okay. Yes sir.
And the displacement that is equals to sir it is 2 Icap. Okay. So that is 2 ICAP. And the next one that is + 3 JCAP.
Okay. So minus of minus 2 KCAP. Okay.
Yes sir. and work done sol. Okay. So 460 S 3 ICAP S plus JCAP.
Okay. Yes sir. And displacement that is 2 Icap plus 3 Jcap. So minus 2 Kap.
Okay. Yes sir. And so it is 9 J that is option A. Okay. 9.
Fine.
Next one. The equation of a projectile is y = <unk>3 x - gx². Okay. So compar comparison. Okay. So y that is equals to it is the tan theta. Okay. So into x minus gx².
So 2 u ² and cos² theta. So compare it is tan theta that is equals to <unk>3 and theta is equals to 60°.
Okay. So that is 60°. Option B. Okay. So option B. Next question. The dimensional formula of universal gravitational constant that is powerus. Okay. So powerus powerus.
Okay. Okay. So power. Okay. So uh so solve m^ -1^ 3 t - 1 so gravitational force that is g that is equ= to f into r² so divided by m² okay so m into m so that is m² it is m^ 1 l1 tus 2 and this is l 2id 2 okay so further simplification it is m -1 l 3 T minus2. Okay. So L^ 3. So therefore eliminated M^ -1 L^ 3 T minus 2. Yes, this is possible and T minus2 is a possibility. Okay. So that is option C. Option C is the right answer. Okay. Now let's move on to the next one. Yes. The P and junction diode is a connected to a battery of EMF 5.5 volt and external resistance that is 5.1 kiloohm. The barrier potential in the diode is at 0.4 volt. The current current in the circuit is so simple current in the circuit that is a change in potential difference divided by total resistance. So that is equals to 5.5 - 0.4.
So divided by 5.1 into 10^us 3 + 3 and 5.1 that is 1 into 10 - 3 amp I is equals to 1 milliamp.
Okay. So 1 milliamp that is option B.
Okay. So option B is the right answer.
Next one. Yes.
A 60 V source emits a monochromatic light of a wavelength.
Number of photons emitted per second.
Okay.
So n is equals to 5 into 10^ 24.
Okay. So that is 5 into 10^ 24. So that is p into lambda. Okay. Lambda. Okay.
And this is the p. Okay. So power sol.
Okay. Solve you get the answer as 2 into 10^ 20. Okay. So 2 into 10^ 20. Okay. So take it as a homework question. Right.
That's it.
Topper of the class is Manasa and Chandraala and Palavi Kiri and Spandana animation Sajjin and RPG Goda Suda and Kiy Rajas. Okay fine. So the top 20. Okay. So top 20 students.
Fine. That's it. So top 100 important questions I'll be discussing on Saturday. Okay. So Saturday discuss.
Okay. So till then take care. Bye-bye.
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