This video elegantly demonstrates how a simple shift in perspective can turn a non-integrable nightmare into a trivial geometric exercise. It is a masterclass in leveraging intuition to bypass analytical dead ends.
Deep Dive
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Deep Dive
The most classic trick of solving a double integralAdded:
One of the most important techniques when we are doing double integrals is to be able to change the water of the differentials. And this is also a very common test questions that you have to know for your calculus three class.
Let's have a look at this example.
On the inside we have e to the x to the fourth power. Unfortunately, we cannot integrate this function in the x world.
It does not have elementary answers.
So, let's try change the water of the differentials. Meaning we want to integrate this in the y world first. And to make that happen, we will have to change this bounds.
And let me show you guys the quick way to do this right here.
So, we are in the x world first. That means x is going from here to here. I can put this down as an inequality.
x is in between of the cube root of y and two.
And notice this time we already know that y is from zero to eight. So, we can say this right here is greater than or equal to zero.
And the reason we want to do that is because now I want to raise everything to the third power.
And of course, because everything is non-negative, when I raise everything to the third power, the inequalities stay.
So, here we just get y and then we get x to the third power and that will be eight. And of course, technically you also raise that to a third power, but that is just still going to be zero anyways.
Good. In fact, we can figure out what the bounds are already.
And later I'm going to draw pictures for you guys to make it more clear. But, that's it.
e to the x to the fourth power dy dx In the y world, here's the y.
Remember, we look at the bottom function to the top function.
The bottom function is zero. The top function is x to the third power.
Done.
And then once we get to the x, it's a left most number to the right most number.
Well, you can look at this and that and then just isolate the x, but you can look back. x is in between of zero and two. So, zero and two.
Same thing. And then you're done.
Seriously, just like that.
Now, here's just a quick picture for you guys.
First, when x is going from cube root of y, imagine if this is equal to x. That means when I cube both sides, I get y is equal to x cubed.
So, it goes like this.
So, this is technically our function.
Cube root of y is equal to x.
So, here it's going to be a left most function because we're in the x world first.
And then we are going to go up to So, two is somewhere right here.
So, that will be my right most function.
So, we are looking from here to here.
And then y goes from zero to eight.
So, the bottom number up to the top number, which is eight.
So, we're talking about this region here.
So, again, left most function to the right most function, bottom number to top number, dx dy.
Now, if I'm looking at dy dx, we are looking at the bottom function, which is x which is y is equal to zero.
This is y equal to zero.
And then the top function is this part.
Which we say that is y equals x cubed.
Let me just write it down right here.
And then once we are in the x world, we look at the left most number, which is zero, and then the right most number, which is two.
Again, we are still talking about this region. So, just like that.
Now, once we have all this, we can just go ahead and integrate it because integrating [clears throat] a constant in the y world is super super easy. It's just going to be y times that.
So, we get zero to two. We get y e to the x to the four. And we plug in zero and x to the third power dx.
Plugging x to the third power here, we get exactly just that.
Plugging zero, it's gone. So, that's very nice. So, that's what we have to do and then dx.
And then right here, let's just go ahead and do a very nice u sub. Let u equal x to the fourth power. du is equal to 4x cubed dx.
We need a four. Let's multiply by the four and then divide it by it right here.
So, we have 1 over 4.
This and that is our du.
And then we have e to the u.
And let's just finish everything in the u world.
When x is equal to zero, we can see that u will be going from zero.
And when x is equal to two, two to the fourth power 16. So, u will be going to 16.
Okay.
Integrating e to the u is just e to the u. So, leave it like this. e to the u.
Uh I will still show you guys all the steps. e to the u and then we go from zero to 16.
I'm plugging 16, plugging zero. 1 over 4 e to the 16 minus 1 over 4 e to the zero's power is one. Right?
And that's pretty much it. I'm going to leave it like this.
Yeah.
Just like that. That's it.
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