Solving a 'Harvard' University entrance exam question

Added: 2026-06-02

[00:00:00]Hello Friends find the value of 'k' If √k√k√k=128 let's have a solution to solve this, you should know that as √k=k^1/2 √√k=(k^1/2)^1/2 k^1/4 √√√k=[(k^1/2)^1/2]^1/k^1/4 then this is same as √k.√√k.√√√k=128 which is same as k^1/2.k^1/4.k^1/8=128 as we know a^m.a^n=a^m+n we have k^1/2+1/4+1/8=1288 take LCM k^(4+2+1/8)=128 k^7/8=128 k^7/8=2^7 as we know 2^7=2.2.2.2.2.2.2=128 now take power (8/7) on both sides (k^7/8)^8/7=(2^7)^8/7 7 & 7 and 8 & 8 cancels we get k=2^8 which is equal to 256 128x2=256 2^8=2.2.2.2.2.2.2.2=256 which is the value of 'k' thanks for watching this video please subscribe this channel to get the notification of my new videos and don't forget to share these videos with your classmates and friends so that they also have a benefit of it ok bye