Crack RRB Group D 2026🚀 | Time Speed & Distance 03 💯+ PYQ 🔥 | Tamil - Part 22

Added: 2026-05-26

[00:00:01]Hello aspirants. Uh welcome to Chandra Max time speed distance RB group.

[00:00:12]So continue first can be if a 5 1,533 m long train crosses a pole in 73 seconds then find the time taken by the train to cross a 420 m long platform.

[00:00:30]Okay.

[00:00:40]foreign.

[00:00:52]So crossing a pole train crossing a pole.

[00:01:15]Cyclist object or negligible platform person speed of the train.

[00:01:46]Speed of train speed equals to distance by time. Okay.

[00:01:56]General concept length of the train distance.

[00:02:05]Length of the train divided by time taken. Time taken to cross.

[00:02:19]Time taken to cross the man or person or pole.

[00:02:28]Man, person train crossing a platform or another train.

[00:02:56]another stationary train.

[00:03:02]So speed of the train speed again distance by time distance length of the train.

[00:03:22]length of the train platform plus length of the platform of the platform.

[00:03:38]So length of the platform.

[00:03:46]So platform bridge tunnel station divided by time. So divided by time taken.

[00:04:08]Right. Okay. So forgatform of the train length of the platform divided by time taken. So in the formula firstgeng speed of the train equals to length 153.

[00:04:54]So 153 length of the train divided by 73 seconds.

[00:05:09]73 21 m per second distance.

[00:05:24]Second time for important. Second formula speed sorry length of the trainformatform second to length of the train length of the platform by timeals 1533 420 divided by uh divided by speed.

[00:06:20]So speed 21 m/s.

[00:06:24]So 153 + 420 953 divided by 21.

[00:06:31]So 9 * 1 uh 80 uh 180 190. So 193 93 * 93 93 seconds right a train passes a station platform in 60 seconds platform.

[00:07:08]Okay. And a man standing on the platform in 40 seconds. Man standing on a platform.

[00:07:26]It is the speed of the train is 63 km/h.

[00:07:30]Calculate the length of the platform.

[00:07:35]length of the train.

[00:07:44]So first length of the train first length of the train speed of the train into time taken 63 questions. So 40 seconds 60 seconds m/s into 5 by 18 into 5 by 18 40 seconds. So into 40. So 2 9 7 9 2.

[00:08:34]So 75 35 35 into 2 70. So 700 length of the train of the platform of the platform of the platform of the platform of the platform equals to speed into time.

[00:09:08]Speedalsengals speed into speed 63 into time platform across So 60 seconds minus length of the train.

[00:09:45]So cancel 29 7 9 2 30. So 75 35 35 into 3 1050 - 700. So total 3 50 m length of the platform.

[00:10:05]So first of okayractice train passes two tunnels.

[00:10:36]A train passes two tunnels of length 2091 m and 1259 m in 89 seconds and 63 seconds respectively. What is the length of the train?

[00:10:54]foreign.

[00:11:10]So speed distance length of the train plus the tunnel.

[00:11:38]Okay. First 2091 of the train.

[00:11:50]Second length of the train.

[00:12:04]Okay.

[00:12:06]speed of the train.

[00:12:19]Same mid 63 seconds.

[00:12:34]So, 1 1259 difference and then 89 63 difference. So 89 63 26 seconds 209 difference 8 32. So 832 relationship. So difference equal to 832 divided by 26 equals to m/s 32 m/ second.

[00:13:39]difference.

[00:13:48]So difference of speed 32 m/s 32 m/s 63t option 32 m/s difference into 63 seconds.

[00:14:16]-1 to 59US 129 32 into 897 speed of the train equals to second formula Speed of the train for length of the train.

[00:14:54]Okay. Second tunnel length of the train distance.

[00:15:02]So 129 plus length of the train divided by 63.

[00:15:15]209 difference 89 63. So 26 seconds 832 m. So 832 mid 26 seconds 32 m/s 632 length of the train.

[00:15:46]A train passes through two tunnels of length 2492 m and 914 m in 81 seconds and 64 seconds respectively. What is the length of the train in meters? Okay. So, so speed length plus 2 4 92 divided by seconds. 2 4 92 first time 81 then equal to length of the train plus 1914 m divided by 64 seconds.

[00:16:44]Okay. So in the difference 2 492 914 81 64 81 64 difference 17492 914 difference 578.

[00:16:58]So difference of speed difference of speed 58 divided by 17. So 34 m/s.

[00:17:16]So 34 m/s the difference of speedt.

[00:17:26]So first 64 34 into 64 91492 62 m. Okay.

[00:17:53]Right. So two trains crossing opposite direction.

[00:18:08]Two trains 259 m and 431 m long are running in opposite directions at a speed of 52 km/h and 56 km/h respectively. They cross each other in 259.

[00:18:38]Relative speedsite plus relative speed.

[00:19:04]Relative speed value S1 plus S_sub_2 S1 speed relative S2us S1 S2 S2 S2 S1 S1 number S1US S2 So relative speed So relative speed relative speed 52 km hour plus 56 km hour. Okay.

[00:20:03]259 m 431 m hour into 5 by 18. So 52 + 56 8 1 8. So 1 8 into 5 by 18. So 5 by 18 2 9 is 12 9 6. So 65 are 30. So 30 m/ second relative speed. So relative speed taken to cross each other. So distance. So 259 plus 431 259 + 431 divided by 30 speed. Relative speed relative speed m/s.

[00:21:19]So 29 + 431 690 divided by 30. So 0 0 cancel 2 3 33. So 23 seconds to cross each other. Right. So two trains are running in opposite directions at speeds of 72 km/h and 1 8 km/h respectively. The length of the first train is 150 m and the length of the second train is 200 m. How much time will they take to cross each other?

[00:22:00]foreign.

[00:22:13]Okay.

[00:22:17]Relative speed.

[00:22:25]Okay.

[00:22:27]Opposite. So opposite relative speed relative speed plus good. So 72 plus 8 speedome again into 5 180 into 5 by 18. So 10 * 10 into 5 50 m/ second relative speed time time equals to distance by speed.

[00:23:09]So distance 150 m 200 m.

[00:23:15]So 150 plus 200 divided by 50.

[00:23:22]So total 350 divided by 50. So 7 seconds right two trains crossing same direction.

[00:23:50]Same direction. opposite direction.

[00:24:02]A train P going at a speed of 84 km per hour completely passes train Q of length 447 m going in the same direction on parallel tracks at 54 km/h in 4.5 minutes. How much time will P take to completely cross train R of length 287 m going at 87 km hour in the opposite direction.

[00:24:59]So Q speed Q length for rail.

[00:25:33]for then speed. Good.

[00:26:02]So relative speed of P and Q P and Q and Q P and Q Q minus 5 m.

[00:26:55]So multiply 54 - 8 84 - 54 30 30 into 5 by 18 3 6 5 6 so 5 5 25 25 by 3 so 25 by 3 Okay 3 6 25 by 3 m/ second of length of length of length of second speed into timegative speed 25 by 3. Okay.

[00:28:07]4.5 seconds 4.5 minutes 4.5 into 60 secondsus length of 447 m right 1.5 1.5 into 60 15 into 6 15 into 6 into 25 15 into 6 90 90 into 25 225 so 22 2 5 0 - 447 so 1 8 0 3 m the length of P in the length of length of time taken by P and So important and opposite directionals to P into 5 by 18.

[00:29:41]So 84 87 add 171 into 5 by 8 29 99 199 19 into 5 95 by 2 m/s right distance by speed. So distance.

[00:30:15]So 1803 length of P 287 divided by uh 95 by 2 90 / 95.

[00:30:35]So cancel 195 45 19 185 uh cancel uh 29 38. So 338. So 22 into 2 4 seconds.

[00:31:01]MD same PQ on the same direction. P are opposite direction.

[00:31:32]Two trains having length of 160 m and 140 m are running at speeds of 100 km/h and 130 km/h in the same direction. The time taken by faster train coming from behind to completely cross the train. So same direction same direction.

[00:32:16]So first speed 100 kmh 130 kmh 130 kmh. So 130 - 100 mg per minute 50 by 3 50 by 30 10 into 5500 m per minute.

[00:33:11]Okay.

[00:33:14]Time for distance by speed. So distance on the train length 160 + 140 divided by speed 500 m 300 divided by 500 300 by 500 3x 5 3 500.6 minutes 0.6 Six minutes Right.

[00:34:08]Right.

[00:34:11]Type 11 train people walking.

[00:34:18]Walking people a train takes two people running along a railway track. The first person is running at 12.6 km per hour and the second person is running at 25.2 km per hour. The train takes 16.8 seconds to pass the first person and 22.2 2 22.4 seconds to pass the second person. What is the speed of the train if both are running in the same direction as a train?

[00:35:09]Okay.

[00:35:19]for person running along.

[00:35:44]Running along railway track first speed of the speed of most of US 12.6 first person first.

[00:36:28]So person firstus second 25.2 So second person of the length of the train speed formula of the train speed into time 12.6.6 relative speed 16.6 seconds. So 16.6 Six seconds.

[00:37:53]seconds. Hour second.

[00:38:12]Okay.

[00:38:16]First length of the train divided by time taken equals to speed formula speed of secondgeng sameus 25.2 Second person 22.4 seconds.

[00:38:47]So 22.4 seconds into length of the same 60 60 then 16.8 22.4 4 cancel 2818 28 88 864 74 uh 3 3747 Okay. So 3 S - 12.6 into 3 36 18. So 37.8 8 4 [snorts] S - 100 100.8.

[00:39:42]So equals to 63 kilome of the length of the train Speed into question.

[00:40:14]A train overtakes two persons walking along railway track. The first person is traveling at a speed of 7.2 km/h and the second person is traveling at a speed of 14.4 km hour.

[00:40:30]speed of minus 7.2 km/ hour.

[00:40:38]Second person minus 14.4 km per hour.

[00:40:44]You second person in the first train takes uh the train takes 29.9 seconds to pass the first person and 43.7 seconds to pass the second person. So if both people are traveling in the same direction what is the train speed length of the train speed relative speed first person s minus s - 7.2.9 into 29.9 seconds first person. So 29.9 divided by again 60 into 60 minutes then second person sus 14.4 then 43.7 seconds. So 43.7 by 60 seconds then 60 60 60 cancel.

[00:41:49]Okay. So 13 into 7 91 uh 26. So 93.6 6 = to 19 S4 80 76 uh 26 266 273 6S equal to in the 30 6s 93.6 273.6 6 remaining 1 8 0. So s = to 30 kilm hour. Speed of the train kilome. Right.

[00:42:55]Right.

[00:43:10]A speed of 126 km per hour is same as per second.

[00:43:25]So 126 kilome per hour,000.

[00:43:53]Okay. So 60 minutes and then 60 minutes 60 seconds 3,600 seconds 3,600 3,600 seconds.

[00:44:28]Okay.

[00:44:31]5 0 0 0 10 by 36.

[00:44:41]So 126 into 5 by 18.

[00:44:49]Yes. Correct.

[00:44:58]2 9 1 9 4 9. So 2 147 7 are 35. So 35 m.

[00:45:14]Okay. Right.

[00:45:23]First, a motorist travels 30 kilometers in 15 minutes. He drives at a speed of x km/h for the first 12 minutes and then 2x km/h for the next 22 minutes and finally x kmh for the remainder of the journey.

[00:45:37]Determine the value of x. So distance first 12 minutes first distance.

[00:46:13]speed into time.

[00:46:20]12 minutes but kilome hour kilome.

[00:46:47]So first 12 minutes then final distance. So 2x 2x 2x 22 by 60 then xm.

[00:47:33]Okay.

[00:47:41]Right.

[00:47:43]Important. So x into 12 12 x 2x into 22 44 16 x 72 x / 60 common denominator.

[00:47:57]uh 72 612 512 6 5 So x = 5 25 kilome per hour. So 25 km right.

[00:48:24]How many seconds will a boy take to run one complete round a square field of 20 m? So square field square field 20 So meter.

[00:49:03]Okay. So m 5 by2 m second kilome per Right.

[00:49:42]20 + 20 total distance 20 into 4 80 m. Okay.

[00:49:52]Okay.

[00:49:54]equal to distance by speed. So 80 divided by speed 5x2 52 80 by 5 into 2. So 80 by 5 19 into 2 sorry uh 16 uh 1 55 5 30 6 5 are 30. So 16 16 into 2 32 seconds.

[00:50:22]from the square.

[00:50:30]A man is walking at a speed of 12 km/ hour. After every kilometer of walk, he takes a rest for 7 minutes. How much time will it take to cover a distance of 6 km?

[00:50:50]So conceptual.

[00:50:54]So timeline a man is walking at a speed of 12 km hour.

[00:51:04]Every kilome of walk he takes 7 minute rest. Okay.

[00:51:11]How much time will it take to cover a distance of 6 km? So every minute 7 minute rest 7 minutes Fifth km 7 minutes rest right next minutes.

[00:52:22]Speedals first speed 12 into 1x 60. So 1x m kilometers per minute speedome 6 by 1x 30 minutes 30 minutes in the part in the part in the part in the part in the part in the part. So travel minutes in the 7 minute resting minute resting resting resting resting.

[00:53:57]So resting uh 57s are 35 35 minutes. Okay.

[00:54:17]1 km 1 km 1 km.

[00:54:23]So 30 minutes plus 35 minutes. So 65 minutes.

[00:54:49]Okay.

[00:55:06]12.

[00:55:08]Sorry. 12 km 12 km in 1 hour.

[00:55:22]point of view. So 12 hour minutes. Okay.aping 7 minutes 5 into 7 35 minutes.

[00:56:06]Simple and easy.

[00:56:22]Okay. Right.

[00:56:27]Walking at 23 of his normal speed.

[00:56:29]Abijit is 18 minutes late in reaching his office. the usual time taken by him to cover the distance between his home and his offices. So the usual speed normal speed foreign.

[00:57:00]So usual speed and speed time. So usual already.

[00:57:27]Okay. So speed 32 2 time speed inversely proportional again speed and time inversely proport 3 is to2 speed 2 is to 3. So in one 18 minutes 18 minutes two parts two part one two parts 36 minutes. Simple.

[00:58:22]Speed and time are inversely proportional. And then time, speed, distance.

[00:58:54]So, comment section.

[00:59:16]Thank you all. Thank you all for watching.

[00:59:21]TNC and thank you. Thank you all for watching.