Law of Mass Action| CEE and IOE| Conceptual Question| Important|

[00:00:00]Hello students important question from chemical equilibrium.

[00:00:30]type of question.

[00:00:34]Conceptual question.

[00:00:47]Consider consider the two gases equilibria involving SO2 and the corresponding equilibria constant Law of massction of mass CC dds electron the reactions That means product formation. This is called the reactant react to that is called the product that rate of forward reaction.

[00:01:45]Rate of backward reactions equivalence at equilibrium equilibrium rate of forward reaction equals to rate of backward reaction.

[00:02:09]C= that is the D reactant that is V that is the law of mass action. and you love.

[00:02:40]Okay.

[00:02:48]Forward backwards.

[00:02:54]reactions equate forward reactions. Rate of backward reactions forward backwards forward.

[00:03:16]So that is the law of mass form.

[00:03:31]First SO2 SO2 gases for 1 by 2 O2 gases for SO3 gases equilibrium. constant. So applying law of mass section product this is the oxygen oxygen this is 1 by 2.

[00:04:19]Now that is the equation one.

[00:04:38]2 S2 gases for O2.

[00:04:55]So K2 S23 that is equation two that is equation one that is equation We know that. We know that rate of forward reaction. A backward reaction into Squaring Squaring both side. Squaring both sid square N square 1 by K1² S O2 square O2.

[00:07:21]So now now now from equation from equation from [clears throat] equation one= SO2 same O2 same SO3 same 1 by 1 1 k1 square.

[00:07:55]I think it's answer.

[00:08:17]Answer comment.

[00:08:28]Like today.