To solve cubic equations like X³/8 = 1, first isolate X³ by multiplying both sides by 8 to get X³ = 8, then rewrite 8 as 2³ to apply the algebraic identity A³ - B³ = (A - B)(A² + AB + B²), which transforms the equation into (X - 2)(X² + 2X + 4) = 0, yielding one real solution X = 2 and two complex solutions X = -1 ± i√3 from the quadratic factor.
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The FASTEST Way to Solve Cubic Equations (Math Hack)Added:
This equation is not as simple as you think.
But believe me, I am going to show you every step I am taking to find all the possible solutions of X.
Pay close attention to this. This equation is very very interesting.
We have X to the power of 3 divided by 8 is equal to 1.
Okay? So, this is a cubic equation. That means we we must have three solutions.
This is very interesting. So, this implies that X cubed will be equal to what? 8 * 1 is what? Is 8.
So, we have transformed it in this form.
Now, we are going to move 8 to the left-hand side. We shall have X cubed.
Now, this 8 can be written as what? -2 to the power of what? 3.
Because 2 to the power of 3 is 8. All this is equal to 0.
Now, let's consider this algebraic identity.
If you have A squared or A to the power of 3 minus B to the power of 3, this is the same thing as saying A minus B multiplied by A squared plus AB plus B squared.
Okay?
So, let's use this identity to solve this.
Okay? So, where our X is equal to A, then our B is equal to that's 2 to the power of 3.
That's um sorry, 2.
Which is 2.
So, put in this into this and see what we shall have.
Our A is X, so we shall have X minus B is what? 2. So, by 2 multiplied by A is X, so we have X squared plus um AB, which is what?
Um X * 2, which is 2x.
Plus b squared is 2. That is 2 squared, which is what? 4.
All this is equal to zero.
So, we we we shall obtain the first solution because x - 2 will be equal to zero, which means x is equal to 2.
That's for x1.
This is interesting, right?
Now, the second solutions or the other solutions is by solving this quadratic equation.
So, we shall have x squared plus 2x plus 4 is equal to zero.
We cannot solve this through a factorization because we cannot um factorize this.
But, we can solve this by using quadratic formula.
So, our quadratic formula said that x is equal to minus b plus or minus square root of b squared minus 4ac divided by 2a.
Right?
Now, in here we shall obtain Look at very well. We shall obtain our uh a a to be equal to 1, then b to be equal to 2, then our c is equal to 4.
Putting these parameters in this in this uh quadratic formula, we shall have that our x will be equal to Our b here is 2. So, we shall have minus 2 plus or minus b squared. Our b is 2.
That means we shall have the square root of 4 minus 4 * um our a is 1 * c. Our c is 4. So, 4 * 1 * 4 is 16. So, we shall have 16 here divided by what? By 2.
So, our a is 1. So, we shall have two times one, which is two.
Right. So, look at this.
So, X will be equal to -2 plus or minus Now, 4 -16 is -12. So, we shall have the square root of -12 divided by two.
Right?
Now, look at this.
This is a complex solution because of this -12.
Let me show you how to express this.
So, this become X will be equal to -2 plus or minus This is the same thing as saying 2i the root of three.
Okay?
This minus the root of -12 is 2i root of three.
Right? Now, all this is divided by what?
By two.
Now, we can factorize this out as our X will be equal to um two into -1 plus or minus I multiplied by the root of three divided by two. Okay? So, that this two will neutralize this two.
Then, we shall have our X to be equal to -1 plus or minus I root of three.
So, our X1 will be equal to -1 plus I root of three or our second solution will be -1 minus I root of three. So, you can call this your X2. You can call this um your X3.
So, these are the solutions to this amazing equation. I told you earlier that it is not that simple because we are going to obtain all the solutions of x, which is a cubic equation. So, our first solution is x is equal to 2, our second solution is -1 + um -1 + i root of 3 or -1 - i root of 3.
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