Stoichiometry (Moles & Volume)

追加: 2026-06-02

[00:00:00]Now, the question says, "Aluminum reacts with hydrochloric acid according to >> [music] >> two blah blah blah. This is the equation for the reaction. So, it reacts according to all this here. Some persons may decide not to give you this equation of the reaction, so you should know what appropriately the aluminum reaction should be with hydrochloric acid because this is the two um elements or the two compounds that are meant to be [music] in the reactants process. However, the question says, "Calculate the number of moles of aluminum and also the number of moles of hydrochloric acid." Firstly, [music] the number of moles this is equation I asked number of moles of what? Of aluminum. Remember that aluminum has its 27 g >> [music] >> per mole. So, once you get the number of moles, that automatically means we're going to be dividing the mass available with the molar mass. [music] So, using the formula n equal to mass number over molar mass. Okay? So, that will give us the mass number here is given to us as 10.

[00:01:04]>> [music] >> 8 g. And then the molar mass is 27 g >> [music] >> per mole.

[00:01:10]And that will give us if you verify this, it will give you nothing else but 0.4 >> [music] >> moles.

[00:01:18]Okay? So, the number of that you get this. However, the next question says, the II aspect aspect of this hydrochloric acid. So, number of moles the same formula for hydrochloric acid we have that of hydrochloric acid should be uh we have 73 g all divided by we have a let me write that 35.5 [music] + 1 because this here is 35.5. Hydrogen is 1. And that will give us 73 g over 36.5.

[00:01:53][music] So, if you evaluate of it will give us what? Two moles.

[00:01:58]So, number of moles is what? It's two.

[00:02:00]Thank you.

[00:02:02]>> [music]