This video demonstrates how to solve complex algebraic expressions by applying algebraic identities (such as (a+b)³ and (a-b)²) to eliminate irrational terms, ultimately showing that the required expression equals zero through systematic simplification.
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An Amazing Math Olympiad Challenge | Can You Crack This?Añadido:
Hello friends, welcome to NC Gyan. Today in this video we have another very interesting question from math Olympiad.
Here we have X equal to a square root 2 plus cube root 3 and it is said to find this required expression. I will call required expression equal to E.
Now we have X which is sum of two irrational numbers.
Now I will calculate X power 6 from X.
So I need to write over here X equal to a square root 2 plus cube root 3.
Now I will cube both sides.
whole cube whole cube Now here we'll be using A plus B whole cube identity. Let me write here so that we can apply directly to our equation.
A plus B whole cube is A cube plus 3 A squared B plus 3 AB squared plus B cube.
Here A is a square root 2 and B is cube root 3. We will get X cube.
root 2 cube root 2 times root 2 times root 2 2 root 2 2 root 2 plus 3 times A squared root 2 squared will be 2 times B will write cube root 3 plus 3 times root 2 times B squared cube root 3 whole squared cube root 9 plus B cube cube root 3 whole cube 3.
In this equation we have cube root 3 and cube root 9 which we want to replace from the known equation.
So, from this equation I can write cube root 3 which will be equal to x minus square root Cube root 3 will be x minus square root Let me write here.
3 equal to x minus square root Now, cube root 9 is also required. So, I need to square both sides.
So, I will put power 2.
Cube root 3 whole square is cube root 9.
In RHS we'll be using a minus b whole square formula and get x square minus 2 root 2 x plus 2.
Now, we have both the values.
Cube root 3 which is here.
And cube root 9 which is here.
We are going to use x cube equation.
Let me write here. x cube equal to 2 square root 2 plus 6 times cube root 3 plus 3 times square root 2 times cube root 9 plus 3.
We have cube root 3.
x minus root 2 And we have cube root 9.
x square minus 2 root 2 x plus 2 Now, we have to plug in these two values to our equation and we will get x cube equal to two square root Now six times cube root three, we will write six times cube root three is x minus square root two.
plus three root two times cube root nine Here we will write x is square minus two root two times x plus two.
Then we have plus three also.
Now we have to simplify our right hand side.
We will get two root two six times x minus root two We'll write six x minus six root two.
Three root two times x is square, we'll write three root two x is square.
Then three root two times minus two root two x, we will get 12 x with negative sign, minus 12 x.
Then we have three root two times two, which is six root two.
plus three Now we have plus and minus six root two over here.
Which we will cancel.
Here we have six x.
And here we have minus 12 x.
So I can write here the last number or term that is three minus six x.
Now we have two root two left and three root two x is square left. From these two terms I will take root two common out. So in the bracket I will be writing three x is square plus two.
And in LHS we have x cube.
Now we are going to add 6x -3 to both sides. Let's add 6x -3.
Or here we will write 6x -3.
So, plus and minus 6x, plus and minus 3 will get over.
We will get x cube +6x -3 equal to square root of 2 3x squared +2.
Now, we have only one irrational term, and once we will take a square both sides this will resolve.
It will be only rational numbers.
Let's square both sides.
So, I will write here whole part two.
Write here whole part two.
Now, in LHS we'll be using a + b + c whole squared.
And in RHS we'll be using a + b whole squared formula.
So, let's use in LHS first x cube whole squared x power 6 + 6x whole squared we'll write 36x squared + -3 whole squared so +9 +2 times x cube times 6x we will get 12x power 4.
Then 2 times 6x times -3 we'll get -36x.
Then we will write -6x cube.
-6x cube.
Then in RHS square root 2 whole squared will be 2.
In bracket 3x squared +2 whole squared will be 9x power 4 + 12 x square plus four.
Now we will expand RHS and we will get 18 x power four plus 24 x square plus eight.
Now we will take all the terms to LHS.
We will get x power six.
Then we can write x power four terms. So I will be writing here 12 x power four minus 18 x power four.
x power four is over.
Now we have x cube term which we will write over here minus six x cube.
Then we have x term and x square term and constant.
So I will write here x square term first.
36 x square minus 24 x square then we have minus 36 x then we have two constants nine and minus eight.
And right hand side will be zero now.
Now we will write x power six first.
Then we have 12 x power four minus 18 x power four which is minus six x power four and it is matching with our required expression over here. Then we have minus six x cube.
Then we have 36 minus 24 12 x square.
Then we have minus 36 x.
Then we have nine - 8 1.
It is completely matching with our required expression equal to zero.
And here we can write e equal to zero.
So our final answer becomes required expression will be equal to zero. I hope friends you will like this video. Thank you so very much for watching. Do not forget to like, share, subscribe. Bye-bye.
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