Class 11 Chemistry NCERT Solutions | Gyanam Tuition

[00:00:00]Hello students.

[00:00:11]exercise.

[00:00:21]Com Fore how much copper can be obtained from 100 g of copper sulfate?

[00:01:20]How much copper can be obtained from 100 g of copperf. Fore SO4 one copper.

[00:02:22]One copper sulfate. Copperf.

[00:02:41]1 into mass 63.5 63.5 into 32 oxygen atom into mass copper.

[00:03:11]63.5 into oxygen atomic mass 163.5 + 32 + 4 into 1649.5 159.59.5 g copper 63.5 63 3.59.5 g of copper 63.5 g of copper 159.5 gulf 63.5 63.5 reaction 159.5 copper 63.5 g 15.5 g of copper 63.5 159.5 63.5 / 159.5 gain 63.59.5 100 copper 100 g of copper 63.5 divided by 159.5 into 100 g of copper 100 g of copper 100 g of copper 63.5 divided by 159.5 into 100 g of copper 63.5 into 159.5 39.81 81 g of copper copper 39.81 gulf 39.81 clear.

[00:06:31]Next question.

[00:06:34]Determine the molecular formula of an oxide of iron in which the mass percent of iron and oxygen are 69.9 and 30.1 respectively. Given that given that mass of oxide is 159.69 69 molecular formulass.

[00:07:40]Relative number of atomic mass. Relative number of relative number of moles.

[00:07:44]Relative number of moles.

[00:08:02]Iron number 69.9% to 69.9% 69.9% 30.1% Iron 69.9% oxygen 30.1% 69.9% 69.9% oxygen 30.1% massic mass Atomic 56to relative number of relative number of 69.9% 69.9 69.9 of oxygen percent 30.1 oxygen 30.12.1 atomic mass 16.1 oygass 16.1.8 oxygen relative number of moles.8 Simple.

[00:10:26]Relative number.

[00:10:42]Relative number.

[00:10:47]relative number of I don't know relative number of 1.2 relative number of 1.8 882.2.8.2.5 simplest.

[00:11:36]Simple number one.

[00:11:44]1.5 number 1.5 ratio 1.5 oxygen simpio for oxygen Simp 1.5 Simpio.

[00:13:09]forculinium.

[00:13:47]55.86 55.85 85 plus 169.79.7 mass divided by empul 159.69.69 divided by empirical formula 159.79.6 6 159 for empul.

[00:14:56]to the power.

[00:14:59]N2 forcul Empty.

[00:15:53]Exercise 1.1 Example for exercise in moles of C2H6 at number of moles of hydrogen atom number of molecules of ethanol Second to number of moles of hydrogen atom to number of moles of One mole of one of contains two moles of carbon atom.

[00:17:32]of carbon contains two of C2 contains two of contains six of six contains two of contains six moles of carbon atoms.

[00:19:13]Second question number one of contains six moles of hydrogen atom. One mo of ethane contains six moles of hydrogen atom.

[00:19:45]One of contains six moles of hydrogen atom.

[00:20:00]moles of ethane contains 3 into 16 into 18 atom.

[00:20:29]of contains contain Number of number of molecules of Number of 6.022 22.022 into 103 6.022 into 10 3 into 6.022 22 into 103 into 6.02 18.06 into 103.22 22.022 18.06 into 103.

[00:22:31]What is the concentration of sugar in mole per liter of each 20 g are dissolved in enough water to make a final volume up to sugar.

[00:23:14]What is the concentration of sugar?

[00:23:27]mass mass often.

[00:24:03]atom 122 atomic mass oxygen oxygen 11 into 16 + 22 into 1 + 11 into 1642 g42 gassute gassute.

[00:24:50]Number of moles of solute divided by volume of solution in liter of moles of solute divided by volume of solution in liter of number of moles of given mass. divided by mass divided by solute mass.

[00:25:34]342 divided by volume of solution divided by volume of solution.

[00:25:55]Number of solute divided by volume of solution.

[00:26:04]Number of number of given mass divided by mass.

[00:26:24]42 / 20 by 342 20 by 342 1x2 by 342 1 by2 1042 342 0.02925 L 0.0292 2925 Example, 10 of it.