To find the sum of all multiples of 7 between 1 and 500, recognize that these multiples form an arithmetic sequence starting at 7 and ending at 497. Using the nth term formula (last term = first term + (n-1) × common difference), solve for n to find there are 71 terms. Then apply the sum formula S = n/2 × (first term + last term) to calculate the total sum as 17,892.
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Sum of Multiples of 7 Between 1 and 500 | AP Sums Made EasyAdded:
This question can save or lose you marks in exams.
Find the sum of all multiples of seven between 1 and 500.
Let's solve step by step. Multiples of seven form an arithmetic sequence.
Now, use the formula. Last term is equal first term plus n minus 1 times the common difference d.
So, we write 497 equals 7 plus n minus 1 times 7. Which gives us 497 equals 7n.
So, n equals 71.
Now, use the sum formula. So, we get s equals 71 divided by 2 times 7 plus 497.
Which gives us s equals 71 times 252.
So, s equals 17,892.
So, the sum of all multiples of seven between 1 and 500 is 17,892.
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