To solve the equation (x³ - 64)/x = 0, first cross-multiply to get x³ - 64 = 0, then recognize this as a difference of cubes (x³ - 4³) and factor it using the identity a³ - b³ = (a - b)(a² + ab + b²) to obtain (x - 4)(x² + 4x + 16) = 0. Apply the zero product rule to find x = 4 as one solution, and solve the quadratic equation x² + 4x + 16 = 0 using the quadratic formula x = [-b ± √(b² - 4ac)]/(2a), which yields complex solutions x = -2 ± 2i√3. The three solutions are x = 4, x = -2 + 2i√3, and x = -2 - 2i√3.
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Olympiad Mathematics | The three solutions | Can you solve this?
Added:Hi, everyone.
How can you solve this problem completely?
Right?
So, what are you expected to do in this case?
The first thing to do is to cross multiply.
Yes.
So, that this will multiply the zero.
And we'll have x to the power of 3 minus 64 to be equal to x multiplied by zero is what?
I hope you know what that is.
So, we have our x to the power of 3 minus 64 and is equal to zero.
So, this way almost everybody will be able to solve it.
But, we know that x to the power of 3 minus um 4 to the power of 3 will be on the left.
Because 4 to the power of 3 is 64.
Because 64 is a perfect cube.
And then imagine that we have a cube minus b cube.
You know, this identity is also equal to a minus b multiplied by a squared plus ab plus b squared.
Now, you have to take note of something here.
And it is the fact that a is representing x and b represents 4.
So, in place of a minus b, we have x minus 4.
In place of a squared, we are going to have um x squared.
Then, ab, that'll be x times 4 and is 4x.
Plus b squared, which is 4 squared.
4 squared is 16.
So, we equate this to zero.
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Now, the next thing to do is to apply zero product rule.
Zero product rule.
Now, what I'm what I'm going to do, I can't do it if this is one.
If this is not equal to zero, what I'm going to do cannot be done.
So, x minus four is either zero or x squared plus four x plus 16 is zero.
Remember, I'm doing this because we have zero on the other side.
From this part, x is equal to um zero plus four then the value of x is four. This is a solution.
Now, to get the other solutions, we'll bring down this quadratic um equation there.
And bringing it down, we have to bring down the coefficients and the constant, right?
Remember, um a stands for the coefficient of x of x squared rather, and that is one. B stands for the coefficient of x, which is four. And [snorts] c is the constant, which is 16.
Now, this a b c, for those of you that do not know, a b c are going to be found in the quadratic equation formula.
Because we're going to use that very formula to solve this equation.
What is the formula?
Okay.
So, the formula now is x equals minus b plus or minus we have b squared minus four a c all over 2 * A.
So, what we'll do now is to put in our values of ABC.
So, that X will now be In place of minus B, we're having minus 4.
Because B is 4.
Then plus or minus In place of B squared, we are having 4 squared.
Minus 4 times A. A is what? 1.
Times C. And our C is what? 16. So, we put 16 there.
This is all over 2 multiplied by 1.
Because A is still 1.
Now, X is equal to minus 4 plus or minus the square root of 4 squared is 16. Then 4 * 16 is 64.
So, we divide all of this by 2. Because 2 * 1 is what? 2.
Yes, 2 * 1 is um 2. Now, let's continue.
Now, this is one thing I know you you might want to do.
You want to get the square root of 16, then minus the square root of 64. But that will be wrong.
What you should do is that you take this out first before you can find the square root eventually. 16 minus 64, that will give minus 48.
Then we divide all of this by 2.
And now we're having negative root. So, this means that we're going to have complex solutions from here.
But here is what we can do first.
X is equal to minus 4 plus or minus square root of 48.
Did I leave anything out?
The answer is yes. I left out the negative.
So, that means I should multiply everything by root of negative one.
And we divide by two.
But if you know very well, you will see that root 48 can be simplified.
Right?
Root 48 can be simplified as we have root 16 * 3.
16 is a perfect square and multiplied by three, we still have 48.
By the way, square root of negative one is imaginary.
And then we divide both sides, we divide all through by two on the right hand side.
At this point, I hope you know we can split this two.
So, we have X to be minus four plus or minus square root of 16 times square root of three times I.
This is all over two.
Okay, I've just obeyed one of the laws of sword.
Now, our X will now be minus four plus or minus square root of four square root of 16 is four.
Multiply by this I, so we have four I.
You know, I've not um written the root three, so we multiply by root three and we have this.
Remember that all of this all of this is over over two, right?
Yes, all of this is over two. Now, let's continue.
From here now, our X is minus four plus or minus Um okay, let's do it this way. That is minus four over two plus or minus four I root three over two.
So, if you go on, you can cancel out so that X will be two into minus four is minus two plus or minus two into 4 I that will be 2 I. Then we have root 3.
So, this is a two-in-one kind of solution.
Let's bring our complete solutions together.
We got X to be 4 as our first solution.
Then the second solution is X equals from there - 2 + 2 I root 3.
Then the third solution is - 2 - 2 I then we have root 3.
So, these are the three solutions to the given equation.
Thank you for watching.
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