Mmm ... Donuts ...

Added: 2026-05-24

[00:00:14]Hello. Welcome back to Cracking the Cryptic and uh puzzle based on donuts today. M donuts.

[00:00:22]Um no, peculiarly I don't eat donuts. I ate almost any unhealthy food, but for some reason I don't particularly like the texture of donuts. Don't know why, but Squander does and has created this new puzzle called square sprinkled donuts. Um there's plenty of rules, but they're very straightforward and and and very clever, very neat. I'll go through those in a moment. Um, I'm going to quickly tell you that Patreon is a fantastic place to go for extra videos, crosswords, there's an extra puzzle from the Spider-Man Sedoku hunt. I mean, there's the whole Spider-Man Sodoku hunt. You could do that. It's the competition's over, but it's still available. Extra puzzle was posted after the end of it. There's um there's solution videos for tier one and a half patrons and above. There's crossword and connections with Geroggram videos. Patreon is a great place to go for all your extra puzzle needs. There are um apps as well and they do feature Domino Sedoku very relevant to today.

[00:01:23]And classic Sudoku 2 and the worms. If you have mastered Domino Sedoku, I suspect you'll find today's puzzle quite easy. I don't know. I mean, I haven't tried it. I just say that. Um but there's the worms as well by blobs.

[00:01:37]Fantastic amongst others. Many other worms, fistell etc. Do check those out.

[00:01:42]And of course, we've got a bit of merch if you were interested in branding yourself with Cracking the Cryptic stuff. Um, you would just look cool if you did it. Give it a try. But let's have a look at the rules of Squander's first puzzle on the channel, Square Sprinkle Donuts. And he says, "Place."

[00:02:02]So, so normal Sudoka rules apply. One to nine will go in every row, every column, and every 3x3 box, but also in the shaded cells. one to nine will go in them as well. Um, now these are the holes in a series of nine donuts, which are the eight cells around the perimeter of each box. That's a donut in this puzzle. And then there are some following additional rules that are dubbed sprinkles that apply to each donut. So these donuts may feature a black crop key dot on which the digits have one be double the other, a white crop key dot with consecutive digits, an X where they add up to 10, or a V where they add up to five. Now for each doughut, which is this set of eight digits, all the possible sprinkles are given. So there can't be a missing.

[00:03:00]These two can't add up to 10 or there would be an X between them. That doesn't apply when you're considering either connections to the doughut hole or across donuts. It doesn't matter.

[00:03:13]But within the eight cell perimeter of each doughut, within the eight cell content of each doughut, all the sprinkles are given. Um and remember that these holes have to be different digits. There was another maths rule in the original puzzle, but my tester says it's not needed. So, we're going to try it like this. Give it a try on the first link under the video. I'm going to try now. Let's get cracking. So, some of these donuts have a lot of sprinkles and some very few. And I mean, isn't that the case when you see a set of donuts? Some of them have got a lot more than the others on. And I would always tend to choose the confectionary with more sprinkles. Let's have a look at this, which has got tons of sprinkles on it, including a sequence of four digits. Oh, no. Let's do V's. They're they're generally useful because we know the digits are less than five on each of them. They are going to consist of 1, two, three, or four. Now, on this donut, we have a sequence of four digits here. Could they they can't in this must include either three or four this V. So the lowest possible sequence here is 4567 and definitely six and seven will be in the sequence. It's 4567 56 78 or 6789.

[00:04:49]Actually, I'm even more tempted by by another donut with a variety of sprinkles on. This one's quite interesting.

[00:04:57]I mean, this is a classic doughut puzzle because you're just moving between the ones that are attempting you. In fact, that digit is two or four.

[00:05:08]Uh because this is a sequence of either 1 2 4 or 2 48.

[00:05:14]And two and four now can't appear on this X. I've I've moved. I've given up on that donut. I've gone straight to this one. Two and four can't appear on the X. So the X is either 3 7 or 1 N.

[00:05:26]This is an even digit because of the white dot. And it's not two or four because they're used in this sequence.

[00:05:33]So this even digit is 6 or 8. And now this can't be one or three by the white dot. And this can't be seven or nine by the X.

[00:05:43]So that was quite interesting. Also, I've only just noted this. This was a 1 2 3 4 quad in the column. Right? I'm coming back here because these two digits will have the same parity because of the white dot. When you're on a white dot, you change par from one cell to the other. So you change back and those will be the same parity. Now there are only two odd digits that could go on a black dot. If these digits were odd, they would be one and three. They would be joined at the hip by a two. And the one on the black dot wouldn't work because two would be there, but the one wanted a two on the black dot. So, these must be even and this must be odd. And I thought that was interesting, but I don't know why.

[00:06:34]Now, is it possible for these two digits? I'm I'm asking because of the x, which is either double even or double odd. Is it possible for that to be double even? Cuz then these would both be odd and they would be 1 and three and these would be two and six and they aren't joined together by any number. So no, that's not possible. So this can't be double even. That must be double odd and is either one 9 or 37 just like that one was.

[00:07:10]Um, I haven't really got very far, have I?

[00:07:14]That 1 2 3 four quad. This digit is not a five. It's 6 7 8 or nine. The five in the column is in one of those two cells.

[00:07:22]Maybe the puzzle is about fives. No, I don't think so. I don't think it is.

[00:07:28]These are even. That's odd.

[00:07:34]At least one of these is even. And they might both be if this was No. Is that possible? No, it's not. Weirdly, could these be the digits 2 4 68? No, because one of them would be one of them would be a six and can't join to two, four or eight on a black dot. So, since we know they can't both be odd because that doesn't work around the corner, and we know they can't both be even because of six, one is odd and one is even. And that means on these two cells, one is odd and one is even. Now, can this be the odd cell? It couldn't be one because it's got two dots and they would both need twos coming off it. If this is the odd cell in these corners, it's a three.

[00:08:32]And that's six.

[00:08:39]This is two or four.

[00:08:46]If that's a three, this is one. Nine. I don't know. I don't know. I thought I was going to reach a conclusion and I failed there.

[00:09:01]Yeah, it's tricky actually.

[00:09:04]I haven't got anywhere. There is either a two or a four there.

[00:09:10]Does that affect this X?

[00:09:14]Oh, if that was a 14 V, this X couldn't use 1 N or 46. Is that useful? No, that's not very useful.

[00:09:26]This white dot doesn't use any of the low digits. So, it's from higher numbers.

[00:09:36]H I don't quite know where we should be starting. And should I be using the negative constraint yet?

[00:09:47]I felt that was for later.

[00:09:52]That may have been cavalier of me.

[00:09:58]Yeah, I mean it's quite interesting to think about five being in one of these cells because if five is here, that digit has to be eight because it can't be next to six. If five is here, this can't be four. If five is here, neither of these can be four and one of them must be one.

[00:10:24]Okay, the negative constraints.

[00:10:25]Interesting, but not I don't know. I don't know what is powerful enough to get us going actually.

[00:10:34]Oh, this is quite low as well. This is become the white dot with 1 2 3 or four.

[00:10:39]It could be a five.

[00:10:42]And this is well, it's not allowed to be six because six is in that sequence. So, we can't have three there.

[00:10:51]Therefore, we can't have four here.

[00:10:53]Therefore, we can't have five here. And these have shrunk down a little bit.

[00:10:58]Now, either this digit is from 1 2 3 4.

[00:11:06]It could be 1 2 or four.

[00:11:10]And that's a quad of those. Or we have to burst out of 1 2 3 4 by this being eight.

[00:11:18]And that won't work. If this was an 84 black dot, this sequence can't happen because you can put five, six, seven on it, but nothing else. So, this is not allowed to be six, which is on the sequence. We've worked out it's not allowed to be eight. It must be from 1 2 3 4. That is a sequence of the digits 1 2 3 4. This is either 5678 with a nine in the hole or 9876 with a five in the hole. So, the digit in the hole is five or nine.

[00:11:50]H um three. Oh no. Yeah, that can't be three on the black dot. So three is on the white dot and one isn't. And now one's on the black dot with two.

[00:12:04]And that means four is in this cell, three is in this one, two on the V, and one on the black dot. And we've got started finally.

[00:12:14]Now that's not four. That's not three.

[00:12:18]And therefore this V, this can't be one anymore. And this can't be even anymore.

[00:12:28]Um, and this is now even as well.

[00:12:37]And that's a 68 pair in the column. And we've had a 1 2 3 4 quad. So everything else is from 579.

[00:12:46]Right. Negative constraint. This can't be five. So if this was a 5678 quad, it must start with the five here.

[00:12:55]Oh, this also can't be eight because there's no black dot. So this can't be a 5678 quad. It must be 6 7 8 9 and six can't be this end because of the four being next to it and no X.

[00:13:09]So they are done. And we get a five in the middle there. Six and one perfectly valid pair to sit next to each other.

[00:13:18]Now we can't repeat five in the center of a donut.

[00:13:23]Um has that sort Yes, it's sorted out this cell. This is now eight. That's two on the X, three on the V. Down here we've got a 1 four pair and therefore we've also got a 23 pair.

[00:13:37]That has become six. This must be seven on the X with three This is now neither of these are seven.

[00:13:44]And this can't be five because we'd have a white dot. So that's nine. That's five. This can't be four or we'd have a white dot. I'm good at spotting the non-white dot connections and probably nothing else. That can't be eight now.

[00:13:58]So there's definitely a two on this black dot. It's made up of one, two, or four. And there's not a two in that cell.

[00:14:06]Now we can't have five in a donut again.

[00:14:09]So five is going to have to sit here.

[00:14:11]and that can't be four. So that's one or eight. And this must be a two four pair.

[00:14:16]And this digit is 1 or eight. We don't have to worry about the center of the donut in terms of the negative constraint.

[00:14:24]This x can't be 28 or 37. It's 14 or 69. And this 49 pair forces the four or nine into those that cell. Um, this doesn't have a five on this digit. Right. There can there are some things I can rule out of here.

[00:14:50]Obviously, 1 2 3 4 5 are all ruled out.

[00:14:52]Six is ruled out because of no x. Eight is ruled out because of no white dot.

[00:14:57]This digit is seven or nine. There is an odd digit here. So, this one is six or eight.

[00:15:07]Um, right. Let's try this. If this if this was 91, this is 84.

[00:15:16]This must be 76 in that case. But I have to get right. The way I should have looked at this is where do I put two and three in this column? Or more simply, where do I put three in the column? It's got to be there.

[00:15:30]And two in the column has to be here.

[00:15:32]Don't worry about them not being connected. They're different donuts.

[00:15:37]Two connects to one there. And we've got eight in the hole.

[00:15:44]This pair. Oh, hang on. This one first is six. That goes with four. These don't have six on. They do have eight on. And this digit is six.

[00:15:54]And that doesn't resolve this one. Three and seven can't be next to each other without an X.

[00:16:03]Um, up here we've got 1 five. That is seven or nine.

[00:16:09]This can't be seven or nine because it would be next to eight with a white dot.

[00:16:13]So, it's one or five. This can't be seven and be next to three or six indeed. And it can't be five and be next to six without a white dot. So, that's one or nine.

[00:16:28]Now by Sudoku, which I've hardly used in this puzzle. 75324 86. This is one or nine. So that seems to be a 1 nine pair.

[00:16:36]Then I can fill in seven and five. Take seven out of that cell. Put it here. And seven next to eight would need a white dot. So that's done.

[00:16:46]Right, we are suddenly motoring. That one and nine is done by Sudoku because of this nine. This is a 257 triple. This is a 168 triple. This is a 349 triple.

[00:17:00]Which of those can't be on the black dot? It's nine. So the black dot cells here are three and four. They must be connecting to six and eight. And I'm going to put one in the donut hole.

[00:17:11]And six or eight on the white dot won't connect to two.

[00:17:18]Six or eight there would connect to seven with a white dot here. And there's no white dot. So that's not seven.

[00:17:26]I can't see anything else obvious there.

[00:17:28]Let's look at this digit which can't be 1 six or eight. It's a it's a black dot digit. So it's two or four. We worked out earlier it wasn't odd. So it's even.

[00:17:40]This is odd and is it can't be one or it would need twos in both cells. So it's three or five. But this can't go 2 3 4 without breaking this.

[00:17:52]So if that's a three, this is a two. If that's a five, this is a six.

[00:17:59]It's all militated by that four.

[00:18:04]Now, this is either Yeah, I don't know what it is. 2 3 4 25 six. Now, one of these had to be odd. We worked out earlier for some brilliant reason because if they were both even, six would be connecting to the wrong thing.

[00:18:19]So, one of them is odd. And it's not.

[00:18:22]Oh, it could. No, it can't be this one.

[00:18:25]because one isn't allowed there or it would need two in both cells. So that's even. This is the odd digit and is I was going to say three, but actually I don't know whether it's one or three.

[00:18:36]What I do know is that both one and three are now used in these cells. And that digit at the top is a four. That's eight. That's seven. This is three. Six.

[00:18:48]Not five adjacent to six because there'd be a white sprinkle.

[00:18:53]That two gives us four here which make which doesn't resolve the bottom cell.

[00:18:59]This one is not allowed to be two though. So it must be eight. And this is seven or nine.

[00:19:07]That's a 1379 quad. We've had eight four.

[00:19:12]One of these I can't use again. Three.

[00:19:15]So that's a five. That's a six. That's a three on the black dot. This is a one nine pair. That's a seven. And we get a two in this in the hole. And that's the sort of thing we wanted because we've had 519 862 in the holes.

[00:19:34]This one can't be seven.

[00:19:37]No, that one can't be four.

[00:19:41]Right. Let's just go up here. We've got 179 still to fill in. Must be one nine on the X and a seven there. How did I get into the colors?

[00:19:51]seven there. That's going with three.

[00:19:54]That puts four in the hole. The other two remaining doughut holes are three and seven. This is a an eight.

[00:20:03]Eight can't be next to nine or we'd get a sprinkle. This is 256. I think the two has to keep five and six apart otherwise they would get a sprinkle between them.

[00:20:15]And one nine here. I can't. Oh, I can do Sudoku. So, the rest is just going to fall out by Sudoku. I think we get a nine and a two four on the black dot. In this row, we've got 357.

[00:20:31]In this row, we've got 168. The one must be there in a column with 68 already in it. 6 and 8. Here, I can't make this a seven or there would be a sprinkle, a white dot. So, that's a five. And now this can't be six. So that kind of sorts it all out. 37.

[00:20:51]Oh, it doesn't resolve that pair. But I'm sure we'll do that shortly. This digit is a naked six touching seven and on the X touching four. It seems to be working.

[00:21:05]28 pair on the X here.

[00:21:09]And we get two and four. And that's not too hard. That's quite fun though. Very nice puzzle. um squander. I think what the original rule was I was told was that these three added up to these three and these three and the same you could kind of draw a region sum line down all of these columns. I mean there's all sorts of roping or something going on here. There's some very similar rows.

[00:21:37]I think we've got maximal No, not roping actually in these three rows, but very similar digits. Anyway, that's a fascinating puzzle and uh the donuts are square and are sprinkled and were fun and we won't squander them. We will enjoy them. Thank you for watching us on the channel. It's absolute pleasure to bring these puzzles to you every day and I hope to see you again tomorrow. Bye for now.