Redox Reactions | Class 11 Chemistry | Most Important Questions + PYQs | JEE & EAPCET | Suhel Sir

[00:01:49]Hi. Hi. Hi. Hi. Hi. Hi. Hi. Hi. Hello.

[00:01:51]Hello. Hello. Hello. Hello. Hello.

[00:01:53]Hello. Hello. Hello. Hello. Hi guys. How are you?

[00:01:57]Reactions. Okay.

[00:02:00]So, this is okay guys. Are you ready?

[00:02:09]Are you ready?

[00:02:13]Say SS SS.

[00:02:19]Are you ready?

[00:02:35]SS hi hi sir mic background sir buzzing yeah now it's clear now it's clear now sound is clear pritu yes it sound is clear very very clear okay now okay Now the sound is clear. Video is clear.

[00:03:09]Everything is clear now.

[00:03:12]Redux reactions.

[00:03:16]Redux reactions. First like the guys.

[00:03:19]Like the first set reactions and the user. How many very very easy very easy.

[00:03:45]Okay.

[00:03:50]Okay. We will do all PQS.

[00:03:55]You have doubts. Okay, Monica, what is your doubt? You can ask me.

[00:04:04]What is your doubt?

[00:04:21]oxidation.

[00:04:24]Okay.

[00:04:26]So that is change in oxidation number that is known as oxidation.

[00:04:43]Oxidation and reduction that is gain of oxygen gain of oxygen and loss of hydrogen.

[00:05:07]Okay. Next. Next gain of hydrogen and loss of oxygen. Same same oxidation number increase in oxidation number.

[00:05:32]increase in oxidation number and uh decrease in oxidation number sir. Okay. What is meant by oxidation number? You doubt don't see what is meant by alteration number anyone have doubt what is meant by oxidation numbering.

[00:06:00]What is meant by alteration number? How many what is meant by oxidation number?

[00:06:10]What is meant by oxidation number?

[00:06:16]Okay. Like only once. So that is one group elements that is all number is one two and that is two. Okay. Now next three group elements three elements four elements.

[00:06:36]So this have the what is your oxidation means increase in oxidation number from reactant to product number.

[00:06:52]Okay. So that is change in number from reactant to product two that is nitrogen family that is three nitrogen family that is five group elements that is nitrogen family oxygen family okay that is minus2 not always minus2 for oxygen 7 group elements that is minus one that is 8 group that is gases that is zero max to max okay and oxygen not always minus2 not always minus2 okay not always minus2. So sometimes it will have KO2 super oxide super oxide. Okay, this is - 1 by2 for super oxides and peroxides H2O2.

[00:08:15]So these times it is it will be have minus1 this is known as peroxides where you went where you gone where you are.

[00:08:43]So peroxide.

[00:08:48]Okay.

[00:08:50]Okay. Now Monica N2 N2.

[00:09:25]Okay. N2 N2US N2.

[00:09:36]So at that two surrounding atoms two.

[00:09:40]Okay. and valence that okay that is surrounding atoms okay and valence electrons of central metal atom okay plus minus Q charge okay plus - Q charge plus - Q charge and uh minus N into valency of side atoms by two. Okay.

[00:10:35]Now 5 + 1 - 2.

[00:10:43]So 2 into 2 that is four.

[00:10:47]4 by 2 that is 2a 1 that is two bond pairs one pair same are you get clear okay now not is it is all electrons SP Guys, guys, not okay for elements. Okay, elements max.

[00:12:11]Max no problem guys because this is the for maximum.

[00:12:40]Okay. Now it is going to be very very easy.

[00:13:06]Okay, next reaction is not topic. Okay, very good.

[00:13:32]Okay, next.

[00:13:35]Okay. So this is also not only not 100%us. Okay. 100% okay same not only guys tomorrow I will give structures.

[00:14:05]Okay.

[00:14:09]Tomorrow I will give lecture and day after tomorrow I will give for formal charge. Formal charge also very very important. Formal charge also. Okay. Now next guys. Hi, why you are not attending that pense and attend sessions and you and uh Sai Krishna also not attended these uh okay joined where where all numbers So we have we have method that all seration number finding by all number finding by finding method.

[00:15:12]So finding the first method is fore another example.

[00:15:41]H4 C3 minus C. So guys, it is very very easy.

[00:15:55]Okay. Okay. Okay. Okay. No problem. So it% chemistry and exceptions exceptions.

[00:16:12]Okay.

[00:16:17]20 + x + x - 10 = 40.

[00:16:28]20 + 40 + x - 10= 40 then x value then x value this guys 20 + x - 10= 40 okay then x value how Okay.

[00:16:58]Answer it guys. 20 + x - 10 = 40 x value.

[00:17:03]Hello madams s. Yeah it is 30. Very good. Yes it is 30. So I'm asking another question that is 10 + x - 2 =0 10 + x -=0 so x value how much no problem okay x How much? 10 x - 2 = 0. How much x value?

[00:17:48]Yes. x = very good. Okay.

[00:17:59]So it is hydrogen, lithium, sodium, potassium. So this is 100. So this is 2 + 200 2x 2x 7 - 7 into 2 that is 14.

[00:18:30]So 2 + 2x - 14 that is charge.

[00:18:37]So charge okay guys. Okay that is belongs to one group elements group.

[00:18:50]Okay. Now, okay. Okay. Okay. Very good. Very good.

[00:19:04]Hydrogen belongs to one group element.

[00:19:09]Okay.

[00:19:11]Okay.

[00:19:20]2. So 4 into 2 that is 8. So - 8 - 8= 0. Okay.

[00:19:29]CL3 CL3 is X X three values 2 so that is 3 into 2 that is 3 into 2 that is - 6= why charge so that is the us.

[00:20:01]So that is x = So oxidation number of cr is 6 that is so = = that is five.

[00:20:27]So these are the oxidation numbers.

[00:20:29]Okay.

[00:20:30]easy. So from that I'm giving you one question. Okay. Now they'll see electrons and group YOU WILL GET VALENCE ELECTRONS VALANCE VERY VERY VERY VERY very easy okay NO2 N2 and NO3 minus answer anyone answer this anyone anyone and answering anyone so everyone for anyone.

[00:22:10]So nitrogen.

[00:22:18]So nitrogen. So x - 2 = oxygen is having soal that is x= next 2 so n2 x - 4 =0 so x = 4 x= 4 + N2.

[00:23:04]So N2 that is 2X - 2 = 0. So X = + 1 N 3 minus. So that is X - 6 = -1. So X = + Okay. So higher NO3 minus NO3US NO3US NO2 NO N2 Answer is D C D is the right answer.

[00:23:46]D is the correct answer.

[00:24:09]D is oxid of H2O2.

[00:24:28]Which of the following reaction is an example of redox reaction? So red reaction both oxidation plus reduction increase in oxidation number increase in oxidation numberation reduction decrease in oxidation number that is known as reduction. Okay, you get clarity. So X E F6.

[00:25:18]Okay.

[00:25:24]X E F that is -4 -4 Z F6 -4 G + 4 G + 6 all situation increase. So oxidation.

[00:26:00]Okay.

[00:26:03]This is plus.

[00:26:10]So, XF2US that is zero.

[00:26:48]So oxidation and reduction taking place only one place is the right answer.

[00:26:58]A is the correct answer.

[00:27:01]A is the correct answer.

[00:27:11]A is okay. Next question. This is for your homework coma.

[00:27:28]Redux reaction. Reduction total that is reduction. It is very very easy.

[00:27:49]Na Na plus CL minus K plus CL minus okay NA3 that is X - 3 - 6 Guys, yes.

[00:28:29]Four. Okay. Now the answer 1 2 3. Okay.

[00:28:37]It is September 2020 question. Okay.

[00:28:43]Okay. Guys, the oxygen set of transition metal atom K2 CR27 K2 CR2O7 K M4 and F2 FO4 sorry K2 FO4 Okay. XY XY Z the sum of XY.

[00:29:17]So transition element that is CR2 M that is D block elements. So D block elements all number. So C2 M and F. So finally guys answer it guys max to It's also candy.

[00:30:06]How's the guys?

[00:30:25]This is X.

[00:30:32]It is all questions K RC 27 answer is X = 6 X = 6 2 + 2X -4 So X Very good. Very good. Very good.

[00:31:24]Yes. Super.

[00:31:28]Okay.

[00:31:30]I'm very appreciate them. Okay, they're also super they're super teachers.

[00:31:37]I'm very happy with them.

[00:31:50]So that is 1 + x - 8. So x = So that is + 7. Okay. + 7 + 6 2 + x - 8 x = + 6. So 676 676 676 that is uh calcul 6 + 7 13 6 19 as answer is 19. So x + x + y + z = 19 is the corre correct answer. Correct answer. Correct.

[00:32:57]Question number is also very very easiest. easiest.

[00:33:27]Increasing order.

[00:33:30]Increasing order.

[00:33:38]Super Malikar zuna. Malikar zuna.

[00:34:10]S3 2 - x - 6 = -2 2x - 8 = -2 2x - 12 = -2. Okay.

[00:34:27]So x -= - x - x = + 4 2x - x= that is 2x 6= 6.

[00:34:51]So 2x - 12= - 2 2x = 10 x= this is 4 this is 6 6 sorry sorry x = 3 x = 5 so 4 3 5 So H2O 2 minus is lesser than SO32 minus S. Answer is C.

[00:35:31]Super super.

[00:35:36]Next one is nexting oxidation.

[00:35:51]Reduction oxidizing sorry reducing agent reduction oxidizing agent.

[00:36:20]Okay, that is texture.

[00:36:30]Actually, this is homework. Homework.

[00:36:33]Homework. Homework. Homework.

[00:36:37]Statement is correct.

[00:36:41]Oxiding agent.

[00:36:44]Oxidizing agent.

[00:36:54]reducing agent under oxidation. reducing agent.

[00:37:03]Okay.

[00:37:08]Sn4 sn reduceuction reduction reduction reduction reduction under reduction. So answer is C.

[00:37:26]and there H2SO3 H4 H2SO3 H S O4 minus so 2 + X - 6 so XA that is 4.

[00:37:55]So 1 + x - 7 - 8 = -1. So six.

[00:38:09]So four that is oxidation.

[00:38:13]That is reducing agent.

[00:38:17]Yes. Answer is C. See that is H SO3 HS sorry H2SO3 H SS O4 minus. So there is a reducing agent. Okay, that is +.

[00:38:54]So which of the following plus oxidation plus 6 ox it is also very very easy.

[00:38:59]Okay, I'm giving you 2 minutes answer this guys.

[00:39:02]I'm giving 2 minutes.

[00:39:06]Answer this Har Krishna Shait 8 minutes break 8 minutes break I'm giving you 2 minutes for uh giving answer Okay.

[00:40:17]Mus x - 8= x = 7 X - C that is - So X - 6 = - 3.

[00:40:42]So x= 3 c 23us root simple 2x - 6 = 2x + 6 oxidation number homework simple 2x sorry x - 2 sorry x - 4 - 2 x = + 6 is the answer d are d are 2x - 6 x = + 3 so as is Oh no. Oh no.

[00:41:44]Answer is place three.

[00:42:23]Okay. Some special cases special cases of finding oxidation number that is I'm giving you example as B R3 I'm giving example as B R3 anyone Answer this. What is the alteration number of P R3?

[00:43:00]Anyone answer this?

[00:43:04]First like the s guys like the s.

[00:43:11]If you have any doubt ask me in chings not spammings.

[00:43:31]Answer this 3x - 16 = 0. So x = 16.

[00:43:57]So we have a particular method. Okay.

[00:43:59]Now we have particular method.

[00:44:03]We have particular method for that. Now by diagram okay so bromoide.

[00:44:14]Okay. So that is the name average.

[00:44:39]Double bond. Double bond. Double bond.

[00:44:42]Double bond.

[00:44:44]Double bond double bond Br3.

[00:44:55]Okay. So double bond this is -2 -2 -2 -2us.

[00:45:10]Okay.

[00:45:18]+ 2 + 2 guys. Super super super.

[00:45:27]So total broine having plus six. The first problem -2 - 2 this is + 2 + 2 this is + 4 - 2 - 2 minus two.

[00:46:17][singing] So plus 6 + 4 plus 6. Okay.

[00:46:29]plus this is very very important guysh this is a J advanc question my my my sir chala Easy.

[00:47:01]Na2 S46 Na2 S46.

[00:47:14]So like that is 2 + 4x - 6 that is equal to 0.

[00:47:31]So 4x = 4x = m.

[00:47:38]So irre + 12 that is x = 2.5.

[00:47:53]So x = 2.5 x = 2.5 X= 2.5.

[00:48:22]Okay.

[00:48:29]So, this is going to be S46. S46. S406 NA2 S406 NA2 S406 S4 600 warm as NA plus So heat.

[00:49:45]only one single double.

[00:49:52]Okay. This is minus.

[00:49:56]Okay.

[00:50:02]-2.

[00:50:06]This is + -2 -1. So this is + 5. Okay.

[00:50:28]This is also so total.

[00:50:49]So total plus this is -2 sorry + 2 + 1 + 2. So total this is plus.

[00:51:13]Okay.

[00:51:26]So total allers all equal to + 5 comma 0 + 5.

[00:51:39]So this is ground.

[00:52:04]Suppose H2 S27 H2 H2 07 H2 H2O7.

[00:52:20]So s double bond double bond double bond double bond single bond single bond single bond single bond hmet.

[00:52:37]Okay guys, so this is a -2 -2 -1 -2us okay + 1 + 2 + 2 charger. Okay.

[00:53:13]+ 2 + 2 + 1 guys.

[00:53:36]+ 5 + 5.

[00:53:40]This is a Okay.

[00:54:20]H2 H2 H2O7 and H2 H27.

[00:54:31]So joint.

[00:54:34]So sulfur joint sulfur sulfur double bond double bond double bond double bond single bond O single bond Oxen that is single bond is so that is the reason. Okay, that is the reason.

[00:55:42]This is minus2 charge minus1 charge. Okay. Single bondus charge.

[00:56:00]Okay.

[00:56:04]So x= that is belongs to oxygen.

[00:56:11]So, so Eusf this is This way we're going to guys hydrocarbons.

[00:57:01]example that is 2 + 2x - 14 = 0. So x = that is plus this is wrong method. Okay. So next step next one is next one is C I okay C I so X - 10=0 X = 10 okay total D2 because so that is C and C R double bond oxygen oxygen oxygen oxygen. So butterfly butterfly butterfly.

[00:58:17]So butterfly y negative means oxygen is having minus2 charge minus2 ox.

[00:58:56]This is -1. This is -1. This is -1. This is -1. This is -2. So + 2 + 1 + 1 + 1 + 1 total this is six charge and two peroxy linkages.

[00:59:16]Okay. Now two peroxil ges one time and two perox also there.

[00:59:51]Okay. No.

[01:02:29]Okay, next question.

[01:02:42]This is advanced version that is first question is uh BR3 BR3 F_sub_2 V H S H S H S H S H S H S H S H S H S H S2 S4 RO 6 H S H S H S H S H S H S H S H S H S H S2 S46 H S H S H S H S H S H S H S H S H S H S2 S500 B3 that is BR.

[01:03:27]So, so this is this is plus four. This is 2 minutes. Okay. F2 F2 F2 Vo F2 F2 F2 F2 F2 So 2 - x =0 So x = + So Thank someone.

[01:04:24]Another H2S4600 So this is the structure. So consider the following B3 HS4.

[01:05:09]So link zero zero oxidation state.

[01:05:17]So, either J + 5 + 5.

[01:05:43]H2S50 S2 S5,000 Yes. Yes. Yes. Yes. Double bond O H double bond double bond double bond double bond single bond O H okay then these three oxidation states are zero So Jesse plus five plus C32 C32 C32 C32 C32 C3, CR2, or CR3. Ah, C3. C3, double bond, double bond, double bond, double bond. This is C3.

[01:07:09]This is C3.

[01:07:21]Okay, these are the types in oxidation number. Next one, types of redux reaction that is combination reaction, decomposition reaction, displacement reaction.

[01:07:35]This is also very well known.

[01:07:42]Double displacement reaction. It is also very well known guys combination combine single product form combination. So that is C plus O2 CO2 H2 plus to 2 H2O.

[01:08:10]Okay.

[01:08:13]the decomposition in the brains of light heat, light, electricity.

[01:08:25]So examples are uh 2 ABR gives rise to 2 A plus uh Br2 in the brains of heat.

[01:08:44]Okay.

[01:08:50]So, one type of endic. Okay.

[01:08:55]Most of them are most of them are uh endothermic conduction.

[01:09:10]So potassium, sodium, calcium, magnesium, aluminium, zinc, ferrus, lead, hydrogen, copper, mercury, silver and gold that is potassium, sodium, calcium, magnesium, aluminium, zinc.

[01:09:38]Ferrus, lead, hydrogen, copper, mercury, a silver, au.

[01:10:02]Okay. Now, so this is zinc.

[01:10:28]So it is easily replaces. Okay.

[01:10:33]Aluminium.

[01:10:37]Okay. That is okay. Next one.

[01:10:44]Double displacement.

[01:10:47]Both ions both ions replaces double disment. Okay. Now both ions exchanged okay are displace. So that is known as double displacement reaction.

[01:11:07]Okay. Next one guys disproportionation reaction. Okay guys, uh I will be back in uh 10 minutes.

[01:11:17]Okay, now 10 minutes. Okay, only 10 minutes. I will be back in 10 minutes.

[01:20:59]Heat. Heat.

[01:29:51]Hi. Hi. Hi. Hi.

[01:30:26]disproportion.

[01:30:28]Okay. An element an element in one oxygen is a oxidation joint both. Okay. Now okay element joint first this is the element in which it goes both reduction.

[01:30:53]So disproportionation reaction.

[01:30:58]So P4 this is oxidation state is zero.

[01:31:03]P4 oxidation state is zero. So PH3 H3 Ponal.

[01:31:13]So that is okay. Now same has 32 PU.

[01:31:22]Okay.

[01:31:24]This is okay. Sous 3 and + one.

[01:31:31]So that is reduction.

[01:31:43]So that is okay. Now that is Next one guys.

[01:32:07]And reversible of reversible of that is protonation reaction.

[01:32:23]Reversible So reversal to protonation reaction. So reaction reaction same reactant. Okay.

[01:34:02]of element oxidation reduction from reactant both reaction both.

[01:34:19]So that is from a single element of product under goes both oxidation reduction.

[01:34:45]This is okay. Next one guys.

[01:34:50]Next one is normality.

[01:35:15]It is going to be very very easy guys.

[01:35:18]Very very easy.

[01:35:24]Okay.

[01:35:58]challenge.

[01:36:00]Okay.

[01:36:03]Normal normal equal to g equivalent into 1,000 by v ml formula. So g equivalent equal to weight by okay equivalent weight by equivalent weight.

[01:36:32]that is given weight. Okay. Next formula normality equal to weight by equivalent weight into,000 by V in ml this. Okay. Second form.

[01:36:52]Next one guys. Equivalent weight equal to molar mass.

[01:37:06]Molar mass by factor factor.

[01:37:18]Okay. This is uh n factor or valency or charge.

[01:37:31]So guys, so that is molar mass atomic weight by molar mass by N factor or valency or uh charge in this quantum. Okay.

[01:38:03]So this is so equivalent weight equal to molar mass by n factor or valency or charge in this.

[01:38:20]So this is okay. Huh?

[01:38:30]So E. Okay. So normal equal to weight by molar mass by N factor.

[01:38:52]Okay. into,000 VL.

[01:39:08]So this is now my final formula is n = that is weight by molar mass and m transpose mole into n factor into 1,000 by v Okay. So that is so n= that is factor into hity that is facul two formulas.

[01:40:15]These are the final formulas.

[01:40:19]These are the final formulas.

[01:40:32]factor into so that factor. Okay. So that is N= VL. So equivalent that is equivalent by equivalent weight by equivalent. Okay. Now this is about normality.

[01:41:01]Okay.

[01:41:06]Okay.

[01:41:17]Okay.

[01:41:23]Otherwise equivalent.

[01:41:36]Okay.

[01:41:54]So next. Okay.

[01:42:09]Okay.

[01:42:15]It is also very very important equivalent rules quotient's law.

[01:42:36]The first rule is 1 g hydrogen or 1 mole hydrogen. This one not H2.

[01:42:48]Next rule 8 g oxygen or 1x2 mole oxygen this.

[01:43:02]Okay.

[01:43:03]1 oxygen atom.

[01:43:06]Okay. Next, chlorine 35.5 g chlorine are one mole chlorine atoms atom.

[01:43:27]This is next 198 g. 198 g au that is Ag or 1 A.

[01:44:04]Okay.

[01:44:09]22.4 L or 32.4 Liter ge this one uh 22 sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry sorry 28 g sorry sorry sorry sorry guys 28 g or 11.2 2 L.

[01:44:30]Okay.

[01:44:48]My first question is equation metal oxide metal oxide metal oxide that is ming metal oxide M okay 60% metal 60% metal and 40% oxygen remaining 40% 60% of metal by mass carry at the equivalent mass of metal 100 equivalent mass of metal So equivalent of equivalent weight rules for finding equivalent weight and Sorry.

[01:45:48]So equivalent weight of metal. So join metal plus oxygen.

[01:45:57]Metal plus oxygen use metal oxide. So uh 60%. So that is 60.

[01:46:09]This is 60 40 60 mass for finding 8 g of the mass mass 8 g. So it is 8 g. So find out. So x = So x = 60 into 8 by 40. So 8 1 are 8 5 are so that is 60 by 5 also. So it is 12 g.

[01:46:55]It is also 12 guys.

[01:47:20]Okay. Metal chloride.

[01:47:23]Okay. metal chloride. So in that metal and chloride so metal is 25%.

[01:47:35]So that is so that is 35.5.

[01:47:43]So x = 25 into 35.5 by 75 1 3. So it is 12 and 11.9 very very simple.

[01:48:06]Okay. Now, answer it. Anyone 74.5 g of metallic chloride? So MCL MCL so in that it is 74.5 g total 7 74.5 g total 74.5 in that 35.5 chlorine so that is 39 yeah it is going to be 39 39. So metal is 35.5 and chlorine that is 39. Sorry, sorry guys.

[01:49:19]35.5 39 So metal 39 metal 39 35.5 so equivalent mass so chlorine 35.5 So x= 39 into 35.5 by 35.5.

[01:50:08]So once cancel. So x equal to 39. Answer is 39.

[01:50:14]Answer is 39.

[01:50:18]That is answer.

[01:50:23]Okay.

[01:50:29]Guys, I'm giving you hints.

[01:50:48]molar mass factor valum or charge.

[01:51:02]Okay. So first that is basicity.

[01:51:18]So that is the name number of H+ ions replaceable individual basis that is That is number of replaceable H minus H+.

[01:52:33]Okay.

[01:52:44]Total charge of positive or negative this total loss of positive or uh negative. Do this one.

[01:53:24]Okay.

[01:53:31]1 2 3 4 3 2 1 0 charge and direct charge that is okay for CO3 2 -1.

[01:53:55]So charge is equal to M& charge equal to okay guys anyone listening the class anyone anyone SP.

[01:55:24]I should have learned it. Equivalent weight mass of SO2 in 800. Equivalent mass that is equivalent weight equal to atomic weight by Equivalent weight equal to equivalent weight equal to that is molar mass by valency and jump.

[01:56:22]So, so SO2 mass mass sorry SO2 Let's balance that is x - 4 =0. So x = + 4 i equal and s3 s3 and that is x - 6 =0. So x = So equivalent equivalent weight of uh first this is first one by equivalent weight of second equal to so molar mass of the atom That is mar mass of the atom only weight of sorry mass of mass of sulfur by sulfur by the four by mass of sulfur equivalent weight of that is the 8. So 8 by equivalent to equivalent to equal to 6x4. So equivalent weight 2 = to 84 32x 6.

[01:58:47]So that is 32x 6 16x3 16x3 answer 16 by3 answer guys So equal management of mass of only so 32.

[01:59:33]Okay.

[01:59:36]So that is mass by mass.

[01:59:48]Okay.

[01:59:52]Equation agent HC Cl2 and H2 CL2 simple equivalent weight of one.

[02:01:30]Equivalent weight of two.

[02:01:37]So that is sorry. Valance is this composite equivalent. Valance is this one valency 2.

[02:01:54]So valent of SL2. So sc2 x - 2 = + 2 equal to0 then x = + 2 so first one get the +2 balancing second balancing s2 that is equal to 0 2x - 2 =0 so x = + 1 so this is second balance okay so 20 guys. Easy there.

[02:02:30]Equivalent weight of 1 by equivalent weight of 2 equal to okay.

[02:02:40]So that is sulfur mass of sulfur by valency. Valance that is two by by by by mass of sulfur divided by one.

[02:03:04]So that is 6 by = 1 by 2. So x = 12 12 g answer is 12 g. So x am that is equivalent weight of sulfur in H2 that is answer.

[02:03:34]That is answer.

[02:03:40]That is answer guys.

[02:03:50]You get clarity or not.

[02:04:51]There you go.

[02:05:23]Ging equivalent weight in charge Okay, that is equivalent weight equal to formal mass.

[02:06:07]Formal mass divided by charge.

[02:06:20]Example C3 2us.

[02:06:26]This is example.

[02:06:29]So C3.

[02:06:40]So CO3 2 minus. So that is 12 plus three into 16 by charge 2. So that is the answer that is the equivalent weight.

[02:07:13]that is the equivalent weight. So that is uh 63 is 48 40 60 by2 that is 30 30 answer 30 answer so 2 minus answer. So equivalent weight equal to equivalent weight equal to S4.

[02:07:40]So sulfur is 32 plus all sides 49 4 into 16 by 2 charge 2. So that is 64 + 32 96 96 by 2 48 coordinate.

[02:08:12]Okay. Now this is equivalent weight equivalent weight in salts.

[02:08:29]Okay. Equivalent compounds that is uh molar mass by total positive or negative. you this.

[02:09:03]This is [snorts] prais.

[02:09:18]So example that is na plus minus.

[02:09:31]So that is equivalent rate equal to ncl is 23 + 35.5 that is 58.5 by 1 same example A L2 S4 thrice that is the plus three.

[02:10:15]So charge equivalent atomic weight.

[02:10:25]Okay. Now mass by charge.

[02:10:30]Okay. Now 2 into 3 that is mass by charge that is.

[02:10:42]Okay. Yeah, special case for uh phosphorus unbonding.

[02:11:11]My questions are H3 P4 H3 PO3 H3 P2 H3 P4 diagram first double bond O double bond oxen combination that is acid.

[02:11:50]So three combinations.

[02:11:58]So that is acidity basicity equal to Three basicity three of them. Okay.

[02:12:21]P bond O Hing.

[02:12:35]So that is the reason E H E H. So that is a1 basicity is two3.

[02:13:02]So that is hydrogen hydrogen. So we could only CCD equal to one of them.

[02:13:38]You want a question?

[02:13:41]Question. Answer.

[02:13:44]Answer this.

[02:13:59]Okay.

[02:13:59]from tomorrow. Next class 12 start.

[02:14:08]Next class 12 solution start solution.

[02:14:36]So start I take only 10 minutes break.

[02:14:46]Okay.

[02:14:49][laughter] Only 10 minutes.

[02:22:59]Hello. Hello.

[02:23:22]here given marity and given S3. So H3 bond single bond O single bond H single bond H that is Havity. So that is that is n factor equal to n factor. So normal dn equal to n factor into marity. So n factor is 2 2 into 0.3. So that is 0.6.

[02:23:59]Okay. Next one.

[02:24:06]So that is before solution and after solution before and uh after. So that is n_sub_1 v_sub_1 = n_sub_2 v_sub_2 and this one.

[02:24:27]Okay.

[02:24:27]Nextures easy. So two three type of solutions mixtures.

[02:24:42]So this is n1 v1 + n_sub_2 v2 plus n3 sorry n1 v1 plus n2 v2 gives equal to gives rise to n3 v3 that is n3 final v.

[02:25:00]So n final guys n final be small transm capital n1 v1 plus capital n_sub_2 v2 u equal to nf final vfal.

[02:25:15]So n final equal to n_sub_1 v1 + n_sub_2 v2 by v this.

[02:25:27]Okay.

[02:25:28]So for mixture two types acid acid okay base so acid acid place that is n_sub_1 v_sub_1 + n_sub_2 v_sub_2 = nf final vf final this mixture mixing acid base n1 N1 V_sub_1 - N_sub_2 V_sub_2 = N final V final this okay these are the final formulas these are the formulas so guys we will do the question question 1 g of Na and 1 g of HCl are mixed with together in one liter of the solution find the nature of the solution 1 g of 1 g of answer it guys.

[02:27:08]It is too easy.

[02:27:14]Very very easy.

[02:27:32]So that is N1 V1 + N_sub_2 that is N1 V1US N2 V2 this equal to N final V why So 1 g= 1x 40 1x 40. So that is 0.25 0.025.

[02:28:19]Okay. 1x 40.0 1x 40. Next one guys 1 g.

[02:28:32]So that is uh 1 by n = 35.5 1 by 35.5.

[02:28:42]So this is acid is greater than basic final answer. So find the nature of solution. So nature of solution that is acidic solution acidic solution.

[02:29:00]Acid solution.

[02:29:03]Okay. So okay equivalent.

[02:29:10]So equivalent weight find the solution for suppose equivalent weight.

[02:29:15]Okay that is acidic solution that is acidic solution.

[02:29:20]Okay. Oh guys, I will give second part of 0.14.

[02:29:45]This is acid.

[02:29:48][clears throat] This is base.

[02:29:54]So n1 v1 mixed. So acid minus n_sub_2 v2 equal to nf v. So n_sub_1 is n_sub_1 is nity n = n factor into marity.

[02:30:19]So h24 that is 2 into marity 0.1 that is equal to 0.2 next to JC this is for first normality of two second one is 0.2 So that is 1 into 0.2. So that is 0.2 this so n1 is 0.2 into 30 ml 30 ml minus n_sub_2 0.2 N2 into 50 ml equal to N final. N final requal that is 30 ml + 50 ml 30 ml + 50 ml 30 + 50 Okay 30 ml of 0.1 m s 4 50 ml of 0.2 MS. So that is 6 - 10 6 - 10 by guys.

[02:31:45]Okay. So plus - So that is 6 - 10 and four is 4 by 4 by 80 = n3 n this is okay now.

[02:32:04]Okay mod this homework change. Okay. Rest remaining. Okay guys. Okay. I'm going to leave the session. Okay.

[02:32:21]Okay. Thank you.

[02:32:29]Bye.