To evaluate a composite function f(g(h(x))), start with the innermost function h(x), substitute its result into g(x), then substitute that result into f(x). For example, with f(x)=x²+1, g(x)=2x-3, and h(x)=4x+5: first compute g(h(x)) = 2(4x+5)-3 = 8x+7, then compute f(g(h(x))) = (8x+7)²+1 = 64x²+112x+50.
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f(g(h(x))) – Composite Function with 3 Functions | Algebra ShortAñadido:
Hello, we want to find the formula of the composite function f of g of h of x.
f of g of h of x.
So, there are three functions being embedded together here. Now, let's start with the innermost function.
We want to start with what? g of h of x.
That is we put h of x inside g.
So, g is the base. We have two Now, where we see x, we write h of x, which is what? 4 x + 5 then minus three. That is it. So, we have put h of x inside g of x. So, by the time we expand, we have 8 x + 10 then um minus three. That will give us what?
8 x + seven.
So, the result of that is 8 x + 7. Now, for the last we have we have we have dealt with this now. Now, put g of h of x inside f. So, f is now the base.
f is now the base. Therefore, You know, we have gotten g of h of x to be what? 8 x + 7. Now, we now put it inside f. Our f is what? x squared + 1.
So, now x will now be replaced by 8 x + 7.
Yes, squared plus one. So, if we expand this by, you know, simple expansion, this one [clears throat] will give you a 64 x squared uh 56 times uh that's plus uh 112 112 x plus 49 then plus one. Yes. That's expansion of this will give you this.
Then remaining plus one, you write it there. So, that was 64 x squared plus 112 112 x plus 50. So, that's the answer. Bye.
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