The explanation is clear and pedagogically sound, making complex roots easy to understand for beginners. However, calling this standard algebraic identity an "Olympiad" problem is a bit of an overstatement.
深掘り
前提条件
- データがありません。
次のステップ
- データがありません。
深掘り
Olympiad Mathematics | Japanese | Can You Solve This One?追加:
Hi.
Let's solve this problem here completely.
We have the square root of two over X to be equal to X over two.
We want to solve this completely. So, what do we do first?
We have to remove the square root.
And we do that by squaring it, right?
Then we have X over two, which will also be squared.
Yes, we have to square both sides of the equation. Now, this will take this out.
So, we have two over X on the left.
And on the right on the right-hand side, we have what we have there.
X over two times X over two.
So, we are going to have um two over X, which is equal to X squared over over two squared.
Okay, if we have to write it that way.
X squared over two squared. Let me write this well.
This is two over X, right? So, that the next thing we can do is to cross multiply as we have X multiplied by X squared to be equal to two multiplied by two squared.
By the way, if you look at this very well, you can conclude that the value of X is two.
The value of X is going to be two. But, we have to solve this completely.
Whether the real and the complex solutions, we want to get them.
So, we continue. X multiplied by X squared is X cubed.
Then two multiplied by two squared is two cubed.
So, bring two cubed to the left.
X to the power of three minus two to the power of three is zero.
And what we have right there is our popular difference of two cubes.
So, we know the identity already.
a cubed minus b cubed is just the same as a minus b and then we multiply by a squared plus ab plus b squared.
Right? You know about this, right?
Okay, so using this identity now, our a minus b will be x minus 2.
a squared is going to be x squared.
Then plus ab is going to be x times 2.
Cuz a is x and b is 2. x times 2 is 2x.
Plus 2 squared is b squared is going to be 2 squared.
2 squared is 4.
And then we are equating to zero.
So, from here we apply this rule.
We apply this rule, which we call um zero product rule.
We apply this every time we multiply two terms to get zero.
Imagine you have p times q to be zero.
How will it be zero? If either p is not zero or q is not zero.
So, one of them must be zero for you to get zero here. The same thing is what we are going to do to this um equation there.
Okay, so applying the zero product rule x minus 2 is zero or x squared plus 2x plus 4 will give us um zero.
From the left hand side, x is going to be zero plus 2.
And the value of x is just two.
This is our real solution and um the first solution.
Now, to get the other two solutions, we will bring down the quadratic equation right there, which is x squared plus two x plus four equals zero.
And this quadratic equation has a to be one, has b to be two and it has c to be four.
A is the coefficient here, b is this two, c is that four.
And um what is the quadratic formula that we're going to use?
It is x equals minus b plus minus we have b squared minus four ac and we divide this by two a.
So, the most, you know, difficult thing to do here is remembering the formula.
Once you can remember the formula, it's simple.
Now, putting the the value of abc, we'll have minus two here, plus minus b squared is our two squared now, then four times a times four cuz a is one, c is four.
So, we're dividing this by two multiplied by one since our a is equal to one.
Then, the value of x will be minus two plus minus two squared is four.
Four times four is 16.
And we divide by two.
We will not stop here and we will not find a square root of four and square root of 16 separately.
So, we have to combine, we have to simplify before we find the square root.
So, X will now be minus two plus minus square root of four minus 16 is minus 12.
And we're dividing this by two.
Okay.
And um let's do this. We have X to be minus two plus minus square root of 12 then multiply by square root of negative one.
This is um possible.
This is possible because if you have square root of A times the square root of B, this is the square root of AB, right?
So, that means square root of 12 times square root of negative one, it will be square root of negative 12. So, that is okay.
But, remember that we're dividing this.
We have to divide the whole of this by two.
Now, look at your 12 there. We can um simplify that 12. So, X will be minus two plus or minus square root of four times three then square root of negative one.
The whole of this is still over two.
Okay, so from here now, we're going to get X to be minus two plus or minus we have the square root of four, which is two then square root of negative one is I, so we're multiplying this by I then multiply by root three.
Three is still there because it's not a perfect square.
And we divide this by two.
So, we can go on to get X to be equal to two into minus two is minus one plus or minus two into two I is I then we have root three.
Okay. Now, let's bring um um the complete solution together, right?
Let's bring the complete solution together. We got x before now to be equal to two, our first solution.
Then, we got x to be from here -1 + i root three.
This is our second solution.
And um the third solution is -1 - i and we have root three. So, these uh the three solutions to the equation.
Thank you for watching.
関連おすすめ
Olympiad Mathematics | Indian | Can You Solve This One?
PhilCoolMath
650 views•2026-06-03
Escaping the Fog
LogicLemurGaming
760 views•2026-06-03
A Brutal Radical Expression Made Easy! The Shortcut Changes Everything.
tamoshop
112 views•2026-06-02
V : jee main /advance class 11 mathematics : Binomial Theorem class-1 ( 29 may 2026 )
dcamclassesiitjeemainsadva9953
125 views•2026-05-29
Is This Pentomino Tileable?
3cycle
241 views•2026-05-30
This Sudoku Has Many Lines!!
CrackingTheCryptic
2K views•2026-05-29
Olympiad Mathematics | Indian Can You Solve This One?
PhilCoolMath
268 views•2026-06-02
Olympiad Mathematics | Indian | Can You Solve This?
PhilCoolMath
669 views•2026-06-02











