This lecture offers a pragmatic and systematic breakdown of core physics principles, making it an efficient tool for mastering numerical applications. It successfully bridges the gap between theoretical formulas and the practical problem-solving skills required for high-stakes examinations.
Deep Dive
Prerequisite Knowledge
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Deep Dive
PHYSICS MOST EXPECTED 35 NUMERICALS | CLASS 11 PART 2 | COMPLETE REVISION | AAU CET 2026
Added:Hello class 11 or part two re okay along with MCQs. Now check first chapter is mechanical properties of solid first elasticity.
Okay. Now the solid like the property by virtue of shape that property is known as elasticity type of strain. Okay.
Now number one is longitudinal normal.
Okay. force normally and or perpendicularly.
Okay. Like this one surface area. Now equal to force per unit area and strain equal to delta L. Okay. Young's modulus modulus is the ratio of stress upon strain and stress force area.
Okay. And also remember strain is unitless. Okay.
And the second one is a shear or tangential check. This is the surface force. Okay.
at this theta is known as like okay checkal force tangential divided by area okay delta by l and delta tan and what is this angle displaced okay shear mod shear modulus this one shear modulus or modulus Okay.
And now the third number is volume volutric or bulk. Okay. Volumetric or bulk stress formula force upon area which is pressure. Okay.
and volume like volume and equal to delta v change in volume divided by the original volume number this one modulus of what bulk modulus okay and formula minus v dp by dv okay now comes hook stress is direct directly proportional to strain Okay. And what is this? This is okay. And this is known as modulus of rigidity. Again, stress versus strain graph. Okay. Stress versus graph.
NC up to this. No. Up to a stress equal to stress directly proportional to strain. Okay.
Okay. Done. Now questions. A force of 100 is applied evenly on on over an area of 2 m². The stress produced stress formula stress equal to force upon area.
Okay.
A. Now a 2 m long wire is stretched.
What is this stretched by? What is this?
This is nothing but delta L. Okay.
Delta L and delta equal to L final L initial delta L. Okay.
Check 0.02 2 by 2. Okay. Delideng 2.
Now question number three. If a material has a stress of 10 pascal and a strain of modulusal stress 100.
Now a breaking stress of a wire is basically material stress again knows that within the elastic Limit the ratio of stress to strain proportional to strain. Okay.
Okay.
Right. Stress upon strain. And uh of course stress upon strain at a constant okay within the elastic limit and this constant is known as modulus of rigidity. Now come to mechanical properties of fluids. First of all the formula pressure. Pressure is important in this chapter. Pressure equal to force by unit area is pascal. Density density is nothing but mass by unit volume. Okay. Relative density. Whenever relative density equal to density of the substance divided by the density of water basically gravity no unit because of course relative Now pressure in a fluid. This is atmospheric pressure like H depress G. Okay. And then now come to this one.
Pascal's law f_sub_1 by A1= F_sub_2 by A2. Okay. This is nothing but Pascal's law.
F_sub_1 by A1 force. Okay. F_sub_1 and this is known as P. This pressure no all travel. Okay. This pressure will travel here here like same pressure. Okay. F_sub_1 by A1= F_sub_2 by A2. This is nothing but P1= P2. Okay. P1= B2. Now surface tension equal to force unit. Okay.
Newton per meter. Okay. Now pressure that's why 4 on the other 2.
Okay.
Capillary.
Okay. Now A1 V1= A2 V2. And what is this? This is conservation of mass bernoli theorem p plus row v square plus row gh okay equal to constant and this is conservation of energy okay this one equation of continuity conservation of mass this one conservation of energy now terminal velocity terminal velocity formula 2x r² row body minus l okay like liquid anywhere. Okay.
Okay.
Fiscus or drag force. Okay.
Okay.
Okay. And what is it?
That one viscosity. Okay. Then questions. Mechanical properties of fluid. Mechanical properties of fluid.
Questions. Check. Number one. The pressure exerted by 10 m deepum of water.
Grow.
Check this one.
10^ Okay. Then a liquid has a density of Okay. This is the row and the mass of 2 m cube of this liquid. What is this?
Volume, right?
equal to density into volume 800 into 2. How much? 1,600. Okay. Done.
Now the water flows through a pipe of iman at 3 m/s. If the pipe narrows to 1 m square, the new velocity but again this is nothing but equation of continuity. Okay.
Um equation of wait equation of continuity a1 v1 equal to a2 v2 okay simpal a2 vs2 a1 Velocity equal to say 2 3 are 6 6 by 1 = 6. Now surface tension of force a new surface tension of force acts on a line of length. Okay. The surface tension surface tension formula first of all s= to f by l. Okay. Now surface tensional 0.2.2 already specific gravity which is 0.8 equality of oil by density of oil.
This is nothing but density of water.
Okay. Unit.
Now density of oil equal to8 into 10^ 3 which is 800. Okay. Done. And now next chapter is thermal properties of matter.
Okay.
properties of nothing plus 273.15° expansional expand final initial 1 + delta t. Okay. 1 + this one delta = l initial alpha delta t. Okay. Now alpha is the coefficient of linear expansion. episode. Uh, next come to my expansion which is a final equal to a initial 1 + beta delta t. Beta what? Beta is coefficient of aial expansion. Okay. This one gamma gamma is nothing but coefficient of volutric expansion. Okay.
This one alpha is to beta is to gamma= 1 is to 2 is to 3. Okay. Now heat capacity. Heat capacity equal to c= to q by d. Okay.
There was a girl. She was she was QT.
Okay. She was a QT. Okay. Done. And this one C into delta D. What is C? C is specific not specific heat capacity.
Okay. Cat capacity. Now specific heat ca. Okay. Specific heat capacity.
Q equal to MC delta T. Okay. MC delta T.
Now heat capacity. Simple change.
Okay. water.
Now this one is known as heat. Okay.
Now water has maximum density atomous behavior of water. Now good conductors are copper and silver or bad conductor wood, air, glass of course. Okay. Now black body is the best absorber and emitter of heat. Black% thermal properties of matter. Okay.
Convert a room temperature of 27°C into Kelvin compound Kelvin equal to what? 27 + 2 73. Okay. 300 kel. Okay.
And also okay boiling point this one freezing pointiling this is freezing pointiling.
Okay.
Loweruspus lower.
Okay.
273.
This one upperus lower 373 - 273°= 273= 273. Simple. Okay. Now the heat required to raise the temperature of 1 kg of water by 10°C. Uh the heat requal c delta d mc delta t. Okay.
1 kg 4 into 0. Okay.
0 then now a 1 m rod has linear expansion if heated by 100 it expansion is I'm basically delta L initial alpha delta t okay this one 100° 10 the powerus 3. Okay. 10^us 3 is nothing but nothing.
Okay. 1 mm. Then the heat required to melt 2 kg of ice. Okay.
This one 3.38 3.34 into 10 ^ 5 3.348 6 3 2 6 Okay 6.68 68 into 10 ^ 5.
Simple. Now, which temperature is equivalent to absolute zero temperature?
Absolute zero temperature - 27 uh 273.15.
Okay. Not kelvin degrees. Okay. - 273.15°.
Okay.
Okay.
Question. Okay. A system absorb 100 and does 40 of the negative flow. Okay. Now the increase in its internal energy is what?
First law of Q plus 100 okay wus 40 60 60 of work then in an iso bar process at a constant pressure of this volume expanded by this work done work done what P delta V okay pressure.
Okay. Now the maximum efficiency of a car engine operating efficienc 400 equal to 1 - 75 I 0.25 which is 25%.
Okay. Then for an idle gas undergoing an isoic process constant volume the work done is check first of all del okay pressure okay. Now and also PV graph of this one is this is okay and this is okay and this is isothermal. Okay.
V this one is pressure. Okay.
This one P versus V graph of isothermal. See and ideal gas according to the ideal gas equation PV = N RT. Okay. Now for an ideal gas the specific heat at constant pressure is CP. Okay.
and value simple 20.7 okaycal and free expansal change in internal energy equal to 0.
Now come to myinetic theory of gases theory in terms of this one Bman's constant temperature this one T is this one energy is directly proportional to what T and if the absolute temperature of a gas is increased by four times see V RMS or formula equal to <unk>3 RT double double. Now the number of translational degree of freedom for a monomic. First of all degree of freedom this one degree of freedom.
Okay.
pressure= right.3 and temperature= 300 divided by volume= 1 okay 1 m final answer 2 490 pascal okay 2 490 pascal Now the total molar mass of oxygen gas is what mass of O2 gas 16 + 16 o 32. Okay, done. Now question number uh chapter number 13 or oscillations. A vibrating body has a frequency check.
Frequency equal to 1. Okay.
Okay. 0.2 seconds. Now spring has restoring force. Restoring force= minus kx. Okay.
And what is this one? This one spring constant 20 x 0.5 okay.
Okayus do not forget the minus. Okay.
Okay.
Okay. The time period of a simple simple pendulum of land L on earth is 2 seconds. What is its amplitude? First of all, maximum length of the pendulum due to cannot be determined from time period.
A particle in SHM has an equation omega t and this is the angle and this is what amplitude maximum amplitude y maximum dise Okay. 4 sin 90 s of 90= to what? 1= 4 cm. Simple. Now for a simple pendulum of length 1. Find its time period. Again this one t= 2 roo<unk> l. Okay.
Okay, done. Now, uh, chapter 14, waves.
A wave has a frequency wavelength.
First of all, like Cal= lambda, right?
Okay.
is 100 and this one wavelength equal to two total 200. Okay.
Now an echo is heard 2 seconds after shouting hours.
First of all, nothing equal to dimple velocity of the like height of the dal by 1 second= 340 m. Simple 340. Now two tuning fork of frequencies iman and are heated or sounded together. Bit frequency difference of the given frequencies simp three bit. Okay bit done. Now the distance between a consecutive node like that position is known as node max right again one more lambda by 4. Okay. Lambda by 4. Then human ears are sensitive to sound frequencies in the range only 20 to 20,000.
Okay.
Okay, done. Okay, we are done with the part two. Thank you. Okay, study hard.
Bye-bye.
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