Install our extension to search inside any video instantly.

Which Is Bigger: e^π or π^e? (No Calculator)

Added:
247 views4likes3:25MathIsAllYouNeedOriginal Release: 2026-07-18

To compare e^π and π^e without a calculator, take the natural logarithm of both expressions to simplify the comparison: ln(e^π) = π and ln(π^e) = e·ln(π). The problem reduces to determining whether π > e·ln(π), which is equivalent to ln(π)/π > 1/e. Consider the function f(x) = ln(x)/x, which reaches its maximum at x = e (since its derivative f'(x) = (1 - ln(x))/x² is positive for x < e and negative for x > e). Since π > e, f(π) < f(e) = 1/e, meaning ln(π)/π < 1/e, so e·ln(π) < π. Therefore, ln(π^e) < ln(e^π), and since ln is increasing, π^e < e^π.