WAEC 2026 Physics Expo? 🔥 Most Repeated Questions & Answers You Must Master Before the Exam!

Ajouté : 2026-06-01

[00:00:00]For student preparing to write YCECS physics objective and theory on Monday, June 4th. So, I ensure you watch this video till the end cuz this is a preparation lesson. Now, let's solve this question. I'm I'll be coming up with some questions for you. I ensure you add up these questions to whatever you are reading. Mind you, this channel we don't support examination malpractice. So, if you have the intention to watch this video or probably to watch this thing here because of you're looking for questions, leaked questions and answer, please do well to swipe off this video with this is a preparatory class or revision lesson. So, we are not engaged we are not practicing in examination malpractice. All these questions they are just preparatory questions for you to add up to whatever you are reading.

[00:00:41]It's not guaranteed that this question will come out, but they are like a guideline to whatever you are reading.

[00:00:45]So, once you have idea about this question, it will have positive impact in your exam. Now, let's solve this question. This question is under projectile as you can see it on your screen. So, you already read the question here. So, let's solve the question here. This is a solution. Mind you, my name is Mat Ken. Do well to subscribe to this channel and ensure you share our video to all other student preparing to write physics question physics physics YCECS objective and theory on Monday, June 4th, 2026. So, now let's look at this question once again. I said this question is under projectile. It's an It is an SS1 topic. While some schools used to learn this topic as an SS2 first term. While some take it as SS1 third term. It depends on your school schedule. So, they said an object projected at an angle to a ground level.

[00:01:31]So, you already have the question there.

[00:01:33]What do you need to do? You need to Since Since Since you are given What are the parameters you are given? You are given the time flight should be 4 seconds.

[00:01:41]So, time flight is 4 seconds. And you're asked to look for the maximum height.

[00:01:45]That is the H max. So, that's what you're asked to look for. Now, how do you get about it? You are not given theta. Take note. Theta is We are not given theta. We don't know what theta is. And the formula for time flight So, that is basically T is equals to um 2 U sin theta over G.

[00:02:03]Isn't it? So, once we have this, then what did we do next? Then, what we're going to do is that we are already given this T. The T is 4. That is 4 seconds equals to 2 U sin theta over 10, right?

[00:02:17]By the time you cross multiply, then we have it as um 40 equals to 2 U sin theta. So, you make theta the subject of the formula. That is going to be sin theta equals to 40 over 2 U. By the time two here one, two here 20. That is basically 20 over U.

[00:02:36]So, that is what sin theta is. Sin theta equals to 20 over U. Now, after taking note of this sin theta equals to 20 over U, then what are we going to do next?

[00:02:49]>> [clears throat] >> What are we going to do next? Now, the next thing we're going to do is that we are going to substitute sin. So, after having that sin theta is equals to 20 over U, then now let us now look for the formula to calculate the maximum height.

[00:03:06]So, formula to calculate maximum height is equals to H M X that is equals to the H M X that is equals to U square sin theta all over 2 G.

[00:03:22]Yeah, that is the formula to calculate the maximum height. So, now how do we go about that? We still we're going to say that we need to we don't know what is U square, right? So, let me still repeat U square. Sin theta will now represent this now. This 20 over U. So, multiply by 20 over U. So, all over 2 G. That means 2 times 10. The G is 10. So, by the time Sorry, sin square theta. Sorry about that.

[00:03:49]Sin square U square sin square theta over 2 G. So, that means everything else going to be squared. So, that's going to be u squared times 20 times 20 times 20, that is 20 squared. So, 20 squared is basically 400. Let me check this calculator. So, 20 multiplied by 20, that's 400, right? So, that will be 400 over u squared over 40.

[00:04:14]Over 20, cuz 2 * 10 is 20. Good. So, this u square eliminates this u square.

[00:04:21]Then finally, we have 400 over 20. And that is going to give us what? 400 / 20, that might actually give us that is 20.

[00:04:30]So, the answer is 20 m.

[00:04:34]Since it is height, 20 m. So, now let's move to question number two. So, question number two says that So, now this question two as you can see it on your screen. Now, before I move to the solution to this question two, now let me explain how WAEC used to set physics question.

[00:04:51]Yeah. The pattern of the question is to work like this.

[00:04:53]It is they will give you 12 theory questions. 12 theory questions. So, the first part is going to be seven questions. So, out of the seven questions, you'll be told to answer just five out of seven. You know, if you answer five out of seven, so let's say five question out of seven. So, that gives 15 marks.

[00:05:14]So, which simply means that each of the five questions is going to carry three three marks. Question one to seven carries three marks. We are going to select five. That's for part one. For the part two, they will give you they will give you five questions. You have to answer three. So, you have to answer three. So, each of the three carries 15 15 marks, which makes it 45 marks.

[00:05:39]Can you see that now? Which makes it 45 marks. So, if you sum of these two marks together, that will be 60 marks in your theory.

[00:05:47]Good. Again, five in in part one, three marks each, equivalent to 15, or you'll be given seven.

[00:05:55]This one is going to be eight to 12. So, the So, the 12 questions is going to be answer um three out of like the eight to 12 is going to be answer three out of it. And each is 15 marks. So, the 15 marks multiplied by three, that's 45.

[00:06:11]So, that is 60. So, the the The objective is 50 questions. So, 50 questions for objective. So, plus 50 marks Each of them is five marks. So, plus 50 marks. So, that's going to be around them 110, right? 110 marks for the theory and the objective. So, your practical is going to be 50 marks as well. So, like Based on what I had, according to the marking guide, WAEC will convert this 110 ques- I mean ans- marks uh marks to 50.

[00:06:41]Whereby your practical is also going to be 50 on its own. So, your practical will not be converted. It's not be divided. They will have the full of the practical be added to the conversion of this 110 to 50. So, that will make it 100. So, that's how the marking guide is. Now, let's go to the question two.

[00:06:58]Now, they said, "What is the SI unit?"

[00:07:00]This question is under fundamental quantity and derived quantity.

[00:07:03]Yeah, this is an SS 1 topic. I think even the second week of your SS 1, that's when you'll be learning the SI unit, fundamental quantity, and derived quantity. So, the solution to this question is this.

[00:07:15]>> [applause] >> So, for the first, which is stress, the unit is the the standard unit for stress is Pascal.

[00:07:25]Pascal. And Pascal is also known as kilogram per meter per second squared. That's just it, Pascal. While the acronym is Pa.

[00:07:34]That's Pascal. So, for the second one, that is number two, the force constant, the unit for the force constant is Newton per meter. You know, Newton Newton is from force. So, Newton per meter. All right. So, that is basically kilogram per second square.

[00:07:54]Kilogram per second square. So, for the third one, that is the Planck constant. Planck constant is joule seconds or joule multiplied by seconds.

[00:08:06]So, whereby if you joule is heat, hm?

[00:08:09]Joule is heat or energy. So, joule seconds. So, the the the unit is also known as kilogram meter square per seconds per seconds. So, that is the answer for the question number two. Now, we'll moving to question number three.

[00:08:24]Um this is to inform you that on Tuesday, that will be January that will be June 2nd, rather, at 7:00 p.m. So, we'll be having a virtual class on Zoom for student preparing to write Y 2026 mathematics. So, we are having a virtual class. We're going to use Zoom for the class. So, if you are interested, please reach out to me. But, the class is not free. It's going to attract a a pay of 1,500 naira.

[00:08:52]So, the Zoom class is going to be 1,500 naira. That's what That's the That's the class. We are starting the class by 7:00 p.m. 7:00 p.m. in the night. So, the class might end maybe around 9:00 or 9:30. It is a master class for student preparing to write Y 2026 for mathematics alone. So, [clears throat] it's 1,500 naira. It's a master class.

[00:09:15]We're going to be looking at some past questions in that class and I'll be revealing the possible things they can ask you in your mathematics. So, if you are interested, please reach out to me on WhatsApp 091-55-10-28-13.

[00:09:31]Again, the class is going to hold June 2nd. That is on Tuesday. So, a day to the mathematics No, mathematics is on June 3rd cuz on Wednesday, but the class is going to hold June 2nd on Tuesday by 7:00 p.m. We are starting the class 7:00 p.m. We are using Zoom app, Zoom. So, if you are interested, you make your payment to this account number, 82068435809.

[00:09:55]So, that is PalmPay. You are paying into this account, PalmPay. The name you see there is Adebayo Ekun.

[00:10:04]So, once you make your payment, then you send your receipt to this WhatsApp number. Send your receipt to the WhatsApp number and under the caption, you write together that you paid for the mathematics class, the math the the mathematics master class. Please, indicate master class.

[00:10:20]The writing there is mathematics master class. Then, I'll add you to the group.

[00:10:23]We are using Zoom. Zoom. So, the thing is that Zoom can only occupy 100 participant. So, once we clock 100, we will no longer accept payment again because there's no way there's no way you can join the class except 100. So, students have been paying since last week, but if you are interested, make your payment. After making your payment, quickly send your receipt to the WhatsApp number. Then, I will add you to the group first. Immediately you have made your payment, I've added you to the group, then you will go to your Play Store or Apple Store to download this app. Please, kindly download this app, Zoom workplace. [clears throat] Download the app, Zoom workplace. So, once you download the app on your Apple Store or your Play Store, once you download the app, Zoom workplace, you sign up. Once you have signed up, then come to the WhatsApp. I'll add you to the group. So, around 5:00 p.m. on Tuesday, I will send a link to those to the group of those who have paid. So, when it is 7:00 p.m. sharp on dot, you will join you will click on the link, then it will take you to the app, then you are going to join the class. The class is a very very very interesting I mean, it will be a very interesting and educating and you class that you are going to learn. Once you join the class, I'm assuring you that you will not have problem on the day of your exam for mathematics because I'll be revealing the possible things you will ask you, the whole thing you need to know, and some things that you should that you need to know that will help in your exam. So, that's why I call it master class. We have been doing that for other classes. We did it for chemistry practical. So, this is the time for mathematics as well. We're also going to do for agric practical as well.

[00:11:52]And also chemistry and some other subject. But currently now, the one on board now is the mathematics. So, if you're interested, please do the needful and join us in class. Now, let's go to this question three. Question three says that we should name two artificial satellites. So, let me write solution here.

[00:12:12]So, we should write two artificial satellite. Now, the two artificial satellite is two common artificial satellite is they are what? The Explorer.

[00:12:21]So, we have the Explorer. And also, we have the Skylab.

[00:12:26]Skylab. So, these are the two common artificial satellites we have. Now, for this that means number one. Now, for the second question, it says that a geostationary satellite is already there. So, you have to calculate the speed. You know, calculating the speed.

[00:12:39]Speed and velocity they have seen in guys per seconds. So, V equals to 2 So, V is equals to 2 pi r over what?

[00:12:48]Over time.

[00:12:50]This is the formula to calculate the speed which it moves in the orbit. So, this is the formula I'm going to use.

[00:12:56]This formula This V represents speed.

[00:12:58]This pi is 22 over 7.

[00:13:00]This is the radius is already there. And this is the time.

[00:13:03]Sorry.

[00:13:05]So, calculating this now, firstly, you have to change this radius to what? To meter. It's in kilometer. Change it to meter. So, changing that, then r is going to be 6,300 * 1,000.

[00:13:18]You understand? So, if you multiply this, I think just put meter there.

[00:13:22]Simple.

[00:13:23]Yeah. You can increase the zero by leaving it this. So, or probably let me just do it this way. Let me add these together. That'll be R equals to 631234512345 m. So, we have this as the radius. Then also, the time is going to orbit in a day. So, the time taken, let me change the You have to convert it into seconds. You know, 1 day you have to convert 1 day to seconds.

[00:13:48]So, that conversion that that's going to be 24 * 1, you know, 1 day 24 * 1 That'll be in 24 hours make 1 day.

[00:13:57]That's 24 hours. Multiply by 60.

[00:14:00]That's in a minute like that. You multiply by 60. That's in seconds. So, if you multiply that, that should be giving maybe 84,000 600 or so. So, you can try that.

[00:14:11]Do the calculation yourself. That's going to T. That's going to be the T.

[00:14:15]So, your sec- your answer will be in seconds.

[00:14:17]Okay. All right. So, after that then, insert all these parameters into the formula. Then that gives you V equals to 2 * 22 / 7 times the radius is now 6300 * 10 ^ 3 then all over the time is what?

[00:14:36]That'll be 24 * 60 * 60. You can put times 1. The unit All this one is going to be meter.

[00:14:45]It's going to be meter, you know. Pi doesn't have any unit. Two doesn't have any unit. So, the unit for this radius is meter. That's going to be meter.

[00:14:53]Sorry. Just unit. Sorry about that.

[00:14:57]So, that's going to be unit.

[00:15:00]All right. So, that's unit I mean, that's going to be meter per and all these ones they are they are already in seconds. That'll be meter per seconds.

[00:15:09]All right. So, by the time you divide that, then you should be having By the time you divide that, then you should be having um having V will be equals to 458.33 m per second. So, that's it. Please, you can check that with a calculator. Try that with a calculator and see what it's going to give you. So, now this is the question four.

[00:15:31]Now, for this question you need to know this question as well.

[00:15:34]So, this question IS GOING TO BE >> [laughter] >> SO, THEY HAVE TO MENTION three distinct So, the first one is that it's going to be um you know, they will definitely have a tetravalency.

[00:15:47]So, they are tetravalent.

[00:15:49]>> [laughter] >> The number of tetravalency that they have is less than four. Do you understand? Okay.

[00:15:58]A good example of that according to the According to sorry, anyway, is this um um this is a nonmetal family. So, carbon is a nonmetal.

[00:16:07]And then, they're nonmetals. So, this is a nonconductor. All nonmetals they are nonconductors.

[00:16:13]So, like silicon here is a good example.

[00:16:16]So, silicon behaves as a semiconductor.

[00:16:19]They are non- I think so.

[00:16:21]Metal and nonmetal, they are conductors and insulators. So, they have like tetravalency plus or minus four. Do you understand? Tetravalent.

[00:16:30]Okay. So, another thing is that they have low electrical conductivity.

[00:16:37]So, they have um low electrical electrical conductivity.

[00:16:50]Okay. So, another thing is that one of another property of them is that they have equal number of charge charge carriers. Yeah.

[00:16:58]Equal number of charge carriers. So, they have equal number of charge number of charge carriers.

[00:17:13]So, that's for question three. Now, put them minute. So, question number five.

[00:17:19]>> [laughter] >> So, we have to state three properties of um laser that make them preferable to a gas laser.

[00:17:28]So, one of them is that these are monochromatic.

[00:17:32]That's number one.

[00:17:37]That's number one. So, another one is that it gives them more intense light.

[00:17:43]So, it gives more intense light.

[00:17:52]So, for the number three, it's probably that it has a very narrow optical bandwidth.

[00:17:58]So, it has a has a very narrow optical bandwidth.

[00:18:15]Yeah. So, these are the three properties