Find a, b, c & d | Cryptarithmetic puzzle

Added: 2026-05-11

[00:00:00]Can you solve this very interesting problem here a b c d are all digits so what can be the value of a can be either zero or one what if a is zero if a is zero from this we get that 0 + b is nothing but 13 now b is a digit so the maximum value of b can be nine.

[00:00:31]So you can't have to be nine because 9 + 0 is not 13. Even if there was a carry from here B + C is nine there would be a carry of at most one. So we can't have A to be zero. So the value of A is one. So What Do We Get Here? This becomes one.

[00:00:59]one b one b c one b c d this has to be one three 95 now let us look at this from here what do we get 1 + b is three and 1 + b + c is nine so from here you will get the value of b to be nothing but two.

[00:01:31]So B is nothing but two. So from the next equations you get 1 + 2 + c this is nine if there is no carry and it will be can it be 19 there is no carry from here and you will have that 1 + 1 + 2 + c is no if there was a if there is a carry from the first step and from this first step we get 1 + 2 + C + D is either going to be five and 15 if there is a carry now if there is no carry then what will happen? Then we get that C = 6 if there is no carry and if you take C to be six then you will get 3 + 6 + D is either five or 15 this there is no carry so it cannot be 15 so this means 9 + d is five.

[00:02:58]So you can't get a value of D. So there has to be a carry from this step.

[00:03:06]So what will you get? You will have a carry of one from here. So you get 1 + 1 + 2 which is 4 + C is no and from this step you will get 1 + 2 which is three. 3 + c + d is going to be 15 because this is giving a carry. Now 4 + C is not this gives us that C is nothing but five. So when I write a five here then from this equation what do you get?

[00:03:47]At this equation 3 + c + d is 15 with c = 5 it gives 3 + 5 + d is 15 and this gives that 8 + d is 15 and this gives us that d is nothing but se so what you get is we have solved it we get one plus 12 plus 125 plus one 257 all add up to one 3 9 5 this is how you solve this problem