In an isosceles triangle where two smaller isosceles triangles are formed by dividing the original triangle, the base angles are equal; using the interior angle sum theorem (180°), we can solve for unknown angles by setting up equations based on the equal angles property. For example, if a triangle is divided into two isosceles triangles with a 75° angle, and the base angles are equal to alpha, then 3α + 75° = 180°, which simplifies to α = 35°.
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Deep Dive
Calculate the angleAdded:
Hi, my friends, and welcome to Math with Alex. Today, I have a beautiful geometry problem for you.
Given is an isosceles triangle, and this triangle is divided into two smaller triangles.
We know that one of the two smaller triangles is an isosceles triangle as well, and we know that this angle is equal to 75° and we are going to calculate this angle alpha.
Okay, in the first step, we label the vertices of the triangles with A, B, C, and D.
Triangle ABD is an isosceles triangle, and in an isosceles triangle, the base angles are equal.
AB and BD have the same lengths, so the base angles are at A and D, and this means that the angle at D is equal to alpha as well.
Triangle ACD is an isosceles triangle as well, because AD and DC have the same lengths.
The base angles are at A and C, so this angle is equal to alpha as well.
And now we can use the interior angle sum to calculate alpha.
The three interior angles of a triangle always add up to 180°.
So, in triangle ACD, is alpha plus alpha plus alpha plus 75° equal to 180°.
Alpha plus alpha plus alpha is three times alpha, so we have three times alpha plus 75° is 180°.
Now, we subtract 75° from both sides of this equation. This means that three times alpha is equal to 105°, and finally, we can divide both sides of this equation by three, so alpha is equal to 35°.
Thanks for watching, my friends, and see you on the next video.
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