This video demonstrates how to solve a geometry problem by combining triangle centroid properties with circle theorems. Given that P is the centroid of triangle ABC, and using the property that the centroid divides medians in a 2:1 ratio, along with the fact that a 90° inscribed angle subtends a diameter, the solution shows that the radius of the circumcircle is 6, and by applying the Pythagorean theorem to find the remaining segment, the length x (CQ) equals 7.
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Norway Math Olympiad Geometry ChallengeHinzugefügt:
Can you find the length x given p is d center of triangle ABC and cq is x and If we extend a suppose this point is M.
Then in any triangle A B C if P is midpoint of BC, Q is midpoint of AC and R is midpoint point of AB.
And if we join A, BQ and C R then they will intersect at a single point that is centrid.
Suppose this point is G.
Then A G ratio GP is equal to BG ratio GQ is equal to CG ratio GR that is 2 ratio 1.
So here P is centroidid that means B M and CM they will be equal.
And also a ratio PM will be two ratio 1 and A is 4.
A is 4. Ratio PM is 2 ratio 1.
That means 4 over PM is 2 over 1. That means PM it will be 2.
PM is two and we have B M is equal to CM.
And now interangle A B C.
It is A B C.
This angle is 90°.
And if we make a circle around ABC, then we know that in any circle diameter makes an angle of 90° on the circle.
And angle B A C is 90°.
That means BC it will be diameter and B M is equal to CM.
That means M is midpoint of BC.
That means m is center of the circle.
So a m will be radius, b m will be radius and c m will be radius and a m is 4 + 2. It is 4 + 2 that is 6.
So, CM it will be also six and now this angle is 90°.
So, inter angle PQM PQs² + Q M².
It will be ps² and pq is <unk>3 s² + q m² is 2 s² and 3 + q m² is 4.
So q m² is 1. That means qm it will be one. QM is one.
And now x is cq that is c m plus qm and cm is 6 + qm is 1 that is 7.
So x is seven.
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