Cracking the Cryptic masterfully transforms a whimsical rat-themed concept into a rigorous exercise in high-level deductive reasoning. It is a brilliant display of how complex constraints can turn a simple grid into a sophisticated intellectual narrative.
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Deep Dive
Which Rat Is Best At Sudoku?! Rat Run: One Year EarlierAdded:
Hello and welcome to Wednesday's edition of Cracking the Cryptic, where as so often in recent months, we have a rat run puzzle to do today. But it's not it's not a rat run, which is the next in the story. um sequence. This is it's called rat run one year earlier.
So it it dates back to before and um have been doing their stuff. Uh and this is of course Marty Sears Magnum Opus this incredible series of puzzles. Um and look look today if we learn the names of all the other rats who were in line with um in line to be the selected rat. So, we've got rats called Albi, Brush, Conquer, Dylan, Ela, Finins, Glitch, Holly, and Ible. I have no idea where Marty is, I suppose. Okay, so he's chosen names that begin with A B CDE E F G H and I chosen Russian Conquer and I do not know. But anyway, let's let's should we read the story? Let's find out what's going going on in the story. So, I've got the page here. You can see it's got a 100% rating. This one, it came out at 2:00 a.m. this morning. Uh, final preliminary trial on the 6th of May, 1974.
Over the weeks, the 250 rats that started these trials have been whittleled down to nine. Today's final trial will decide which rat will participate in the full three-phase study starting in June. Elliot has kindly offered the use of his lab and says he has some exciting ideas of his own that will add extra complexity to the mazes, allowing the chosen rat to be challenged in completely new ways. I don't recall seeing him this enthusiastic about a project before. I am intrigued to find out more. Ah, it's just fantastic, isn't it? It is fantastic. Now, if we if we skim down a bit, there are there are a range of comments here. Uh, some of which I I really I'm going to read actually. Viking Prime says, "I still can't believe this is the final season. I wonder if there will be a spin-off series or at very least a revival series a few decades hence."
Viking Prime, I couldn't agree with you more. Um, Calvin Paul says, "I can't help but wonder how science would have been different today if Ela had made it.
Wonderful puzzle. Thanks again, Marty."
Silver Scree says, "That felt absolutely brutal to break into, but in retrospect, it feels quite fair. I can feel us careering towards a finale, and I'm finding myself unexpectedly and quite deeply emotional about it. I look forward to revisiting these puzzles and this story in the future." I Yeah, I totally agree with you, Silvercree.
Um, okay. and I'm just skimming the rest of the comments, but they're basically all saying it's wonderful. I mean that we wouldn't expect anything less, would we? Um, so anyway, we'll read the rules of this together and tackle the latest rap. I mean, Wednesdays are like Christmas Day if you're a puzzle solver at the moment.
Every time we get to do one of these incredible puzzles, it is fantastic. Um, but let me just skip through some other things that are going on. Um, firstly, you you knew I was dogsitting yesterday.
Um, I am indeed dogsitting again today.
Um, but it was considered incredibly remiss that I didn't let you see a picture of the dog that I'm sitting for.
So, I'm putting that right today. There we go. There's little Dillis. Um, Dillis is a remarkably small dog who makes an enormous amount of noise sometimes. Um, but as you can see, very cute indeed. So I I I will continue to look after Dillis as as well as I am able. Um what else?
Oh, I messed up on birthday earlier in the on on uh Monday. It would have been I said very happy birthday to Sotare. Um including uh from from Saut's father and it should have been today. So I'm very sorry I messed that up. Um and hopefully you can forgive us for doing a rat run today. But I think hopefully you did see that Mark did one of your puzzles on Monday evening. Anyway, so I hope another birthday wish from me and I hope that you get some excellent chocolate cake, of course. Um, what else? Oh, rat run merch. Let's um let's have a look at that because Marty, who is not just a Sudoku wizard, is also a design wizard. So Marty's made um this merchandise. Um this is the most popular thing, the the um the the black anything with the black maze on it. Um people like that very much. And um yeah, so this is all available right now.
There t-shirts, water bottles, all sorts of things. Um so do check that out.
Very, very good stuff indeed. Um, and the only other thing I will mention is that over on Patreon, we have our monthly competition up and running themed on Spider-Man. Um, do check it out. It's um, eight puzzles in all.
You've got until the 20th to to um um to to send in your entry and be in with a chance of winning the competition and coming on to the channel to make a Sudoku video. But looking at my list, I think that's everything. So, shall we have a go at Ratrun one year earlier by Marty Sears? I'm going to have to try and remember these names, aren't I? But here we go. What do we have to do? We have got for the final preliminary free roam trial. The nine short-listed rats were placed in a 9x9 space and their movements were observed and recorded.
Each of the digits 1 to nine appeared in each row and column.
Okay, so it's it's basically a sedoku, although we haven't got 3x3 boxes yet.
Um, observations.
Every cell in the grid was visited exactly once. No rat's path contained any repeated digits. Okay, so it is going to be it's going to be like a chaos construction, isn't it? No rat chose to move diagonally at any point.
Every 2 by two area was Oh, every 2 by 2 area was visited by at least two rats, right?
Okay. So, that's actually precluding any 3x3 boxes appearing in the grid. You couldn't have um how should I do this? You couldn't have that as a shape because there would be so many 2 by twos in it that weren't visited by at least um two rats.
Um no two rats started on the same digit. No two rats ended on the same digit. Oh goodness, Marty. That's evil.
What that means is that these numbers are effectively an extra region of the sudoku. If I'm allowed to call this puzzle a sudoku, they have to be the digits 1 2 3 4 5 6 7 8 and 9 without repeat. And then wherever the endings of the ah hang on a minute.
Yeah, the Okay. Um, no two rats ended on the same digits. The endings all have to be different as well. Um, all black currents and red currents were eaten.
All black currents and red right somewhat somewhat terrifyingly. Um, my OBS just glitched, which is the the way I record the puzzle. Um, and I've restarted my computer as a result. um because I saw that Nvidia had a display driver update that was available. So, I'm hoping that things are stable again. Now, um the very good thing about recording in OBS is that you don't lose the footage up to the point that it goes crazy or you have a computer crash. So, I do think um we're okay up to that point in the instructions that I was doing. and it does seem to be trying to record. So, I think I think we're okay. I think we're okay to continue. I really hope that doesn't happen again. Um, anyway, oh, and actually, and when I turned on my computer, I had a Facebook message from uh an old friend of mine, Steve Mullikin. Steve, many happy returns.
Um, I got the message in the middle of doing the instructions, which is quite funny. Um, anyway, where were we? We Oh, yeah. We were doing we we we were told all black currants and red currants were eaten by the rats and no grapes were eaten.
No grapes were eaten. Okay. So any So this rat isn't going to go into that. It could go into that cell, but it can't also then go into that cell presumably.
Now black currents, if a black current sits between two digits, one is double the other. So if this was a four, this digit would either be an eight because 8 is double four or a two because four is double two.
If a red current sits between two digits, one is odd and the other is even. So they alternate par. So if this was two, this could be 1 3 5 7 or 9.
There's there's only one more rule.
There's no test constraint today. If if a grape sits if a grape sits between two digits, they have a difference of at least five. Right? So if this was a one, this could be 6 7 8 or 9. That's how grapes work. And they are they are all the rules. Do have a go.
The way to play is to click the link under the video as usual. But now I get to play. Let's get cracking.
So Oh, I know what I'm going to say first actually. Um, when I was reading the instructions, it said it had this line. It said, "No two rats ended on the same digit."
And I I was confused by that as I read it, but perhaps I shouldn't have been because the what the rules say is that every cell in the grid is visited exactly once, which I think means I think what Marty's trying to tell us there, let me just go to the coloring tool. Let's look at Let's look at.
So, if went there, I I think what we're being told is that that is an impossible. Oh, it's not even nine cells. Um 2 3 4 5 6 1 2 3 4 5 6 7 8 9. I think that is an impossible region for a couple of reasons. Firstly, which would be the end cell that to be different from all other end cells?
That's one reason I think this this would be problematic. But perhaps a better reason it was problematic is it says every cell in the grid was visited by the rats exactly once. Now, how would visit each cell in her region exactly once?
She could go up here and visit this cell, but then to get to this cell, she'd have to backtrack and she'd visit all the well, all those cells twice. So, I actually think that what Marty is saying in not so many words is that Albi Brush, Conquer, Dylan, Ela, Fininks, Glitch, Holly, and they all form bits of spaghetti. They all start at one end of a spaghetti and end at another end of a spaghetti. So, we're not cupcaking today. We're spaghettiing in the sense that a region is going to have to look like a piece of spaghetti without going through other rats, obviously. Uh 1 2 3 4 5 6 7 8 9.
That's too many. Uh so maybe that could be a region.
That's got a start. It's got an end. And it basically operates like a snake or a piece of spaghetti. There's no branches in it is what we're saying. Um, so anyway, that was one thing I wanted to say which I noticed as I was reading the instructions.
But right, let me just let me just sorry when the computer goes on and off and you get interrupted, I lose my train of thought.
So every let's color let's color in all the rats, shall we? Um, so I'll use I'll use every every color in my palette. So I'll just go in order.
So this one can be a green rat.
And then my next color is indigo. They are in A, B, C, D, E, F, G, H, I as well. So this is fine. So we'll go gray, lime, purple, orange, red, yellow, blue. Right. So these are my rat colors.
And we're being told now, we were told something about what we were and weren't allowed to eat.
All black currants and red currants are eaten.
And okay, hang on. That's going to be problematic though, isn't it? I mean, I know that those are in the same color, but I don't know. I don't know. It's one of those colors.
Right. What we should do, let's go to the line drawing tool. Let's start to delineate between rat paths.
And we were told no grapes were eaten.
So, we can always always do this where there's a grape.
Um, and all all black currents and red currents were eaten. So let's use red probably because what we're saying effectively is that all of these currents they form paths for some rat or other.
So, does this rat join to that is the first question that looks quite a good one because ah that's interesting as well because if um what's her name?
Holly. If Holly joins to here, Holly has to go there and then she would have to go here because we can't have a branch.
Holly couldn't do that and that because she would visit more than one cell. Um well, cells would be visited twice in order to form a region like this. So Holly would have to do that 1 2 3 4 5 6 7 and then either she would go up there or she would go there and then she couldn't form a 2x two because there's no 2x twos in this puzzle.
So that so if Holly did go here, I think Holly either is that shape or that shape.
So Holly would be there and those or there and those now um G glitch glitch is not the same color as the sort of boundary around her.
I'm saying glitches are her. Do we think glitches are her? I've just noticed Albi is definitely a boy's name, isn't it?
Dylan's a boy's name.
Ible I'm not sure. Conquer Brush. Basil.
I don't know. Ela. Ela feels like a distinguished male name. Um, so it's really the name of an island, isn't it? I don't know. Um, okay. That's not my phone buzzing at me.
Please don't be my phone buzzing at me.
No, that's fine. Um, those ones, no, they could belong to Conquer if Conquer did that or Dylan if Dylan did that.
Forming an electricity sign as Dylan goes electric controversially in the puzzle. That would be quite that would be quality. Um, I don't know. What do we me? How do we start this? Do we?
So, we've got to draw. It's basically a chaos construction with definitely no 3x3s and snakes. I suspect knowing Marty, it will be something like, how do you get two snakes into that part of the grid?
So, it won't be the obvious. It won't be um not not that anything is particularly obvious, but is it is it hard to get two snake paths or two rat paths into the top 2 by two?
Not actually. It's not very difficult at all.
It's not black current logic, is it? So, if you have black Yeah. Okay. So, black currents in the same region can't repeat digits. So, where you've got three cells joined by two black currents, they're going to have to include the digits 2 and four because we're either looking at a situation where we've got a 1 2 4 sequence or a 2 4 8 sequence. We couldn't have a 3 612 sequence or a 363 sequence because we'd either repeat a digit or we' we'd get to a nonsoku number. So, there's got to be a two and a four on that sequence and a two and a four on that sequence. Uh, no, that's a red current. Um, those three are different from that one.
because that they're all in the same region. And that's a 2 by two. So that is a different a different color.
But that I think that could be a lot. I don't maybe that couldn't be a cuz I'm not sure. I I don't I I I don't think it could be a because I think that would not be able to form a snake. So, what what I'm saying there is I'm just going to make that an arbitrary color.
And I'm I mean, this could be any of these colors. Literally, I'm not saying what rat this belongs to. I just want to draw that in as a as an example wall.
This cell, let's make it yellow cuz yellow's down here. This cell is clearly not indigo by 2x two. So, I've got to join that to a rat, but I've got to join it to a rat that that where where this could either be the last cell of a rat or along a path of a rat.
So, if this was um if this was actually Albi, this would have to be the last cell of Albi because this definitely isn't Albi because of the grape. So, this would have to be the ninth cell of the Albi region. I just don't think it can be, can it? Isn't there just no way that I mean, if anything, it's going to be the third cell of Albi. It's not going to be the ninth So that cell is definitively not Albi.
But does that mean that indigo isn't Albby?
Or maybe it means indigo is Albi if um Oh, goodness me. I don't I don't even know how to think about this. If well let's think about let's actually paint it in. If that's Albby, how would that work?
Uh okay. So if if this is Albi, in order for Albi to get to this cell, Albby could do this or this, but in some way yellow is getting a bit trapped, isn't it? Yellow couldn't yellow couldn't be uh Dylan for example because if Dylan goes down there then Albby can't get to this cell.
So yellow is going to get out that way.
So yellow yellow is a bit constrained there because yellow looks to me at first blush like it could only belong to actually because because uh um this cell uh maybe this is the point. Does this cell have to get to a rat?
But it can easily it can easily get to Dylan if if this is an Albi.
So if Oh, I mean this is this is very subtle actually, but it's it's true. Albi is not this this sequence and for this reason um Albi in order for this three cell sequence to be Albi Albi has to join to this cell at some point on Alb's journey. Now what's the very latest that Albi could join to this this cell? Well, if Ali tries not to join to that cell, Albi could take five cells before arriving at this cell, which would make this the eighth cell on Alb's path.
So, Ali would have to go there.
Remember, yellow has to get out. So, Alb's definitely got not going to the top row. So, yellow now goes like this to get out in this situation. In fact, that would actually be yellow as well in this situation. But but now we've got the problem of what do you connect yellow to?
You've got four cells from this point.
In fact, we've only got three because that would have to be yellow. But you can't get to any rat in only four cells. It just won't work.
And of course, I say of course, there's nothing of course about it. But if Albi makes a quick run, you've got a bigger problem because now Yellow has to go well, you've got Yeah, you've got the same problem. It's just worse because now now Alb's path has 1 2 3 4 5 6 Three more cells to run. Can't go to the top row cuz yellow has to get out. So it's going to go over there somewhere. And then you definitely can't get yellow to a to a a rat. Brush won't reach. Not even close. That's That's a very long region I've just drawn there. Actually, it's not. It's not actually. It's only 10. Well, it's just too many. And for some reason, I felt that would be absolutely impossible. But it's it is impossible, but only just Okay. So what I'm concluding here is that right so Albi is going to have to get out down column 9. Albi can't join this.
We've explained that Albi can't join Indigo. So how does Albi form a spaghetti?
Alb's going to have to take that cell.
Right. And now this is good. This is good because once Albi takes this cell, Albi must take all of those cells because how could Albi not? If if another rat came in here, then Albi couldn't connect to this cell um without crossing another rat's path. So Alb's going to do this and come out 1 2 3 4 5 6. Now, now don't we still have a bit of a problem connecting yellow to a rat? May I might be thinking about this incorrectly? It might have been more logical to think about that cell, work out it couldn't be Albi, and then just ask what rap it could be.
I mean, I feel it has to be this one. I feel it has to be Dylan.
But feel feelings are not.
How could it be this route?
No, it could it could it couldn't be conquer because conquer if if this if yellow is conquer then indigo is not conquer. So to get to con to get yellow and conquer connected is impossible. You'd have to go rounds now. Oh, actually could ah hang on. I hadn't thought of this. No, no. I I think I did think of this. If If thinks Ah, I've had a different idea.
Oh, I've had a much better idea.
Bishop's moves.
Well, no. Okay, maybe it doesn't work.
Okay. No, it doesn't work. All right.
Here was my idea. I was then thinking, okay, if we've got strings of spaghetti running through the grid, then the ninth cell on any rat's path must be on the same bishop's color as the first cell on the rat's path, i.e. the rat itself. because in order to um move nine cells orthogonally in a grid, you're you're always going to end up on the same bishop's color in positions 1 3 5 7 and 9. And so I was then thinking, ah well that's not on the same bishop's color as this. But then I realized that that that's could because this could be the final cell on's path.
That that doesn't work though. That really doesn't work. If this is then in order to get here, Vinx is going to have to surround this indigo piece, which means that this is the final cell on some rat's path. Well, which rat's that? It can't be these rats. These are really close. And if there was some other rat that came in, that's a branching path. That doesn't work. So I don't think that can be fin.
3 4 5 6 7 8 9. It definitely can't be a brush. So it definitely can't be elbow.
So its only options its only option is D. That has to be D. Um and therefore that is a path.
And therefore this is the fourth cell on Dylan's path. And Dylan is is not going electric. We're not getting an electricity symbol. But Dylan is going 1 2 3 4 5 6 7.
I was going to say this has to be conquer, but I've realized it doesn't.
If that was the final cell of of some path, then that would be okay. Possibly this one.
1 2 3 4 5 6 7 8 9 something like that might be possible.
That wouldn't be branching.
And then conquer could maybe do that or or that if that's the ninth cell of another path. This is really interesting. It's not it's not at all solving how I thought it would. But look, I can Oh, I know what I should do.
I can draw a path around the grid like this.
I can draw a path there. I can draw No, no, no. Be very careful about that, Simon. That is not valid because I suspect actually that is going to join to to conquer now.
So So Albi need still needs three more cells.
So Albi can't join to this.
Yeah, that's obvious. If if Albi if Albi was this color, Albi would be at least 10 11 cells large cuz Albi would do the whole of column 9 plus those two cells.
So, so this sequence is either conquer or it's very straightforward. If it's probably Well, actually, it might it might simply be impossible for it to be fin. 1 2 3 4 5. No, it's impossible for it to be.
Even if you're efficient, it's a 10 cell region.
So, it's not So, this is not it's either or conquer.
So, if it's conquer, if it's conquer, it can't conquer can't come down like this because that's going to trap um glitch in.
Glitch couldn't get nine cells. So, conquer would have to sort of come like that. What? 1 1 2 3 4 5 6 7 8 9. Ah, but hang on. We have to be careful with making sure Albi can be a Albi still has to be a a snake. So Albi, it's not it's not acceptable for Albi to do that. That doesn't work.
No, it you can't do it. You can't do it.
Conquer can't come in here. Let Let's just draw it in. Just do it slowly. So if Conquer came in here like this, this is the ninth cell of Conquer's path just by count. 1 2 3 4 5 6 7 8 9. So somehow Albi has to take three more cells in a row without cutting off Conquer's path and without making a 2x two. So something like 1 2 3 something like that. And you can see that's just making Conquer's path too long. So this is good. This is good.
I think this sequence is Ible.
And then these two cells must be as well because if anything interfered with Ibel's ability to get to these cells, I would have to go through a wall of another rat's path. So I 1 2 3 4 5 6 has to go there. Seven.
Ah. Ah. Glitch has to eat. Glitch.
Glitch has to eat a red current which he's on. Have I not done that in other places? That would be completely remiss of me.
Okay. I I think that's the only example of that. But that's good cuz that forces I to go further. 1 2 3 4 5 6 7 8 I is done. Ible I've done I've done one rat's complete path. Um and then Glitch has to turn. Must make a 2 by two. So that's got to be some other some other rat. Oh, Albi. 1 2 3 4 5 6 7 8. Alb's got to come there. If Albi goes there. Oh no. I was going to say if Ali went there that would No, that doesn't work. If Albi went here for her ninth cell or his ninth cell, how would we deal with this pentomino?
C would have to be indigo, wouldn't it?
So, we'd have to do this, which means this can't be anything. It couldn't be belong to a rat. No rat can get to this cell. And if C goes into this cell, C can't go into the indigo stretch because you'll make a 2x two. So, Albi has to go down.
And that finishes off Albi. That's going to extend glitch.
Uh oh, this is now looking very well. What's this? Is that or is it Holly? Or is it even Ela? 1 2 3 4 5 6 7 It could be Ela. Could be Ela.
It can't be. I don't think it can be conquer because this glitch thing has to grow to be nine cells large and then conquer would have to come around the edge to get this cell. So this cell I think actually it might not be able to be Holly because that would be the ninth cell of Holly.
How would Holly do that given we couldn't make two by twos? You couldn't.
You couldn't do it.
It is on the ah bishop's color. Bishop's color.
That that is legitimate. That's undoubtedly the final cell of a right. That is undoubtedly the final cell of a path because it's a culdeac.
So, it needs to be on the same bishop's color as a rat. Now, which rats work?
Actually, Holly does work, but if Holly goes here, for example, she'd have to she'd have to do a really wide loop. And if she goes there, how does she get to this cell?
It's impossible. You can't do it. So, Holly is not this one. Fin is on the wrong bishop's color. So, Finins is not there. C can't get there. So, I think it has to be Yeah, it's going to have to be Ela. So, that's purple.
So now right now if you if we just use our minds to envisage the path that Ela takes I without specifying it you can see there's going to be a wall of Ela connecting this to this somehow that you know there's going to be a wall of Ela the great wall of Ela.
So, what rat is going to be in this area of the grid?
It's going to have to be Holly, isn't it? I mean, um, what's this one's called? Brush. Brush can't get there without making a 2x two. So, so Holly has to live in this space of the grid without making uh a 2x two.
So Ela, so so this this little connection of digits there is made up of Ela and Holly. And Holly is going to clearly be on the outside of Ela. So that is forced. Ela goes there.
Um Holly can't branch. So those have to be Ela. And now we have to just close Ela up. So Holly 1 2 3. So, Holly does go up column column one, which is something we thought about earlier on.
Ela's finished.
And slowly but surely, we are we are managing to work out where the rats move.
Okay.
Now, okay, maybe I is this is this conquer?
If it was conquer, conquer would have to continue and then Dylan would have to continue. In fact, if it's conquer, if it's conquer, because you'd have to do that. You'd have to you would have to do that as well. 1 2 3 4 5 6 7.
I don't know. That doesn't look impossible to me.
The other option is that conquer is not part of this indigo string. So conquer would have to then go that way and most of that path would also be forced by glitch and by 1, two, three.
Yeah. So, conquer would do this sort of thing.
2 3 4 5 6 7 8. That's impossible.
Uh, no, I'm wrong. Uh, no, hang on.
Or five. No, I think it is impossible.
Genuinely, I do think it uh 1 2 3 4 5 6 7 8 Oh, maybe not.
No, it is impossible. It is impossible.
The re the reason is uh if if we sort of v Well, we don't have to visualize it.
Let's actually paint it in. I can see there's a problem up here. Um if conquer goes this way, you can see glitch gets forced around the outside. That's some pop song, isn't it? So, like this. So, Conquer has to go up here. Conquer hasn't finished yet, by the way.
Conquer's only had eight cells at this point, but Fhinx is going to go up here.
But can you see the problem?
The problem is this area of the grid into which I have to get two different rats. Now, the only two rats that can reach that 2x two are at this point.
thinks has got plenty of spare cells and uh brush but brush is clearly on the outside of so brush would have to hug the perimeter like this and that that's about a million cells that the size of that region 1 2 3 it's maybe maybe more than a million four five six seven eight n it's it's just thousands of cells it's it's not right you can't do that.
So I don't think conquer can go this way. I think conquer is at long last we have proved that conquer is this original indigo segment and that's going to force this it's going to force conquer into this black current because she can't make a 2x two here and that's going to finish off Dylan. So Dylan goes there.
Um, we can do some of Conquer's path.
This, Ooh, right. That's got to be the final cell of a path, which is definitely not glitz or glitch because that wouldn't be nine cells and any rinky dink would cause a 2x two. So, something is coming down there.
It can't be fin would make either a 2 by two or a um it couldn't be the ninth cell, right? So that has to be rush, which is not what I was expecting actually.
I mean logically it's like it's like the Sherlock Holmes axiom when it when you've eliminated the impossible. All that is left however unlikely is that brush is connected to that uh which is going to force glitch along here brush along here. So does this is that always the shape of glitch? 1 2 3 4 5 6 7 8. Yeah, that's glitch.
So brush brush has to come out. So has to go over the top now. Hopefully. 1 2 3 4 5 6 7 8 9. Beautiful. That's correct.
Now Conquer is going to go there. 1 2 3 4 5 6 7 8. Okay. So Conquer is going to have to go there for a ninth in order that Binks gets row one, column one. There we go. That does actually work. Isn't that lovely? That's very different to a normal rat run. but no less enjoyable.
Um, okay. I think I've drawn in all the paths. So, what do we have to do now?
Okay. Now, we have to put the numbers in the grid.
We've got Yeah. So, it's just a chaos construction.
And what's going to give us? We can get rid of the ready things, can't we? We don't need them anymore. They were they were trying to tell us which rats were eating which things.
So, it looks like um Holly's got the most information in her region.
Yeah. Okay. Holly has three separate dominoes of black currents. Now, in Sudoku, if you're looking for digits that can be in a doubling relationship with other digits, the only digits that work are 1 2 3 4 6 and 8. Think about 5, 7, and 9. How could they be in a black current relationship?
Five, double it, you get 10. Have it, you don't get an integer. The same is true for seven. The same is true to a nine. You get two big digits if you double them. And non- integers if you half them. So five, seven and nine are going to be in those cells.
Now two of those are on red currents. So this digit and this digit have to be even.
Yeah, you can put one and three on black currents and they are valid.
And this one is on a grape.
I mean, you can't I mean, all what do we know about grapes? You can never put five on them because there's no dig sodoku digit that's five different from five at least.
Um I mean, if that was four or six, this would be 1 or 9. That would be restricted. But if it's two or eight, it's really not.
Oh, and Marty, have you have you set like an evil irregular sedoku here?
It could be like law of leftover stuff.
Um, let me try and spot a good example of that.
Yeah, I I mean that cell, where does that cell go in lime green?
because this rat thing um it's see say this was a it can't be five say it was a four then it couldn't go in any of those cells so it would it's it's always going to go there yeah okay in fact that digit is going there actually I might make it a it's alb's digit and then it's going there so it is a two or a four you that that's really interesting that digit is two or four um because it's in the center of this black dot sequence and we said that a black dot sequence within this where the three digits have to be different was either going to be 1 2 4 or 2 4 8. So this digit is 2 or 4 which means this digit is 2 or 4. This digit is 2 or 4. Now ah nearly Well, okay. Let's keep going with that because that digit is actually the same digit as these three because it this digit whatever it is, it's the same. It has to appear in orange, but it can't now be in any of those cells. And it can't be on the rat because all the rat cells are meant to be different from one another.
So, it's got to go there. And this is on this is on a grape. So this is lower than five. So in order for this to be um sufficiently different from two or four, if this was four, this would have to be nine. If it's two, it can be 7, 8 or 9, but it has to be. So those four digits are all the same.
And that digits got to go into indigo.
Um, I think it's got two possible two possibilities. Let me just label it there.
I think it's in one of those two cells.
And it's got to go into red.
It's in one of three cells there.
And it's got to go into purple four cells there and it's got to go into well it is two or four isn't it? So it's ah okay so it's not that digit.
So in column one, it's in column one.
It can't be this one because it sees it in its row.
It could be that one. Could be that one.
Could be that one, I think. So I think it's in three possible positions in Ah, but hang on. It's got to be in the end of a region as well, doesn't it?
That was a rule.
So this this digit which we're calling al albby the albby digit the digit that is in the albi rat that's got to be in the end of a region. So is that what it's one of the it can't be it can't be in that one because that that's oh hang on that's a rat. I could have just got rid of that straight away but but it definitely it definitely can't be there.
Does it have to be here?
I mean, it must be one of those cuz it's two or four. So, it's So, it's definitely not the end of that region.
In fact, ah, hang on, hang on, hang on.
It's not that digit either. It's in one of those one of these two cells cuz it must be it must be on a three cell black dot sequence. A two and a four.
I think it does. I'm just trying to say which end cell whe whether it's two or four. It must be in the end cell of a wrap path. And I think the only one available is this one which is going to place this digit which is two or four in this region here.
Oh, I've seen what this is going to do.
Oh, Marty, you are a total genius.
This is good. Um, there's loads going on now. Uh, I I've managed somehow to get the A digit. Oh, could it not be that one?
Maybe it could actually. All right, that doesn't matter. That's not the point I've spotted anyway. Um, yeah. So, what I want to think about is I have worked out that this digit and this digit are the same digit. Now, if they were both four, what would that mean for indigo?
This would be a nine on this grape, and this would be a nine on this grape, and we'd have two nines in this region. That can't be right. So, what we're being told here is that this digit is two.
This is two.
This is not two.
And two is fine on grapes because it has three possible neighbors.
So it's not nearly as restricted. Aha, look at this. So now this two is in the middle of these black currents. So it is surrounded by one four.
I mean this is quite deliberate by the way. It's quite deliberate. Marty has set this up so that this this digit propagates down. I don't know whether he could have I don't know whether he could even have designed this to do this at some early point. I wouldn't put it past him.
Now, what does this mean?
That's going to be the next question, isn't it? What does this mean? So, the ah this digit is now. So, there's a two in one of those, which means this isn't a two.
Is that meant to do something?
Wow. I don't know. Um, I don't know.
I know one of these is a two.
So, it's either So, this is if this is two, this is going to be four. This is going to be eight, which would make this six on the grape. So, this would be a one.
That would be a two.
I don't think that works. Actually, I feel like I've got too many twos in this region.
Ah, okay. I can see this a different way. I can see this a different way.
What I'm going to do is I'm going to ask where those four digits here go in's region. These four digits.
Now, in's region, it looks to me like they must be those four digits, mustn't they?
So, two of these are 579, which can't go on black dots. So, that So, two of these three cells are 57 or 9. If this was a 63 pair, if this was six and this was three, this digit would be a three or a six. Well, it's definitely not because it's on this three cell black three cell black current sequence. So, that's definitely not six. This is four or eight.
So, this digit is 1 2 4 or 8.
Right? So in this row now um I've got I I don't know what this is actually. This is what started me to think about this.
But if this is four, this is going to be two. This is going to be one.
So now so now this is a two four pair. It must be because we know two and four always appear on this sequence. And I've got this as not being able to be four. Now, why why can't that be 4 2 1?
Um, I don't know. I feel like I've Okay, I'm not sure about that. I'm not sure I trust my my own pencil marking.
I mean it's certainly true. Let in fact let's delete everything. It's certainly true that these are all from one 2 48 and it's certainly true that the central digit is 2 or four. That that much is definitely I'm very comfortable with.
Now, why did I think?
Oh, was it because I got rid of two here?
If I get rid of two here, what does that do to our paniply of options? I don't know. So, I do know there's definitely a two in that domino.
That's true. And if this is two, why couldn't it why couldn't it have gone one two four?
Oh no, that wouldn't work now. That would break this black dot. Yeah, once this black dot can't be 3 six, it needs to have a two or a four on it because it's either going to be 1 2 2 4 or 48.
Well, if this was a two four pair, this would be a 1 eight pair and 1 and 8 are not in a doubling relationship. So, so it was right. Okay, sorry. I I didn't trust my pencil marks. Um, but this is now a two four pair.
And now, and now this digit's an eight. That's so beautiful, Marty. You've done it again.
Why? Why is this an eight? Well, let let's look at this digit. Um, this digit here, and ask where it goes in purple.
That digit, I don't know where it goes.
It's in one of those three cells.
But therefore this cell sees this cell via purple and it sees this cell in its own row. So it can't be two or four. So this digit is eight.
And therefore this digit is four and it's black dot. So that's four. That's a two in the corner.
This is a uh well it's a black currentable digit. But it's got to be five different from eight at least. So it's 1 2 or three.
I think all of this is now this is not four.
This is a one by Sudoku cuz this is a 124 sequence.
And these digits up here, I mean, it's an excessive pencil knob, but forgive me. They they've got to be these three digits, don't they? But because of this sort of law of leftovers thing we've been working with.
So one of these that we don't have any more eights here. One of these is a one two pair which might we might be able to get that now. How could this couldn't be a one two pair? It can't have two on it.
So that's got to be a three six pair which means this is a one two pair and we know the order.
So now the two which is I think I can get all my twos. That's the point, isn't it? 1 2 3 4 5 6 7 8. That's the ninth.
We've done We've done all the twos. All your twos are belong to us. Four has to be in one of those three cells by Sudoku.
Okay, that's definitely a win for the goodies.
That is definitely a win for the goodies. as I keep looking down OBS in the bottom right to check it's still recording, but I think it is. Um, right, there's got to be a one in one of those cells. Okay, there's some digits that are not allowed to be on rats.
Um, only only I think we've only discuss Oh, that hang on. This is on a this is on a grape. So, that's 7 8 9.
This black dot is 3 six because it can't be it can't involve 1 2 or four. So it can't be can't involve an eight. That's got to be a 3 six pair. This black dot is either 48 or 36.
It can't involve a two.
So these other gray digits here are the digits 5 7 8 9 in case that's going to be this these these can't be eight because of sedoku.
So eight is in one of two places if we had a rat that is an eight yet. Um probably not.
We could um I mean it's not it's not desperately obvious is it where where we look next the those four digits have to be these four digits in the green region. Now the two is placed. So these digits are from four 57 89 by sort of law of leftovers type logic. I'm I'm getting overly pencil marky here, aren't I? I really I really have to try and concentrate on not doing that. Ah oh, this is good. Right, this this cell here can't be a six because six only has one neighbor on a grape and that's the digit one. And if I put one there, apparently I can't put one anymore in purple. So that's going to be three. That's going to be six.
Now, three can be next to eight or nine on um on a grapey thing.
Now, I've got a 789 triple in indigo.
That feels like it's trying to do something for me, doesn't it?
How do we How do we do that? Um, I don't know.
This eight is looking at that cell. So, that is a that's a that's a ratty nine there. Okay. So, that gives me a 78 pair. Why is my Okay, I can't deal with that. Now, this is a five seven pair at the top of this column, right? So, these two digits are this is perfect. This 57 pair knocked those down to being eight or nine. This nine sees that one. So, I now got an eight in a rat, which is um conquer. I've got a nine in a no, not in a rat. I've got eight coming out of these cells by sodoku. Eight coming out of this cell.
This eight means this is a seven. So, this is an eight.
I've got a rat here that can't be a nine anymore because of this.
So, okay. So, what what what rats have we've discovered so far?
We've discovered a nine. We've discovered an eight. We've discovered a two.
We've got a five or a seven there.
Yeah, we might have to label them or something like that, I think.
But there might be easier easier pickings if I can just spot them.
No. Okay, that can't be an eight.
Okay, that's quite interesting. No, no jokes at my expense. Look, these digits here.
Oh, hang on. That doesn't work then, does it? Cuz didn't one of those have to be an eight?
Or am I going crazy?
So I labeled these cells.
Ah, this is going to be the eight. No, this is good. This is good. Right. I think what I did earlier was I looked at those four and then pencil mark those options into these cuz they have to appear in green.
But now these can't be eight. So these can't be eight. So where do we put eight in the blue region? It has to be exactly there.
So maybe eights is where I should be thinking more or the the place I should be considering in more detail.
It is a bit restricted in dark green.
Not hugely, but a little bit.
Actually, it doesn't. The shapes don't lend themselves to getting all the eights, unfortunately.
I don't think they do anyway. Um, I mean, oh goodness, I've just spotted something else. This is crazy. Look at Look at the indigo region. It ends in a seven.
So, that can't be a seven or gray would end in the same digit. That's vicious. I really hope I'm not going to have to do that all the way through. I will be terrible if I have to spot things like that.
Um, okay. Let's let's pencil mark row four.
We need 1 4 5 6.
But we might be able to do better.
That can't be one. That can't be four.
Oh, is that really all I get for that?
Um, these two, one of those has to be a three.
I can't I can't see how to do that.
Okay, let's try column two then. 1 3 4 6.
So this is one, three, or four.
No, that was not where to look. That's that's really Oh, can I use the rat thing to get rid of anything from there?
Because I Right. What rats have we had now in ter Have I had more than I had had before?
Yeah, maybe this is what I have to do. I might have to actually pencil mark the Oh, either pencil mark the starts of rats or the end of rats according to according to what I can and can't have.
Like I've had a three at the end of this path. So what I could do is, you know, I could go there and say that's not a three, for example.
I don't want to do that, but maybe that's sensible.
or this route. That is 35 679.
But we've had a nine.
Have we had 3, five, six or seven?
Oh, the nine was up there anyway.
Bother.
Um, okay. That doesn't work.
Five in lime green is in one of these three cells. So it is not there. I mean it could be you know picking away at digits like that which would be a terrifying prospect.
Um 8 has appeared as a final digit.
I almost need a there's no spaces. No. I was wondering whether I could click on something outside the grid to try and keep track of which final digits and which first digits I've actually had. Um I mean this digit has to appear in this row somewhere and it can't repeat in red. So it's it's three or six on the from this cell. Five seven or nine from this cell. So, but we know it's a rat, so it can't be a nine. So, that's three, five, six, seven. Same as this one. So, that's three rats that are selected. So, that maybe there's only one rat that can start with a four. Um, what can this rat be?
It could be a four as well, I think. I think four is one. And it could be 1, three, five, seven, possibly.
Oh golly. Okay, that's terrible. This is not how to do it. There there's something I think a lot more straightforward. I just need to spot what it is. Um, right. Where do we look?
Um, it's it could be a grape that I've not spotted.
There's a grape here. Grape here. Grape here. Grape here. Grape here. Okay. It's not one of those.
It could be a parity. Ah.
Is there a reason this is restricted in par Oh, black currents.
Do I somehow know what goes on there?
Don't think so. Not certain, but don't think so.
Ah, hang on. This digit here, if we look at from a law of leftovers perspective, this digit can't be seven. You wouldn't be able to put seven into this um this purple region. It can't be five for the same reason. That is three or six.
That's nearly really good, but not quite good enough.
six because it doesn't tell me the parity of this one.
But that digit then is it's not that one is it in row in row row seven. It's that one. So that is three or six then which means these are the one four pair.
Now that means this is not a one or a four.
So that's three or six as well. Maybe it's three something to do with three sixes and coloring them or something.
Um, okay. Those two digits are the same.
So this digit is the same as that digit.
So that's 5 7 or 9 in in in this region. And that's a 579 triple, which means this digit is a four. Good grief.
And this four means this is four. So I've got I've got ah I've got a ratty four there. I wasn't expecting that. So this is not ratty four. This is not ratty four.
And with my 579 triple, I still haven't put three and six into indigo. So this is a 3 six pair. So these don't include six anymore.
So this digit is 1, four or five by sudoku. It's not four by sudoku. So it's now one or five.
Yeah, every we've only got odd digits left to place in in row five.
And I must be better off on my rats now, surely.
Um, I'm sure I am somehow is but it it clearly is quite lore of leftovery this this isn't it that I'm having to work quite hard on law of leftovers and I've only got 5 minutes because I have to go out. Um but but at least I think I've if I've broken the back of it, I won't feel very guilty if I have to take a a quick pause. Um, but I don't I don't think we're a mile away from solving it. Maybe if I can get one more deduction in the next couple of minutes, it might flow.
Let's hope that's true.
So, from a rat perspective, this I've got three, five, six, seven into those two.
5 six here.
There should be one more rat. Oh, it's this one. Is it? So 3657 are the four rats I haven't found.
I think three, five, six, seven.
And is there anything we can say about any of those? We can say one of these is a three. So that isn't a three. But I mean things like that are not probably what we have to do.
Or maybe I've got to keep track of the fact I know those digits are the same.
1 4 5. I know one of these is a six. Is that somehow helpful? If I knew that was a six, I would know this was 48.
Um, okay. I haven't got anything at the moment.
What do I need into this column then? I need 5 7 8 9. Now there is a seven and a nine in this one and there is a five in this one and in this one there's not very much but what that does ah that's quite good.
So now in the orange region where is four? I don't know but it's in one of those cells which means this digit is a one and this digit is a four. Now does that do anything for me? Now this is not a four.
So, this is not an eight.
One has to appear in orange. It is now there. So, that's Oh, I hadn't got that.
I think that was available if I'd seen it. I I didn't realize I hadn't got it.
So, this is a five. I've now got seven and nine. Ah, which are those two digits, aren't they? Cuz they have to appear in column nine.
So, this is a So, this rat is not seven anymore.
And where's SE? Oh, no. I thought I was going to get the seven, but I don't quite get it.
Ah, but I get that digit for the price of nothing. That's a three, which turns out to be absolutely hideously unusful. That's distressing.
Um, okay. And I think I've underused all of this stuff I've just earned.
So, I've really got to pay attention and try and get this row. Maybe one, five, and eight left to place.
Can we do anything with that? Ah, yeah, we can. That's naked. That's I mean, that's hard to see. That is hard to see.
This digit is a naked single. It sees one and eight in the column and everything else in the row. So, that is a five, which makes this rat a six. Now, if that's a six rat, what can we do with that? We can get rid of six from here.
So, which rat? Where's the other rat that I haven't done?
Cuz it can't just be these two. There must be another. Oh, it's this one. Ah, so that's a three. So, that's a five.
That's a seven. That's a nine. Okay, now that might do some thingies for us, maybe.
Um, these two digits are a 3 six pair now.
Whoa. So, I've got a 3 six pair in this column. This digits become an eight.
This has become a four. Therefore, this is not a four.
In this column, we need a one and a nine. I can do the one because it can't be in the same region it's already been in.
And oh really I'm running out of time but never mind. Uh in this column what do I need? 3 six 356 is it into these cells and that can't be three.
Oh I bet you I bet you it's to do with the last digit in a Yeah, we've had a five at the end of a region already. So that has to be a six. I mean that's that's absolutely vicious, isn't it? Uh so this is now five. It sees everything else.
Therefore, that's a seven by the mechanism of nonsenses that we're trying to navigate here. This is a five. That's probably been available for ever by the looks of things. That's now become an eight. So we get a 79 pair here. This has become a six.
Um, and this has become a six. That's become a three.
And okay. All right. I think I think slowly but surely we are getting there.
One, four. This is a five. Therefore, let's get rid of that pencil marked eight. I need a 1 168 at the top here.
So, that's naked. This is a 1 six pair in the top corner. Do not know the 79 doesn't reveal what it is. This column column five 378 to place.
So the three can only go here.
Seven goes here. Eight goes here. Ah, this is a parity dot. So I need an even digit. That's got to be a four or a six.
Somehow that's not resolved. That's extraordinary. Uh, is that really not?
Oh, no. It is resolved. Right. I was going to say that feels very harsh. Now, this is a seven or a nine. That gives me a seven and a nine in this row. So, this is a four and a five.
Uh, 1 2 3 4. This is 58. We can do it. 8 5 4 1 What do we need in this? 69.
Yeah, that's good. 9 6 6 3 We need a one in that column. That does my one. That does my six. What do I need in this row?
Three, by the looks of things. So, something has got to undo these sevens and nines. Oh, it'll be the funny rule about not having repeated digits at the end of So, where I've got a seven at the end of that one, so that has to be nine.
That's absolutely brutal to unwind the deadly pattern at the end. And there we go. Boom. Yes. Preliminary phase completed. Trial date ' 06 to the 5th, 1974.
All nine remaining rats performed magnificently. But one rat went above and beyond, displaying innate flare and understanding of numbers by visiting the digits 1 to nine in perfect numerical order. I had a feeling there was something special about, and I must admit, I'm delighted at this result. She will begin tackling the mazes next month, starting with primer. Once the designs for phase 1 are complete and Elliot has fully tested the technology, I can't wait to fully explore what Vhinx is capable of. And more than anything, I'm excited to be working more closely with my friend, Marty. You are a genius.
Loved it. Loved it. Let me know in the comments how you got on with it. Enjoy the comments, especially when they're kind. And we'll be back later with another edition of Cracking the Cryptic.
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