Crack RRB Group D 2026 STATISTICS 02 + PYQ | Tamil - Part 52

[00:00:01]Hello friends, welcome to Max.

[00:00:09]So second part of the video next type medat list of data right if mean of 25 29 25 32 24 and x is 26 then the median of the data Yes.

[00:00:53]26.

[00:00:59]25 29 25 32 [snorts] 24 then x Okay 26ap 29 26 gap 25 26 gap 20 32 22 26 24AP 25 26 gap 25 number one the difference 25 - 26 - 1 29 - 26 + 3 25 - 26 - 1 32 - 26 + X 24 - 26 - 2 then x 2 So right -1 + 3 + 2 + 2 -1 + 6 + 7 + 7 - 2 + 5 So net + 5 + x Find the med of the data.

[00:02:59]order. So number 21, right?

[00:03:14]24 29 32. So list of numbers in order. Okay.

[00:03:41]1 2 3 4 5 6. So even number of numbers.

[00:03:46]Even number of numbers even number 25 simple odd number of numbers Med number of observations.

[00:04:20]Odd number of observations.

[00:04:22]Middle value.

[00:04:28]Even number of observations.

[00:04:35]Middles.

[00:04:37]Average. Average of middle.

[00:04:41]Okay.

[00:04:46]Right. Right.

[00:04:50]The median of the following observations is 58. So number 46 64 87 41 58 77 35 90 55 92 33 58 median. If 92 is replaced by 99 and 41 is replaced by 43 in the given data the new median is okay.

[00:05:11]Number 46.

[00:05:13]33. Number 1 2 3 4 5 6 7 8 9 10 11 numbers. So for Odd numbers lowest number.

[00:05:55]Okay.

[00:05:57]Uh 30 series, right? 401.

[00:06:05]Highest number 87.

[00:06:12]92.

[00:06:22]92 is replaced by 99.

[00:06:25]92 99 41 41 series 46 41 46 41 43 41 43 4 3 4 9 somewhere 58 So med is not affected by extremities.

[00:07:52]Sixth observation.

[00:07:55]Sixth observation. Sixth observation.

[00:08:02]So median is not affected by extremities.

[00:08:11]Theoretical point, right?

[00:08:29]Find the median for the data. 9 6 8 11 16 22. So med ascending order. So 6 8 9 11 16 22. So number 1 2 3 4 5 6 number 9 + 11 by 2. So put 20 by 2 10. So med simple simple answer right median from grouped data group for group data Median for grouped data for L + N / 2 - C / F into Hrack The mode of the given data is 22.75.

[00:10:12]Find the median.

[00:10:29]79 x3 sorry 22.7 22.7 so 21 to 28 22.75 corresponding frequency Sorry.

[00:11:04]Model class.

[00:11:07]Okay.

[00:11:22]- f_sub_1 by 2 f_sub_m - f_sub_1 - f_sub_2 limit. So in the in the limit on the lower limit 21 L plus FM on the frequency of the median class 11 minus F FM 11 F_sub_1 9 divided by 2 into FM 2 into 11 - 9 F_sub_1 F_sub_2 succeeding so X into H1 class width 21 28 difference 22.7 right 21.75 so 11 - 9 2 2 into 7 / 2 into 11 22 22 - 9 13 - 227. So cancel 14 uh 27 27 3 5 735.25 uh 2 cancel 0.125 1 by 8. So 13 - x = 8. So x 13 - 8 5. So, right, right into H. Okay.

[00:13:42]Cumulative frequency. Cumulative frequency 0 to 7.

[00:13:55]0 to 7. 7 to 14.

[00:14:00]14 to 21.

[00:14:03]21 to 28.

[00:14:06]28 to 35.

[00:14:10]35 to 42.

[00:14:18]Frequency frequency frequency.

[00:14:37]Frequency 0 to 7 to 14 11um frequency.

[00:15:09]8 + 9 [snorts] 17 28 28 33 right 33 36 So frequency frequency frequency Med.

[00:15:58]So 36 sum of all frequencies. So the sum of all frequencies by 2.

[00:16:10]So 36 by 2= 18 17 28 33 36 first time 28.

[00:16:31]So median class. Okay.

[00:16:44]Med.

[00:16:55]So cumulative frequency 36 sum of all frequency 36 then medus c by f into h lower limit of the median class lower limit median class 21 to 28 Lower limit 21 small capital Cumulative frequency of the class preceding the model classulum frequency 17 value 17.

[00:17:54]Medul frequency of the median class frequency of the median class 11. So median class 28 frequency frequency frequency into H class width class 28 28 21 difference.

[00:18:22]So 21 to 28 right 21 + 18 - 17 1 1 into 7.

[00:18:38]So 21 + 7 by 11.

[00:19:05]So 21 + 7 by 11 1 into 7 by 11 7 by 11 so 21 + 7 by 11 so approximate 21.64 21.64 64 approximately.

[00:19:29]So first model then previous question find the mean of the given data if the cumulative frequency is 45. So cumulative frequency 45 cumulative frequency 45 by 2 22.5 45 22.5 Okay.

[00:20:19]1 to 11 11 to 21 to 31 31 to 41. So table form then respective frequency f1 to 11 1 10 11 to 21 11 21 to 31 x 31 to 41 11 Okayum frequency total frequency 7 9 11 in the frequency column 10 11 x 11 So frequency column 10 + 11 + 11 value 11 22 32 45 So you'll get 13 right then First 10 copy.

[00:21:48]Then 10 + 11 21. Then 21 + number 13 34.

[00:21:58]Then 34 + 11 45.

[00:22:07]So nx 22.5.

[00:22:12]So 22.5 21 then 34 median class 21 to 31 median class right formula.

[00:22:37]So median class formula median formula L + N /X 2 - C by F into H L lower limit as usual. So median class lower limit 21 plus n /2 already 22.5 minus c uh class preceding the median class cumulative frequency of the class preceding the median class 34 21 so c divided by f frequency of the median class frequency of the med class 34 then into h class width 21 31 Answer 10.

[00:23:18]Okay. So 21 + 22.5 - 21 1.5 1.5 into 10 15.

[00:23:27]So 15 by 13. So 21 + 15 15 by 13 1 2 3 1 2 3 2. So 21 22. So 22 2x 13 answer right. 15 by 13 mixed fraction 1 2x 3 22 2x3 right empirical formula mode = 3 median minus 2 mean. So equals to 3 medus 2 meanal distribution normal distribution.

[00:24:47]Normal distribution [clears throat] skewed distribution.

[00:24:58]So normal left side 50 right side 50% only distribution Right.

[00:25:35]A set of data is given. The mean of the set is 40 while the median is set as 70.

[00:25:39]Find the mode of the data. So mode formula three median minus 2 mean.

[00:25:47]So med value 70. So 3 into 70 - 2 into uh mean order value 40. So 370 210 - 240 80. So subtract 130 210 - 80 13.

[00:26:11]Right? Okay.

[00:26:14]If the mode of a data exceeds its mean by 10.8, 8 then the mode exceed median - 10.8 + 10.8 modeus 10.8 mode 10.8. So 3 medus 2 meanus 10.8.

[00:27:32]So 3 medus 2 into mode 2 mode - 2 into - 10.8 21.6 + 21.6. Okay.

[00:27:44]Right.

[00:28:45]Three medusals 21.6 So minus median 21.6 6 / 3 7.2= two. So, the product of mean and mode is 24 and Product of median and mean is 32. The square root of the sum of squares of mean 3 * median and mode is a into roo<unk> b into 11. Find a root over a bode mean into mode into mean.

[00:30:22]Okay. and plus median a into roo<unk> b into 11 root of a right. Okay.

[00:31:21]So mode by med by median.

[00:31:26]So by med 38 modeals 3 medus three median Medus mode by 2.

[00:32:01]So 4. So 3 4 are 12 - mode on 3 / 2 12 - 3 9x 3x med 4x.

[00:32:19]Okay.

[00:32:22]information mean 9 by 2x into mode 3x 3 24 times x into x² = 8 into 26 by 9 x² 16 by 4 by3. Okay.

[00:33:00]So 9 by 2.

[00:33:07]So 9 by 2 into 4x3 3 cancel 2 2 cancel. So 6 3x 3 into 4x3 4x 4 into 4x3. So 16x 3 median mode 4 right. So mean square 6² + 3 into median 3 into med 16 by3 the whole square plus mode 4² into b into 11 right. So 6 square 36 + 3 3 cancel as 16 square 256 + 4 square 16= a² b into 11. So uh 60 72 uh 38 = a² b into 11 2 8 11. So a square b 28 a square b 28 possibilities 28 1 into 28 2 into 14 3 4 into 7 then 7 4 into So a square B 7 A + Boo 2 + 7<unk> 9<unk> clear step by step First mode, then a square. A square.

[00:35:49]Possibility.

[00:35:51]A square. B7. A 2 B 7 A 2 + 7 line right solution.

[00:36:23]So download.

[00:36:31]So in the video I think the last of the RB group series quantitative aptitude series last few days.

[00:36:51]So exam practice.

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[00:37:50]45.

[00:37:59]Do best practice.

[00:38:10]Most of the basics, but you might need more practice than you think.

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