The Pythagorean theorem (a² + b² = c²) is used to solve right triangle problems by relating the lengths of the two legs to the hypotenuse; for example, in a rectangle with length 12 cm and diagonal 15 cm, the width is found by solving w² + 12² = 15², yielding w = 9 cm.
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GED Math Geometry Practice: Full Solutions & TipsAdded:
GED math geometry practice.
Question one. A rectangle has a length of 12 cm and a diagonal of 15 cm. How wide is the rectangle? Option A, 6 cm.
Option B, 8 cm. Option C, 9 cm. Option D, 10 cm.
The correct answer is option C, 9 cm.
Use the Pythagorean theorem because the diagonal is the hypotenuse. W squared plus 12 squared equals 15 squared. So, W squared equals 81 and W equals nine. A and B are too small because they would not make a 15 cm diagonal with length 12. D is too large because 12 squared plus 10 squared gives a diagonal greater than 15.
Question two. A ladder leans against a wall so that its base is 5 ft from the wall and its top reaches 12 ft high. How long is the ladder? Option A, 13 ft.
Option B, 14 ft. Option C, 15 ft. Option D, 17 ft.
The correct answer is option A, 13 ft.
The wall, ground, and ladder form a right triangle with legs five and 12.
So, the ladder is square root five squared plus 12 squared equals square root 169 equals 13. B, C, and D are longer than the Pythagorean result.
Question three. The hypotenuse of a right triangle is 25 cm. One leg is 7 cm. Find the other leg. Option A, 20 cm.
Option B, 22 cm. Option C, 24 cm. Option D, 26 cm.
The correct answer is option C, 24 cm.
Use the Pythagorean theorem. Other leg squared equals 25 squared. 7 squared equals 625 to 49 equals 576.
So, the leg is 24 cm. A and B are too short, and D is impossible because a leg cannot be longer than the hypotenuse.
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