Equating basic radical simplification with Stanford-level intelligence is a pretentious reach for clicks. It’s a standard math tip wrapped in unnecessary academic elitism.
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Solve this and you're smart enough for Stanford..Added:
Solve this SAT problem. You're smart enough for Stanford. Um 2 to the 2/3.
That's like the cubed root of the number squared. Oh, wow. That actually worked.
Okay. Inside the radical 2/3 squared. We square the top and bottom. So 4 over 9, the cub root of that. Now we can apply the cub root to both numbers. So the cube root of 4 over the cubet of 9. Now 1 over the cube root of 9 can be expanded as 1 over the cube root of 9 * the cube roo<unk> of 9^ 2 over the cube root of 9 squared. Looking at the denominator we can combine. The cube root of 9 to the 1 * the cube roo<unk> of 9 2 is the cub root of 9 cubed.
Sweet. Cub root of 9 cubed. That's just 9. Now the numerator 9 is 81. So cubet of 4 * cubet of 81. 81 is 27 * 3. We can split this up. So cube<unk> of 4 * cube<unk> 27 * cub<unk>3 cube root of 27 is 3. So the 3 over 9 we can reduce to 1/3. We're left with cub<unk> 4 * cub<unk>3 over 3. We can combine the things up top into cub<unk> of 4 * 3 or the cub<unk> of 12 over 3. That's simplified. Want more SAT hacks? Click the video below.
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