🔥 PP RULE = 4 Chapters DONE in Minutes 😱 | RE-NEET 2026 Chemistry Game Changer 💥

Hinzugefügt: 2026-05-25

[00:00:01]Hey all my dear students, welcome back again to HSP in world of chemistry.

[00:00:06]Right now I will tell you one simple fundamental thing that is going to solve near about four chapters questions.

[00:00:16]Now see let's start with you know you can call it Nandu and call him to be Hu. There are two type of people Nandu and Hu. As you can see Nandu is weaker and Hu is double means powerful. Hu is more powerful. Now how to find out that Hu is more powerful because here to have drawn the diagram but in the examination you have to deal only with chemicals. So once you can correlate the chemicals with person with whole everyday life you can talk about then definitely the question paper you can solve the chemistry you will start loving chemistry right now see hu is double power because hu is H2SO4 and H2SO4 can release you see how many H+ ions two H+ ions so it's power n factor we call power is two, n factor is power and it can release just one O negative ion. So its N factor is one. So what we are getting? Remember in your brain that N factor is the power. Let me write down here your N factor is equivalent to power.

[00:01:35]And now you see his power is double and its power is single. If they want to equal fight this is basic army and this is acidic army this is hero this is villain if you want that fight should be equal that no one is going to win or they will remains on same position so see if I say it's one mole people are there one mole in his army basic army one mole people and if I say in this army also there are one mole so who will be winner definitely he is going to win this game because his one mole army can kill his two mole army person right so definitely if you know why why I'm saying because power is double than that he is heavier than that he is more powerful than that so if you really want to make this fight to be equal so make it into one into two moles. So two moles because one mole will kill its two moles. Now you know this is the fight.

[00:02:48]We have easily solved it but by chance if it is coming in the chemistry we will won't be able to solve anything.

[00:02:57]Oh my god what's happening? What's happening? What's going on?

[00:03:04]So let's see in the chemistry how to do that. Now by fight you know two mole of this person and one mole of this person all they will fight together and they will convert into another type of people that salt and water. Now see the chemistry if I say it power is one. So just remember n is number of mole of people and nf is power. NF is power number of moles of people and this is the power. So what is the thumbnail? What was written on the thumbnail? PP rule. People power people power PP rule. Just remember one thing number of people's and the power. PP rule PP rule that you have to put it in your brain. PP P for people. P for power. Now see if I say NNF NF of acid or base is equal to NNF of acid.

[00:04:13]This is known as law of chemical equivalence. Law of L O C E. What I'm saying? Law of chemical equivalence. Now see my dear students if one thing is given suppose about this is given one mole. It's 1 mole is given and its power we are getting from here and its 1 mole is given then we can find out the power or power is given we can find out its mole if its moles are missing we will say 2 into 1 if I write here n mo moles so you see 2 into 1 2 and n into 1 so n is equal to two so it's 2 moles will be required is it clear first of all tell me if power is less more people will be required. If power is more, less people will be required.

[00:05:05]And this law is valid everywhere. You must have seen N_sub_1 V_sub_1 is equal to N_sub_2 V_sub_2.

[00:05:15]If I talk about gaseous law, then P1 V_sub_1 is equal to P2 V_sub_2. If something is constant everywhere, I have written just four chapters. My dear student, I can kill eight chapters with one simple rule. PP rule, power and number of people. Now see first question in front of you. Just see this question.

[00:05:39]Is it visible to all of you that it's written N2 + 3 * H2 gives 2 moles of ammonia.

[00:05:47]Read it out everyone. Just read it out then I will explain then Baba will explain to you. First everyone read it out. He's process. This is from chemical kinetics chapter chemical kinetics.

[00:06:08]Now see what they are asking the rate of reaction and rate of disappearance of H2 will be and what is given about ammonia is given. This is the concentration moles per liter. Now you will say sir how to apply PP rule because there you said number of people and n factor here number of people are not given. So remember that number of moles per unit volume concentration is nothing number of moles per unit volume and this reaction is taking place in the same flask. So volume will remain same. So if volume is same then number of moles and concentration is same. Now just see from here what you can see that rate of appearance of ammonia is given this much and they are asking rate of disappearance of H2 that means they are comparing in between H2 and ammonia. If you see the previous one if I say its N factor was 1, its N factor was 2. When N factor was X ra to Y crisscross molar ratio will be Y ra to S. If n factor is x ra to y molar ratio will be y ra tox remember that if n factor you know you can balance the reaction this is the next application a balanced reaction you know you can find out the n factor crisscross a balanced reaction stoometric coefficient is 2 to1 then n factor will be 1 to2 it stoometric coefficient it's its power its stoometric cofficient it's its power right right now see so you see if I say there n factor if its stoometric coefficient is two its n factor will be two and if it stoometric coefficient is three that should be its what n factor so can I write here that twice of no don't let let us write it n factor vector. So here is H2 and here is ammonia. Now I will say number of moles that is a concentration per unit volume number of moles that's number of moles will become concentration will become number of moles and its n factor is two two and its number of moles and its n factor will be three.

[00:08:36]Right? This thing you are able to understand and I will put equilibrium sign is equal to because n_sub_1 f_sub_1 that is n factor n is equal to nn right now see what information we are getting ammonia is given 2.4 Therefore it's moles per liter that is the concentration we can write here 2.1 into 10^ -4 into 3 is equal to this two we know this we don't know so I can write n = and divide it by 2 now see 2.53 are 2.53's are 7.5 and 7.5 into 10^ -4 7.5 into 10^ -4 4 divided by 2. Now what I will get 275 75's half is if I say 74 that is 30 7 37.25 37.25 so it will become 3.7 uh 5 3.75 yeah 3.75 into 10^ -4. Now 3.75 into 10^ -4. So this is wrong. This is wrong. In both of these 3.75 into 10^ -4 is given. Why? R our work is solved.

[00:10:03]Now if you really want to solve even this question also the rate of reaction.

[00:10:08]The rate of reaction is always measured with one stoometric coefficient. So you can see it's stoometric coefficient is half of it. So half of it or you can write directly write rate of reaction is equal to this is the product 1 by 2 with the concentration of ammonia that was given this concentration of ammonia I will write here so I will write 1 by 2 into 2.5 into 10^ -4 10^ -4 so you will definitely get half of 2.5 is 1.25 1.25 25. So this will be your correct answer.

[00:10:50]I hope this is clear. This is clear. You can only solve this question once you do the practice. I have taken this much of time because I wanted to tell you in detail. Now let's see second the instantaneous rate. Once again this question is from you see chemical candidates but it must be looking like redux reaction. Are you getting my point? Now see the instantaneous rate of disappearance of M4 negative M4 negative pink purple or red ion in the following reaction is this much. And what they are asking the rate of appearance of I2 that means M4 negative law of chemical equals that is with I2.

[00:11:36]Now we know that its N into N factor will be equal to its N into N factor.

[00:11:42]Now what is given? We know that concentration number of moles per unit volume. Volume is same. So concentration will be equal to number of moles. So about M4. But let me tell you the balanced reaction is given. So no need to find out the N factor otherwise N factor we must have calculated with the help of oxidation state that M4 negative is changing into M&2 plus its N factor is C. Let me tell you its n factor is five and this I negative is changing into I2. Here it's not required because once the balanced chemical equation is given no need of n factor. I've told you when n factor is x raed to y molar ratio will be y raised to x. Now but let me make it clear if by chance they have not given the n factor or the balanced reaction how to do it. I negative is changing i2. So it's n factor 1 i negative is changing to i2. So -1 to 0 -1 to 0. Can you see what should be the n factor? n factor. So -1 to 0. So its n factor is coming one. So if I write this is five then that should be how much? If this is five but see this is the n factor of i negative. But we are supposed to calculate of I2 because in the question they have given I2. So that will not work. Let's calculate N factor of I2. I2 is changing into I negative. So N factor is equal to number of atoms into absolute mode of final oxidation state minus initial. So its n factor is two.

[00:13:26]Its n factor is two.

[00:13:29]So see five and two. So two and five matching or not? It's exactly matching.

[00:13:35]But here because the balanced chemical equation was given so no need to find out the n factor. Now let me write down let me write down its n factor is two moles I don't know its n factor is five and moles are given the concentration 4.56 4.56 into 10^us3 into 10^us 3 and its n factor moles I don't know moles moles moles the rate of appearance so moles is not given this is the n factor so let me write down moles I don't No n factor once again let me tell you moles and concentration we can take same because the volume is same so only we are find out we have to find out n because n factor is two so let me write down here 2 so n will be equal to 4.56 into 10^ -3 into 5 55 5 divided by 2. Now if you divide by 2 so this will become 2.56 28 28 into 10^ -3 into 5 now 5 2's are 10 10 if I write something more than 10 into 10^ -3 something more than so can I write 1 something into 10^ -2 this is the answer 1 into 10^ -2 1 into 10 is -2. So fourth is the correct answer. Got it kids? Is it working?

[00:15:18]Are you getting my point?

[00:15:21]Everyone, are you getting my point? Now next question. By chance, if you're not able to understand anything, you can ask me in the comment section. Okay. Now let's see another question.

[00:15:33]This is from mole concept.

[00:15:36]mole concept just see to it when one mole of SO3 1 mole of SO3 and 1 mole of O2 1 mole of O2 are made to react for completion. Now see SO2 and O2 their power is not same directly you can apply unitary method when balanced reaction is given you can directly apply mole concept but I will let you know NNF nanaki factory so see when two moles of this is required it's one mole will be required so what they are saying one mole of SO3 one mole of SO3 is required half mole of that will be required but this is given one mole so who is limiting reagent 1 mole of O2 requires 2 moles of SO2. 1 mole of O2 requires two moles of okay 1 mole of SO3 and 1 mole of O2 are made to react.

[00:16:30]Something is wrong because it will not be SO3 because they are reacting. So here SO2 will be there. Correction sorry misprinting is there. So one mole of O2 will require two moles of SO2 but only one mole of this is given. So this is this is your limiting regent. One point is clear and the product will be decided by limiting regent only. Now you will say sir what happened to your NNF PP rule you are doing it by unitary method has it got failed? No my dear friend let me tell you if I tell you SO2 N into NF of SO2 right N into NF of SO2 you see its stoometry is 2 its stoometry is 1 that means its N factor is 1 and its N factor is 2 when N factor is X to Y mar ratio will be Y ra to X so SO2's N factor is 1 so let me write around one and moles moles are given SO2 1 mole SO2 is given 1 into 1 it's coming out 1 mill equivalent we will say 1 m equivalent now let me write down O2 about O2 if I write down O2 NNF N into NF it's 1 mole is given and N factor is two so it is coming out two who is more this is more and that is less the less one is limiting reagent.

[00:18:04]Less one is limiting regent. I hope this point is clear. This is the limiting regent and limiting reagent is going to decide the product. Always the product is decided by limiting regent. LR will decide product.

[00:18:30]So it's very clear from the mole concept two mole of this it's forming two mole of SO3 for one mole of this will form one mole of that hence very clear right now you will say what happened sir once again you are doing it by inventory method what happened to NNF okay see PP rule everyone just see to it PP rule 2 and two that means n factor is same 2 two n factor is same so let me correlate SO2 and SO3 so it's people into power people into power so about whom we know we know about SO2 one into two I know power I don't know n into two so the value n will come out one n will come out one so one mole of SO3 will get produced and oxygen was in excess So this is wrong.

[00:19:30]If this is wrong, so this is wrong. One one m of S. So because it was the limiting region, limiting region will get consumed fully that will not left.

[00:19:40]Now you see is it clear to all of you once again if it is clear do let me know in the comment section that yes sir it's clear. Now next one you see this question is from mole concept.

[00:19:56]Nice slides.

[00:20:02]Nice slides. My speed is a little bit more because you are having less time.

[00:20:07]That's why I'm speaking very speedily.

[00:20:09]Right now see one mole of this army two moles of this army when they are getting died during fight one mole of C is getting formed.

[00:20:19]One mole of this one mole of is getting fight then this this this is the stoometry ratio. So why you are telling us stoometry ratio? Just do it with PP rule. People add power rule. Okay, I will do it now. See five mole of this A and B. A and B. So it's N stoometry is one. It's two. So it's N factor will be two and its N factor will be one. When stoometry coefficient is X to Y, N factor will be Y to X. If n factor is x to y, stochometric coefficient will be y tox crisscross. Now let's see a and let's see b. It's n into n factor people into power will be equal to its n into n factor. So what they are giving? Now first we have to find out who is the limiting regent. How to find out limiting regent? Let's see the limiting regent. If I say a is factors 2 and they have given five mole of a 5 into 2 and about this right now we don't know whether they are equal or not equal 1 into 8 this is coming out 8 only and that is coming out 10. So definitely this is more and that is less. Are you getting my point? This is coming out 10 and that is coming out eight. So definitely this is your limiting regent. Limiting region will decide the product firmed this is going to decide. Now if you are really having too much brain you must be saying why are doing people and power rule you directly you will apply because the reaction is balance just apply both unity method that one mole of this are killing two moles of that. So five mole of this will kill 10 moles of that but they are just eight. One mole of this army will kill two mole of this army.

[00:22:19]Five mole of this army will just kill twice of that army. That two 10 moles but this is only 8 mole. So this is your limiting region. Now let's decide in between B and C. B and C. So that's gone and they are not equal. So this is the limiting region. B is the limiting region. So we will compare B with C. Now it's double its N factor is one. Then in its n factor will be twice because you correlate this. Now what they are asking this and this is reacting will produce what? Now see let me tell you with this to this directly you can see two moles of this is producing one mole of that.

[00:22:57]So 8 mole of this will produce half of that four moles of that. So answer is second very clear. But let me tell you people into power rule. through people into power rule. You can do it.

[00:23:11]Say about B and C N into NF. N into NF. Now you must be thinking sir if we can solve it through unity method. Why? Why you are applying this N into NF? Because mole concept unity method somewhere it will work some other place it will not work. But N into NF will work everywhere. My dear students, whether the reaction is balanced or not balanced, this will always work. So always go with this. Now see number of moles 8. N factor is one number of moles I don't know n factor is 2. So the value of n will come 8 by 2. So n is equal to 8 / 2 that is four. We are getting answer. I think one more question will be there. Let's see last but not the least. I hope everyone is able to understand each and everything.

[00:24:08]Now this is from redox a lovely redox redox chapter let's see how many ms of parasulfate I have told you now I have told you now here reaction is not balanced and that's why I'm telling you that two by pp rule power and people number of moles of people and power let's that K4 in acidic medium. First of all, let me tell you about K4 in acidic medium. Always remember that K M4 whether the medium is given or not given. If it is being acidic form like this if even the medium is not mentioned always take it to be acidic. Right? So see from + 7 it is getting changed to +2. So its N vector is five.

[00:25:08]We got its n factor. Now let's go one by one. Ferrus sulfate. Ferrris can change to feric. Ferrus can change to feric green to yellow. Its end factor is coming out one. Ferrris and factor is one. So let's compare uh K4. Let me write down here. K4 where to write down? Let me write down here. K M4 and this ferrris NF it's N factor it's NN factor and we know that how many moles of ferosulfate it is required by K4 by 1 mole of KO4 so 1 into 5 is equal to I don't know N I know 1 so N is coming out five it has to start with five the first answer is five so this oh my god these can't be the So only with one we are getting. But let me solve H2C24.

[00:26:06]H2C2O4.

[00:26:08]If I say H2 C24.

[00:26:14]Now they have not written. Now see carbon is in +3 oxidation state. Maximum oxidation state of carbon is +4. So +3 to +4 but two atoms. So its n factor is 2 into absolute mod of 4 - 3 that is coming out 2. So 2 let me solve it over here for this this this what this one H2C24. So this is CO4 that is H2 C2O4 N into N factor PP rule N into N factor its moles one N factor is five it moles I don't know N factor is 2 so the value of N will be equal to 5 by 2 5 by 2 5 by2 it's written over here now let me solve for ferrrailate also so in ferraxilate two things are there one is feros Ferris will convert from ferris to feric. So its n factor contribution is 1. And oxilate we already know its n factor because we have calculated over here C24 2 negative is changing to carbon dioxide. Its n factor contribution is 2. So 2 + 1 that is coming out three. So overall its n factor is three. So let me solve over here. CO4 into ferosxilate Fe C24.

[00:27:42]So let me write down N into NF is equal to N into NF. It moles given 1. N factor is 5. It moles we don't know. N factor is 3. So N value will come out 5 by3.

[00:27:56]5x3 you see 5x3 we have got the answer.

[00:28:00]So my dear friends I hope that you must have enjoyed this lecture.

[00:28:06]Write down in the comment section I will bring number of such type of concept.

[00:28:11]Baba is having so many concepts that you can solve just the whole chemistry with few rules only. Okay, I said that only four chapters you can solve with this. But later on I will let you know that near about all the chapters of inonic chemistry also you can apply and number of other physical chemistry chapters you can apply this fundamental thing.

[00:28:35]Bye-bye. Take care. All the best.