REDOX REACTIONS

[00:00:00]Welcome to another video class of Entry everyone.

[00:00:02]Dear friends, the topic that we are going to discuss in today's class is called Redox Reactions. This topic is very important for any exam from LDC to HSA. Be it LDC, Plus Two level exams, LPUP, KTET, Degree level exams, chemical reactions. Redox reactions in the topic called Chemical Reactions are the most important topic for any exam. So here we are going to see the oxidation number.

[00:00:43]Similarly, we are going to give some reactions and see if they are redox reactions or not. So our main purpose here is to discuss those questions. I have brought a few questions related to that here. I will teach you that. So, if you are crystal clear and listen to the class from the beginning to the end, whatever your doubts are, If you have any doubts about the class, please comment below this video.

[00:01:13]Okay, let's get into the class. Okay, then before I tell you the content, let me introduce you to some extra things first. Listen, because after learning those things, we need to go to the content. Okay, first of all, let's learn to see the oxidation number. Learn to see what.

[00:01:36]I'm going to teach you to see the oxidation number. If you have any doubts, ask me. If you ask me how to see the oxidation number, you all know. When I tell you to see the oxidation number, we need to know the oxidation number of some people without seeing it.

[00:01:52]We need to know the oxidation number of some people without seeing it.

[00:01:55]Who are they? I'm going to tell you.

[00:01:58]First of all, hydrogen. The oxidation number of hydrogen plus one. Always study the oxidation number of hydrogen plus one.

[00:02:08]Don't forget the oxidation number of hydrogen plus one. The oxidation number of hydrogen plus one is the same, not chlorine, the same. The first group that comes in the first group, what is the name of the first group, alkali metals? Who comes in the first group? Lithium, sodium, potassium, and so on, rubidium, cesium, so you don't have to learn anything about everyone. Learn about sodium in the first group, that's also plus one. Learn about potassium in the first group, that's also plus one. That's enough for now. So hydrogen's plus one. Sodium, potassium, and all of these in the first group are plus one. Now you should know the same thing. Know the charge of chlorine.

[00:02:54]How much is minus one? Minus one is minus one. The oxidation number of chlorine is minus one. You should know the same thing. Oxygen is minus two.

[00:03:05]Oxygen is minus two. So now, similarly, those who come in the second group, who come in the second group are beryllium, magnesium, calcium, strontium. It goes like this. So you know the name of the second group.

[00:03:21]Alkaline Earth Metals. So everyone, the second group group comes. Magnesium, know that the oxidation number of magnesium in the second group is plus two.

[00:03:35]Listen carefully.

[00:03:37]Calcium, which is in the second group, also has plus two. So you should know this much crystal clear. If you have any doubts, you should ask me. So, write this down in your notebook.

[00:03:49]Whenever I ask you, you should tell me. The oxidation number of hydrogen is plus one. The oxidation number of sodium is plus one. The oxidation number of potassium is plus one. The oxidation number of chlorine is minus one. The oxidation number of oxygen is minus two. The oxidation number of magnesium is plus two. The oxidation number of calcium is also plus two.

[00:04:06]So, how can we find out? Ready?

[00:04:10]First, I will show you the easiest way. Let me give you the following.

[00:04:24]Potassium dichromate. There is one fact that you should know. If you ask me what color KC2O7 is, it is orange.

[00:04:35]Don't forget, if you ask what the color of potassium dichromate is, it is orange.

[00:04:46]Don't forget, the color of potassium dichromate is orange. In the compound called ketasida, we need to find the oxidation state of chromium. Let's find the oxidation state of chromium.

[00:05:03]Dear friends, first of all, you should change it here and write down the ketasida. Who are there? If you say KK, there is potassium. If you say CR, there is chromium. If you say Chromium, there is oxygen.

[00:05:21]I wrote down the ketasida. Who are there? I wrote down the potassium. Cr, there is chromium.

[00:05:27]Similarly, O, there is oxygen. Now let's write down each one. The oxidation number of potassium is one plus one of chromium.

[00:05:36]We need to find the oxidation number of chromium. I gave it as X. Next is oxygen. I gave the oxidation number minus two as potassium plus one chromium x oxygen minus two. Now listen carefully to what I say. The oxidation number of a potassium is one plus one, so how much potassium is there here? Listen to the two beloved ones with your heart. Listen with your heart. One of a potassium.

[00:06:08]So how much potassium is there here?

[00:06:11]Two. Then I am writing. I have not finished one plus. Next, who is chromium? We do not know how much of a chromium we have taken. So I have taken one of a chromium as X. So how much chromium is there here? Let me say one more time. X of a chromium.

[00:06:33]So here we have two chromium.

[00:06:36]So how can we write 2.

[00:06:40]After X plus, the next oxygen is one oxygen minus two. So how much oxygen is there here? Seven of an oxygen minus two.

[00:06:50]So here we have seven oxygens. So how can we write this. Emu is two equals zero. If you don't forget, okay, then look, 2 even, okay, plus 2 even, don't forget, next plus, this is my minus, this is my minus, how many minuses are equal to, how many minuses are equal to, my dear, zero is equal to zero, do you believe that you don't forget, now I'll leave 2x there, after I leave 2x there, after I leave 2x there, I'll bring everything else over here, if I want, I'll erase it and write it down, write it down, write it down, write it down, I'll erase it and write it down, write it down, I'll leave 2x there, and bring everything else over here, minus 14 when it comes over here, plus 14 when it comes over here, minus 2a will come up, we'll get, right, what do we need What do you do when you multiply it? What do you do when you come to this side? What do you do when you divide it? If there is no charge, then you should give it as plus. Plus six.

[00:08:27]How much is the oxidation state of chromium? Plus six. Is this easy or not? It is very easy to find the oxidation number.

[00:08:32]Dear friends, you should not think of any difficulty. If so, you can do this question yourself.

[00:08:41]I have a belief that you will do it yourself.

[00:08:42]Okay, the next question is M2O5. In this, we need to find manganese. M2O7.

[00:08:54]In this, we need to find the oxidation state of manganese. So, we need to find manganese. We don't know how much manganese is.

[00:09:02]So, let's give MA manganese eq. Next, oxygen. Let's give how much oxygen. Let's give minus two. No, oxygen. Let's give minus two.

[00:09:15]Now it's easy. The content is very easy.

[00:09:18]Listen to what I'm saying. Look at the X of a manganese. So how much manganese is there here? Two. So how can we write? Did you say that? 2 EUA plus the next is oxygen minus one oxygen.

[00:09:33]So how much oxygen is there here? Seven. So how do we write it?

[00:09:38]What is this It will be zero.

[00:10:00]The sum of the oxidation states of the elements in a compound will be zero. So I left 2x there and when I get minus 14 on this side, I get plus 14 as 2a = 14. We need x. So we have x. So we have 14 on this side. We have multiplied two here. When we bring the multiplied two to the equal sign on this side, we divide. So we divide 14 by two.

[00:10:27]Our answer is plus. You see, plus. You tell me. Does this work? Does this work? Does it work? Does it work? Does it work? No. Let's believe it's easy. The next question is when I say the question, the smart ones are the ones who post the video and do it. Did you post the video and do it? Don't wait for me.

[00:10:51]I'll come and get you ready. My dear friends, the next question is this. H2O2O2 in sulfuric acid. We need to find the oxidation state of sulfur in sulfuric acid. We need to find the oxidation state of sulfur in E2E. So first, in that Who is there? There is hydrogen, there is sulfur, there is oxygen, right? Let's write hydrogen. We need to find the hydrogen plus one of sulfur. So sulfur has six oxygens. We know that minus two is ready. Minus two is ready. If you look, you are one of hydrogen. So here we have two hydrogens. So how do we write 2 one plus the next is sulfur.

[00:11:44]So here we have one sulfur. There is nothing written under sulfur.

[00:11:48]That means there is one sulfur. So how do we write one plus the next is oxygen. So here we have four oxygens. So how do we write pha pha mydu equals how much is zero? Equals zero. If so, look, 2 one pha pha mydu equals zero.

[00:12:21]Clear else four x equals mydu here.

[00:12:27]What happens when you come here? When it comes, what will be minus two? Is it clear, then it will say 8, please tell me sincerely, do you understand this or not? Is there any difficulty?

[00:12:42]Dear friends, is this a fact that you can do? If so, I believe that you will do all this.

[00:12:50]Post a video. After posting the video, do you do one of the FECs right now?

[00:13:02]What is the oxidation state of Fe in FeC?

[00:13:07]What is the oxidation state of Fe in the compound FeC? In this, we need to find the F of the F.

[00:13:15]We need to find the F. So X is also chlorine, so we know that chlorine is minus one, right? The charge of chlorine is minus one. Given that chlorine is minus one, we have one F of X. So here we have one F of E. So we write E. Plus. Now we see one chlorine minus one. So here we have three chlorines. So this is my one equal to zero dear friends.

[00:14:11]I have a belief that if it is so, let's move on to the next topic. Next, we will find the oxygen state. This is not the same as this. There is a difference. So let's tell you something.

[00:14:22]Listen, if you have any doubts, you should share it with me. Listen, don't worry, I'm not going to bother you. I'm going to start my dear ones. Let's start with the name of the dichromate ion. Let's start with the name of the dichromate ion. Let's start with the name of the dichromate ion. Let's start with the name of the The oxidation state is what you need to find. So I'll tell you how to do this.

[00:15:08]You first listened to it.

[00:15:12]We need to find the number of chromium. So we don't know the number of chromium. So let's give it X. Let's change it down to find the number of chromium.

[00:15:25]We're going to find the number of chromium. So since we don't know the number of chromium, I gave it X. Clear. Now the next one is oxygen.

[00:15:39]We know that there is one oxygen minus two.

[00:15:42]Clear. Now listen carefully. The oxidation number of one chromium is X. So how many chromium are there here? Dear friends, there are two chromiums. There is one chromium. So there are two chromiums. So, look at what I'm writing. 2 x is not difficult. Plus, the next one is one oxygen minus two. Right? So how many oxygens are there here? Seven is one oxygen minus two. So there are seven oxygens here. So I'm writing seven.

[00:16:19]Minus two is equal to how much is zero seven into minus equal to zero. Now listen to what I'm saying.

[00:16:26]How much is 2 EUA? Sorry, sorry, sorry. 2 EUA.

[00:16:32]We'll jump in and write how much. We'll write equal to zero. It's not zero here. Why isn't it zero here? Let me tell you why it's not zero here. If you ask, "What is the charge of that compound here? Minus, it's an ion. It's a charge. Minus, then what is the sum of its total charge? Not zero. It's a charge. How much is the charge minus?

[00:16:59]So in cases like that, when people give you a charge like this, you should be careful. When you give the oxidation number, don't write equal to zero. If you put equal to how much, you should write that charge minus. Do you understand why we wrote zero just before? Correct. There was no charge there. When we gave EFA, there was a charge above. No. When we gave it, there was a charge above. No. No. No. When I gave it, was there a charge above or not? When I gave it, was there a charge above or not? So there we wrote equal to zero, there is a charge here, so write equal to zero, write the charge as minus, write it as minus, and it is clear. Pay attention, 2 is how much 2 is minus, how much is minus, is it clear? So I left 2x right there, and when I left x there, what will happen when this minus comes to the equal sign, and the minus comes to the equal sign, dear friends, it will become plus, so already there is minus, and when it comes to plus, it will become plus, so if we subtract the smaller from the larger, and then go to the 14th on the right, we get 12, so the next step is equal to 2a, we need to find x, so we have multiplied here, and when we come to the right, we divide it, and divide by that. If you have seen this, if there are those who do not understand this, just press back and listen to it and go.

[00:18:47]Do not leave the mark of this question for any reason.

[00:18:52]Do not leave the mark of this question for any reason. If it is clear, then I am going to give you another question in the same pattern. Let me see how many of you will do it. If you have any difficulty, you should ask me. Okay, if you have any difficulty, you should ask me. This question is Mn of MMF MMF minus. In this, I posted a video to see the oxidation state of manganese. I tried to be smart and try to see it. MMF minus. I will show you. I believe that you have posted a video and got the answer. What you need to see is S of manganese. So let's give manganese an X.

[00:19:37]Next is oxygen. Let's give it a minus. Ready. Okay, look, you have a manganese X. So here is manganese. How did you understand that, sir?

[00:19:51]Here is a There is nothing written below the manganese, which means there is one manganese there, so the charge of one manganese is X, so here is one manganese, so we write one eq plus, okay, next is minus one oxygen, so here are four oxygens, so we write eq minus, you say eq, let me give you zero, can I give you zero, no, very good, eq, I can't give you zero, because there is a charge here, how much charge is one minus, so let's give it minus one, see, now let's do it, dear ones, eq How will you come then? x = -onepa so x =ctu Subtract the smaller from the larger and subtract the sign of the larger from the eight. The sign of the larger is seven. I believe that the oxidation state of manganese is plus plus clear in plus plus. Okay, with the belief that you are somehow set to find the oxidation number, you have put X to find the oxidation number.

[00:21:34]Yes, but how can you find the oxidation number without putting X?

[00:21:40]That's what I'm going to teach you next. If you know this technique, if you give some reactions, we can very quickly find out whether they are redox reactions or not.

[00:21:50]Without wasting time, then you should think about this technique. HCL, have you listened to me? My dears, HCL, okay, let's say this is a compound. Let's say it is a molecule or a compound. Let's say the hydrogen in this compound is What is the oxidation number of chlorine and zero?

[00:22:13]Why is there a charge on top here?

[00:22:15]No, there is no charge on top.

[00:22:18]So their oxidation number will be zero. So let's see. First, HCA. The first one is hydrogen. Tell me, dear ones.

[00:22:29]What is the charge of hydrogen?

[00:22:34]Plus one. Plus one should be total zero. If it should be total zero, then how much chlorine should be? If hydrogen is plus one, then to make that compound zero, how much chlorine should be minus one? Add plus one and minus one together. Zero is clear, right? You can do it without putting X. You can do it without putting X.

[00:22:57]Look. MGCA is an easy way to say it. Okay, this is a compound that has no charge. This is a compound that is neutral.

[00:23:10]How can we see its total charge or what is the sum of its oxygen states? It should be zero. The second one is the one we know. Let's solve it first. First of all, solve the chlorine, chlorine, how much is one chlorine, dear ones, you know, right? What is the charge of one chlorine? I'm giving you that minus one.

[00:23:35]You tell me, minus one of one chlorine.

[00:23:38]So how many chlorines are there in total? There are two chlorines. So, with those two chlorines, how much will the total be?

[00:23:46]Minus one of one chlorine.

[00:23:49]So, there are two chlorines there. So, the total is my two. In our mind, it's enough to be minus two.

[00:23:54]We know that the total here should be zero. If it's minus two, it should be zero. If it's negative two, then how much magnesium should be? Tell me, how much magnesium should be.

[00:24:06]Correct dear ones, think about it.

[00:24:10]This is minus one of one chlorine. So, how many chlorines are there? Two.

[00:24:16]Then the total there should be negative two. Then, if it's negative two, then, if it's negative two, then, if it's negative two, then, how much magnesium should be?

[00:24:25]See, plus two. Okay, then, zero, this is plus two. All this is minus two plus two minus zero. When you add all this here, it is zero. Isn't it easy? Dear friends, we can do each of these things without bringing something called X. Do you see that if it is so, then I have a belief that is smart and says that the total charge of FZ is zero because there is no charge on top. The total should be zero.

[00:24:55]FZ. Let's do it. FZ.

[00:24:57]Let's do it.

[00:24:58]Dear friends, I wrote minus one of one chlorine.

[00:25:01]So there are two chlorines here. So the total is minus two. So if we want to be zero, we only have FE. If we want to be zero, how much will F be? Plus two is clear, right? Plus two is minus one of one chlorine. So there are two chlorines. So 2 is my one 2 is my one. When we add two more, we get zero. If it is easy, then we will go to a more complicated method. CS.

[00:25:43]Pay attention to this. CS. This is what I will set with today's class.

[00:25:49]Dear friends, this video You are the ones who are watching, let me tell you something. At the bottom of this video, you can see whether you have understood the class or not. You should comment below this video even if you are sure. Don't leave without commenting. Whether the class was useful or not, you should leave after commenting.

[00:26:07]Okay, listen carefully. Calcium carbonate is Cs. So let's find out one for each of you. Let's find out in peace. First, how many of you have written down what calcium is? I said, in the first one, you should not go to the exam without studying. Don't go to the exam without studying the oxidation number of as many people.

[00:26:35]Okay, calcium is a second group element. It is the second group element. So how much is plus two of calcium?

[00:26:47]Listen in peace and write. The next one is oxygen. We know, right? Dear ones, it is one oxygen minus two. Now let me ask you something. This total has no charge, so it should be zero. Let's give the charge of each of them in the way that it becomes zero. I gave plus two oxygen I gave minus two You look, minus two of one oxygen, right? So how many oxygens are there here? There are three oxygens, minus two of one oxygen. So there are three oxygens here. So the total oxygen is minus six.

[00:27:25]Now to be zero, we need to be plus six. Calcium plus two. If calcium plus two, then to be plus six, then how many carbons should be correct? Plus four and plus two. Here, plus six oxygen alone minus six when you add both together, total zero is easily found like this or easily found loved ones.

[00:27:54]My mind tells me that there are those who do not understand this.

[00:27:57]For those who do not understand and those who half understand, let's find out the CAC of each one.

[00:28:02]First, let's come to calcium. Calcium is a second group element.

[00:28:07]Calcium is a second group element.

[00:28:10]How much oxygen state of calcium have I given?

[00:28:12]I am giving plus two oxygen.

[00:28:16]You know the oxygen. You know the loved ones. How many oxygens are minus two. Okay so. The total should be zero. You see, the charge of one oxygen is minus two. So there are three oxygens here now. So the total there is minus six. Now, if the total charge here is zero, there needs to be plus six. If calcium is plus two, then to be plus six, calcium has plus two. Now, if it is plus six, how much more carbon is needed to be plus six? So, let's find out everyone's oxidation state like this.

[00:28:52]Okay, I believe you understand. I believe you can find it very easily.

[00:28:57]You understand.

[00:29:01]Okay, with the belief that you understand, now let me move on to the next point.

[00:29:04]Dear friends, are you ready to listen?

[00:29:06]Now, one fact that I am going to tell you is that the oxidation number increases, that is the oxidation state. When we say oxidation number, we mean oxidation state.

[00:29:22]What do we call the action of increasing oxidation number? It's called oxidation.

[00:29:28]I heard that oxidation was once a question for the PSC exam. When this question came up for the PSC exam, it was called oxidation. In Malayalam it is called oxidation. Malayalam Oxidation Oxidation is the process of increasing the oxidation number. Pay attention to the same thing.

[00:29:56]Oxidation is the process of releasing electrons. Oxidation is the process of releasing electrons. So tell me again what is the special feature of the oxidation number. The process of increasing the oxidation number can be called oxidation. The process of donating electrons can be called oxidation. Similarly, the process of adding oxygen can be called oxidation. The process of adding oxygen can be called oxidation. So the process of increasing the oxidation number is called oxidation. The process of removing hydrogen is also called oxidation. The process and the process of removing hydrogen are called oxidation. Together, the action of increasing the oxidation number, the action of giving up an electron, the action of adding oxygen, the action of removing hydrogen. What is the name of all these? The action that takes place at the anode is this previous. The action that takes place at the anode is oxidation. Which is oxidation? If you ask what action takes place at the anode, it is oxidation. The next point to pay attention to is the name of the atom that undergoes oxidation. Reducing agent In Malayalam, we call reducing agent in Malayalam. Redox agent. You heard that the action of increasing the oxidation number is oxidation. The action of increasing the oxidation number is oxidation. The action of giving up an electron is oxidation. Similarly, the process of adding oxygen is oxidation. Similarly, the process of removing hydrogen is oxidation. The process that takes place at the anode is oxidation. The atom that undergoes oxidation is called the reducing agent. I believe that many people who are watching this class have got this fact. I believe that you have written it down.

[00:32:25]Okay, ready. So, let me put it in that corner. Okay, okay, let this lie there. Let's take it at any moment.

[00:32:35]What can we do?

[00:32:36]Okay, now listen to the next point.

[00:32:40]Share with me if you have any doubts. So, since we have studied oxidation, let's connect this and study reduction. Let's connect this and study reduction. There is no problem. Dear friends, what should you look at to study reduction? First, isn't reduction the process in which the oxidation number increases?

[00:33:00]Oxidation, or the process in which the oxidation number decreases? We can call it reduction in Malayalam. Reduction in Malayalam is called reduction in Malayalam. Reduction in Malayalam is called reduction in Malayalam. The process in which the oxidation number increases is oxidation. Oxidation, or the process in which the oxidation number decreases. The decreasing process is reduction or reduction. Now oxidation is the process of giving up electrons, but the process of accepting or gaining electrons is the process of accepting or gaining electrons. Reduction or reduction is not complete. Isn't oxidation the process of adding oxygen? Then, what reduction or reduction is the process of removing oxygen? Don't forget, dear ones, oxidation was the process of removing hydrogen, but if you ask which process is adding hydrogen, it is also reduction or reduction. Now, the process that takes place at the anode is oxidation. Isn't it correct? The process that takes place at the anode is oxidation. So, tell me, which process takes place at the cathode? The process that takes place at the cathode is reduction or reduction.

[00:34:34]Reduction or reduction is the process of accepting or gaining electrons.

[00:34:36]Dear ones, think about it.

[00:34:39]What did we call the atom that underwent oxidation? The atom that underwent oxidation? What did we call the atom that undergoes oxidation? The name we call the person that undergoes oxidation is reducing agent. The name we call the person that undergoes reduction is oxidant or oxidizing agent. Don't turn around. The name we call the person that undergoes oxidation is reducing agent. That is, the name we call the atom that undergoes oxidation.

[00:35:45]The name we call the atom that undergoes reduction is oxidant. Okay, so I have given you so many points here about oxidation and reduction. Okay, so the oxidation number increases and the oxidation number decreases. The name we call the atom that undergoes oxidation. Correct reducing agent or reducing agent. Now the atom that undergoes reduction is oxidant or oxidizing agent.

[00:36:02]I have a belief that the agent will not forget. I have a belief that you have received this content.

[00:36:06]Okay, let me tell you something.

[00:36:08]Oxidation and reduction occur together.

[00:36:20]Oxidation and reduction occur together.

[00:36:26]The name of the reaction that occurs together is called redox reaction. If you believe that you have understood all this crystal clear, then we are going to ask the next question. If you have any doubts, you should share them with me. Okay, keep that in mind. Now, look at the question given below. Chemical equations are given. This question, which you are seeing on this screen right now, is very important. I have not seen it asked in competitive exams yet. But it is a good question that can be asked in our exam related to the topic called chemical reactions. Before asking, let's go ahead and study it. Isn't that smart?

[00:37:10]Okay, chemical equations are given.

[00:37:13]Calculate the oxidation number of the atoms and check whether these are redox reactions. This is The question lying in the SCR is the question lying in the SCR. I have brought it to you here.

[00:37:27]How do we do this first? Let's first move this question up. Let's move this question up. That's it.

[00:37:37]I can show you below.

[00:37:39]Okay, ready. Okay, very good. Okay. Now, let's find out whether the given reactions are redox reactions or not. No need for any tension. I want to teach you something. Let's first do a question here.

[00:37:55]Option B. Let's look at Option B. Let's look at Option B. Let's write Z plus 2 HCl. Geez. Zn Ca2 plus A2.

[00:38:19]I have written the reaction.

[00:38:20]Dear friends. Zn + 2 Acl Geez. Zn Cl2 + H2. So first, let's write the oxidation number of each of them. You don't need to worry about the number on the left side. You can delete it. You can delete all the numbers on the left side. Try it without it. It's enough to do without it. It doesn't matter if it is there or not. That's why, or maybe I heard something like this, when you go to write the Option PSC exam, the question is the number between the two. We call it the stoichiometry coefficient. Remove the stoichiometry coefficient and write this question on the question paper. ZDSSS +EDA.

[00:38:58]Now you can see the oxidation number of each one.

[00:39:00]Dear friends, zinc is standing alone. Isn't zinc right? Zinc is standing alone here. Always keep it written in your heart that if an atom stands alone, there is no one else with it. Is there anyone else with him besides Zink? No, if it stands alone, what is its oxidation number?

[00:39:24]Zero, you see, here is H2. Is there anyone else besides hydrogen with H2? No, then let's give how much of H2 and V. Let's give zero. I believe it's not difficult. I believe it's not difficult. Okay, now the next step is to come to HCA. Dear friends, don't put an X in it and find it yourself. I taught you a while ago. Tell me how much hydrogen is in HCl. If it's plus one, it should be zero. If it's zero, it should be zero.

[00:39:59]How much chlorine is minus one? Right? If it's zero, chlorine is minus one.

[00:40:07]Now listen calmly. If you have any doubts, ask me.

[00:40:13]Come to ZDS. Let's give those who know first. Let's give those who know.

[00:40:18]You can give them directly. ZDS. There is chlorine. How much chlorine is in one chlorine? Dear friends, how much chlorine is in one chlorine? Correct minus one. I will give you minus one. We know the total. The sum of the oxidation numbers must be zero. So we have given that one chlorine is minus one. So how many chlorines are there here? There are two chlorines. There are two chlorines. So there are two chlorines here. So the total should be minus two to zero. If it should be plus two, then you tell me what the charge of zinc will be because we know that its total charge is zero. So if one chlorine is minus one. So if there are two chlorines, then it should be minus two. If it should be zero, then how much zinc will be? Clear, isn't it clear? So we have found out for everyone.

[00:41:12]Zero.

[00:41:15]One chlorine. My one.

[00:41:20]Zn The oxidation number was zero.

[00:41:38]After the reaction, how much did it change to plus two? Before the reaction, the oxidation number of zinc was zero.

[00:41:48]After the reaction, it changed to plus two. More or less, so the oxidation number here is also there. So let's say that the process of increasing the oxidation number is called oxidation. So oxidation has occurred here. Now next, you look at hydrogen.

[00:42:10]Dear friends, how much hydrogen was plus one before the reaction? First, after the reaction, how much did it change to zero? Look at the reaction.

[00:42:22]First, it changed to plus one. After the reaction, it became zero. So plus one has decreased to zero. So the process of decreasing the oxidation number is called reduction.

[00:42:43]So oxidation has occurred here. Reduction has occurred. So there is no change in chlorine.

[00:42:48]So we only need to consider chlorine because Mynavn Myva both should consider this up.

[00:42:52]The question is whether there is a change here or not. Is there a change in the oxidation state or not? The oxidation number is increased, the oxidation number is decreased, the reduction is also happening. So in this one reaction, in this one reaction given above, oxidation is also happening, reduction is also happening. So since oxidation and reduction are happening, what chemical reaction can we call this? Correct redox reaction. Let's call it a redox chemical reaction. It's clear. It's a redox chemical reaction or a redox reaction.

[00:43:37]Because there is oxidation and reduction happening there. Okay, if that's the case, let's move on to the next quest. The next quest is this. FE plus 2ACA2. I don't want to write HCACA gives FEC A2PA2SA2+A2. Let's see how we can do this.

[00:44:10]We can write things like "We know that we don't need to worry about our loved ones" first. F stand alone. I just said it a while ago. What would be the oxidation number of an element if it were standing alone? Zero here H2 you look standing alone. E2 standing alone how much will his charge be zero clear right now come to the next HCl dear ones HCl hydrogen we know plus one if it should be zero if it should be zero how much will be chlorine dear ones minus one clear now next is FCA2 one chlorine minus one so there are two chlorine so total then how much will be minus two if it should be zero if it is FE then how much more should it be how much more will it be zero plus two got everything got everything clear now let's see first let's see EF before the reaction FE iron charge was zero but after the reaction how much did it change to plus two Apo's faith went from zero to plus two. Since the oxidation number has increased more or less, what can we call that reaction? Let's call it oxidation. Is it clear? Now, the next hydrogen knock reaction was plus one before the hydrogen knock reaction.

[00:45:36]It was plus one before the hydrogen knock reaction. After the reaction, how much did it change to zero?

[00:45:39]Hydrogen was plus one before the reaction. After the reaction, it changed to zero. So, it decreased from plus one to zero. So, what happened there? Reduction or reduction occurred.

[00:45:54]So, in this given reaction, oxidation has also taken place. Reduction has also taken place. So, what can we call that reaction? If oxidation and reduction have taken place, it is a redox reaction. Is it clear? Is the fact okay? Here, oxidation has taken place. Reduction has also taken place. If oxidation and reduction have taken place in a chemical reaction, we call that chemical reaction a redox reaction. What to call then, with the belief that that fact is okay with you, let's go to the next option, okay dear ones, the next option, CS, this is a good question to ask, now if you ask this, don't get carried away, don't throw it away for any reason, dear ones, next, look here, you CS, you're going to pass, you're going to pass, so how can we do it, everyone, no one is standing alone there, so jump in and give it zero, don't you?

[00:47:05]You have to look first, let's go to the first one, calcium, we know that calcium is an element that comes in the second group, so what is the oxygen state of the element that comes in the second group, I just said a little bit, plus two, then I'll give calcium plus two, okay, plus two, plus two, now next, you look at oxygen, it's in it, oxygen is in it, minus one oxygen, so let's take the total here as zero, let's take the total here as zero, okay, then look, minus one oxygen, so there are three oxygens here. So if the total is minus six to become zero, we need to add plus six.

[00:47:52]Calcium plus two is there.

[00:47:55]If it is plus six, how much carbon will it be? Then it will be plus four. Okay, carbon plus four will be okay.

[00:48:02]So you have got the oxidation number of everyone there. Calcium plus two. Carbon plus four is oxygen minus two.

[00:48:09]Now, let's come to calcium oxide.

[00:48:15]Dear friends, one oxygen in it is minus two. We know that one oxygen is minus two. If it is minus two, then it should be zero. If it is zero, then how much calcium will be plus two. We already know that it is an element that comes in the second group.

[00:48:31]Calcium will be plus two. Let's go to the next carbon dioxide.

[00:48:35]Given that one oxygen is minus two, one oxygen is minus two. But there are two oxygens there. So 2 is my two my four. So if the total is zero, then how much carbon will it be? It will be plus four. If it is zero, then it should be plus four. I believe that it is clear. Okay.

[00:48:55]Okay, everyone, now let's see.

[00:49:00]Before the reaction, calcium's plus two.

[00:49:07]After the reaction, calcium's plus two is neither more nor less. Before the reaction, plus two is neither more nor less. After the reaction, plus two is neither more nor less. Similarly, before the reaction, carbon's plus four is neither more nor less. After the reaction, carbon's plus four is neither more nor less. Clear, right? Before the reaction, oxygen is minus two. After the reaction, oxygen is minus two. So, here, neither the oxidation number of anyone has increased nor decreased. Therefore, oxidation has not taken place. Reduction has not taken place. So, since oxidation and reduction have not taken place here, the reaction given above was not that or not. This reaction written as C S T P C E O Geess Can you cross-check whether it is a reaction or not? Do something like this and see how many people comment under this video. Let's see how many people comment under this video.

[00:50:18]Okay, then ECAC will look at this reaction. Is this in the SCR? That's why I made it. It is not a redox reaction.

[00:50:25]So, how do you find out if a reaction is a redox reaction or not? Do the option. Now, I will give you a question in the same way.

[00:50:38]H2 plus I2 GSH1. You have to find out if it is a redox reaction or not. So, I have given two questions to the work. If you have watched the video and are sure about your opinion, then you should comment below this.

[00:50:53]Many people are not commenting.

[00:50:56]You just have to watch it like a teacher who teaches you your loved ones. I hope you will comment below this video after you have confirmed your opinion about the class. I hope you will share this with your other friends. Okay, let's move on to the next question. Okay, this is the last question.

[00:51:11]Let's wind up today's class by doing this quiz.

[00:51:12]Below are the statements given. Write whether these are true or false.

[00:51:17]One, oxidation is the process of increasing the oxidation number. We have learned that oxidation is the process of increasing the oxidation number.

[00:51:24]That is true. Two, oxidation is the process of decreasing the oxidation number. That is false. The process of decreasing the oxidation number is reduction. Isn't that the process of increasing the oxidation number? Oxidation. The process of decreasing the oxidation number is reduction. In a chemical reaction, the oxidant is reduced. True. In a chemical reaction, the oxidant is reduced. That is, the person who undergoes reduction and reduction is called the oxidant. The person who undergoes reduction is called the oxidant. Then the person who is reduced is the oxidant. Correct. In a chemical reaction, the oxidant is oxidized.

[00:52:09]False. The person who undergoes oxidation is called the oxidizer.

[00:52:19]So, in a chemical reaction, the person who undergoes oxidation is called the oxidant. The oxidizing agent is oxidized.

[00:52:27]Okay, so there are three questions.

[00:52:30]We have done all three correctly.

[00:52:34]Look at the oxidation number of the compound sulfur given below.

[00:52:43]You can easily do it with or without the X of sulfur to see the oxidation number of sulfur.

[00:52:44]You can do this for work. You should do these questions even if you are sure. There will be questions for the exam. There have been questions from this chapter and there will be more.

[00:52:53]So I hope today's section was useful to you. I hope you have written a comment related to this video below. I hope you have understood the class.

[00:53:05]Thank you.