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Trapezium geometry
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901 Aufrufe3Likes1:05:09AamraSikhiStudyOriginalveröffentlichung: 2026-05-22

In a trapezium ABCD where BC is parallel to AD and EF is parallel to AD, corresponding angles are equal (angle C = angle J = angle X = 50°), and consecutive interior angles sum to 180° (theta + 50° = 180°, so theta = 130°). Using the quadrilateral angle sum property (360°), the unknown angle Y can be calculated as: 50° + Y + 120° + 130° = 360°, yielding Y = 60°.

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