When solving radical equations, squaring both sides can introduce extraneous solutions that do not satisfy the original equation; for the equation √(5x - 4) = -6, squaring both sides yields x = 8, but substituting back gives √36 = 6 ≠ -6, demonstrating that the original equation has no solution since the principal square root cannot equal a negative number.
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The equation that breaks the rule of Mathematics ! | Can you solve ?Hinzugefügt:
Hello, welcome back once again.
Today, we have this interesting radical equation problem.
The square root of the quantity 5x - 4 is equal to -6.
In this video, we're going to find the value of x that will satisfy this equation, if possible.
Now, let us take note of the following.
For real x, right?
We have that the square root of x is greater than or equal to zero, right?
But here, remember we're solving for the real value x.
And we have that the square root of this quantity here is negative. So, it shows that this is out of this domain, right?
So, we can conclude from this that there is no solution, right?
There's no solution.
Okay, awesome.
But [snorts] what happens when we square both sides of this equation?
Okay, so let's try that.
If you square both sides to get the square root of 5x - 4 whole squared is equal to -6 whole squared.
From here, this square gets cancelled with the square root.
Then, we have 5x - 4 is equal to -6 squared will give us positive 36. Awesome.
Now, we add 4 to both sides of the equation to get 5x - 4 + 4 is equal to 36 + 4.
From here, we get 5x is equal to 40, right? So, divide both sides by 5.
Here, this cancel. We get x is equal to 8.
So, with this squaring of both sides we have a solution.
But I want to let you guys know something. Sometimes squaring both sides of an equation will break in an external solution. For example, we have that X is equal to 2. If we square both sides, we get X squared is equal to 2 squared, which is 4. If you now try to solve for X here, we now have X is equal to -2 or X is equal to +2. But the original solution here is 2. So, you see, with the means of squaring both sides, we now have external solution in this case.
So, this may be external solution. But let us find out if this will satisfy the given equation. For the left-hand side, we have that the square root of 5x -4 must be equal to -6. So, when X = 8, we get the square root of 5 * 8 -4 is equal to the square root of 5 * 8 is 40 -4. This is equal to the square root of 36, which is equal to +6.
But the +6 is not equal to the left-hand side, which is -6.
So, this is not a solution. It is extraneous, right? So, don't be surprised. Square root of 36 is just the principal square root.
So, it should not be -6.
So, that's why this falls out of the solution.
Therefore, what should be our conclusion? Our conclusion is that there's no solution.
Both real and complex.
No solution.
Both real and Both real and complex.
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