This video demonstrates how to find an unknown length X in a geometric figure by applying the isosceles triangle property (equal angles imply equal sides), rectangle properties (opposite sides are equal), and the Pythagorean theorem (a² + b² = c²). The solution involves recognizing that triangle BCP is isosceles with BC = CP = 10, then using the Pythagorean theorem in triangle BCQ to find CQ = 6, and finally calculating X = DQ - PQ = 5 - 4 = 1.
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Can you find the length X?追加:
Can you find the length x?
Angle CPB It will be equal to angle ABP That will be theta.
This angle is theta.
And now in triangle BCP It is B C P This angle is theta.
This angle is theta.
That means BC and CP, they will be equal.
And BC is 10.
So CP it will be also 10.
CP is 10.
And now from point B if we make a perpendicular on CD Suppose this point is Q, then ABQD it will be a rectangle.
So, BQ it will be equal to AD that will be eight.
And DQ it will be equal to AB that is five.
So, BQ is eight.
And DQ is five.
And now in triangle BCQ BQ squared plus CQ squared it will be BC squared.
And BQ is eight squared plus CQ squared.
And BC is 10 squared.
And 64 plus CQ squared is 100.
So, CQ squared is 100 minus 64.
And CQ squared is 36.
That means CQ it will be six.
CQ is six.
And now PQ is CP minus CQ.
And CP is 10 minus CQ is six.
That will be four.
PQ is four.
And DP plus PQ is DQ.
And DP is X plus PQ is four.
And DQ is five.
So X will be five minus four.
That means X is one.
>> [music]
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