To solve exponential equations with variables in exponents, apply laws of indices (a^(m+n) = a^m × a^n, a^x / b^x = (a/b)^x) to simplify the equation, then take logarithms of both sides and use log properties (log(a^b) = b·log(a), log(a/b) = log(a) - log(b)) to isolate the variable and find the solution.
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Olympiad Mathematics | Germany | Can You Solve This?追加:
You're ready? Let's provide a solution to this.
This is an exponential equation, but then it can be confusing.
- 3 to the power of x + 4 This is giving us zero. So, what do we do?
We're going to apply our laws of indices.
One of the laws of indices says that a to the power of m + n is the same as a to the power of m * a to the power of n.
So, using this identity, I mean using this law we're going to express this as 4 to the power of x * 4 to the power of 3.
Then, we do the same thing here. We have 3 to the power of x * 3 to the power of 4.
This is equal to zero.
Okay?
So, from here now, we are going to have 4 to the power of x um multiplied by 4 to the power of 3 is 64.
- Here, we have 3 to the power of x and then 3 to the power of 4 is 81.
This is equal to zero.
Now, if you look at this, we have x spread out. We have x here and over here.
So, the first thing we do is to bring terms without x together and then bring terms with x together.
So, I would divide this by 64 and divide this by 64.
So, that this can take this out.
And on the left-hand side, we have um On the left-hand side, we have just 4 to the power of x.
Then, we have minus 3 to the power of x.
Okay, we have 81 over 64.
This is equal to zero.
So, from here now, remember I told you we have to bring terms with x together.
So, I'm going to divide all through by 3 to the power of x.
Okay, so um this will cancel out.
So, we now have 4 to the power of x over 3 to the power of x minus 81 over 64 to be equal to zero.
Now, this is negative 81 over 64, so we can take it to the other side.
So, that we can have 4 to the power of x over 3 to the power of x.
Like this, will be equal to zero plus this, and that will be 81 over 64.
So, what do we do next? Apply another law of indices.
I told you we're going to look at laws of indices.
Here, we have the same powers. So, there's a law that says if you have the same powers, you can, you know, combine the base, you know, and let them have the same power.
So, we have 4 over 3.
Then we have x as the power for both of them.
This is equal to 81 over 64.
Now, the base on the left and on the right are not the same.
So, there will be need for us to take the log of both sides. So, let's do that.
Okay, so like I said, we're going to take the log of both sides. So, we have log 4 over 3 to the power of x equals log 81 divided by 64.
So, what do we do? Remember this law.
Log a to power b is the same as log b log a.
Okay, so in this case, the unknown is x.
So, to find the unknown, we have to bring it down based on the law that I just explained.
So, we have x and we have the log of 4 over 3 and it's equal to the log of 81 over 64.
And there's something else we can do from here.
You know that log a divided by b is also the same thing as log a minus log b.
So, if this is true, then I'll write these two in this form.
So, we have x into log 4 minus log 3 and it's equal to log 81 minus log 64.
Okay, this is um done based on the law that I explained earlier.
To get the value of x, divide this by log 4 minus log 3.
You know, this will cancel the whole of this.
But then the other side will divide by the same thing which is log 4 minus log 3.
So, here we have x left and that x will be equal to log 81 minus log 64.
This is over log 4 minus log 3.
Now, if you decide to stop at this point, it's okay.
But then, we can, you know, press a calculator and approximate the value of X.
So, what do we do? Our X will be from my calculator, log 81 minus log 64 is approximately 0.10 23.
This is an approximated figure.
Then, log 4 minus log 3 is approximately 0.12 49.
So, the approximated value of X will now be equal to Um we have 0.819.
That's this divided by this.
So, this is our approximated value of X.
Now, let's go put it put this value back into the equation very quickly.
Okay, so this is the original equation.
And our value of X is approximately um 0.819.
So, this means that we have 4 to the power of 0.819 plus 3 minus 3 to the power of 0.819 and plus 4.
This will be equal to what? That's what we want to know.
So, here we have 4 to the power of this plus this 3.
3.819 Then minus here, we 3 to the power of 4.
point 819. That is the addition of that.
I mean the addition of the power here.
So if we go on from our calculator, 4 to the power of 3.819 is approximately 199.19.
199.19.
Then here we have approximately 3 to the power of 4.
819 is 199.
18, right?
So the difference here is 0.01.
And ordinarily we're expecting zero.
But because the value of x that we're using is an approximated value, we cannot get the exact zero.
But this is still correct because the value, which is approximately 0.819, truly satisfies the equation.
See you in the next video.
But make sure you subscribe, you like, you comment, and you share.
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